第十章 分式 单元练习 2025-2026学年苏科版八年级下册数学

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分式单元提升巩固小练

一、单选题

1.代数式eqId0f22da00c89815690e04582ae451de05中,属于分式的有(     )

A.2个 B.3个 C.4个 D.5个

2.要使分式eqId5e504a461db88828c16187aa7fa172f0有意义,则eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围是(  )

A.eqId38f0e9c04402a0ffdaa25c3e3c82c7dd B.eqId0935b0d5568370418871fa7a6c47162d C.eqIdf23d29646155e27b172ecdf263e2d702 D.eqId8ad2b31cfb9939e45bdb29af8139af06

3.下列分式变形一定正确的是(     )

A.eqId6160342729eb1c26d637e64fee75f14d B.eqId366d8cdd5a3cee073744d6452cf273c9 C.eqIdadfcacb394123dda5398298c3543f15b D.eqId98f0a69f8fe30d809e46f6127b693ffb

4.如果把分式eqId5a1561f5900b4314def868e0a8c5a374中的x和y都扩大3倍,那么分式的值(   )

A.不变 B.扩大3倍 C.扩大6倍 D.缩小3倍

5.若关于eqId81dea63b8ce3e51adf66cf7b9982a248的分式方程eqId9ea4e2d5e12656992b47d2e6a51a0c5d的解为正数,则eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围是(     )

A.eqId00c698cdb6982beeaa266ac9170cabd4且eqIdea4967f87cd5be9fed1587f48324b12c B.eqId0bd8ba8bfcbf4c2e2c47e83403bd8902

C.eqId00c698cdb6982beeaa266ac9170cabd4 D.eqId0bd8ba8bfcbf4c2e2c47e83403bd8902且eqId2aed0bfba78e2be6a0a8c500ce0eb8a1

6.若eqId3571836cc85e05a58d2eec39c61bf42f且eqId9897b78a9ce93c29bd4df8b283a7829b,则eqIde15a5486f04b60ca88eca7223f293bd9的结果为(     )

A.1 B.3 C.6 D.eqId4dac452fbb5ef6dd653e7fbbef639484

7.已知 a 为正数,且eqId37c84b49231d0344d0813a7bbd2acdaa或eqIdf184ef9e0d57554e95f369c9d4bbfea1,比较eqId4bbce77ea0763787901a1cae61889ab5与eqIdff4b49d33aafe9a6f05e065773508d07的大小,可通过作差法判断,则 P 与 Q 的大小关系为(     )

A.eqIdc1bad90eaa7e0907a78bf26843c5caef  B.eqId1635bf5d02c31bc54dc5ecfd1cf2d79b  C.eqId09339ae9b0197a423427c489673a5664  D.eqId6fa992a70282ea2b66419a3826ad6492

8.要使eqId91efa4f3e3eea68d0b02e6ace9681b51的值为整数,下列选项中,eqId81dea63b8ce3e51adf66cf7b9982a248的值不能是(     )

A.2 B.4 C.5 D.7

9.若eqId69fa88c6067600f8f279243972cd791b,eqId58b0ba5c937b27a27b5ef5ab9e51a935,则eqId4fdf59d731196ce7b2567c2b7ad21a6e的值等于(   )

A.eqId459c84c9addfbd1cdd0a877ba7c584e4 B.eqId3389f53711264b0acba3ba6019f8b908 C.eqIdacbc6a613224461ade69362d46550474 D.eqId4e8b4bbd2f9912adfc9864c0e1e76a9d

10.对于实数eqIdf0a532e15e232cb4b99a8d4d07c89575进行如下eqIdb6a24198bd04c29321ae5dc5a28fe421次操作:eqId25ff3e91737156f670218e162888449f;eqIdcfcf6fae01f3aa62762842b18afdcb84;eqId33fd43ad6ade1665bc199383b45606fa;eqIddaa5e9bd516f6282483b92cfe6074623;eqIde6620d115810d7c748daa668117ef70d.下列说法:①若eqId03030ddf48d8ac0130873602773789a8,则eqIdf8e69866076dcff686a05e9e91e61e68;②若eqIdc80675947e08f855094dc8492f503ec9的值是1,则eqIdd3a2a34b4317deffa40ba34e269c2b81;③page number 0

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eqId57289ba013bc5342acc52ee7eca806e1的值为2,则eqIdf0a532e15e232cb4b99a8d4d07c89575的值为eqId4dac452fbb5ef6dd653e7fbbef639484.其中正确的个数是(   )

A.0 B.1 C.2 D.3

 

二、填空题

11.化简:eqId758e47cc2c04c85f65becef5784754ea_______.

