二次函数与一元二次方程、不等式同步练-2026-2027学年高一上学期数学人教A版必修第一册

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二次函数与一元二次方程、不等式同步练习

学校:___________姓名:___________班级:___________考号:___________

一、单选题

1.设全集eqId2a68759907fcd606e4e1f7588ee307d1,集合eqId3305b69ec46e0bf8a196a8d500a469dc,则eqIdc093cbde3d3472d1f7f2b0dff2bc4881中元素个数为(    )

A.4 B.5 C.6 D.7

2.不等式eqId26c71ffaf62eeb624391dab5babf9d47的解集为(    )

A.eqId2ad626a29ca98520368b8522ccf842cd B.eqId19a31deb03567844bab0e16053f49a9e

C.eqId48c82801a4a7e0b2c8b33d5825189013或eqId55756b18ae8c86d05f16ed0366947978 D.eqId974fc6c50dee420e62ee6957678619a9或eqId57dfa5281529b8c6998b69b321478757

3.若不等式eqId5b5f28031b036e4a37be931d5ff28368的解集为eqIdff6fc762c6bf13764516d2f0575fa7c7,则不等式eqId23e045220e5071c3a7adc357816db322的解集为(    )

A.eqId66232de5df15393fe94943e7b8097516 B.eqIda75c7dfd5bd6c6d3dfa3de447a037c32或eqId01c5c48552684aad1637b0834225c2e0

C.eqId90762bc00a826b133d3a18be084385c8 D.eqId7f956a6c246da358d19de8e6b993c094或eqId5d2212ca63a0f4cac1086319559aa388

4.若一元二次方程eqId9080124b199b1e89dc16d0e12af028dd(eqId20849c00c47cbdc43f18d53341b6c4e5)有一个正根和一个负根,则有(    ).

A.eqId9e10e1c43b86a8cd4360ca9b57232164 B.eqId94440d3e4c073f94f2b266ff99d50e74

C.eqId3002ad1638f25e355d70d5ab63e637f4 D.eqId1d33da711e50e96568facb18cef27165

5.若一元二次不等式eqId5b5f28031b036e4a37be931d5ff28368的解集是eqIdbe953202a0096c3536565ac26145f43a或eqIdc241cb7b380c084e45ea3f86cd561bd5,那么下列选项正确的是(    )

A.eqId9e10e1c43b86a8cd4360ca9b57232164 B.eqId4944b18a1daae0480089124e5551107f

C.eqIdbd04c6b9cc47521108979a622c2b7c83 D.eqId13fa32c1e926f40a0722d106563777ef的两根为eqIdd70bd347c9149626acd45115ba278c1e

6.已知命题“eqId8645952ea14b25443f411d39bdec641e,eqIde1d2c57497482e8d2002eac9e49b4636”是假命题,则实数eqId0a6936d370d6a238a608ca56f87198de的取值范围是(    )

A.eqId092db4e0fdaf2bd7109585e10a1c3891 B.eqIdcec0a4e9bc883e4a75383d9a31d4c894或eqId055365d21f92fdb6881310bda08c3f75

C.eqIdc3d708f26c6f2c54d80405b4c8250d9c D.eqIde9ee71d55403212e8e1613b18ad38196或eqIdb87ecc31822d729a45488d803fff4e16

7.对任意的eqId66692ec49a458f9e48c7315d03dfc37b,eqId697da80270be67c88c6f742a75457d4f恒成立,则eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围为(    )

A.eqIded6d804ef44bfc64f824b0ccef71765e B.eqId455ba3d3e46977fcbe5b71f8bb9df4be C.eqIdbe381da62d4a042476aa11dbd5824e8d D.eqId9b4280adea02588850b0a1af4844fcea

8.命题:“eqId3bb562af502e665a339456398580e876使得不等式eqId2ed5269d881008e538cef586e1cc18bd成立”是真命题,则实数eqId0a6936d370d6a238a608ca56f87198de的取值范围是(    )

