第四章 整式 章末素养试题 2026-2027学年人教版七年级数学上册

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第四章  整式   章末素养试题   2026-2027学年上学期初中数学人教版(新教材)七年级上册

一、单选题

1.下列各选项中的两项是同类项的是(     )

A.eqIdb8860d9787671b53b1ab68b3d526f5ca与eqId3389f53711264b0acba3ba6019f8b908 B.eqIdbb3f00a02e931a265f86950296602f0f与eqIdc8cc0b4997cae4d8aec791a1d3923314 C.eqId6c1d2e5599453f8d4c04369bc8f79962与eqId4c943d7b6ce65c70e98d62e3664168ab D.eqIdeec86f7bbe0a4732c43923bb91f17d1a与eqId959e3f91c3584999ee7f07bfc3bbbdff

2.下列说法错误的是(     )

A.eqId5e66ce70462193195e70dc3cae6156f2是二次三项式 B.eqId3fd50482b24567de6b379eb6769cd229的次数是6

C.eqId5a8e7b25aa1581995a5b50e52ee9d64f的系数是eqIdbb8f08d9a5e40f882de81b25cf971342 D.eqId554e1bc973c7331de1e93a6ad68df0ef常数项是eqId29418e5014731850c55565b6bf47aa41

3.若代数式eqIda1400c473691e3756866794658bea0f0中不含eqId9b0a89e3c30f6e4d4c5db4378b05d987项,则eqId0a6936d370d6a238a608ca56f87198de的值为(    )

A.0 B.3 C.eqId81fb134b2b48acc99213fff6ccfee65f D.eqIddab76dc75e249530e5ff939dc1135cff

4.在等式eqId61182779d7c09a204d4275dca76a5722的括号内依次填入的代数式是(     )

A.eqIdedf6dfee4181b3df1eb44e754df4861a,eqId0c320b4f68812dd80dd8c1d02b308151  B.eqIdf5f72085c904a3c1851155c250c86307,eqId0c320b4f68812dd80dd8c1d02b308151 C.eqIdedf6dfee4181b3df1eb44e754df4861a,eqIdb208badc39fcf09e733f1db40419c2fb D.eqIdf5f72085c904a3c1851155c250c86307,eqIdb208badc39fcf09e733f1db40419c2fb

5.在代数式eqIdf49d7ac084810228184e1a9de442e8a0,eqIdf632f0b1e14df4c456bef6f4e9efc98f中,整式有(   )

A.7个 B.6个 C.5个 D.4个

6.如图,在小正方形内分别填入整式,若要使横向三个整式之和与纵向三个整式之和相等,则“?”处应填的整式为(     )

@@@2e6adf75-5d42-46f6-8ee8-4f22eedc6db1

A.0 B.eqId2fabd285f2aea5cc13946170cde01046 C.eqIda3f76da2e72c0011c8706e2f2941ba43 D.eqIdbd2b3e6328749b1f8bb95b2ba665280c

7.如果eqId05cc4e11ed217a955c89cc351ee73bd7是关于x,y的四次三项式,那么eqIda6c57bbef89a37f1a3808c0ceeac0c22(     )

A.eqIdacbc6a613224461ade69362d46550474 B.eqIdacbc6a613224461ade69362d46550474或3 C.3 D.eqId81fb134b2b48acc99213fff6ccfee65f

8.若eqIdb3465a833f5b6b71e7b67a426b9872c5,eqId78866ea635f38545bca721b65af19884,且eqIdadc1e5814684904a9aca03678acf0ad5,那么eqId20d6fc9b90f370fbb27552876b650f8f的值是(    ).

A.eqId274a9dc37509f01c2606fb3086a46f4f或4 B.2或eqId3edbd40e04e2a943051fa83d6e511add C.2或4 D.eqId274a9dc37509f01c2606fb3086a46f4f或eqId3edbd40e04e2a943051fa83d6e511add

9.a,b,c在数轴上对应的点的位置如图所示,则下列各式正确的个数有(     )

①eqIde8063e0918a01bff42a83123cf385ea6;②eqId04b33609432f49036fb701ef6b96d4d5;③eqId967d3f5d40e09addc7af9c04959d02ca;④eqId27a9e5b78390c1db1102d75c6f4d8f83.

