8.1平行四边形同步练习2025-2026学年苏科版八年级数学 下册

| 9页
| 166人阅读
| 2人下载

苏科版八年级下册数学8.1平行四边形同步练习

学校:___________姓名:___________班级:___________考号:___________

 

一、单选题

1.在平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,已知eqId4449f229f26e5f21ccb6c25f367886c1,则eqId194741f4d2ae7ee44cafca780361446a的度数是(    )

A.eqIdc3ad1b0a76a887783392268ae203ad22 B.eqId5511a89c160d515716f514c7f9041f91 C.eqId84288b493b64c3a30466fb9075621da4 D.eqId819bb4e60d3e13bf0a6bc1cc688757ee

2.如图,在eqId5138a9f70d5e8b0580e30fef6eb7baef中,点E在线段eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的延长线上,若eqId42e172a343112fa9c75d53b282482745,则eqIdce2a8bf5e05a07c93a7104839fc21849(   )

@@@4a849a56-2d3b-4f24-aeb1-bbe8a58847dd

A.eqId97f38acaaa4d4110b7ca927fdf7a8b6c B.eqId2fb94bd9eb80fb9f5f02f518bb8f2211 C.eqId6db4f0391c6406ff2da3c1f8d0ca5dfd D.eqId2f124aa6c15a72314d59122603b4af79

3.如图,在eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqId73949ad4bd387fb0e55e278df72482fc,则eqId194741f4d2ae7ee44cafca780361446a的度数为(    )

@@@b265b9e3-9c0d-4c05-a78b-f7f07f3c2fbe

A.eqIdbe6a6301878fed2a01413020b27310a5 B.eqId391479c151307826c9765a47a5f10503 C.eqId85e283d58ea8a48989988ce61df58688 D.eqIda6c0927afc571a7c966c98192040979e

4.如图,在平行四边形eqId5cb3f9a5da641be35117fd35ba07a6aa的两对角线相交于点eqId1dde8112e8eb968fd042418dd632759e,eqId9673115f12f3860e25aa7ff57660931d,eqId76d527d4795ece4a5756d1cf8dba31e1,eqId50456e6fa59a67ef02a1580abe49abdd的周长为(    )

@@@6b7d657f-dde6-4fab-91f4-fa346e8ee3b6

A.9 B.10 C.11 D.18

5.设四边形eqId5cb3f9a5da641be35117fd35ba07a6aa的对角线eqIde1a9c6a736e6eac98a676fa3232db5a5与eqIdb3182db896bc2462331796e2a6108363相交于点O,下列条件中,不能判定四边形eqId411b38a18046fea8e9fab1f9f9b80a5f是平行四边形的是(    )

A.eqId8a11029ca6b4b9e7f777af0280cf163c,eqId6dceb5cc71fc50f20649f6b9535fd914 B.eqIdc220eadc312101e2fb89dfe920f7b30d,eqIde8d2530e7023b2345c651e8f53629ff1

C.eqId9a23f35ebcd9799d82c1e41c09781a4c,eqId0866e1551b61074ca8e61261ecd1f9dc  D.eqId8a11029ca6b4b9e7f777af0280cf163c,eqIde8d2530e7023b2345c651e8f53629ff1

6.如图1,这是某校的电动伸缩门,图2是该校电动伸缩门抽象出来的几何平面示意图,已知eqId671573fba65ba4ec75e631c63048d414,eqId6dceb5cc71fc50f20649f6b9535fd914,eqId274cf35acb4a1748d15c39d15a9bea7b平分eqId79cd9d0d73549e2944578f3513631ce5交eqId03902478df1a55bc99703210bccab910于点eqId895dc3dc3a6606ff487a4c4863e18509,若eqIde8ed6ea635c2ebd0d9a371a0b9dbd538,则eqIdd5b69d40b75d582c4b8ffa2369af1d41的度数为(   )page number 0

试卷第1页,共1页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


@@@c62b5ea2-da56-4dac-9a98-62e209185dbd

A.eqId16aa0b9869db50a9ab48cc32925d8e96 B.eqId27ef3e89c37d21fd86537bee7c57b053 C.eqId17910022fc9a7ea596967fcabdab7493 D.eqIdcd043e9e5adc0719acc9f82d664a785c

7.如图,eqId5138a9f70d5e8b0580e30fef6eb7baef中,以点eqId7f9e8449aad35c5d840a3395ea86df6d为圆心,适当长为半径作弧,分别交eqIde58e08ee0b2580a62cf20f709b5e90df于点eqIdad056c25c0fdcbcc765eb5cbc6093f2b,分别以点eqId2a30f3a8b673cc28bd90c50cf1a35281和点eqIda0ed1ec316bc54c37c4286c208f55667为圆心,大于eqId52d092504d3c33c48be43f23b788efd9的长为半径作弧,两弧在eqIdd39b8d91afc34e4a9b0fdbb6bafb9087内交于点eqId1dde8112e8eb968fd042418dd632759e,作射线eqIdaaf1438142deeac876fc7dc50552e552交eqId03902478df1a55bc99703210bccab910于点eqId895dc3dc3a6606ff487a4c4863e18509,交eqId9d78abbad68bbbf12af10cd40ef4c353的延长线于点eqId73465a1f9aa03481295bf6bd3c6903ac,若eqId3d9fb806bf3862d351dc4e4ffa3a2283,则eqIdc7e4fa04825ac7d071968056322d88be的长为(    )

