8.1 平行四边形 同步练习 2025-2026学年苏科版八年级数学下册

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8.1平行四边形 同步练习

一、单选题

1.如图,在平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,E是边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1延长线上一点,若eqId7cd5bbbbe6603e98b0b08bd38b2d6cca,则eqId1384d0a02d097ac7aa8a19e8da6f9767的度数为(    )

@@@9649a4d8-2e24-41a9-987f-ed64b5bcd7fe

A.eqId2fb94bd9eb80fb9f5f02f518bb8f2211 B.eqId391479c151307826c9765a47a5f10503 C.eqId85e283d58ea8a48989988ce61df58688 D.eqIdcef5188670b78eecf710cdf8d080462f

2.在平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,对角线eqId60ef95894ceebaf236170e8832dcf7e3与eqIdd40b319212a7e7528b053e1c7097e966交于点O,eqId4494a85de0be0b97a69348115aef8513,则eqIde2c3d2cba96f6f03520c0b3f6e4da03e的长为(    )

A.2 B.4 C.6 D.8

3.在eqId5138a9f70d5e8b0580e30fef6eb7baef中,若eqIdf0250df14df77229ede4ebdeb7af0be5,则eqId3818a2c9919d358b4c3713396093822b的度数为(    )

A.eqIdd36581140ebac5d28438ea63b1b23b65 B.eqId16aa0b9869db50a9ab48cc32925d8e96 C.eqId391479c151307826c9765a47a5f10503 D.eqIdc02b54dc6b3e1bb6544f47d4c8743fcf

4.如图,eqId5138a9f70d5e8b0580e30fef6eb7baef的对角线eqId60ef95894ceebaf236170e8832dcf7e3与eqIdd40b319212a7e7528b053e1c7097e966相交于点eqId98db29aae292e40b55df445a45467508,若eqId5b5cbb92530893433224f0f81abcd07e,则eqIdd40b319212a7e7528b053e1c7097e966的长是(   )

@@@f81cea7c-b560-4be5-b63d-1cfb77f621cb

A.5 B.eqId38acfaa0f912c2598cc341ec98da8a08 C.eqId71569a09b88bbb31038406b5edd2216a D.6

5.数学活动课上,已知eqId15c0dbe3c080c4c4636c64803e5c1f76,惠卓图同学利用尺规作图找一点eqId8455657dde27aabe6adb7b188e031c11,使得四边形eqId411b38a18046fea8e9fab1f9f9b80a5f为平行四边形,以下是其作图过程:(eqIdbdaa19de263700a15fcf213d64a8cd57)作eqId1cecb98f2569e9c8fc6b29b2e5fece38;(eqId61128ab996360a038e6e64d82fcba004)以点eqId5963abe8f421bd99a2aaa94831a951e9为圆心,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1长为半径作弧交eqIde2c3d2cba96f6f03520c0b3f6e4da03e与点eqId8455657dde27aabe6adb7b188e031c11;(eqId5ca7d1107389675d32b56ec097464c14)连接eqIde1ffb98f1e3c1317c0db403d3af04bdc,则四边形eqId411b38a18046fea8e9fab1f9f9b80a5f即为所求.在上述做图中,可直接判定四边形eqId411b38a18046fea8e9fab1f9f9b80a5f为平行四边形的依据是(    )

@@@8de87a30-2032-4a20-80e6-5b70b798a590

A.两组对边分别平行 B.两组对边分别相等

C.对角线互相平分 D.一组对边平行且相等

6.如图,eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqIdb9f79d7939c88e9702962e5917cad290平分eqId4189a0821a0ffab9dc171ecd279ba442,若eqIdc898f061882233b9d7315a397bbaaf14,则eqIdee2ef38925946da1145a68651da67da9(  )page number 0

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@@@e470150b-3a96-4d61-b0ce-803e8cd3294e

A.eqId85e283d58ea8a48989988ce61df58688 B.eqIdd36581140ebac5d28438ea63b1b23b65 C.eqIdbe6a6301878fed2a01413020b27310a5 D.eqId391479c151307826c9765a47a5f10503

7.数学家莫伦在eqId1141b52cd0ac47f5a764eebafc901a7a年发现了世界上第一个完美长方形(如图eqIdbdaa19de263700a15fcf213d64a8cd57),即它恰好能被分割成eqId294f43677db00ba65a7f96fc49627d70个大小不同的正方形,从这以后人们开始热衷图形完美分割的研究,平行四边形eqId611f100dcfa7803db6eb233e2e7f2dab被分割成eqId80ad9c4320d0ae02f1ccec8f5e0f9688个小正三角形(如图2),已知中间最小的两个正三角形eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIdd7ac5396c5ea442e0364b50c1db3d2da边长均为eqIdb8860d9787671b53b1ab68b3d526f5ca,平行四边形eqId611f100dcfa7803db6eb233e2e7f2dab的周长为(   )

