安徽省六安第一中学2026-2027学年高三上学期第四次月考数学试题

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六安一中2027届高三年级第四次月考

数学试卷

 

时间:120分钟               满分:150分

一、单项选择题:本题共8小题,每小题5分,共40分. 在每小题给出的四个选项中,只有一项是符合题目要求的.

1.复数eqIdf6cd9ed5c28611a0d50f9731078f4bca,则eqId0d8b9ad2fcfff3dd546c5fdbedfe6238在复平面内对应点在(    )

A.第一象限   B.第二象限    C.第三象限   D.第四象限

2.若eqId65d1d292ef200c73532b84de2410c53a,则“eqIdc3beeff6e99727230196ae409fc18c08”是“eqId301c3d4cbe02776b719e0f0406db38c3”的(  )

A.充分不必要条件  B.必要不充分条件

C.充要条件                         D.既不充分也不必要条件

3.设数列eqId83cf38189d5cbf627d2b82ac0eb76006满足eqId23093a3f4c23494a943e3957596fee92,且eqId0ea8d0e50065114b05ef2dc1ea1129cf,则eqIdafd21f4cb498101d26b4aaa2e1a6addc(   )

A.eqId274a9dc37509f01c2606fb3086a46f4f            B.eqIdf30d314a642667fef559032264647366                 C.eqIdf89eef3148f2d4d09379767b4af69132             D.3

4.已知向量eqId7a2f4b1178f68bd147d1a2a6acd04435,eqIdc94075193c11fe43f2396cff5a485054满足eqId70e310702748855c3edccd151aae0143,eqId6b532ff725ed321148010644e7f0e05f,eqIdc17efa486730dd08dc535c1145a579ce,则向量eqId7a2f4b1178f68bd147d1a2a6acd04435与eqIdc94075193c11fe43f2396cff5a485054的夹角为(     )

A.eqIdac1a63ab608517bb10aa036783dfb51f          B.eqId15615de1a6df206dbd081251f676578e                C.eqId290710d643ab6cd3b9edd73815b1d8ee             D.eqIdc0211da37e92f915e781691296578ba0

5.已知eqId649646a673a45fa6c679ffa8109c0bf6是偶函数,则eqId380bbacf854e30e2e747fc286d2b9997(     )

A.eqId274a9dc37509f01c2606fb3086a46f4f            B.eqId61128ab996360a038e6e64d82fcba004                 C.eqId3389f53711264b0acba3ba6019f8b908             D.eqIdf89eef3148f2d4d09379767b4af69132

6.若数列eqId83cf38189d5cbf627d2b82ac0eb76006满足eqId039e4fe671d61e59b96ee525c9df43e8,eqId92e21c3910cd909d8c795b25feef87a8,则eqId29d8bcf37114e33abb06bb53be67113d的值为(     )

A.eqIde8d02ea8c4988c5c28ab93f0d70fb55a             B.eqIdd07ae0b4264da6a8812454ffd2f20d94               C.eqId2d0b71b8d2c183154221f717ce09077b             D.eqId8da45c443af7994a26ffa9d8894e7262

7.已知实数满足:,则的值是(     )

A.eqIde8d02ea8c4988c5c28ab93f0d70fb55a             B.eqIdd07ae0b4264da6a8812454ffd2f20d94               C.eqId2d0b71b8d2c183154221f717ce09077b             D.eqId8da45c443af7994a26ffa9d8894e7262

8.若点eqId1dde8112e8eb968fd042418dd632759e为eqId15c0dbe3c080c4c4636c64803e5c1f76的外心,且满足eqId930d575e72cfd1e6dc1ebd63d3e98137,则eqId721e29b775e696045f44a4b1e7f74ef2的最大值为(     )

A.eqId827ccf0c04aa941ba20d5f4c6068b46b             B.1                  C.eqIda7ffe8515ff6183c1c7775dc6f94bdb8              D.eqId18483c9c195ecd922772527fa85c0fcb

二、多项选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求,全部选对的得6分,有选错的得0分,部分选对的得部分分.

