反比例函数 2025-2026学年中考数学 专题训练

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反比例函数 2025-2026学年中考数学 专题训练

学校:___________姓名:___________班级:___________考号:___________

 

一、单选题(共30分)

1.(本题2分)下列式子中,eqIdd053b14c8588eee2acbbe44fc37a6886是eqId81dea63b8ce3e51adf66cf7b9982a248的反比例函数的是(  )

A.eqId0eaeeef60273e0fbec9b47d608059f01 B.eqId344ccbf79da6ad7e3709d6fa72efb756 C.eqId895e4d902a72654623f7fef3b3933d41 D.eqIdfd3bbc0c9391ea2d605272f6f35e5d09

2.(本题2分)已知反比例函数eqId498bcfd1aac03057dcd0adef2dd113a3,下列说法正确的是(   )

A.当eqId08115d6d9f876dea921a4d32260ff1fb时,eqIdd053b14c8588eee2acbbe44fc37a6886随eqId81dea63b8ce3e51adf66cf7b9982a248的增大而增大

B.当eqId9e541ea2f855f981c96207070683d388时,eqIdd053b14c8588eee2acbbe44fc37a6886随eqId81dea63b8ce3e51adf66cf7b9982a248的增大而增大

C.该函数的图象位于第二、四象限

D.点eqId3654254401fc902c3cb4912969f21f88在该函数的图象上

3.(本题2分)对于反比例函数eqId85410ff00c81839ff9a64bf86dc36f5e,下列结论中错误的是(   )

A.该函数的图象与坐标轴无交点

B.若点eqIdba7204f43679af6935e494c59d40c6ff在该函数的图象上,则点eqId49b337b4df16c47fa1773ddd3db7a115也在该函数的图象上

C.若点eqId434ccdb0e64ad2a799ce7bcf2d6bd263在该函数的图象上,则eqId0b550ee821ee1838384835e81fc34b67

D.满足eqIde6d97c5dd615b7752e1eb6c139891f54的eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围为eqId7f5c837522a811402efb9762210c5362

4.(本题2分)反比例函数eqId07854693dd2e33f66030d6106eb6e0ee的图象经过点eqIdb4105356617d9d05b2c07bc24252c6cf,eqId7cdab55e893ab6c38203654cc194c6f5,则a的值为(   )

A.eqId274a9dc37509f01c2606fb3086a46f4f B.eqId81fb134b2b48acc99213fff6ccfee65f C.2 D.3

5.(本题2分)反比例函数eqId8f647db75e79757c4031b749613f344f的图象如图所示,eqIdd931bce6368ba976d026f1f0984ca3d0轴,若eqId15c0dbe3c080c4c4636c64803e5c1f76的面积为6,则eqIdf0a532e15e232cb4b99a8d4d07c89575的值为(  )page number 0

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@@@4f1acb87-5d51-4a02-bac3-74af89d92872

A.eqId95e35f76e01c3979ae5987f7729f9856 B.12 C.eqId01317332a203c898536b1d0459f51d23 D.6

6.(本题2分)已知点eqId5c41e921734694f53b250b16b8926249,eqIda8f25bb854783fc46bed37763bfb78f2都在反比例函数eqIdef854dfcbba9b7dedc1bc52f6332b011的图象上,若eqId9e1113e9b568fb9ca3286582368e257a,则m的取值范围是(   )

A.eqId3dc3eb2b0592ef2352237c35fdb50cd7 B.eqId58b140e221ddf537b8964fff8557cca0 C.eqIdfa204d6b5183969f6da37f369eb7293d或eqId58b140e221ddf537b8964fff8557cca0 D.eqId232961f0b0cbe58baf7522762876dfbc

7.(本题2分)已知点eqIdc2e88ebfb5c0d6cce558b515be06404d在反比例函数eqId07854693dd2e33f66030d6106eb6e0ee(k为常数且eqIdf2c80c26a794a844127aae7dee87c93b)的图象上,则下列不在该函数图象上的点是(    )

A.eqId0481d24e2af1e0cd348732b9444d1dde B.eqId76095b03d243fead89a6493614e4b68a C.eqId6d0d32ea3bbad35e0af9ecff1c62d044 D.eqId4ed3636ebd750003453533da1463036b

8.(本题2分)若点eqId58868ee4b44a89589f73878316ea15eb都在反比例函数eqIda90678a404b0c5a139c5ed8a51be1b62的图象上,则eqId05b8ec9d4206ea66a02de5c4a1e1e911的大小关系是(    )

