内容正文:
第六部分
因式分解
练习51用提公因式法因式分解
建议用时:15分钟实际用时:
做对
题答案见P10
把下列各式因式分解:
(1)18a3bc-45a2b2c2;
(2)-20a-15ab;
(3)15a3-10a2;
(4)-20c(a-b)2-25(b-a)3;
(5)15(a-b)2-3y(b-a);
(6)-ab(a-b)2十a(b-a)2-ac(a-b)2;
(7)18xm+1-24x”;
(8)(m+n)(x-y)-(m+n)(x+y);
(9)4xyz-4x2yz-12xyz;
(10)20am+b2m+4-12a2m+1bm+2.
57
计算高手数学八年级
练习52用公式法因式分解(1)
建议用时:15分钟
实际用时:
做对
题
答案见P10
1.把下列各式因式分解:
(1)a2-49;
(2)x2-2x+1;
(3)x2(x-2)-16(x-2);
(4)3(m+n)2-27n2;
(5)a2+8a+16;
(6)25m2-80m+64;
m需
25y2;
(8)x2y2-9;
(9)、1
2+9y,
(10)(a-b)2-4b2;
(11)a2(a-b)+b2(b-a);
(12)a3-9a.
2.已知4m十n=90,2m-3n=10,求(m+2n)2-(3m-n)2的值.
58
因式分解第六部分
练习53用公式法因式分解(2)
建议用时:15分钟
实际用时:
做对
题
答案见P10
把下列各式因式分解:
(1)(m-n)2-1;
(2)4x2-(x-y)2;
(3)-(a+b)2+(2a-3b)2;
(4)49(x-2)2-25(x-3)2;
(5)x2-6xy+9y2;
(6)1xy+4、
(7)a4b4+4a2b2c+4c2;
(8)x4-18.x2y2+81y4;
(9)-a2-9b2+6ab;
(10)16m2n-64m4-n2;
(11)a4-9a2b2;
(12)4(x+y)2+25-20(x+y).
59练习50易错专题训练
1.(1)x>2
(2)x>-2
8z≤-1④x≥9
2.(1)x<-1(2)4≤x<6
8)-1长<340-}<<8
3由3x+m<0,得z<-学
:原不等式组有解,不等式组的解集为一5<x<一空
,不等式组的所有整数解的和为一9,
.不等式组的整数解为一4,一3,一2或-4,一3,一2,一1,0,1.
当不等式组的整数解为一4,-一3,-2时,有-2<-号<-1,
解得3≤m<6:
当不等式组的整数解为一4,-3,一2,-10,1时,有1<-号
≤2,解得一6≤m<一3.
综上所述,m的取值范围为一6≤m<一3或3≤m<6.
第六部分因式分解
练习51用提公因式法因式分解
(1)9a2bc(2a-5bc)(2)-5a(4+3b)
(3)5a2(3a-2)(4)-5(b-a)2(4c+5b-5a)
(5)3(a-b)(5a-5b+y)
(6)-a(a-b)2(b-1+c)(7)6x(3x-4)
(8)-2y(m+n)(9)4xyz(1-x-3y)
(10)4am+1bm+2(5b+2-3am)
练习52用公式法因式分解(1)
1.(1)(a+7)(a-7)(2)(x-1)2
(3)(x-2)(x+4)(x-4)(4)3(m-2n)(m+4n)
(5⑤)a+402(6(5m-82((品x+5)(6x-5y)
8w+3(y-3》(9(3+2)(3y-7x)
(10)(a+b)(a-3b)(11)(a-b)2(a+b)
(12)a(a+3)(a-3)
2.原式=(m+2n+3m-n)(m+2n-3m+n)=(4m+
n)(-2m+3n)=90×(-10)=-900.
