【期中考前指导练习】2026-2027学年人教版数学九年级上学期第25-27章易错练习

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【期中考前指导练习】人教版第25-27章易错练习

学校:___________姓名:___________班级:___________考号:___________

一、单选题

1.下列方程中,两根分别为eqId395addb4439331615a7f220289d8b62c和eqId5ca7d1107389675d32b56ec097464c14的方程是(     )

A.eqId2dac77366c746161a381e0589d63e451 B.eqId65332a7ad556099b04d8250cefaa0c78

C.eqId52c5982838c13f0ec24306242f8d5e9f D.eqId8b2ca415ab67c51270589743526fadba

2.要得到二次函数eqId851deeab8e4eb44525d09f875c80338f的图象,需将eqId108c18cb76d7d34b05c991a644c8b136的图象(     )

A.向左平移2个单位,再向下平移3个单位

B.向左平移1个单位,再向上平移3个单位

C.向右平移1个单位,再向下平移3个单位

D.向右平移2个单位,再向上平移1个单位

3.已知反比例函数eqId07854693dd2e33f66030d6106eb6e0ee(eqIdf0a532e15e232cb4b99a8d4d07c89575为常数,且eqId44a4eaa80b44625890339d6a0065c241),若点eqId5c41e921734694f53b250b16b8926249,eqIdb3316464faa4c460d8ea308c194667a9都在该函数的图象上,则下列结论正确的是(    )

A.eqIdd169bec4e9c8a895eb7af42e8237e190 B.eqIdd5fe9adf12c8d9f3dc78b46b2d9a16f7 C.eqId19e81af897866d805ad30f4d7bfa3bb0 D.eqIdb661fffd4937990909dac0e9c4d3e085

4.若点eqIdaff9743e4c17c3ce80fcbbd65243a47e,eqIded040f6dc702e40e79ab32e201efe12d,eqIdf3131435a15069a6b7466cd9b42266df都在反比例函数eqIdb2880d0d781b4d1173b9212fa842b9c5的图象上,则eqIdc814128ea2139e33db94ea590e7c2223,eqIdaec19b68e3add9d5bfcc6269a1855b87,eqId291c25fc6a69d6d0ccfb8d839b9b4462的大小关系是(     )

A.eqIddcae962fec6ca82929f3ac218c3a4ce4 B.eqId382a7df4ba3c87825970bcd6848599b4 C.eqIde1310a7a80d1f8751a3f8cafe7f8c8b4 D.eqIdb4317817e09ea2b8a669f5a5217503c5

5.若反比例函数eqIded74c10da0e19653d92d717648552995的图象,当eqId9e541ea2f855f981c96207070683d388时,eqIdd053b14c8588eee2acbbe44fc37a6886随eqId81dea63b8ce3e51adf66cf7b9982a248的增大而增大,则eqIdf0a532e15e232cb4b99a8d4d07c89575的取值范围是(     )

A.eqIdf9412eb2931f9f75d199b94a1fe558e0 B.eqIdd20ea8c7c6af2a5cff13894c968cdf24 C.eqId21a56f4e1380569bc8bd3aabc8fa5730 D.eqId835c74bbb8c61dd2d2f008664a8c8810

6.已知二次函数eqId22e59da5115d0dafea24822245f92c48(eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183为常数),eqIdbb45f673c56a289ea78831c9237e8d20与eqIdf23d29646155e27b172ecdf263e2d702时的函数值相等,且它的图象与eqId81dea63b8ce3e51adf66cf7b9982a248轴的两个交点之间的距离为6,若点eqIdd5343f6dee6d12906b09ff03166350a5、eqIdc06d5758035f6a317e9629490a3c8846在该函数的图象上,则eqId8fd1f0ace9ca0b79929e73af6c201c2e的值为(     )

A.eqIdacbc6a613224461ade69362d46550474 B.1 C.eqId91498d22fa9e1bae4ee8399259d9cfd3 D.15

7.嘉淇准备解一元二次方程eqId2cbb8e932c825be3ec0e3d013c81493b,发现常数项“■”印刷不清楚,嘉淇妈妈看了该题的答案后说:“这个方程是有实数根的.”则印刷不清楚的常数项“■”可能是(     )