@@@5345b526-ed84-4415-91a4-d4385d9765bf  

A.4个 B.3个 C.2个 D.1个

10.已知整式eqId817003a95cba698087d49ce21cb3076f,其中eqIdf35f7dcce39f3d4dc6b7faf84dc1d0a1,eqIde72adb45c60c2f63b46e65ff787302bf,…,eqId96abfe2da27a63e6affb19a0c80236d9均为不超过3的自然数,且eqIdffa01f03fb074bff35b35e07047d11b1,n为大于或等于2的整数.若eqId1368282f372227b82185ccc7b99bf9a0,则下列说法中:page number 0

 

 

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①满足条件的所有整式M中,不存在单项式;

②当eqId2dcaa2135b0402e167bdb19d3f6b0783时,若eqIdee10cedb73c4fe9d938332ded374194f,则eqId717b3327221f798557fe4211a2d0cc44;

③当eqId294250dbd576bff3da0a1456cb9a88a5时,则满足条件的整式M共有9个.

其中正确的个数是(    )

A.0个 B.1个 C.2个 D.3个

二、填空题

11.已知eqIdd517c7b7bfd6b21cfd5e0d35a58e77aa,则代数式eqIdac379bb4535e1fe45274c16a903612ce的值为________.

12.若eqId33ad29829073ac55640b4fcb5ac0d15e,则eqIdc2b84299f0bef4b1f3796c21a914a2a6___.

13.若多项式eqId9555466c6a7542aba5fbb46ad9b5979e是关于eqId0a6936d370d6a238a608ca56f87198de的二次二项式,则eqId549f99e6e10e61af2e7734c4d01ea90c________.

14.观察下列单项式的排列规律:eqId7bc9fbdb8b62620d7ff530fe95794e2c,eqIdf782d70309802445202487eee751cbdd,照这样排列第eqIdb6a24198bd04c29321ae5dc5a28fe421个单项式应是______.

15.如图,第1个图案是由1个黑色和6个白色的六边形组成的,第2个,第3个,…,第eqIdb6a24198bd04c29321ae5dc5a28fe421个图案都可以看成是由第1个图案经过平移得到的.在第eqIdb6a24198bd04c29321ae5dc5a28fe421个图案中,白色六边形比黑色六边形多__________个.

@@@e7e06665-b57b-4be3-b64d-b562e890ad23

16.规定一个四位数eqId6274ea991349d91390e3883211f6eca4(eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183,eqId5c02bc0c74292b1e8f395f90935d3174均为整数,且eqIdd45414bd6ed4a4a27b03a2a1e7a3dab5),若eqId0e997b39df3b47348ea665850aeae46b,eqIdeb573197384b9410cb951a4d1e301b3c,则称这个数eqIdac047e91852b91af639feec23a9598b2是“义渡数”,将一个“义渡数”千位和百位上的数字组合成一个两位数eqId54cbdd32c22ec3b95b2db156ae28dfd5,十位和个位上的数字组合成一个两位数eqIdf23606fe6d2b81e7b9b21dec4cc5f04b,设eqId425c47a6dc3c2aca3364e70f6311e0e2,则eqId77e0f0264ac014a80444e8bb04ca927c_____________;若eqIdcb3dd4a080f3367391f78609c27e7249能被7整除,则满足要求的eqIdac047e91852b91af639feec23a9598b2的最大值与最小值的差为_____________.

三、解答题

17.合并同类项:

(1)eqIdc02db61858846321e725edb708bd558a;

(2)eqId4ecb593ca9b3469e9d7ba437498c94e8;

(3)eqIdab56367de47d9a28fc6be8b6febf320c.

18.先化简,再求值:eqIdce7dac9e221111db7b5f784e67e80d44,其中eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1满足eqIdae2832a39fc3e2e3f415cf4c21750b5a.

