9.2提公因式法课后同步培优提升训练 2025—2026学年苏科版数学八年级下册

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9.2提公因式法课后同步培优提升训练苏科版2025—2026学年八年级下册

一、选择题

1.若eqIdd873405c90a3e9bc1b8f52bcd2852e43,则eqId6bd0c3c32ef25f217d1724c0593b4b26的值为(   )

A.1 B.2 C.3 D.4

2.已知eqId895e4d902a72654623f7fef3b3933d41,eqIde8e6b2da2900f092af0ae8794d99e849,则eqIdda962b9b5bc2c32b7a88b6969dccdc84的值是(   )

A.8 B.eqId8bf3d3564c61e5e9c39a9e2cf2de048b C.2 D.eqId274a9dc37509f01c2606fb3086a46f4f

3.计算eqId8a5c99297a63b90e9374ba2d1526d505的结果为(   )

A.eqId2d042dd925871bf9563405f0e36fa92f B.eqIdc648baa6b597a1e8f4f9638af464853b C.eqId25c15d9432e19fc88f6c26473ecf9ef1 D.eqIdae6efe4523fe9d31503aa4e148bf3262

4.将eqId80716210f33510f02258d60e64b520fd分解因式,正确的是(      )

A.eqId03a56c56663121268d5dada88bfdb632 B.eqIdb8079840c982a8211b03bac2438f3e73 C.eqId3d41ea61db9c423245b8bb5b4414ad7b D.eqIdfe2e6bf11a69a67b51462f9abc6beae1

5.单项式eqId4f282e3d26265cb3ef4f5ca3916d1658与eqIda60ecaba669f83bb98d735db0f7ca384的公因式是(    )

A.eqId164f1a0bf05e618427721f0fdfec7d3c B.eqIdd3f7570d73c5e03c09a7746a6db372b3 C.eqId48b67b94762209376341fc7669ecc4ef D.eqId1c5e87c4ac6995b742a44d7da8831643

6.若eqId2f64b430cd473c6a93a08510efc6f063,则eqIdb6a24198bd04c29321ae5dc5a28fe421的值为(    )

A.10 B.6 C.5 D.3

7.如图,有一张边长为b的正方形纸板,在它的四角各剪去边长为a的正方形.然后将四周突出的部分折起,制成一个无盖的长方体纸盒.用M表示其底面积与侧面积的差,则M可因式分解为(    )

@@@812d7217-0c93-4d16-b547-003c73d3a876

A.eqId701d5799dcb0cf254cdd1d5ffb5ecaca  B.eqIde9b266ccacb9e0a30de1477749648179   C.eqIdc894ea7b7a50925a0f4353143521347d D.eqIdcba7fef1d0cb633b236b9a7a4e43b617

8.将多项式eqIdd50ce97454dd2fa482966de24929576b提公因式后,另一个因式为(  )

A.eqIdec7cd469863fb7278f7a5193db259d15 B.eqId66b0c4e284c862e67d6f03489ccebaf3 C.eqId3398d3638dab12501afd492aa6e578c6 D.eqId201a886f9a6d757e87e1a5fd404eb5a3

二、填空题

9.已知a+b=4,ab=3,则a2b+ab2=_____.

10.因式分解:eqId6d6c209856e543f47a63217ebf872ea2____________.page number 0

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11.如果eqIdf53daf728deabdbf36ac2e6b6bd9a815,那么eqId481a6038fed9aca45f163c496f8f709b的值是______.

12.若eqIdf86d68cf64e6e9c86b78e5a96a7e8290,则eqIdb6a24198bd04c29321ae5dc5a28fe421的值为_____________.

三、解答题

13.把下列各式因式分解:

(1)eqIdfd7b97761d91bed957292a8d20736247;

(2)eqId0fae06f641cb7eafd711ad3cb0dc1d90;

(3)eqId5ad7c45e499ff1c48b92834c3d35aa7a;

(4)eqIdeb9e9794a072d53c6841171de6a5372f.

 

 

 

 

14.阅读下面因式分解的过程,并回答所提出的问题:

eqId2aed7036a6599a495832de60a413abc0

eqIdf661035389295e6dd51503a6ba97abca

eqId3f5d30ba4c3736ccbc35484af5de1682

eqIde3c62ce629e259a4365a3f2e7bf1a8c9

(1)上述因式分解的方法是______,共用了_____次;

(2)把多项式eqId48f6262a4ece62a60775277cc3f93e5d进行因式分解,结果是_____;

(3)依照上述方法因式分解:eqId754e02ac0e110f83f450328e0f030ce1(eqIdb6a24198bd04c29321ae5dc5a28fe421为正整数).

 

 

 

 

 

 

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15.利用因式分解进行计算:

(1)eqId87d18db95d87d44557ccddf9ab3da27b;

(2)eqId592246d3ff824b9342ae96bcdbb8c0be.

 

 

 

 

 

16.先分解因式,再求值:

(1)eqId4fcc5caa48bffe8d2c56e15cd5bd1748,其中eqId0b550ee821ee1838384835e81fc34b67,eqId03837b3769eda7f0d3804cc5ad4a6d60eqIddcb5bac75f36bb1dc5c8190d4dbe681d,.

(2)eqId9fded42ff02de7dadc5136ae17063713,其中eqId9b384412acba251d87902ab928902f16.

 

 

 

 

 

 

17.已知实数eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1满足eqId20d6fc9b90f370fbb27552876b650f8f是17的算术平方根,eqId18f0281e6bbdbe08beeccb55adf84536是eqId8bf3d3564c61e5e9c39a9e2cf2de048b的立方根.

(1)求eqIdc925be255ca736a53b24d13ddede1a86的值;

(2)求eqIdafc34eada0302668395804832dc405e1的值.

 

 

 

 

 

 

 

 

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