A.eqId5ca7d1107389675d32b56ec097464c14 B.eqIdd91e07104b699c4012be2d26160976a2 C.eqId6f8c4c029e552954bd493b49aeab82d5 D.eqIdcd3304e23f3b0f9569c4140ca89b6498

8.关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次方程eqId1c65ebeb20f264a2223ffd70e6ac6644,有下列四个结论:①若eqIdb8a454588e9beb97c69a0332a7c5c796是该方程的一个根,则一定有eqIdfd9e1fcd03b65563659fe40d47dc3af1成立;②若eqId5ae8cd75b68f412bf2b33e62258506bb,则方程eqId13fa32c1e926f40a0722d106563777ef有一根为eqId99c6875d552e9fff3c7d655f3a59b166;③若该方程的解为eqId707ea658f3a9359f5740d5aab48f7948和eqId5fac9575a5985527e283f7295fdaf72c,则方程eqIdf7cc27b5b2d918d1f28071b2bfb24ab7的解是eqIde55aa0a20848c37c1892c567b2315e04或eqIdb650820d7bed48ed67a2869ad8c65ff1;④当eqId9e10e1c43b86a8cd4360ca9b57232164,eqId39a38efe32b0f0306f1dd1158ac2bd6e,eqId5290494a1d1027898952b63bc99723a7时,方程一定有实page number 0

 

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数根.其中,正确的个数有(     )个

A.1 B.2 C.3 D.4

二、填空题

9.如图,已知点B在反比例函数eqId646e11d5bff57e56ce82c2339f2d71ce的图象上,eqId0f07aeaad7ee076170141958bc50c281轴于点A,连接eqIdb90e0f35eda1a729fed485f83da5ea9d,则eqIdb9ada0072e539afa0793b120eb2a262d__________.

@@@acf9098d-65c8-47d7-a2a9-f6d5253f8f1b

10.已知eqIde47fa086665315012831e66ab3a22993和eqId47b5ebdf14bd72d1693ebb5fca0411f6两点在反比例函数eqIdef854dfcbba9b7dedc1bc52f6332b011的图象上,若eqId19e81af897866d805ad30f4d7bfa3bb0,则eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围是_____.

11.抛物线eqId2f24a1fbeedf2f66af731fb62bfe92a4的对称轴是直线eqId4ec0618ae3a4fde6d6220010af229b9a__________.

12.一元二次方程eqIdde825075b31e40ba4ab3a742bd0cfc7f的两根分别为eqIdc814128ea2139e33db94ea590e7c2223和eqIdaec19b68e3add9d5bfcc6269a1855b87,则eqId5ceddc345bfa05b7c0c61ec02470188a的值是_________.

13.设eqId0877194ab8760f54c35527177b03ff93是一元二次方程eqIdbcd0b018a937c42db3e5f9226b5f9b12的两个根,则eqIdd5e838051afb670b58bf7c62b2ab7da9__________.

14.已知抛物线eqId737e6be32c76ae051aee5b3d9636c9ba与eqId81dea63b8ce3e51adf66cf7b9982a248轴交于eqId5963abe8f421bd99a2aaa94831a951e9、eqId7f9e8449aad35c5d840a3395ea86df6d两点,那么eqIdc26a46e7879436d532af3f4b6e258a81________.

15.若二次函数eqId8352b2e643a7ce605334f1b0e572bfb0中,函数值eqIdd053b14c8588eee2acbbe44fc37a6886与自变量eqId81dea63b8ce3e51adf66cf7b9982a248的部分对应值如下表:

eqId81dea63b8ce3e51adf66cf7b9982a248

…

eqIdacbc6a613224461ade69362d46550474

eqIdc95b6be4554f03bf496092f1acdfbb89

eqIdbdaa19de263700a15fcf213d64a8cd57

eqId61128ab996360a038e6e64d82fcba004

…

eqIdd053b14c8588eee2acbbe44fc37a6886

…

eqIdc95b6be4554f03bf496092f1acdfbb89

eqId81fb134b2b48acc99213fff6ccfee65f

eqId3edbd40e04e2a943051fa83d6e511add

eqId81fb134b2b48acc99213fff6ccfee65f

…

则当eqIdc1dbe0d4a121e1b69c2ad3b14d25d1e5时,eqIdd053b14c8588eee2acbbe44fc37a6886的取值范围是___________.