9.已知,为复数,则下列说法中正确的有(    )

A.  B.若,则

C.若,则 D.若,则

10.已知eqIdce613eaa5df46a50174085ef5d1087fb,且eqId27def65b46225ac64b02a19aa5911489,eqId8c0d2b7d558996d2e2a2ed1ce3011d7e,eqId016e3bb82b9f4e58e81f192de82fadc9成等差数列,则下列说法正确的是(     )

A.eqId652d6397728f49fe43fd061bc57607c7                        B.eqId4b93952044f5f1c1734aa9545d04bdf6

C.eqId27def65b46225ac64b02a19aa5911489,eqId2dd30334193d24c291ac481232bba3b8,eqIdacba71db7c33599b1d0ca0a3e24f0fb6不可能成等差数列  D.eqIda5139456a0bb17071a05c257aa5624a7,eqIdd4e61f5ee4b08a93a35728cb574243c4,eqId24c7a523628b42d031da268096775e9f不可能成等差数列

@@@d48af892-20de-4f14-9e41-96d770848fb011.某公益组织一直关注青少年的成长,该组织的会标设计灵感便来源于“成长”一词的拼音首字母eqId70c688cf3eaf7bf0fac09e2bcf7e0d01,该会标的大致轮廓为如图所示的一个以eqId1dde8112e8eb968fd042418dd632759e为圆心、eqIdf52a58fbaf4fea03567e88a9f0f6e37e为直径的半圆,和一段eqId0d8b9ad2fcfff3dd546c5fdbedfe6238形折线eqId411b38a18046fea8e9fab1f9f9b80a5f组成, 其中eqIdbba7732ffb8fa3c714d1ca1924cb2103. 现有两动点eqIdf6bce3d91ca23b86d8c6625f2632e437在圆弧eqId16d65cecaf8a3dc2953f4109c75a981e和线段eqId8cca04b2a2b61d62a809776670a60c09(包含端点)上运动, 则下列说法正确的有(      )

A.eqIda3d87446c9ef0230285d9b08127fce5c的最大值为eqIdf2a04c700a775406b4b2f5a27c88f871

B.若eqId8ac09354f448248f1fda4fdeb910b93f,则eqId2cbc8207d75822c19a9aad4aa0c18814的取值范围是eqIdab6f4285af622b69648780bde9ddf7bf

C.eqId5e7a97b93b5b39e4bab75222e6b36c63最大值为 2page number 0

 

 

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D.若eqId1d42a9c373d043838ec71e8e1b004d56,则eqId4bad299e2782c072d27e1c54422cc8fc在eqId083a20abb668d4c26fe5039bd108b40a上的投影向量模长的取值范围是eqIde046dd83fe3d2bca3e142f38930b05b5.

 

三、填空题:本题共3小题,每小题5分,共15分.

12.化简eqId2168a454d83ada881a8a2cbaf4fa6610__________.

13.已知eqId7c67cab5c65842970779a28ada3a405c,eqId1d2cdfeeac24caf327d5f744ba1c9053,则eqId72bd9ece0b06833975db0d9d5c824a01______.

14.将关于eqId81dea63b8ce3e51adf66cf7b9982a248的方程eqId85fc19a717d1bb33e68fac476a01c89e(常数eqIda4456675a5dbe545462a22cef9aca8fe,eqId8326eccb6fccce4cad9ff889bf0febbe)在eqId5ed2f490aac02631c2ed9e6b76354a49上的解从小到大排列构成的无穷数列记作eqIde976c0663fa749ca749f99842d21ca03,若eqIde976c0663fa749ca749f99842d21ca03是等差数列,且eqIde976c0663fa749ca749f99842d21ca03中属于区间eqId5265d99095b635f62c7915298ec0e963的项恰比eqIde976c0663fa749ca749f99842d21ca03属于区间eqId4f7f25d9a3327e5fb7bef56462358917中的项少2项,则eqId074c228ffc7b1e306f8410afe7bc4b5c的取值集合为________.

 

四、解答题:本题共5小题,共77分. 解答应写出文字说明、证明过程或演算步骤.

15.(本小题满分13分)

已知等差数列eqId83cf38189d5cbf627d2b82ac0eb76006的前n项和为eqId08eb71ecf8d733b6932f4680874dbbf3,且eqId2693734765399876e9e93cdb110231c4,eqId3aa54a479e4178d698818f69d859fe13.

(1)求eqId83cf38189d5cbf627d2b82ac0eb76006的通项公式;

(2)数列eqId034ba25825c13725931c483aa47c9363满足eqId0a5c304f7e10b322731f7ecab57fb08a,eqIdfa3b1a577a8126904e8f31a75362b1cb,求eqId034ba25825c13725931c483aa47c9363的通项公式.