@@@b8c7f5df-2851-4f8a-a92d-a2b99ba7b158

A.1 B.2 C.3 D.eqIdcf298f00799cbf34b4db26f5f63af92f

8.如图,在eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqIddeb6694f3443cc5f4d09948679251b61,要在平行四边形的边所在直线上找点E,F,使四边形eqId3512c930b485925336cba23212f3660b为平行四边形,下面的两种方案中正确的方案是(   )

@@@87824c14-0f50-4f79-a95c-0000c4dad597

A.方案1 B.方案2 C.两种都正确 D.两种都不正确

9.如图,在平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,利用尺规在eqId98efae3dffa2db7004f5a937ff503171上分别截取eqId6b352224f4c340d324f746317865e4a5,使eqId9d96a5d40d0aea9f4398ca4d0fe9b0dd;分别以eqId3cf9b288c48c73463a2f214f02b6952a为圆心,大于eqId52d092504d3c33c48be43f23b788efd9的长为半径作弧,两弧在eqId3c42b59b76eafbbe36f13b2daa60132c内交于点eqId895dc3dc3a6606ff487a4c4863e18509;作射线eqId06e322e0c87479bba874db9ae9ba36b5交eqId9e52a8f07834cbbbe4224962672fbbb2于点eqId73465a1f9aa03481295bf6bd3c6903ac.若eqId71d7f12ff280c7eebd79c494e6b99818,则eqIdc7e4fa04825ac7d071968056322d88be的长为(    )page number 1

试卷第2页,共1页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


@@@33dc2652-1c7c-41e9-978e-2267bbf87c1d

A.4 B.3 C.2 D.1

10.如图,在eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqId3d2c15801fee2405573677484f5dcfa4,eqId07160f14b3b453bebb64cb2bf96dc85a,eqId32436704a722d5e568ff5c175bf3c662,点eqId2a30f3a8b673cc28bd90c50cf1a35281,eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3,eqIda0ed1ec316bc54c37c4286c208f55667,eqIdac047e91852b91af639feec23a9598b2分别在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId9d78abbad68bbbf12af10cd40ef4c353,eqId67d822262ff00915910e5b87d81ad1ba上,且eqId49b50357a6545cae8348e3059312f520,eqId411461db15ee8086332c531e086c40c7将eqId5138a9f70d5e8b0580e30fef6eb7baef分成面积相等的四部分.若eqIdadc90c2d45477e166b02359525f40aa6,则eqId411461db15ee8086332c531e086c40c7的长为(    )

@@@cce1229c-0e13-4ae9-bd98-130f2a49a087

A.eqId2bbbd1a17ed8399ecd127987bee94a3b B.eqIde760755d93e6aebc787d644e734c2e05 C.eqId16e67b25b3c7b44f4dfa42af296082e7 D.4

 

二、填空题

11.在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,已知eqId4adf90a8c2b29334cdc5aa5b554991f9,则只需添加一个条件_____,可证明四边形eqId411b38a18046fea8e9fab1f9f9b80a5f为平行四边形.

12.已知eqId5138a9f70d5e8b0580e30fef6eb7baef三个顶点的坐标分别为eqIdcd07d5b71137893619772f8e782202e0,则顶点eqId8455657dde27aabe6adb7b188e031c11的坐标是_____.

13.如图,eqId5138a9f70d5e8b0580e30fef6eb7baef的两内角eqId2947ca8e0cdbeb4aab80ce9e7b63ba98,eqId3981e7286d41960daf4e110c1c84e03a的平分线eqId68a83fdd2ba72a2dba0b6b10bb3e06b9,eqIdd004d2d115b477ade6af7ddb93db0df8分别交eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边于点eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667.若eqIdaeedb5f361a1baff6338436fff6c471d,eqId9f08273d339dc5ddbb89aa67bb8205e6,则eqId03902478df1a55bc99703210bccab910的长为________.

@@@b87d77ba-a2fe-4cd6-824f-1aaacc043e08

14.如图,eqIddcb49df05f2e31d005735c3f14a21d30是以eqId5138a9f70d5e8b0580e30fef6eb7baef的对角线eqId60ef95894ceebaf236170e8832dcf7e3为边的等边三角形,点C与点E关于x轴对称,若eqIdc5db41a1f31d6baee7c69990811edb9f点的坐标为eqIdef25df191e70dfb68fffc518cdc5c830,则eqId8455657dde27aabe6adb7b188e031c11点的坐标是______.page number 2

试卷第3页,共1页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


由于学科网是一个信息分享及获取的平台,不确保部分用户上传资料的 来源及知识产权归属。如您发现相关资料侵犯您的合法权益,请联系学科网,我们核实后将及时进行处理。