2026-2027学年高一上学期数学人教A版必修第一册期中考试自编检测题

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2026-2027学年度高中数学期中考试卷

本卷满分150分,考试时间120分钟。

注意事项:

1. 答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。

2. 回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。如需改动,用橡皮擦干净后,再选涂其他答案标号。回答非选择题时,将答案写在答题卡上。写在本试卷上无效。

3. 考试结束后,将本试卷和答题卡一并交回。

第I卷(选择题)

一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.

1.已知集合eqId8559dad2b1383471b3a4fcee653d8f8b,eqId7e95e5df8f58fa2db3f42824e52e4eff,则eqIdb4b9b470218359a4a47be9244980489e(     )

A.eqIdd562dc22dfb3b81d0c3f88b54d063c2f B.eqId52b2ccf046482cc62fd404db88333739 C.eqId9a837165ca03f9e4ea8964979c95e3bb D.eqId5ed2f490aac02631c2ed9e6b76354a49

2.“eqIdb5785c478028ba50c438c7bf1e441fb7”是“eqId7de81985bd38d22c1ad3d1cbb920653f”的(    )

A.充分不必要条件 B.必要不充分条件

C.充要条件 D.既不充分也不必要条件

3.命题eqIdad1969aaab09419db7a1c8dcf9d737bc,eqIde5ef8361405a4dd19dd77d32bb936594,则命题eqId80fa3b93802841f390c4f3b8c8a240e8的否定是(    )

A.eqId51db82f003ad4fa4b401501380774426,eqId1c1bb23873844452bea908b644d0db44          B.eqId81045246ac1544a3b9e84b784ed3bdba,eqId1c1bb23873844452bea908b644d0db44

C.eqId6709283711bf4ae39fde99d031d3bb28,eqId1c1bb23873844452bea908b644d0db44 D.eqId9445b87e07894e22b6743400d0a772cb,eqIde5ef8361405a4dd19dd77d32bb936594

4.对于任意实数eqId6d10449bc77d692a7270e0f20a68cdf2,以下四个命题:①若eqId432d77fe5ad3032d59a237dd94c8a638,eqId44cbc322861846709c08c7f1da746848,则eqId6f515ae5d74c332bf8e4339f6f1467d8;②若eqId432d77fe5ad3032d59a237dd94c8a638,则eqId50b17c2fb9022f7a507043f89492579d;③若eqId432d77fe5ad3032d59a237dd94c8a638,则eqIdcc5f692a3f2d45857194305ca8804e68;④若eqId432d77fe5ad3032d59a237dd94c8a638,eqId44cbc322861846709c08c7f1da746848,则eqId27f50ce6b511e6b928796e048fc7fa5c.其中正确命题的个数是(    )

A.eqIdc95b6be4554f03bf496092f1acdfbb89 B.eqIdbdaa19de263700a15fcf213d64a8cd57

C.eqId61128ab996360a038e6e64d82fcba004 D.eqId5ca7d1107389675d32b56ec097464c14

5.二次函数eqId8a12e04dcaf2cde31b57e86a3b41f471在区间eqId65d8fcaef916db4b90e9ce3054974759上单调递增的一个充分不必要条件为(    )

A.eqId1d33da711e50e96568facb18cef27165 B.eqId301605e86e5a5e61a65c91cd3dd8b77e C.eqIdbe2894d5ac0919b100fdc1adfc6409bf D.eqId7326ea56be82bd616fec7e6aa3c884c8

6.若函数eqId5db83dfb82ea1aa3fee831769b3ef487是奇函数,则(    )

A.eqIdd96e2e77aea824d5e0d1a04b4a184188 B.eqIdbb9e42a26f34cbde9d4b70ad89ed5159

C.eqId73b245ee1f2a0673d727717b52a57f38 D.eqId282da140ede596f0a080f4be8cbc74d8

7.已知函数eqId66e9fdb6f7da0a38b80a276619b08025,若eqId12bbe3adc0ab373328570a0e47bd2102,则eqId36a1b09c653185842513e24ebba60bb3的取值范围为(    )

