江西南昌新民外语学校2025-2026学年高二下学期期末考试数学试题

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新民学校2025—2026学年度第二学期期末考试

高二数学试卷

时间:120分钟    分值:150分

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一、单选题

1.设集合eqId6bcf8675b3e41693e9ad890fcc8c339c,eqIdad5cdd142f55ebfdceced9b2180b1323,则eqId8fdbfa7a63fdf5717d40c8c9a73ec160为(    )

A.eqId7a92ba8b43bebdf7d6c40917f4d3e110 B.eqIdbeb9168e93287e7bf0e28e5fd341a194 C.eqIdd4dd57b188b9e28d95ab2a24831b580c D.eqIde565001c699e5e221ed616dd7be2bb83

2.命题“eqId8ccd7af9298cd5ff19d8866fedb42ec4,eqId40dc0edad8fc6bc6b1fa560bbb16c7fa”的否定是(    )

A.eqId4ad5fe274cfc8da2dacfb65801f344ac,eqId33f1fd2e4df62d7d587309ea09aff81c B.eqId4ad5fe274cfc8da2dacfb65801f344ac,eqId9bc7284e1864051256ba2d4dee2f2bab

C.eqId8ccd7af9298cd5ff19d8866fedb42ec4,eqId1b0d5814a65c212822f74ba12845f2bd D.eqId8ccd7af9298cd5ff19d8866fedb42ec4,eqId40dc0edad8fc6bc6b1fa560bbb16c7fa

3.已知命题p:eqId8b0410944f3ca8df82d676975f517426,命题q:eqIdf6f364d884f8360badadb9977260c5ab,则下列判断正确的是(    )

A.p假q假 B.“p或q”为真

C.“p且q”为真 D.p假q真

4.不等式eqId24f3384072239b162560dbdc0f34b3e4的解集为eqId989232b16e26e6b71330b7bd5eac5bc9,则eqId20d6fc9b90f370fbb27552876b650f8f的值为(    )

A.3 B.1 C.eqId81fb134b2b48acc99213fff6ccfee65f  D.eqIdacbc6a613224461ade69362d46550474

5.若函数eqId85d9c017d5b260176c9cc2658c04c586为幂函数,则函数eqId09f86f37ec8e15846bd731ab4fcdbacd在定义域内为(    )

A.增函数 B.减函数 C.奇函数 D.偶函数

6.已知eqIdadc3e5be1796493161a4df7e28a6f6b7,则 eqIdb84f2eabee583f05e72db0c576e01662的最小值为(   )

A.3             B.4                C.5             D.6

7.关于eqId81dea63b8ce3e51adf66cf7b9982a248的一元二次方程eqId13bae5c4c239c4fcad53bc42faebd151的两个实数根互为相反数,则eqId0a6936d370d6a238a608ca56f87198de的值为(   )

A.2 B.0 C.1 D.2或0

8.已知函数eqIda2b5c9b9934c72b4523acd7f5ce72a94,则不等式eqIdccfc2b489e0d8539cc40174820f2ce85的解集为(    )

A.eqId9a7e88b74f492f89e21e4cf65353bdb6 B.eqIde2ce2f5e22175e3ff8ab5e0afca58f9c C.eqId5b469f31458c14208fddf45ff9cc81c4 D.eqId138506a762e636aa75a4d54f5b739b89

二、多选题

9.已知实数a,b满足eqId00a46433ca824e9557482dc47f93e147,eqIde484cf0deeccef062ce5644a3602c2bb,下面说法正确的有(     )

A.eqId85bdfc3ec4a2df1157baa8bc341fcce5      B.eqIded3f588c3867c8da69c6112b19219303

C.eqId1efd5be1b5cb8eee051d13ab05656105      D.eqId08f6cba08276a3aac5e77f996c7fd4cf

10.已知eqId294f5ba74cdf695fc9a8a8e52f421328为任意实数,关于eqId81dea63b8ce3e51adf66cf7b9982a248的方程eqIdc02295d8544d32a61cf38639a321fe54,则(   )

