2026年九年级数学中考二轮复习轴对称综合题(角度问题)解答题专题提升训练

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2026年九年级数学中考二轮复习轴对称综合题(角度问题)解答题专题提升训练

1.已知:正方形eqId411b38a18046fea8e9fab1f9f9b80a5f,以A为旋转中心,旋转eqId03902478df1a55bc99703210bccab910至eqId20a541b81584a032f571159ea152c85a,连接eqIdce1fc0c9ccf812357f9df55816e10e43.

@@@6348bb6c-6b2b-4002-802e-d03ae9d4a397

(1)若将eqId03902478df1a55bc99703210bccab910顺时针旋转eqIdf6b86c22b670a8e9f3896f9e8883fbbb至eqId20a541b81584a032f571159ea152c85a,如图1所示,求eqId6fbf1667b21a273bf5dd007d65eeda7c的度数?

(2)若将eqId03902478df1a55bc99703210bccab910顺时针旋转eqIde170f206fdbbd834aad7580c727e2cc6度eqIdb3cc97a6f5f711b174535317d7b87f1f至eqId20a541b81584a032f571159ea152c85a,求eqId6fbf1667b21a273bf5dd007d65eeda7c的度数?

(3)若将eqId03902478df1a55bc99703210bccab910逆时针旋转eqIde170f206fdbbd834aad7580c727e2cc6度eqId56c611dbd6ec62e20aee303a9412abbc至eqId20a541b81584a032f571159ea152c85a,请分别求出eqId708d48b595c17d4dccf9b4086d7e664e、eqId33ac762a2899a58faa0d3ab44f1281fa、eqId13b5ea2fc43b19ca043581eb94197234三种情况下的eqId6fbf1667b21a273bf5dd007d65eeda7c的度数(图2、图3、图4).

2.【问题背景】如图1,点eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIda0ed1ec316bc54c37c4286c208f55667分别在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f的边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上,eqId192155e6a3aade305b76b1eb7c75e30c,连接eqId49b50357a6545cae8348e3059312f520,我们可以通过把eqIde742966e3711cfa53dce04022acf4bcc绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针旋转90°到eqId3bbd6f0a0412d0f43ce1f7c1d530e56e,容易证得:eqId7c9af98a1a048b1e2f7c71e83c33498c.

@@@48babd0c-badf-4353-8ddd-ef9c3eef4274   @@@f91fce09-b01a-405c-9fc9-4ff70d2ba8b6   @@@a9a27060-2847-472b-a270-1c0c016ccc65

(1)【迁移应用】如图2,四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2e735a28578ba191da6d4f3b0f8e8729,eqIdce0d7095ddd69d6ceaf1065b1bc2c79d,点eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIda0ed1ec316bc54c37c4286c208f55667分别在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上,eqId192155e6a3aade305b76b1eb7c75e30c,若eqIdfebc9a89d0d1c97b88c0f4acd32b4e67、eqId0c543c3ddc3723fde6bbfca3ea3b921b都不是直角,且eqId173904239da66b7bef7cb1d997cc40ed,试探究eqId49b50357a6545cae8348e3059312f520、eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqIdd004d2d115b477ade6af7ddb93db0df8之间的数量关系,并说明理由.

(2)【联系拓展】如图3,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9c06154cae3bf7a8ce5a1e97a7380875,eqId047dc9795efa99b6fb9fdf9778085dab,点eqId8455657dde27aabe6adb7b188e031c11、eqId2a30f3a8b673cc28bd90c50cf1a35281均在边BC上,且eqIdc76805974fefbe166b90d260e822ab5a.猜想eqIdd40b319212a7e7528b053e1c7097e966、eqIde6e490f703eb6c9bb1278c78ebc2d661、eqId1fc56c77464a17a1e97b568762a3e2c6满足的等量关系(直接写出结论,不需要证明).