A.eqIde1310a7a80d1f8751a3f8cafe7f8c8b4 B.eqIddcae962fec6ca82929f3ac218c3a4ce4 

C.eqId96ee96a30e2953639f0f375a4f096785 D.eqIdb4317817e09ea2b8a669f5a5217503c5

9.(本题2分)已知反比例函数eqId2734866d4a5434c9b63d7049de57b5d8中,eqIdd053b14c8588eee2acbbe44fc37a6886随eqId81dea63b8ce3e51adf66cf7b9982a248的增大而减小,则点eqId393671ec14036e8bc4b9b31a758996b8关于eqIdd053b14c8588eee2acbbe44fc37a6886轴的对称点eqIdd6f8906c9d7ce68defb89848faa531ca在(    )象限

A.第一象限 B.第二象限 C.第三象限 D.第四象限

10.(本题2分)如图,已知正六边形eqId9165d9bfbb0f0d19eb482c2a4c1b29b7的边长为eqIdd91e07104b699c4012be2d26160976a2,一边eqId9d78abbad68bbbf12af10cd40ef4c353在eqId81dea63b8ce3e51adf66cf7b9982a248轴上,点eqId7f9e8449aad35c5d840a3395ea86df6d在eqIdd053b14c8588eee2acbbe44fc37a6886轴上,反比例函数eqId70a8b6fe6b9add4a965ac32c1fc51c6b的图象经过点eqId5963abe8f421bd99a2aaa94831a951e9,则eqIdf0a532e15e232cb4b99a8d4d07c89575的值为(   )page number 1

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@@@d11c6e62-72ab-4c6d-b595-b1278dc25e3a

A.eqIdd91e07104b699c4012be2d26160976a2 B.eqIdffa37aefb6d45efe4e20ba48c2e7dfa8 C.eqIdd07ae0b4264da6a8812454ffd2f20d94 D.eqId87a828992f21655b98dd997b1a20be4c

11.(本题2分)用扳手拧螺丝时,拧动螺丝的力eqIda0ed1ec316bc54c37c4286c208f55667(单位:eqIdcad135b14c9dcd83eab6618d7694c7b0)与扳手的长度eqId0c88d9142df6ba8e43c1a93bd04a1362(单位:eqId9efa9fbcfb9595e2f031aa691db4564b)满足反比例函数关系.当扳手的长度增大时,所需用力会(   )

A.增大 B.减小 C.不变 D.无法确定

12.(本题2分)如图,线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e的两端点分别在eqId81dea63b8ce3e51adf66cf7b9982a248轴正半轴和eqIdd053b14c8588eee2acbbe44fc37a6886轴负半轴上,且eqIde2b83beedb3438153e6f728545fe3e03的面积为eqId6f8c4c029e552954bd493b49aeab82d5,若双曲线eqId7cf73d83a3e4ffc758854ceea98daf41恰好经过线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e的中点eqIdac047e91852b91af639feec23a9598b2,则eqIdf0a532e15e232cb4b99a8d4d07c89575的值为(    )

@@@a97f5eea-5672-419c-9ffc-4040a3fd276c

A.eqId6dbf80cb71406fd14621139149f7ed9e B.eqId395addb4439331615a7f220289d8b62c C.eqIda44986287ed599f86a23cfffe788cc76 D.eqIda67312d6fbde2db992b25a11f4ec102b

13.(本题2分)如图,点eqId2366fb0bebbb6d218029c51aebbaa6a5在双曲线eqId07854693dd2e33f66030d6106eb6e0ee(eqId2f0d68648b10fce54dfc19c5ee60086d且eqId08115d6d9f876dea921a4d32260ff1fb)上,作eqId0f07aeaad7ee076170141958bc50c281轴于点A,eqId05de5eef286a1b48012246c0cf88a1c7轴于点C,将四边形eqId132de9682ce9a412b7b517aa209726ed绕点A顺时针旋转eqIdf7a0387fc1258f31e44a10068c0ccfd0得到四边形eqId2b96f07f79eb40f5f3e15f6113aedacb,若双曲线eqId07854693dd2e33f66030d6106eb6e0ee经过eqId0215e13a9fb5574d5194aeb9507a98aa的中点P,则eqIda0be44077d42cfffece905b1af13e000的值为(    )page number 2

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