内容正文:
练习16整式的乘除(3)
同行学案学练测
计算高手
(难度等级:★★★★)
七年级数学下BS
基础通关
(④星a26(-2ab)°÷(-0.506)
1.计算
(1)(-a)1021÷(-a)1o20=
(2)(x2y2)2·(x3y3)3=
(3)(-a3)4÷(-a4)3=
(4)(x2y3)4+(-x)8·(y)2=
(5(号6-2ab)·2ab
67pg÷(-8pg)
(5)(3x+y-2)(3x-y+2)
(7)(3a+b2)(462-3a)=
(8)(x-y)7÷(y-x)3÷(y-x)2=
2.计算.
(1)(15x3y5-10x4y-20x3y2)÷(-5.x3y2)
(6)(3a2+a-1)(-2a2+3a+2)
(2)(-2a2b)3+8(a2)2·(-a)2.(-a)3
(7)(3x-2y)(y-3.x)-(2x-y)(3x+y)
(8)(2x+3y)2-(4x-9y)(4x+9y)+(2x-
3)(-4z2y)…gxwg÷(分w))月
3y)2
.19
(9)(6.x3y-2x2y2-2xy3)÷(-2xy)-(3x+
能力通关
2y)(y-x)
3.已知m-n=4,mn=-3.
(1)求m2+n2的值.
(10)(2x2-x+3)(-x2+4x-1)
(2)求(m2-4)(n2-4)的值.
(11)(x3m+1)(x3m-1)-(x3m-1)2
(3)求8m·32”÷4m+2m的值.
(12)(2x”+1)2(-2x”+1)2-16(x+1)2(x"-1)2
20·(④1a6)2a6《0a(⑦3-号-1
3解:1①原式=4红一,当x=一2,y=号时,原
3.獬:(1)原式=4a2-2ab,当a=2,b=1时,原式
式=-10.(2)原式=5ab-b2-3,当a=-
5’
=12,(2)原式=-x+.当x=号y=2
b=2时,原式=一9.
时,原式=2
5
4.解:原式=(x+1)(x-1)(x2+1)(x4十1)×…×
(x28+1)=(x2-1)(x2+1)(x4+1)×…×
练习14整式的乘除(1)
(x208+1)=(x4-1)(x4+1)X…X(x2048+1)=
18
2号926是
(6)-1
(x8-1)X…X(x208+1)=x4096-1.
2.(1)0.04x2-0.09(2)-2a20(3)-2a7b3c2
练习16整式的乘除(3)
(④m-20m8-12m2(6)是y-9m2
1.(1)-a(2)x13y3(3)-1(4)2x8y12
0-x+2y-日
(5写a26-a6(60》音g(⑦)6-9a2
(7)-5.x2-2x+3
(8)-(x-y)2
(8)a2-3ab-6b2(9)-3a2b-3ab2
2.(1)-3y3+2xy2+4(2)-8ab3-8a9
(10)c2+b2+d2+2bd-2bc-2cd-a2
(3)-2xz(4)-2a(5)9x2-y2+4y-4
1112-a12-5y2-2zy+2y
(6)-6a4+7a3+11a2-a-2(7)-15x2-y2
+10.xy(8)-8x2+99y2(9)-y2
3.解:(1)原式=20y-8x,当x=1,y=2时,原式=
(10)-2x4+9x3-9x2+13x-3(11)2x3m-2
2(2)原式=9x-5,当x=-号时,原式-
(12)24x2n-15
3.解:(1).m-n=4,mn=-3,∴.m2+n2=(m
-8.
n)2+2mn=42+2×(-3)=16-6=10.
练习15整式的乘除(2)
(2)(m2-4)(n2-4)=(mn)2-4(m2+n2)+16.
1.(1)-2m(2)-4x8y4(3)9a4(4)-a4
mm=-3,m2+n2=10,∴.原式=(-3)2-4×
(6)2女2-2y2(64
10+16=9-40+16=-15.(3)8m·32m÷
2.(1)4x2-12x(2)-5ab3(3)-2xy
4m+2n=(23)m·(25)n÷(22)m+2m=23m·25m÷
(4)4n'n6-
8mn0(5)-40m+15m-1
22m+4n=23m+5n÷22m+4n=23m+5n-2m-4n=
2m+"..m-n=4,mn=-3,∴.(m+n)2=(m
(6)2m+8(7)4b2(8)-2xy2+3y-1
n)2+4mn=42+4×(-3)=16-12=4,∴.m+n
(9)-12x3y+24x2y2+3xy3
(10)-8y2+4xy+2x-2
=2或-22=4或是
.28·