3.如图,eqId15c0dbe3c080c4c4636c64803e5c1f76是等边三角形,点D是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边的中点,以D为顶点作一个eqIda6c0927afc571a7c966c98192040979e的角,角的两边分别交直线eqIdf0d54431bbb28ebd98db5c1dc6083a75于M、N两点,以点D为中心旋转eqId3a54e7b35c73ee578c4d01479ddb74cc(eqId3a54e7b35c73ee578c4d01479ddb74cc的度数不变)page number 0

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@@@d65aab92-5255-4468-8de1-96e8774abe96

(1)如图①,若eqId3c7ad8d177fc4dcb983c5952ad5533b9,求证:eqIdb81bff6ab5dca29789ae05b7f00c4f49;

(2)如图②,若eqId15a424b50eaeafa6f302ffd95476cb86与eqIdf52a58fbaf4fea03567e88a9f0f6e37e不垂直,且点M在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e上,点N在边eqId60ef95894ceebaf236170e8832dcf7e3上时,(1)中的结论是否成立?并说明理由;

(3)如图③,若eqId15a424b50eaeafa6f302ffd95476cb86与eqIdf52a58fbaf4fea03567e88a9f0f6e37e不垂直,且点M在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e上,点N在边eqId60ef95894ceebaf236170e8832dcf7e3的延长线上时,(1)中的结论是否成立?若不成立,写出eqIdc42f073f8b21226c476497cb37e38f3e之间的数量关系,并说明理由.

4.已知eqId15c0dbe3c080c4c4636c64803e5c1f76是等边三角形.

  @@@45ba92a4-9926-4a3e-9701-393976ba958c

(1)将eqId15c0dbe3c080c4c4636c64803e5c1f76绕点A逆时针旋转角θ(eqIde30af76bf4cc9658e721471fbddab7f1),得到eqIda25c28359f8d8da9eaf4672a6cf8ae4f,eqIdd40b319212a7e7528b053e1c7097e966和eqId1fc56c77464a17a1e97b568762a3e2c6所在直线相交于点O.

①如图a,当eqIdcde36c2a0552e7a0a679f5763d6cc588时,eqIdab2a2834d80ff574e79eae8ca8d4e94f与eqIddcb49df05f2e31d005735c3f14a21d30是否全等?___ (填“是”或“否”),eqId1b7c903121c158dafe5e7f3712897ed8___ 度;

②当eqId15c0dbe3c080c4c4636c64803e5c1f76旋转到如图b所在位置时,求eqId7307ac7510cf35f74337d368b94da4e5的度数;

(2)如图c,在eqIdf52a58fbaf4fea03567e88a9f0f6e37e和eqId60ef95894ceebaf236170e8832dcf7e3上分别截取点eqId3953cec61ac602ce5eb59b7912352179和eqIdb4c8a9c4957431681ddfc77895a88508,使eqId3a27fbd3e0086e6c309508434ff295a9,eqId2127f7289f47a5d8a278ac9514fa9f2a ,连接eqIde737bc35da650eda3825d29799b5f86f,将eqIdc021993da445858448d368df42554c8b绕点A逆时针旋转角(eqIde30af76bf4cc9658e721471fbddab7f1),得到eqIda25c28359f8d8da9eaf4672a6cf8ae4f,eqIdd40b319212a7e7528b053e1c7097e966和eqId1fc56c77464a17a1e97b568762a3e2c6所在直线相交于点O,请利用图c探索eqId7307ac7510cf35f74337d368b94da4e5的度数,直接写出结果,不必说明理由.