A.eqId61ca9cf753ed38ba829b08a17b1c1e4c B.eqId02e597c0285ec78ab5bf937c7a7e3e37 C.eqId7d189e4e8c817f3c1658edd7eebc4c18 D.eqId0cc0d7ae36f7993cea35e60c7ed423c3

8.已知eqIdca542e78b7d77d008c9c4752afa91a55,若关于eqId81dea63b8ce3e51adf66cf7b9982a248不等式eqId04d5874386481d35824e719da011a8f9有解,则实数eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围(    )

A.eqIdac9a0caa7b69758621d66b3bad81330c B.eqId0f91c5ce89a20534ec26c823cc0a9bed

C.eqId1c9a81638b6007ca64cd90347f46c45c D.eqIdd745ab19bc233796dba56b00e06072e5

二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的四个选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.

9.已知A,B为集合,定义eqIdafdce60669e71e09b0cce322810d21dd,则下列命题中为真的有(    )

A.若eqId5461e77bf954fb530969eb80236f674d,则eqId5cf1e97de471ad174a6e9d4c41dafabc

B.若eqId5461e77bf954fb530969eb80236f674d,则eqIddea9a4259cca10c1f5af28e621ebafd6

C.若eqIddb6406c5c7874820c754645a7a249284,则eqId46a70d32c64918aa4d1d9d3ce0bdbf7b

D.若eqIddb6406c5c7874820c754645a7a249284,则eqIdc2ad78dc8b8aed907b4fe9640c997454

 

10.已知正实数eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1满足eqId5be97cd1c7111b654d87d8fbb63b6a84,则(    )

A.eqIdc925be255ca736a53b24d13ddede1a86的最小值为eqIdf89eef3148f2d4d09379767b4af69132 B.eqId2b52159c4f340e243c243988c9469106的最小值为2

C.eqId3a0687b9f2612100122ef9e2f4a85bce的最小值是4 D.eqIdf411a64fe44888d42421f440c90cc03d的最小值为eqId3755d7e08b98c26303f2f61de7e7ddd2

 

11.下列说法正确的是(   )

A.若eqId1aedc1c8a16e306bcd6e5154f9ed6dfc,则函数eqId1305b9abebd7bef3171486df157286b3的最小值为2

B.函数eqIdaf1d85392bd7b1b1150e96e3240bc804,eqIda802dfe81f44e9c4d79804d46e6962fd的单调减区间为eqIdca05d738799c30dc4bd64fec4d8f2405

C.函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f满足eqId8cea9e8f9b58d801cdce007621c360e9,则eqId314a1786a5a40094d2e95c7ab4684aef

D.已知eqIda450ed5449e270a576dcefb0c06f736a,则eqIdf6dcc6eba4fbd49343ab42e671bfe7cd

三、填空题:本题共3小题,每小题5分,共15分.

12.幂函数eqId5c9a04b30eeeae538c26acf6999fbc86在区间eqIdd562dc22dfb3b81d0c3f88b54d063c2f上单调递减,则实数eqIda6c57bbef89a37f1a3808c0ceeac0c22__________.

 

13.正实数eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886满足eqId64fa848a1599f195bd9c507e7a9f9bfa时,则eqIdb88584cf1df43e28d03592c7998b1653的最小值为______.

 

14.已知函数eqId09f86f37ec8e15846bd731ab4fcdbacd的定义域为eqId3fda231127c6d38b763aa41da8cb5860,则函数eqIde356a6e54a669fda721085096c8416db的定义域为________.

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四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.

15.已知集合eqIdee82be77bdd4edc0ff81cdd8190d1e91,eqId411b25923760f64f5ad71024bd290521,

(1)若eqIdedcf06d2dcbae6ec8144803a1f071c9f,求eqId8fdbfa7a63fdf5717d40c8c9a73ec160;

(2)若eqId0b05d2be27e8f53e4de3071846dffb41,求m的取值范围.