 

 

 

 

16.(本小题满分15分)

如图,设eqId46c092d69df76faf1e2133dc96b466ef是平面内相交成eqIdbe6a6301878fed2a01413020b27310a5角的两条数轴,eqId10814bc3db929e79874befe96cf4e3d4分别是与eqId81dea63b8ce3e51adf66cf7b9982a248轴、eqIdd053b14c8588eee2acbbe44fc37a6886轴正方向同向的单位向量.若向量eqIde5253a9a71037d60059b60237824193b,则把有序数对eqId0203b006524305c3d8ee0b6c34cd872b叫做向量eqId91174b2336306191ba275a87864172b7在坐标系eqId20a9e1eb4c3226489d1344321b10b7de中的坐标.假设eqIdff9bb23c6c5930773107a9e89fd79376.

(1)设eqIde6d9a25d20b86c2583f6c071091e8e3a、eqIdf015b086875c4b5f9cfa53929d9bffd9,若eqId5963abe8f421bd99a2aaa94831a951e9、eqId7f9e8449aad35c5d840a3395ea86df6d、eqIddad2a36927223bd70f426ba06aea4b45三点共线,求实数eqId294f5ba74cdf695fc9a8a8e52f421328的值;

(2)是否存在实数eqIdb6a24198bd04c29321ae5dc5a28fe421,使得eqId82973c2b6d1c407318545f1c0f32ec2e与向量eqId9b41e851f57a03deac4f7093165ef8e6垂直,若存在求出eqIdb6a24198bd04c29321ae5dc5a28fe421的值,若不存在请说明理由.

@@@e0efe82f-23f6-4c1a-875b-24d24e1348b7

 

 

 

 

17.(本小题满分15分)

@@@272f3bc1-fd7f-45a5-8f53-c5ced46a47fa在锐角中,角eqId5963abe8f421bd99a2aaa94831a951e9,eqId7f9e8449aad35c5d840a3395ea86df6d,eqIdc5db41a1f31d6baee7c69990811edb9f所对的边分别为a,b,c,且eqId8e258ab9e600435b37465092243d99f6,eqIddca3159cc2ad67661426b66f6bace0d2,eqId73465a1f9aa03481295bf6bd3c6903ac为eqId15c0dbe3c080c4c4636c64803e5c1f76的垂心,eqId5963abe8f421bd99a2aaa94831a951e9为外接圆半径.

(1)求eqId5963abe8f421bd99a2aaa94831a951e9;

(2)证明:;

(3)求的最大值.

 

 

18.(本小题满分17分)

已知函数eqId78a3f62a6a1e1bc9b7fbdb9a1658a6f1的极值点构成数列为eqId51bff410a80f0a7d1254e23cf9de3106.

(1)求证:当eqId97720b60cd5317f0fd8728c383ff0e12时,eqId7293652365f644a6423158607331bbb6;

(2)求函数eqId78a3f62a6a1e1bc9b7fbdb9a1658a6f1的单调区间,并求eqIdc1fd18a909cecbaee7115d6b15631d83通项公式;

(3)若不等式对一切eqId36a11b8baa52b0907ec8638530f1a388恒成立,求eqId0a6936d370d6a238a608ca56f87198de的取值范围.

 

page number 1

 

 

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19.(本小题满分17分)

定义:设函数eqId0afb80007983e5b99dcdeebf87d18ff4在区间eqIde105760638b22b26ff8bec4354255e4c上有最大值eqIdac047e91852b91af639feec23a9598b2,最小值eqId294f5ba74cdf695fc9a8a8e52f421328,则称eqIdf511880834175ac4546ea7cc7758b1b0为函数eqId0afb80007983e5b99dcdeebf87d18ff4在区间eqIde105760638b22b26ff8bec4354255e4c上的“最值距”,eqId0ed83485b04357536c07c06cdd74f149为eqId0afb80007983e5b99dcdeebf87d18ff4在区间eqIde105760638b22b26ff8bec4354255e4c上的“中值”.