16.如图,二次函数eqIda90385c676848de67293e3ed6bc000fe(eqId20849c00c47cbdc43f18d53341b6c4e5)图象的一部分与eqId81dea63b8ce3e51adf66cf7b9982a248轴的一个交点坐标为eqIdcb442fb1fe1a5d9768cf11c3e1b7ec5b,对称轴为直线eqId9b384412acba251d87902ab928902f16,给出下列结论:①eqId73c21bd0bd90a89b7ff5ac0eacf612a5;②eqIdaa285de4d015f208441ffe9a84bbd780;③eqIdda68ff94b0877adb96abbc3e0fa52d86;④当eqId0b83a660527359758db64e6566466293时,eqIda57458464618fcf619375a93d3c66d69;⑤若点eqId2e0a28abd3f18a7d2aec9e526d73425e,eqId88444ca60dc1ff65c314195a520e92ec均在该二次函数图象上,则eqId1292c47f62023b747f1a4bd615c75284.上述结论中,正确结论的序号是_____.

@@@fbfedac6-a9f6-410d-b67b-70949235ce00page number 1

 

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三、解答题

17.解下列一元二次方程:

(1)eqIdc75cd53007a5eeeff2e7cb2ac0830807

(2)eqIdd8e4a08bab21b4d918f28f9d4475d529

18.已知抛物线eqIda90385c676848de67293e3ed6bc000fe(a,b,c为常数,且eqId20849c00c47cbdc43f18d53341b6c4e5)与eqId81dea63b8ce3e51adf66cf7b9982a248轴的一个交点坐标是eqId1d7a999c36de5c9a9ce876a4a56fa34c,顶点坐标是eqId8833ba3833480237f47774984958c01d.

(1)求该抛物线解析式中eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183的值;

(2)直接写出当eqId1c9d8f26bb5f53a17f9cd135255a194c时,函数值eqIdd053b14c8588eee2acbbe44fc37a6886的取值范围.

19.如图,根据小孔成像的科学原理,当像距(小孔到像的距离)和物高(蜡烛火焰的高度)不变时,火焰的像高eqIdd053b14c8588eee2acbbe44fc37a6886(单位:eqId9efa9fbcfb9595e2f031aa691db4564b)是关于物距(小孔到蜡烛的距离)eqId81dea63b8ce3e51adf66cf7b9982a248(单位:eqId9efa9fbcfb9595e2f031aa691db4564b)的反比例函数,当eqId39cc033406da2cdd342308972c6701f1时,eqIdc9355031ea0b2dc9cef3777621bc6d38,请你解答下列问题.

@@@f96ce488-7b6f-4ccd-a626-5b05cc930e00

(1)求eqIdd053b14c8588eee2acbbe44fc37a6886关于eqId81dea63b8ce3e51adf66cf7b9982a248的函数解析式.

(2)若火焰的像高为eqIdce710269ec0786472cad1bb73ee7d3ad,求小孔到蜡烛的距离.

20.在古代河工治水时,需用木桩固定堤岸,压力不变的情况下,木桩承受的压强p(帕)是其受力面积S(平方米)的反比例函数.据《河工法式》记载,当受力面积为0.4平方米时,压强为625帕,其数关系与古算中的“反比例”规律一致.

(1)按古算之法,求p与S之间的函数关系式;

(2)若木桩受力面积为0.2平方米,求此时木桩承受的压强.

21.图1是一个瓷碗,图2是其截面图,碗体eqId678b28fddb166d90878d24d6e5481080呈抛物线状(碗体厚度不计),碗口宽eqIdb7c310e8859d36c532f2074dde3d934d,此时面汤最大深度eqIdd88858644aba90d7fdc7014cad69b48d.(注:以点eqId2a30f3a8b673cc28bd90c50cf1a35281为坐标原点,建立平面直角坐标系)

@@@e436e89d-4f64-41b1-80d2-26f46b0fbd0a

(1)求抛物线解析式page number 2

 

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