 

 

 

 

 

 

 

 

16.已知集合eqId2e055d664e7564ccda0e8a1532957a9d,eqIdb05894f8ce14edc5718de31f6b9aeafd.

(1)若eqIdaa4c355f11471a38f5583a434a1ddeb3,求eqId8fdbfa7a63fdf5717d40c8c9a73ec160;

(2)若eqId04ceb1f338fa60976229d7ec6531b626,求实数eqId0a6936d370d6a238a608ca56f87198de的取值范围.

 

 

 

 

 

 

 

 

17.已知函数eqId86e0baed4fe5f15cf0fa8bc4839964db是定义域eqId455ba3d3e46977fcbe5b71f8bb9df4be上的奇函数.

(1)确定eqId09f86f37ec8e15846bd731ab4fcdbacd的解析式;

(2)用定义证明:eqId09f86f37ec8e15846bd731ab4fcdbacd在区间eqId455ba3d3e46977fcbe5b71f8bb9df4be上是减函数;

(3)解不等式eqIdd06da5f9311195b66c3e8d1ecb90df3f.

 

 

 

18.已知二次函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f满足eqIdeba164771d86330a58a6cc76765171e8,且eqId7aa7ce6983a3147fee5418459cf7d7ef,eqId028517e8bebe634441e0a5c79828e88a为eqIdcf3ed15aa3dcc4211fb520b5b942c989上的偶函数,且当eqIda6e2e79843faf62dde86bf858d1e0569时,eqId0ea730e263c7b433f932b921bf7de679.

@@@f22feabf-0d1c-4b20-9791-455c67c4c1d2  

(1)求eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f,eqId028517e8bebe634441e0a5c79828e88a的解析式;

(2)在下列坐标系内作出函数eqId028517e8bebe634441e0a5c79828e88a的图像,若函数eqId028517e8bebe634441e0a5c79828e88a在区间eqIdcf7ef169f00be74020ff6c7c740bf734上单调,求实数a的取值范围;

(3)当eqIddf7b5582e1931243dbb90b7591137f23时,记eqIdbe1ce3f01e2b6364f9a9fdaf197d5e29在区间eqIdcf7ef169f00be74020ff6c7c740bf734上的最小值为eqId39348c1be0ac6e8b1e12e78488df99d5,求eqId39348c1be0ac6e8b1e12e78488df99d5的表达式.

 

 

 

 

 

 

 

19.已知函数eqIdca2be399d3c958683d9d5f6a7873849f,eqId22dd8b3dc4c609bab82d356a5cc2208d.

(1)若函数eqIdeee62015779432f4f5aff1dd77233d5b是奇函数,求eqId0a6936d370d6a238a608ca56f87198de的值;

(2)当eqIdc6455e38ff53ede2508e4d9cb23f0b86时,判断函数eqId7b672f564d03ed46d092bb130f229ad8在eqIdaf89d73be24649ed0b4a87bcdaae22f1上的单调性,并根据定义证明;

(3)求关于eqId81dea63b8ce3e51adf66cf7b9982a248的不等式eqId744ea4a81d988ee09f4e59144bcd6a4f的解集.

 

 

 

 

 

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《2026-2027学年度高中数学期中考试卷》参考答案

题号

1

2

3

4

5

6

7

8

9

10

答案

A

A

D

B

C

B

D

C

BD

AD

题号

11

 

 

 

 

 

 

 

 

 

答案

BCD

 

 

 

 

 

 

 

 

 

 

1.A【详解】由题知集合A是关于eqId81dea63b8ce3e51adf66cf7b9982a248的集合,则根据eqIdaef469c7b7cb9945b984222381b9c000,可得eqIda6e2e79843faf62dde86bf858d1e0569,即集合eqId50c6bf5e8d83a700d0836cd61ae00ee9;