A.当eqId561800aa679a45da4dbe0e323de1fd59时,方程有两实数根

B.当eqId65d1eec645764636c0e23b05e8f93234时,方程有两异号的实数根

C.当eqId711b21672fd907c5c92fee1d649e7003时,方程有两实数根eqIdc814128ea2139e33db94ea590e7c2223,eqIdaec19b68e3add9d5bfcc6269a1855b87,则eqId8afaea411eb2b776ab07d93d8c25239b

D.若方程有两个实数根eqIdc814128ea2139e33db94ea590e7c2223,eqIdaec19b68e3add9d5bfcc6269a1855b87,且eqId5a494d0d8305b6586808c7c400bbcce8,eqId311cff32b515f4fa954a3a5731cbb52c,则eqId83c5188962ddff1aa8150245068e6caf

11.已知定义在R上的函数eqId4fe7d5809da02c15a43a0e9a898b9086满足eqIdbd384d86840b7b158af41f56fe29c7d1,当eqId08115d6d9f876dea921a4d32260ff1fb时,eqId018857ec6e498113b3b12a730d9313da,eqId99d002d8423808d081345bdac6c25f07,则(   )

A.eqIda78503abdf5311be4a685eee205442f6 B.eqId4fe7d5809da02c15a43a0e9a898b9086为奇函数

C.eqId4fe7d5809da02c15a43a0e9a898b9086在R上单调递减 D.当eqId7da6d82d173ad18cc040e94c925b5ab9时,eqId32eeeef91c865e097c41d9f1c8a347ee

三、填空题

12.已知集合eqId1646475774b63f4a04ca62961afdbecf,且eqId35a2410ce34b36954ed4923e600d42f5,则eqId380bbacf854e30e2e747fc286d2b9997___________.

13.函数eqId862609e8b86f4c07221ed0390385fff2(eqId94440d3e4c073f94f2b266ff99d50e74且eqIdc400a615a16a1662de98dfb4e49d58d3)的图象过定点eqId5963abe8f421bd99a2aaa94831a951e9,则点eqId5963abe8f421bd99a2aaa94831a951e9的坐标是________.

14.设函数eqId210f72b5afa2a576e19610ac6773c3f2对任意eqIdf0407c62eb735b44cf221fe2442c1580有eqId53a57d6d7b74ae630e6ce3b43afe6060成立,则实数a的取值范围是________.

四、解答题

15.已知集合eqIde8902c32ff3b0442f86904dc2cebaa93.

(1)若eqId3b4d795709b0abcf47bceec2250f2f9b,判断集合A与集合B的关系;

(2)若eqIde23af61cd402b3789af2401bde9cbefe是eqId6ed006b944ea64f970fee46e2f558467的充分不必要条件,求实数a的取值范围.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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16.已知eqIdb1010846eeec6c9da29640f5aa3f8738:eqId04ff04c4dbac50829387114e1c3dde3d.

(1)若eqIdb1010846eeec6c9da29640f5aa3f8738为真命题,求实数eqId0a6936d370d6a238a608ca56f87198de的取值范围;

(2)已知eqId9aa8a716a31b0f51b70fdf9bdb257909:eqId3e6fcfdcd0fcf0cb1fb3df6d36cc91b7,如果eqId0cd5371a6f0f82c65dd22f75f8b807c1都是假命题,求实数eqId0a6936d370d6a238a608ca56f87198de的取值范围.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

17.已知幂函数eqId8e1dba989fad5e558cff74144c8ee728的图象不经过原点.

(1)求幂函数eqId09f86f37ec8e15846bd731ab4fcdbacd的解析式;

(2)若eqId7e090ef7dbb50d679885c1f89dad0a92,求eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

18.已知函数eqId4f212e63cafd79ee0a45b0bd5581b723的图像经过点eqId7362fa526a84b0ce2f5a2021dbc44399,其中eqId94440d3e4c073f94f2b266ff99d50e74且eqIdc400a615a16a1662de98dfb4e49d58d3.

(1)求eqId0a6936d370d6a238a608ca56f87198de的值:

(2)若eqId307670730f1e0f4dfb8d9f65f9548e03,求实数eqId79b752f0f189e5d8666daea73e145dff的取值范围.