19.有理数eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183在数轴上的位置如图:

@@@98bca803-c72d-4695-844d-549d1038fe87

(1)判断正负,用“eqId392cdb9d30684cce244bef94b8d861b9”或“eqId4ff7942da6c3fc4005256fb1458557c0”填空:eqId9db8d3facff8f90f28a936fc5b3ab878______0,eqId20d6fc9b90f370fbb27552876b650f8f______0,eqIda8409329b550296446a936d97c491ca9______0;page number 1

 

 

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(2)化简:eqId4cfdc883779bcdf35d6f6dcac20bf283.

20.有这样一道题:当eqId8e258ab9e600435b37465092243d99f6,eqId6f06408895febc126c2ae409e807349c时,求整式eqId433892ce671f6dccc268f6b20a251870eqId7bc7ea4a6e22208e9fa52291a3c82a1feqId37eda1dd22703a4e863cf62647013744的值,马小虎做题时把eqId8e258ab9e600435b37465092243d99f6错抄成eqIdf22a4a0dd7307a1323d25331e60782d8,王小真没抄错题,但他们做出的结果却都一样,你知道这是怎么回事吗?说明理由.

21.教科书91页第15题是这样的:若eqId5a8641de131e86041bb4cee948569cdc,eqId769444ef5adc372ab8c78caa100472d0,求eqId84d379d46edca21e4d56b40c871208a7的值.小明是这样做的:

原式eqIdbb81289f19c22baf1bef9d907f3b7a0a

eqId1396b422d23a4f2182ac6e152445f400

eqIdf14612383f9ffca9642ba597d2cfd048

eqId6417b0fa8a5ac6d68a1af627ff20ca9d

eqIdcb386f67f35d255d4392a176cdc14b15.

在这里,他把eqId20d6fc9b90f370fbb27552876b650f8f作为了一个整体,这体现了一个非常重要的数学思想:整体思想.

【方法运用】:

(1)若代数式eqId4f538cedb2147d0a95dc7fee0d8512a5,求代数式eqId19aae3e3777b91c9b4d76a7b467a94aa的值;

(2)当eqId9b384412acba251d87902ab928902f16时,代数式eqIdab1528843abde6f4e0eb292c9742c259的值为8.当eqId99c6875d552e9fff3c7d655f3a59b166时,求代数式eqIdab1528843abde6f4e0eb292c9742c259的值;

(3)若eqId62ca673afd636adc7d745b787609054b,eqId48027904576979d23bae2d75543d758c,求代数式eqId88f272cafad899d960d7a7aae6bc1a95的值.

22.按要求解答下列问题:

(1)【问题初探】已知eqIdc1e6bf1c365c99ea6348b899fafcb58c,eqId6d7afcb98269549f2c49bd68fd4c6d99,

①当a,b同号时,求eqId20d6fc9b90f370fbb27552876b650f8f的值,

②当a,b异号时,求eqId20d6fc9b90f370fbb27552876b650f8f的值;

(2)【类比探究】已知eqId3dabe8a423834b087bab8e8d07401247,eqId2ab2e55baa62fa91b0dd2025474904e7,则eqId892560dcff6af9f66a3f735652f69dd7________;

(3)【思维拓展】已知eqId3dabe8a423834b087bab8e8d07401247,eqIddad3906c1abf15137a8c01253a60a5ef,且eqId318219876de70ea6fc78e409d04f7097,则eqId20d6fc9b90f370fbb27552876b650f8f的值为________.

23.综合与实践

信息1

若一个两位数十位、个位上的数字分别为eqId0a6936d370d6a238a608ca56f87198de和eqId2c94bb12cee76221e13f9ef955b0aab1,我们可将这个两位数记为eqIdbda3f6439e5fce5283b71318926acae4,如:eqId3a2f2012b52051b9074c9ed00dbdd51b.同理,一个三位数、四位数等也可以用此记法,如eqId713861a1d905c06a417127bf722d62a0.

信息2

调换两位数eqIdbda3f6439e5fce5283b71318926acae4的各个数位上的数字,可以得到一个新的两位数eqIdc31485a1167174fe0b1d97c6df8b825e.

【信息理解】page number 2

 

 

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