A.eqId535a01c69c5b4aeaf9d99f48e95e37e1 B.eqId55a21b2c529e79ab1381567bbb7138e9 C.eqIdacf90d778689e6aea33e053960f1a47f D.eqId824a1067cc97e5499efd6cc269d8ed74

二、多选题

9.已知关于x的不等式eqId5b5f28031b036e4a37be931d5ff28368的解集为eqId11926ae5b477d7848f9dcc39416bcbf0,则(    )

A.eqId1ac9eb4f13a6ec140f7050e8d7dde52cpage number 0

 

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B.eqId12e7ef804eeb23618fbf91ead47587f2

C.不等式eqId42afcaa5895d8f16e8280d004cec4da2的解集为eqId121003590fe11f01ab3d694c8b8080cc

D.不等式eqId23e045220e5071c3a7adc357816db322的解集为eqIdfcc91ac75763686cd9fcc7ac25b38057

10.已知关于x的不等式eqId5b5f28031b036e4a37be931d5ff28368的解集为eqIdf896211a4b21a5fee93200ed27efa900,则(    )

A.eqId9e10e1c43b86a8cd4360ca9b57232164

B.eqId12e7ef804eeb23618fbf91ead47587f2

C.不等式eqId23e045220e5071c3a7adc357816db322的解集为eqId84d3d7fd4826c1fb2e9c8169e0e99d6a或eqIdf327e561a69328350a191c6c50555616

D.不等式eqId23e045220e5071c3a7adc357816db322的解集为eqId8b5bb33148f010837b5e1730db8024e9

11.下列说法中正确的为(   )

A.集合eqId5c51f18ce4bff97ce71d4f59bf09ca90,若集合eqId5963abe8f421bd99a2aaa94831a951e9有且仅有2个子集,则eqId0a6936d370d6a238a608ca56f87198de的值为eqId9e0262791cc14598c6fc5ed0937d0124

B.若不等式eqId9b8b28f36caad1aaecf07a4e93958743的解集为eqIdcf3ed15aa3dcc4211fb520b5b942c989,则eqIdf0a532e15e232cb4b99a8d4d07c89575的取值范围为eqId5ca31c862890af181c5603111a77c970

C.设集合eqIdeb79be29344d7c97f5b44057d18f7520,eqIde10e7da3c45fb4daa2029f16065a7673,则“eqId0b550ee821ee1838384835e81fc34b67”是“eqIdd9d0d79fd0efdb59c9ca65bfae4a0861”的充分不必要条件

D.若正实数eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886,满足eqId131ac7eb1e911c9a40e84235bf3742ed,则eqIdd17f8f3c528d139b64499e30c3a6bc29

三、填空题

12.已知关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次不等式eqIdc84f791dabaf4e6dd3e0da98c6501a9e的解集为eqId989232b16e26e6b71330b7bd5eac5bc9,则实数eqId0a6936d370d6a238a608ca56f87198de的值为_________.

13.已知eqId9e10e1c43b86a8cd4360ca9b57232164,则关于eqId81dea63b8ce3e51adf66cf7b9982a248的不等式eqIda8c72612b37ec0b52079d003fb5c3abb的取值范围是________.

14.若命题“eqIdd3c069daa14dce1925218ed0fd042407,不等式eqId1a123454ffadc4ccc6fcdf1b40093e33恒成立”为假命题,则实数eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围为__________.

四、解答题

15.已知eqId2bfafbd8566a0f92d1e8228fb626587e,eqIdbc74000932d10f3a3ea299c18881304c.

(1)若eqIdcf0086b054ef120408acac806a1b1318,eqIdb1010846eeec6c9da29640f5aa3f8738,eqId9aa8a716a31b0f51b70fdf9bdb257909有且只有一个为真,求实数eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围;

(2)若eqId9aa8a716a31b0f51b70fdf9bdb257909是eqIdb1010846eeec6c9da29640f5aa3f8738的充分不必要条件,求实数eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围.

