内容正文:
课时4独立性检验
x
x
n(ad-be)2
(a+b)(a+c)(b+d)(c+d)
H。XY
之3
心
X Y
X Y
C
x2≥xa
Ho
X Y
O
人Xa
Ho
X
之3
X Y
i
x
0
x
a
x
A
B
2×2
2×2
23
x
4
p
p
0=0.001
x2=
n(ad-be)2
a+b)(c+d)(a+c)(b+d)
P(x2≥K)
180
9
200
10
9
p=
10
Ho
2×2
X2=10020×20-180x7802_6125
765.625>10.828
0=0.001
800×200×200×800
8
Ho
A
B
S
t
s t
A
B
p
p
0=0.01
A
B
x2=
n(ad -be)2
(a+b)(c+d)(a+c)(b+d)
P(x≥xo)
xo
s=100+80=180t=80+70=150
A
B
80
4
p=
180
9
2×2
Ho
A
B
400×(100×70-150×80'
≈6.734>6.635
0=0.01
250×150×180×220
H
A
B
产品件数/件
7
60
40
30
0
10
0
0k40
60≤Q<90O>90质量指标值
☐升级前☐升级后
=0.1
P(X≤1)
P(X≤1)
I=
n(ad-be)2
0.68≈0.0168
a+b)(c+d)(a+c)(b+d)
0.69≈0.01010.60≈0.0060
p(r≥x
Xo
Ho
2、
200(80×10-90×20)2
≈3.922>2.706
0=0.1
170×30×100×100
H
0.1
0.4
X~B10,0.4)
P(X≤1)=C×0.610+C10×0.4×0.6=0.60+4×0.6°≈0.006+4×0.0101≈0.046
P(X≤1)≈0.046
0.046
95%
99%
p=0.5
p>p+1.65,
p1-p)
n
x=
nad-be)2
a+b)(c+d)(a+c)(b+d)
n=a+b+c+dV150≈12.247
P(x2≥x)
150(26×30-24×70)75
3.841<4.6875≤6.635
50×100×96×54
16
4.6875
95%
99%
96
=0.64
p=0.64
150
p=0.5
+1y2-031
0.51-0.5
≈0.5+1.65x
0.5
≈0.568
150
12.247
币>p+1.65,
p(1-p)
n
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