(1)请直接写出eqId9a45f09624affe7f6158b42b7d9c4f61在区间eqIde17fb106c200fea9c75789071108d1bb上的“最值距”和“中值”;

(2)求证:不存在区间eqIde105760638b22b26ff8bec4354255e4c使函数eqId301d0bff9e0e04c2cfdbd20f4ad4d420在区间eqIde105760638b22b26ff8bec4354255e4c上的“最值距”只与eqId2c94bb12cee76221e13f9ef955b0aab1有关;

(3)若eqIdc876e751d81032c8070c06da693845c5与eqIdfa31c029484ec102b3ee6b7ce91259fe在区间eqIde105760638b22b26ff8bec4354255e4c上的“最值距”相同,求:eqId02f196f6236188084f3b2c9f2b68c05c在区间eqIde105760638b22b26ff8bec4354255e4c上的“中值”.

 

 

 

 

 

 

六安一中2027届高三年级第四次月考

数学试卷参考答案

1.D【详解】eqId2e77d08de377aa52085dca2e5ee8bd04, 故选D

2.A【详解】“eqIdc3beeff6e99727230196ae409fc18c08”可以推出“eqIdcec0c0f2ce3b37b5a495066f951a4530”,当eqIdd2a317ebe6d8b5de335b06cb8198dd47,满足eqId301c3d4cbe02776b719e0f0406db38c3,不能推出eqId9e669c00f1e4e6eac2ccde4d6f6c9cac,所以“eqIdc3beeff6e99727230196ae409fc18c08”是“eqId301c3d4cbe02776b719e0f0406db38c3”的充分不必要条件.故选:A.

3.A【详解】由eqId23093a3f4c23494a943e3957596fee92,且eqId0ea8d0e50065114b05ef2dc1ea1129cf得eqId8064ccff82e514db1b2aa8a0ad747c43,

故数列eqId83cf38189d5cbf627d2b82ac0eb76006为周期为eqIdb8860d9787671b53b1ab68b3d526f5ca的数列,所以eqId90625fcf55999c2098fb32581367b76e.

4.C【详解】因为eqIdfc1cde4efdb7b31eeeb9b98095866ead,则eqId77803b09195ce0df0d06c48e8791b295

解得:eqId16a11c78461c823371842d92a5c57c96,所以eqId7a2f4b1178f68bd147d1a2a6acd04435与eqIdc94075193c11fe43f2396cff5a485054的夹角为eqId290710d643ab6cd3b9edd73815b1d8ee

5.D【详解】函数eqIdd479a86a1711709b2d100fe4daf3e7cf的定义域为eqId0fb141842d8f7b20a1ee68a99fdee841,关于原点对称.

对任意eqId2ac1b64cb76717bd87cd068fbaf1cf6c,有eqId062197c443a0b593f95a70929f4bff03.由于eqId2ac1b64cb76717bd87cd068fbaf1cf6c且eqId9db3ed7e5249b5b547f1993c8e3ac67e,偶函数条件eqId76785106b85302fab1042342dfe9d3eb等价于eqId3dae08bb2f43b57d934c19b4a697c671,由指数函数的单调性得eqId93ceb348cb463852f63cb1c4691d6116,此式对任意eqId2ac1b64cb76717bd87cd068fbaf1cf6c成立当且仅当eqIda44d1b71578bf30436c7176aa688fbca.

6.B【详解】由eqIdc3464a1349abe4abcad185a56b911c8a及eqId92e21c3910cd909d8c795b25feef87a8得eqId9ae74bb6259a4ce9212c13a12c308c53,即eqIddf0e8155038857af22e2a31bfd946010,即eqIdbae0f93b8c343f3b3be6f970ada607da,所以eqIdc696ceabd10036fa7932bfa2fb9c8405,即eqId19a643885117f1df06a1a52ca74ef0c2为常数列,

又eqId758bf04c537de3f7a1c74799f96c55a6,所以eqId25b8ed577f6b1fa63af8df793203b6ed,即eqIdbd365ebdd2d7c33735a9c3a47dd40ff7,所以eqId7a11673c2d8166fc057ec79c94dcbd22,所以eqId2bac1f0582dcff4c98fd46bb6315bb4a.故选:B

7.C【详解】,则,即,令,则,令,为单调递增函数,故选:C

8.C【详解】设eqId7f6a9f66fff371d8ad889914e29918a9,

eqId3bb0617cdf819c331f8712db97883e41,eqId1beafc3511cc50a7415622b93f470c56,page number 2

 

 

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