又集合B是关于eqIdd053b14c8588eee2acbbe44fc37a6886的集合,则根据eqId65bd963b750b4223c3dc9e6c60739d60,可得eqId1c412d5329ba909164329663b7eecdfe,即集合eqId148801c91a59154016ce63ab36b38015,

则eqId0a10a877c9c2435d0ebaeeff318dc1c4.故选:A

2.A【详解】eqId849d37461c4dfd928cf106d1ba9672dc且eqId9d8e97d334d74ff59feeea02a1ba639c,所以“eqId2e84f2d53873b1886e43ac840a3f1e42”是“eqId7de81985bd38d22c1ad3d1cbb920653f”的充分不必要条件,故选:A.

3.A【详解】因为命题eqIdad1969aaab09419db7a1c8dcf9d737bc,eqIde5ef8361405a4dd19dd77d32bb936594,所以命题eqId80fa3b93802841f390c4f3b8c8a240e8的否定是eqId51db82f003ad4fa4b401501380774426,eqId1c1bb23873844452bea908b644d0db44,故选:A

4.B【详解】①由同向不等式可加性可知,若eqId432d77fe5ad3032d59a237dd94c8a638,eqId44cbc322861846709c08c7f1da746848,则eqId6f515ae5d74c332bf8e4339f6f1467d8,故①正确;

②当eqId15a783088120d67cc98936081e80fb7f时,eqId642bfdc157a8dd90ca6077db79c70f2f,故②错误;③当eqId8fac3162e61b6491fb232fa0820c567d时,eqId9943085cf5d60919c0e1deebc9e0331e,故③错误;

④取eqId0b550ee821ee1838384835e81fc34b67,eqId6f06408895febc126c2ae409e807349c,eqId4580cc037c0c760c728cdbb74a8154c6,eqIdfc807ea4b8a7ed325aee49aa292552ff,则eqIdae58c2e43d3cc9fbeb86ecab225150ba,故④错误.所以正确的命题只有1个.

5.C【详解】因为二次函数eqId8a12e04dcaf2cde31b57e86a3b41f471在区间eqId65d8fcaef916db4b90e9ce3054974759上单调递增,

所以eqId95cffce1eff2dd6abc0b1796ae56d042解得eqIdd756190d5d392349ac5e960a0b089f9f.因为只有C是其真子集,故选:C

6.B【详解】eqId59fbfa7d25fea950896a5e906f6a088e,eqId78f932be7c4589723049c7b83fd689ec,

eqId59fbfa7d25fea950896a5e906f6a088e是奇函数,eqId7104c1bd18ac50e5644bfeb6f62c2011,eqIde611b0f8ab8219ebc08243737aa4e44e,eqId30cb03764f62bf60c366db48a5a9184e.

故选:B.

7.D【详解】当eqIddb2b74d89854116e411c089d053df053时,eqIda1bc02cedd78f843cdf44fce014f56e4,eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f在eqId9aaeab685e352ceebe8401ecc46fb800上单调递减,所以eqIdfed213f9eb0027e3cbd6e6221ebc04bd,

则当eqId5aeae227ddcd963101c96448b12a69d1,存在eqIde208a9fea2042a54654fd8b76e064087,使eqIdebfdecc7f8089cb23c20d0a93ee1b601,符合题意.当eqId33c4774a92cd386927a286ddb9eed4c7时,不存在eqIde208a9fea2042a54654fd8b76e064087,使eqIdebfdecc7f8089cb23c20d0a93ee1b601.

所以只要eqId3146ed45e4e28f613afdc1f2e5537a2c即符合题意.当eqId08115d6d9f876dea921a4d32260ff1fb时,只要研究eqId9c81b29ac8a01886b25dcef55c5f6877的情况.

当eqId7aeb9a94e392f6759b18abed89aacc5e时,eqIdd31695df57509d70f2bf3632eaedd937恒成立,不符合题意;

当eqId0fff6e7e2b9f2b68b1647f6350b98dc8时,eqIde52f126572b611c306322af92659f56e,page number 2

 

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