 

 

 

 

 

 

 

 

 

 

 

 

 

19.已知函数eqId61031f8f6c127f6d60ff1c76744d3dd9(eqIdd5f7f23e7f20dd8bc65a4967cd306782 且 eqId20849c00c47cbdc43f18d53341b6c4e5)是偶函数.

(1)求实数eqId0a6936d370d6a238a608ca56f87198de的值;

(2)若 eqId10e569bbdd0770b2c6a83d2c31e8a4c1,且对于 eqId72fa139aad70ad1ac124affc3fe5d75c,不等式 eqIdaeaee3e0aff7a2a6349678f98e17bf10 恒成立,求整数eqId294f5ba74cdf695fc9a8a8e52f421328的取值集合.

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《高二数学期末考试卷》参考答案

题号

1

2

3

4

5

6

7

8

9

10

11

答案

D

B

B

A

C

A

B

D

ABD

ABD

ABD

 

1.D

【分析】先解绝对值不等式得到集合eqId7f9e8449aad35c5d840a3395ea86df6d,再结合集合的交集运算求解即可.

【详解】由eqId64eee39ec6e6109772cf17e10498faaa,即eqId66545c16c7ff3d10fc3d760c971df0ab,解得eqIda417f68c6538bfb63e729c047755b4ef,

则eqIdf5e1f4f339bf00e957f59bb5674ec62c,

所以eqIdb66abdb69e502a8799030d626088475c.

2.B

【详解】解:命题“eqId8ccd7af9298cd5ff19d8866fedb42ec4,eqId40dc0edad8fc6bc6b1fa560bbb16c7fa”的否定是“eqId4ad5fe274cfc8da2dacfb65801f344ac,eqId9bc7284e1864051256ba2d4dee2f2bab”.

3.B

【分析】逻辑联结词,第一步判断两个命题的真假性,第二步利用含有或且非逻辑联结词复合命题判断真假.

【详解】命题p:eqId666c76fd866a9f25ce96a242a1e5477f 命题正确,命题q:集合eqId0910c9bcf1199aaa0e205c24297fa403是含有一个元素的集合,不是空集所以不正确.选项A,不正确,选项B或命题“有真则真”所以正确,选项C且命题“有假则假”选项D不正确.

故选:B.

4.A

【分析】根据一元二次不等式和一元二次方程之间的关系,判断出不等式对应方程的根,结合根与系数的关系可得答案.

【详解】因为不等式的eqId24f3384072239b162560dbdc0f34b3e4的解集eqId989232b16e26e6b71330b7bd5eac5bc9的端点值就是相应方程的根,

即方程eqIdb68902249ea08c054b18439dbebaaf0a即eqId08625bcb19f467f562521b704cf8afe3的两根为1和2,所以eqId230a4422a64b0bdf792be23d5577785e,

故选:A.

5.C

【详解】函数eqIde1853b28bafe7fcda9f61633a7265096为幂函数,eqId294861b37db0dd8da84bc4de774fd851,得eqId7aed39f5aca78934fb383402433fe549,

eqId0bd988a6cc9707906aac546537aa004d,定义域为eqId13bfbe78dc3ca9fa141e1710738a7f33,

eqIda60b6dfd543413f23af227fa123bf163,故eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f在定义域内为奇函数,故D选项错误,C选项正确;

根据幂函数的性质知eqId35efb70f9ffdc5502eb038a4264f1e5b在eqIde63fc1514bf033da290fd9f4b35c9a3c,eqId6cd50020c0e3198d4a6b2d26a413b1b8上单调递减,但在其整个定义域上不具有单调性,故选项A,B错误.

6.A

【分析】根据基本不等式即可求解.

【详解】当eqIdadc3e5be1796493161a4df7e28a6f6b7时,eqId815d001ad540c93e4c63736b6c57767c,所以eqIdbe36bcb20223781070ec7c8033d4633c,当且仅当eqId53ad7ff9629fd99159da58d1a59560f6,即eqId9b384412acba251d87902ab928902f16时等号成立,故eqIdb84f2eabee583f05e72db0c576e01662的最小值为3.

7.B

【分析】通过韦达定理求解,并验证即可解page number 2

 

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