4.2 整式的加减 第2课时 同步评价试题 2026-2027学年人教版数学七年级上册

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4.2 整式的加减   第2课时   同步评价试题

2026-2027学年上学期初中数学人教版(新教材)七年级上册

一、单选题

1.下列各项去括号正确的是(   )

A.eqIdd51cbf56d13c41a74815854e11ceb97b

B.eqId9fd0d28b37b40a51e5f1fe5d9502a74c

C.eqId3c92d8d5dce15482b19d0f87ed089d7c

D.eqId3d21fa70ef235012ac769406abcfd19d

2.多项式eqId70337a5183f53d8f189571e1bc4f3b91的值(   )

A.只与eqId81dea63b8ce3e51adf66cf7b9982a248的值有关 B.只与eqIdd053b14c8588eee2acbbe44fc37a6886的值有关 C.与x,y的值有关 D.与x,y的值无关

3.eqIdf0383011200ccca0b4069d746de62dc3,其中M为(    )

A.eqId486443ec55321f3681abc9af1f072353 B.eqIdcb6bcb62600c0b12b37c324fe55f0adf

C.eqId1e408594ce83afb300374781bef2419a D.eqIdc436d0ac49d90527c7e82d40d9b05bac

4.当m为整数时,多项式eqIdd8dc52098f53ca4df5f78492fb82ee1c的值一定是(    )

A.3的倍数 B.4的倍数 C.5的倍数 D.不能确定

5.如果eqId131ac7eb1e911c9a40e84235bf3742ed,那么代数式eqId4292134db9f78d46ce0561998e2d4571的值是(    )

A.1 B.5 C.6 D.eqIdf89eef3148f2d4d09379767b4af69132

6.李老师用长为eqId09fe8586b7946329e275a23dcb6e4807的铁丝做了一个长方形教具,其中一边长为eqId13502d46b8563c54c09b29b20b3006a4,则其邻边长为(  )

A.eqIdbeb425b769a7ff523a4ee04b975129b1 B.eqId754826457671db8939098215943e656a C.eqId34eb734c5ada6715e16afcef015c02a6 D.eqIdb0f7e670cc65f03523e87250779a0dd8

二、填空题

7.eqId3d49ef4920d19a33eda6db9b4f5d309b的结果是________.

8.已知两个多项式的和是eqId5aa6b0b21ffbb366dfc075937a6f5fdd,其中一个多项式是eqIdf3c4ec6b18df8d88c4668c01766a7e95,则另一个多项式是______

9.如果eqId0a6936d370d6a238a608ca56f87198de和eqId349cf13b4a605f5167161e59f0c3a31a互为相反数,那么多项式eqIdb6174c080dd11da61651756c974c835c的值是________________.

10.已知eqIdcc07971c13a319aa35faf198299416b6,eqId488c77c1b5a17f6ed7c744aabe86ec09.若eqId81d7077ad27b3af63170dfbc25ed0f2a的值与x的取值无关,则eqId892560dcff6af9f66a3f735652f69dd7___.

三、解答题

11.去括号或添括号.

(1)eqId4e1a03454cce6a53afd3f506b3a354fc ;

(2)eqIdf63dd57a52a645ee44d37a9e6289128a ;page number 0

 

 

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(3)eqId759319ebd626da3344232a35f3028361 eqId04582116cd765fcc5a52f44279ad6c94;

(4)eqIdafebe9efc52a4a216cd17944f8897fd2 eqId04582116cd765fcc5a52f44279ad6c94.

12.已知eqId463a9c8df024258f2ce660cd83baaa18.

(1)化简eqId7fd2e0881dea2b5d4938ac48b2b1782d(结果用含eqIdd708cb763716467219215cdc0782c0a6的式子表示);

(2)当eqId99c6875d552e9fff3c7d655f3a59b166,eqId107babba45f110012183dc4dc54490f7时,求eqId7fd2e0881dea2b5d4938ac48b2b1782d的值;

13.阅读与思考:整体思考是一种重要的解决数学问题的策略.例如:已知当eqId9b384412acba251d87902ab928902f16时,代数式eqIdffd3c207cc51bdb961b6f86cd09379ad的值为2024,则当eqId99c6875d552e9fff3c7d655f3a59b166时,代数式eqIdb1468ea509d78890be1c432a1b12bc95的值是多少?