12.已知实数eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1满足eqId36a4babdf8f99492001c26d90372b08f,则eqIde5474612cc18977f0a66c0c2c321555d的值为______.

13.若分式eqId8111580783b64dfb693f0d514f833f89的值为零,则eqId4ec0618ae3a4fde6d6220010af229b9a______.

14.当eqIdfadd2e6f0aa16c2c466c904474ffc79c时,计算eqIdd5b3d23e2ba82bd69bcce711bad99602的结果是__________.

15.已知eqId69fa88c6067600f8f279243972cd791b,eqId58b0ba5c937b27a27b5ef5ab9e51a935,则eqId9e0541697f9fffb316df0f64bf409847的值为________.

16.对于实数m,n,定义两种新运算:eqIde47e041f8d508613fa9d99ac1cd80240,eqIdafd4e01fa5f05a5c2c786fe6f57fbdf4,则eqIdec3f9997a976855621217cfa2bd15d3f的值为______.

17.如图,甲正方形的边长为a,乙正方形的边长为b,eqId432d77fe5ad3032d59a237dd94c8a638,按如图所示的两种方式放置.图①中阴影部分面积为16,图②中阴影部分面积为12,则eqIdd5e1e74f56e6e22a25caa52a44eef98b的值是______.

@@@1eeb57ef-507c-4bd7-904a-d5510f2c04e6

18.观察下列分式:eqIdf86cd6618a7ccc50128e4ffd64b02c7b,eqIdd1246816fbdcd32358c03fb720529db2,eqId6c0efd0d5d90c8cf02979d254ca06e7c,eqId9f4896b09282879e5dca3dc39b6bc380,…(其中eqId20849c00c47cbdc43f18d53341b6c4e5,eqIdfef20073a12bab727faa217718b63414),用任意一个分式除以它前面一个分式得到的结果是_____,根据规律,请写出第2026个分式_____.

19.已知eqId81dea63b8ce3e51adf66cf7b9982a248为整数且满足代数式eqId441ebb63171e3a1cdc8fba352547661d的值为整数,则eqId81dea63b8ce3e51adf66cf7b9982a248的所有取值为______

20.实数a,b,c满足eqId09b53673a49ee39543026966bc7aaa4f,eqIdf0fe9f204eeb884e3001726b261ca8bf,则eqId86de17957f02ce8c75e88dbccaec43a6________.

 

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三、解答题

21.解方程:

(1)eqIdb2ee9ab2d9429f768db013b431c26a79;                          (2)eqId13c6dfe6bbb390aca7034173ee08b6f1.

 

 

 

22.先化简,再求值:eqId63ca5c3d9dff234f24be015add7e995f,其中eqId495736ab23ceeaf548a3f02340ad8095

 

 

 

23.已知关于eqId81dea63b8ce3e51adf66cf7b9982a248的分式方程eqId35b3ad66c59f2680dc5c2a36afe4f0d8.

(1)当分式方程有增根时,求eqId294f5ba74cdf695fc9a8a8e52f421328的值.

(2)当分式方程的解为正数时,求eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围.

(3)当分式方程有整数解,且eqId9f2665abd566cac008c474985d0d1da5时,直接写出所有满足条件的整数eqId294f5ba74cdf695fc9a8a8e52f421328的和.

 

 

 

 

24.湖南师大附中团委组织八年级部分同学到长沙县“慢天使”之家给脑瘫儿童送新春慰问.在准备礼品时发现,购买一件甲礼品的费用是购买乙礼品的1.5倍,并且花费600元购买甲礼品比花费600元购买乙礼品的数量少4件.

(1)求甲、乙两种礼品的单价各为多少元?

(2)学校准备购买30件礼品送给“慢天使”们,正逢商店新年促销,甲礼品打八折,乙礼品打九折,要求购买礼品的总费用不超过1500元,那么最多购买多少件甲礼品?

 

 

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