16.已知函数eqId570766a38c907eaca3ccddf32400f665.

(1)若不等式eqId018857ec6e498113b3b12a730d9313da的解集为eqId927144b706e72fd77615f26d694931c3,求实数eqId632244ea6931507f8656e1cc3437d392的值;

(2)当eqIdc3ca73685936467413d10511fdad8679时,求不等式eqId22e38c541dec8fce1d26886e5ef7d21f的解集.

17.已知不等式eqId96b2133f906594e0000744fce58470fc的解集是eqIdcd366ca13f1325bc135f33ee6393f4ee.

(1)求常数a的值;

(2)若关于x的不等式eqId9a5d927e2599f12392bb31c6ee317da8的解集为R,求m的取值范围.

page number 1

 

试卷第3页(共2页)

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《二次函数与一元二次方程、不等式同步练习》参考答案

题号

1

2

3

4

5

6

7

8

9

10

答案

C

C

C

A

D

A

D

C

ABD

ABD

题号

11

 

 

 

 

 

 

 

 

 

答案

BCD

 

 

 

 

 

 

 

 

 

 

1.C

【分析】先解出全集eqIdb52b4f24969673c863b5aff4fb6751ce再计算eqIdc093cbde3d3472d1f7f2b0dff2bc4881即可.

【详解】由eqId9f7c6de5f126adc38c8e5cc7fcbc0fa4且eqIdf6b54fdc920fd0a627959bbc5bd292d3,解得全集eqId77eba8cd7b562a514c52a1bf0d7b2287,则eqId3e2aadb7e40c4911d2d7630bb09db4ae,共有6个元素.

故选:C.

2.C

【分析】把原不等式两边同时乘以eqIdacbc6a613224461ade69362d46550474,把二次项系数化为正值,因式分解后可求得一元二次不等式的解集.

【详解】由eqId26c71ffaf62eeb624391dab5babf9d47得eqIdb8d3d8d716b30b2c09ae2160d3f58a9c,即eqIda3f8716c6a1254ed90a8a6a71c1edceb,解得eqId16139d5c75ad4498e5d8526679ad009e或eqId0fde64f4d3c38e43fbdee24eadc4b0dd,

所以不等式eqId26c71ffaf62eeb624391dab5babf9d47的解集为eqId4ac6d85378dae2f303a74b436de78abf或eqIdeb6b253b187fe36e6bd40c46bcfc114a.

故选:C

3.C

【分析】根据不等式的解集可得参数的关系,代入所求不等式后可求其解集.

【详解】因为eqId5b5f28031b036e4a37be931d5ff28368的解集为eqIdff6fc762c6bf13764516d2f0575fa7c7,

故eqId9e10e1c43b86a8cd4360ca9b57232164且eqIddd9bc1d1f79c4f82e074170d7a433f6b为方程eqId13fa32c1e926f40a0722d106563777ef的解.

故eqId61c5c9fecc1fc91be89e879b3e964ee8,故eqId21bf2710f2e948ea4e27852b71edafa5,

故不等式eqId23e045220e5071c3a7adc357816db322即为eqId10d1656ff52949161717bb5765c45ba1,

故eqId355756e5289c6c589ed7ad9d9c7f172e,故eqId4b575f57cb9663fb419f4754964e512a,

故不等式eqId23e045220e5071c3a7adc357816db322的解集为eqIda73bd095bdeb381ea30df9b7110b853e,

故选:C

4.A

【分析】根据一元二次方程根与系数的关系求参数eqId0a6936d370d6a238a608ca56f87198de的取值范围.

【详解】由题意:设方程eqId9080124b199b1e89dc16d0e12af028dd的两根为eqIdc814128ea2139e33db94ea590e7c2223,eqIdaec19b68e3add9d5bfcc6269a1855b87,(eqId4a7b0c34c4a6e7be6f08ef7b7829c4b8).page number 2

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