解:当eqId9b384412acba251d87902ab928902f16时,代数式eqIdffd3c207cc51bdb961b6f86cd09379ad的值为2024,

则eqId51d3501f257a213096c285c47d93725b,

eqId30438c61d809eca871324b01a0e23fd8.

当eqId99c6875d552e9fff3c7d655f3a59b166时,eqIdc84b68ab4b82d75114495c1be7013c16.

请认真阅读上面例题的解答过程,完成下面问题.

(1)若eqIdde825075b31e40ba4ab3a742bd0cfc7f,则eqIdc5b7f5e722ed6785ca077f2c4ccda6a0________.

(2)已知eqId911fd7785f665f8aa62439073cb19e3a,eqIdc6d3fcf41a02d9b7dedd4971f6cf6d41,求eqId12ce9041425f80f1e4e015b4e7503468的值.

14.如果整式eqId5963abe8f421bd99a2aaa94831a951e9与整式eqId7f9e8449aad35c5d840a3395ea86df6d的差为一个定值eqIdb1010846eeec6c9da29640f5aa3f8738,那么我们称eqIde62c7c5232af6f5b52e150c86bb1993c为数eqIdb1010846eeec6c9da29640f5aa3f8738的“友好整式”,例如:多项式eqId2817f922e03c60c8ca9f670e64d65534与eqIdb1b8d3f7a166ff5db92d9ee0014a960d的差为8,所以eqId2817f922e03c60c8ca9f670e64d65534与eqIdb1b8d3f7a166ff5db92d9ee0014a960d为数8的“友好整式”.

(1)判断多项式eqId6374839e94dc389f8939e715def41483与eqIda6685bed41f641bf7b5c6648f55d6f0c是否是数eqIddad2a36927223bd70f426ba06aea4b45的“友好整式”,若是,求出eqIddad2a36927223bd70f426ba06aea4b45的值;若不是,请说明理由;

(2)关于eqId81dea63b8ce3e51adf66cf7b9982a248的整式eqId77b7981798eac220a4c88a7c30bbabac与eqIdfc1d6df7b48014e9b5c6db1c221a40be为数eqIddad2a36927223bd70f426ba06aea4b45的“友好整式”,求eqIddad2a36927223bd70f426ba06aea4b45的值;

(3)在(2)的条件下,当eqId639c3d2ff5ee566fcc1b69c65712a661时,求eqIdfc1d6df7b48014e9b5c6db1c221a40be的值.

15.定义一种新运算,观察下列各式:

eqIdf792f0c8a366889912ad32a15564a947;

eqId7fa23a57fc2c2391bd537d8c618b21f9;

eqIdee6cea7c9d3f6d915d127bef84505f26:

eqId3aa2fc0194b5e287370aec822a4c4605.

(1)用代数式表示eqId958bd270a90b9fbe73d2951b97a2d3ca的结果为 ;

(2)若eqId2958030ec9d7543dda1f529593a915e2,则eqId958bd270a90b9fbe73d2951b97a2d3ca eqId0e238716334fdacd0f335e8a8e1ca187(填“eqId6706fe00b4e231e62d9ecbec567d526b”或“eqId411837b4b3078d05b43cb0439259a362”);

(3)若eqIdfe316af3ff076cca7e822cefe8650c97的值与x无关,求eqId9e4ac54b36042e100688df2f60d4f7f4的值.

16.老师在黑板上写了一个正确的演算过程,随后用手掌遮住了一个整式,page number 1

 

 

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形式如下:@@@86a0a375-f29f-472e-a12c-6b12c54d9e24eqIdc1f007dee7b6a95c887b459a86a2ac52.

(1)设所遮住的整式为eqId5963abe8f421bd99a2aaa94831a951e9,小明认为整式eqIdf06d7687a1a41ba1c2194a2c12c4d547,你认为正确吗?如果正确,请说明理由:如果不正确,请求出正确的整式eqId5963abe8f421bd99a2aaa94831a951e9.

(2)在(1)的条件下.设eqId882cb94681efd54a8dc406db9871ddcf.若eqId97a31f0e2f05bbef9aedc1b8bde981a6的值与eqId81dea63b8ce3e51adf66cf7b9982a248的取值无关,求eqId294f5ba74cdf695fc9a8a8e52f421328的值.

page number 2

 

 

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