练习53用公式法因式分解(2)
(1)(m-n+1)(m-n-1)
(2)(3x-y)(x+y)(3)(3a-2b)(a-4b)
(4)(12x-29)(2x+1)(5)(x-3y)2
(6)1-g)'()a26+2e)8x+3rz-3yy
(9)-(a-36)2(10)-(8m2-n)2
(11)a2(a+3b)(a-36)(12)(2x+2y-5)2
练习54因式分解(1)
1(1)5x2y(3xy+1-4y2)(2)7(x+2y2)
(3)(7a+3b)(3a+7b)(4)(x+y+3)2
(5)(a-2)(2x+y)(6)(3x-y)2
(7)(x+2y)2(x-2y)2(8)ab2(b-2)2
(9)3(x+y)(x-y)(10)m(x-2)(m+1)(m-1)
(11)(a-3b+3c)2(12)2(x+2)(x-6)
2.(1)原式=(38.9-48.9)2=102=100.
(2)原式=(34+16)2=502=2500.
1
练习55因式分解(2)
1.(1)x(x-5)2(2)2x(x-2)2
(3)(x+2)2(4)(x+3y)2
(5)2m(x-y)2(6)ax(z-2a)2
(7)(m3+n2)2(8)(x-y+4)2
(9)a(x2+3y)(x2-3y)(10)(x+y)2(x-y)9
(11)3a(b+3)2(b-3)2(12)(a+b)(a-3b)
2由题意,得m十4+(n-2)2=0,则m十4=0,n-2=0,解
得m=-4,n=2,.2nx2十y2-mxy=4x2+y2+4xy=
(2x+y)2.
练习56因式分解(3)
1.(1)3a(x+y)(x-y)(2)3(1-x)2
(3)-8a(x-y)2(4)-3ab(a-3b)2
(5)-a(1-a)2(6)4(3x+y)(3x-y)
(7)(m+3n)(n-m)(8)xy(2x+y)2
(9)(a-b+2)(a-b-2)(10)(x-1)4
2:(y-x)(x-y)=-1,.(x-y)2=1,
_(x-y)21
3.,x2+y2-4x+6y+13=(x-2)2+(y+3)2=0,.x-2
=0,y十3=0,解得x=2,y=一3,则x2-6xy十9y=(x
-3y)2=112=121.
练习57因式分解(4)
1.(1)y(x+3)(x-3)(2)3m(a-b)2
(3)(a-b)(a-b+1)(a-b-1)
(4)(x+2)2(x-2)2
(5)(9x2+4y2)(3.x+2y)(3x-2y)
(6)(x十y)(x-y十a)
(7)2m(m-n)(5m-n)
(8)-4ab(2a-3b+a2b2)
(9)3x(x-y)2(10)-4x(x-1)2
2x4+64=x4+16x2+64-16x2=(x2+8)2-16x2=(x2+
8)2-(4x)2=(x2+8+4x)·(x2+8-4x).
练习58因式分解(5)
(1)(p+q)(6+a)(6-a)
(2)m(3x2+y)(3x2-y)
(3)(a-3)(m+2)(m-2)
(4a-xa+1D2(5)-22x-1D
(6)3m(2x-y+n)(2x-y-n)
(7)a2(1+4b)(1-4b)
(8)-4(2x+3)(3x+2)
(9)8(a+b)(a-b)(10)a(x+5)(a-1)
(11)(ab-2)2(12)(1+m-n)(1-m+n)
练习59因式分解(6)
1.(1)(x-2)2(2)(a-b)(a+c)
(3)(x+y-1)(x+y+1)
(4)(xy十2)2(xy-2)2
2由题意,得a十b=6,ab=2,
,.原式=ab(a2+2ab+b2)=ab(a+b)2
=2X62=72.
揭秘新考法
【全解】(1)把x=1代入多项式x3十3x2一4,多项式的值为
0,.多项式x3+3x2-4中有因式(x-1).可设x3+3x2-4=(x
-1)(x2+x十n)=x3+(m-1)x2+(n-m)x-n,∴.m-1=3,
n-m=0,.∴.m=4,n=4.