5.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId27557ad8d2618454755309fad45cb69e,eqId4b10134e7a46e6f6f7cb9d5e2371727d,点eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281分别在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId60ef95894ceebaf236170e8832dcf7e3上,且eqIdd8225b3e02f5a9f1fd5a09ada650cb78,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,点eqIda0ed1ec316bc54c37c4286c208f55667为eqId85c4bdfb0db1e31e8459df1d15f9ab55的中点,连接eqIdd004d2d115b477ade6af7ddb93db0df8,eqId4cae70b8a9d2d2e96dea62c00ced04b9.page number 1

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@@@1f2e3c5c-ab3c-4677-aef1-cafd52077e59

(1)观察猜想:线段eqIdd004d2d115b477ade6af7ddb93db0df8,eqId4cae70b8a9d2d2e96dea62c00ced04b9的数量关系为 ;eqIdd004d2d115b477ade6af7ddb93db0df8,eqId4cae70b8a9d2d2e96dea62c00ced04b9的位置关系为 .

(2)探究证明:把eqIda25c28359f8d8da9eaf4672a6cf8ae4f绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针旋转到如图所示位置,试判断(1)中的关系是否仍然成立.如果成立,请加以证明;如果不成立,请说明理由.

(3)拓展应用;若eqIde76faa363d8d18fce35d03cb8b32a414,eqId78c1e75eb744576c32eed3f9d20f9558,把eqIda25c28359f8d8da9eaf4672a6cf8ae4f绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针旋转的过程中,请直接写出当eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqId7f9e8449aad35c5d840a3395ea86df6d三点共线时eqId4cae70b8a9d2d2e96dea62c00ced04b9的长度.

6.在等腰eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId45acdbac251ca6b76a166c1242e71df9,eqId3570a95f68349fcd9417fcda62e78e7e,将斜边eqId60ef95894ceebaf236170e8832dcf7e3绕点A逆时针旋转一定角度得到线段eqId03902478df1a55bc99703210bccab910,eqId03902478df1a55bc99703210bccab910交eqId0dc5c9827dfd0be5a9c85962d6ccbfb1于点G,过点C作eqId0b62ce0cbffa4758c7a0e6fb7ca4d24e于点F.

@@@9c0e495e-9711-4596-83a0-a6945a0bd77c

(1)如图1,当旋转eqIdcbe53cbaa36cecf802efc9e81e9937ac时,若eqId88ee3e567700c1d5b17944ffc6229c78,求eqId60ef95894ceebaf236170e8832dcf7e3的长;

(2)如图2,当旋转eqIdf6b86c22b670a8e9f3896f9e8883fbbb时,连接eqIdd40b319212a7e7528b053e1c7097e966,eqId9d78abbad68bbbf12af10cd40ef4c353,延长eqId4cae70b8a9d2d2e96dea62c00ced04b9交eqIdd40b319212a7e7528b053e1c7097e966于点E,连接eqId31e55e398e8520d8a36fb5a625a085b8,求证:eqId6f58d038e0d499d0b567e1a27ed3b571;

(3)如图3,点M是eqId60ef95894ceebaf236170e8832dcf7e3边上一动点,在线段eqIde69d2b798744645af88a4fa411344a83上存在一点N,使eqIdda3f32876a704e1535decbaaec3a9b75的值最小时,若eqId30e6e370d8b20ed469be978c80e92f14,请直接写出eqId3a5012ed46db544acaaa1e5dd76f100f的面积.

7.在一节数学探究课中,同学们遇到这样的几何问题:如图1,等腰直角三角形eqId7bef5239ddbb0972700ce01daf9ee7cf和eqIdb9a32bd7a1b78b5a0ec562c4025aea8c共顶点A,且eqIdc5c40e45fdb98b87035089ba2d435eb4三点共线,eqId4f45ec6cfa31ceea170942fea9e648e9,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,点G为eqId85c4bdfb0db1e31e8459df1d15f9ab55的中点,连接eqIdabf80148409afb32ced0b4f59f1ba709和eqId1e72b2e1ff83e95df048745322982451,请思考eqIdabf80148409afb32ced0b4f59f1ba709与eqId1e72b2e1ff83e95df048745322982451具有怎样的数量和位置关系?page number 2

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