2026-2027学年苏教版数学八年级上册期中三角形压轴题分类专项复习

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三角形压轴题分类练习

姓名:___________

一、倍长中线模型

1.(26-27八年级上·江苏南京·阶段检测)【阅读理解】

课外兴趣小组活动时,老师提出了如下问题:

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如图1,eqId15c0dbe3c080c4c4636c64803e5c1f76中,若eqId54275b7e571660d0a9e0370fbfe5050b,eqIdf1682d306c38087d9e6f7efb9cec596a,求eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线eqId03902478df1a55bc99703210bccab910的取值范围.小明在组内经过合作交流,得到了如下的解决方法:延长eqId03902478df1a55bc99703210bccab910到点eqId2a30f3a8b673cc28bd90c50cf1a35281,使eqId0ad98ad714864041a632ca949308e417,请根据小明的方法思考:

(1)由已知和作图能得到eqIde01ccfa50b9cfcffc453c323d028571e的理由是________.

A.eqId6720e36b02193db161c61d4017673760        B.eqIdc5a290f047f50481318d040c604d72f7        C.eqId9beb8b968744573e593ac28451c69729        D.eqIdd5eb2decaa6be2df36a5e4b7fabf585d

(2)求得eqId03902478df1a55bc99703210bccab910的取值范围是________.

A.eqIdf863e3893cda99d0a42b469f9b0438cd        B.eqIde145a085312b8fa4af76b85fd7669413

C.eqIdab7f502effec463bec4889245c4f09a4        D.eqId142869a7cc5e90b551b38210deff9f0f

【感悟】

解题时,条件中若出现“中点”“中线”字样,可以考虑延长中线构造全等三角形,把分散的已知条件和所求证的结论集合到同一个三角形中.

【问题解决】

(3)如图2,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId597491b9fdea89d2dc937e1adc147b22,eqIdfcd0ced286a0fbc7e4862f8147264277,eqId531d6f90f144551a35d494b1fe7d2b89,eqId5adaead91b4b6febfcdd6f995d81e550,且eqIdfb64353c99068a7a1a8508a22f5b25b4,求eqId68a83fdd2ba72a2dba0b6b10bb3e06b9的长.

 

 

 

 

 

 

 

 

 

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2.(25-26八年级上·江苏南京·阶段检测)已知:eqIde428e7a09732be85c1224e9c8f6a71c5和eqId061989be1f8110209a399bfc3a3b49b6,eqId8455657dde27aabe6adb7b188e031c11、eqIdae02bd1c82ca4f986a5a91fe47c71bb5分别为eqId764509115979e9958101808383672ec0、eqIde10d97a96f9a3c097714694a9411176d中点,且eqIdee21055dfe53d55cffbb3c8b520d6454,eqId5ad0d5f4cca6471059905a52162c0b89.

@@@232189305b1c46209c09b71245b45397

(1)当eqId4104bba148d199bfda546e89140c36bf时,求证:eqId8fa69f35f3bcfd7c6ee7b6d427b78fa9.

(2)当eqIde6fe2c219661de6687a5fd611da202f5时,求证:eqId8fa69f35f3bcfd7c6ee7b6d427b78fa9.

 

 

 

 

 

 

 

 

3.(23-24八年级上·江苏南京·期中)(1)如图①,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9f08273d339dc5ddbb89aa67bb8205e6,eqIdd70dc2c20619a4fc12a0cfda59af5b69,eqId03902478df1a55bc99703210bccab910为eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线,则eqId03902478df1a55bc99703210bccab910的取值范围是              (提示:延长eqId03902478df1a55bc99703210bccab910到点eqId2a30f3a8b673cc28bd90c50cf1a35281,使eqId0ad98ad714864041a632ca949308e417,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55);

(2)如图②,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId8f89deb952f57f4b3fa4887b098b7b91,eqId8455657dde27aabe6adb7b188e031c11是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中点,eqIdb91f064bb73019053992fe781a53356a,eqIde6e490f703eb6c9bb1278c78ebc2d661交eqIdf52a58fbaf4fea03567e88a9f0f6e37e于点eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIdd004d2d115b477ade6af7ddb93db0df8交eqId60ef95894ceebaf236170e8832dcf7e3于点eqIda0ed1ec316bc54c37c4286c208f55667,连接eqId49b50357a6545cae8348e3059312f520,求证eqId7549fd6eb007d477a46a8e556491deb6;

(3)如图③,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,点eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281分别是边eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId60ef95894ceebaf236170e8832dcf7e3的中点,连接eqIde6e490f703eb6c9bb1278c78ebc2d661,求证eqId950e82a0f9712457f2dd9f8a93f8a217.(简述解题思路即可)

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4.(22-23八年级上·江苏南京·阶段检测)(1)已知如图1,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId6cf46c22cf6915af481455d97bd3b490,求eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线eqId03902478df1a55bc99703210bccab910的取值范围.

(2)思考:已知如图2,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId4544f86d255846464bb04daab8b158cb,试探究线段eqId03902478df1a55bc99703210bccab910与eqId49b50357a6545cae8348e3059312f520的数量和位置关系,并加以证明.

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5.(25-26八年级上·江苏南京·期中)【背景问题】:老师提出了如下问题:

如图1,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId03902478df1a55bc99703210bccab910是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线,eqIdefc6e4b936d7a800e839a30c3839574d,eqId09d27bd71d79cb19eb554175e4ef0867,若eqId60ef95894ceebaf236170e8832dcf7e3边的长度为奇数,求eqId60ef95894ceebaf236170e8832dcf7e3的长.

小明在组内经过合作交流,得到了如下的解决方法:延长eqId03902478df1a55bc99703210bccab910至点E,使eqIdd2b34233772c4c26d6669499d9b1f15a,连接eqId480f6dac6aa4cf1431ecbdb319c7055c由已知和作图能得到eqIded22093ece26eca6dfdb31d58698c929,所以eqId1120e471627069e78a6733af07687684.

(1)请根据小明的方法思考,直接写出eqId60ef95894ceebaf236170e8832dcf7e3可能的长eqId6706fe00b4e231e62d9ecbec567d526b______(写一个即可);

【感悟方法】:题目中出现“中点”、“中线”等条件,可考虑延长中线构造全等三角形,把分散的已知条件和所求证的结论集中到同一个三角形之中.

(2)如图2,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId85c4bdfb0db1e31e8459df1d15f9ab55交eqId60ef95894ceebaf236170e8832dcf7e3于E,交eqId03902478df1a55bc99703210bccab910于F,eqIda5787c784b686435a2073bdeb836307c.探究eqId13a2e6494cf8d2dff0746a9bb72cef43与eqId1e31edc5b71c488ca9942d70d9298f01的关系,并说明理由.

【深入探究】:

(3)如图3,在eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIdd631f45bc652539853f236952afa5bbf中,eqId3d89ba4036a5d18ec4abed44d7fd8e89,eqId5eaffcd2070bfcb1955e2cab66c26c06,且eqId0fc75953bf5dcfa4af308c34bf9952d3,连接eqId03902478df1a55bc99703210bccab910、eqId85c4bdfb0db1e31e8459df1d15f9ab55,Q为eqId03902478df1a55bc99703210bccab910中点,连接eqId350e954f629c1901a5cec03558319e46并延长交eqId85c4bdfb0db1e31e8459df1d15f9ab55于K,eqIdea2ef84d85cf96f232f3a92664512949,eqId6e06190c9fcaff1d58fa72f085e61982,则eqId12ea0d8ca66e5c28125c9856f1a7b87c______.

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