@@@d93ee46a-c640-42d6-bd09-4abc44c0d2b0  

A.eqId69d7568b826853653903b2f26a145ec0 B.eqId1654d3f1737f2190cb3bce94d8587639 C.eqIdf91004c7a2409cbd151a9a571f0a631d D.eqIdfab3fd81afea12a399bae7261d5f5bdf

8.如图,在平行四边形eqId5cb3f9a5da641be35117fd35ba07a6aa中,对角线eqIde1a9c6a736e6eac98a676fa3232db5a5,eqIdb3182db896bc2462331796e2a6108363相交于点eqId1dde8112e8eb968fd042418dd632759e,过点eqId1dde8112e8eb968fd042418dd632759e作eqIda0fa2e0cf33a1ee02b5f109f62084cb9,交eqId764509115979e9958101808383672ec0的延长线于点eqId2a30f3a8b673cc28bd90c50cf1a35281,交eqIde1ffb98f1e3c1317c0db403d3af04bdc于点eqIda0ed1ec316bc54c37c4286c208f55667,若eqId42d9cf9c16f7268adc6baa9018062725,eqId50068845f69569915473fe86aecb94e3,eqId995c569ac2b958ec2531e0620084ffec,eqId14a13c67f6211cb9aaa665822ce24c5a,则下列结论中:①eqId89228eb0607106eca7e6d012c3cee9bb平分eqIdcd2725ce7f749e2192944fbc098b1072;②eqId6d9a68b1c9dfb79f98996ac32d572685;③eqId9c37b29d0492932e351c31398d76f38f;④eqId6c2288992a5ce06d69001877ce0e3940.正确结论的个数序号是(    )

@@@b43bab70-2120-48ee-84c6-62c39aee3e17

A.①②③ B.①②④ C.①③④ D.②③④

二、填空题

9.如图,点P为平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f内的任意一点连接eqId7eb6099cb3d24e0096b6c2f7aa432abe.设eqId2205cffebf8c4d5f81d15ed7b85c8936、eqId1c025ee3317be1099b7bf03a11e37ed4、eqId177678001b2ccde1db8f57fa5e017002、eqId55a675310c8ba418e5a59beb7317e21e的面积分别为eqId362a7268135630dc8ab6b7301d91312e,则eqId362a7268135630dc8ab6b7301d91312e之间的等量关系为                .page number 1

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@@@9ea0a6fa-b495-4c7d-ba3f-ddf2cee3580d

10.如图,在eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqId85c4bdfb0db1e31e8459df1d15f9ab55平分eqIdd39b8d91afc34e4a9b0fdbb6bafb9087交eqId03902478df1a55bc99703210bccab910于点E,交eqId9d78abbad68bbbf12af10cd40ef4c353的延长线于点F,若eqIdfb5e85d57d44685c2d72e306181e0d4f,则eqId506bbc434d386f2d8e10607b70c56c18的长为    .

@@@baaa3c5b-cbec-490a-87a0-40ef183be087

11.如图、在eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqIde075468e7fb0bf30229aec01a7205977,eqId3d2c15801fee2405573677484f5dcfa4,eqId07160f14b3b453bebb64cb2bf96dc85a,对角线eqId60ef95894ceebaf236170e8832dcf7e3,eqIdd40b319212a7e7528b053e1c7097e966交于点eqId1dde8112e8eb968fd042418dd632759e,eqId497846628a41a9bc750a645e045afb47,垂足为eqId2a30f3a8b673cc28bd90c50cf1a35281,连接eqIda299d2b999568e80be8005565ba209a4,则eqIda299d2b999568e80be8005565ba209a4的长是      .

@@@0f377bf7-52b4-450b-bb57-f485fa13aa98

12.如图,平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f的周长是eqId9822e15763be5cb6c49936df274a6748,对角线eqId2d578394cd8e4d7a705599269c512960相交于点eqId1dde8112e8eb968fd042418dd632759e,eqId299fe914d64f3a06f9b641d5591fc47a交eqId03902478df1a55bc99703210bccab910于点eqId2a30f3a8b673cc28bd90c50cf1a35281,则eqIde742966e3711cfa53dce04022acf4bcc的周长为      eqId9efa9fbcfb9595e2f031aa691db4564b.

@@@8d0744a0-a474-4ede-9c11-8770d2f5971b  

13.在平行四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId5ac2a5b9f08b1c21cabf0ec9b2cec3b2,eqId212bfbd5575772ca36d6fc3e7b246e49,将eqIdd7ac5396c5ea442e0364b50c1db3d2da沿对角线eqId60ef95894ceebaf236170e8832dcf7e3翻折至eqId80651f797ab9dccfd7163c605b091ad5,连接eqIdccaee8f228ff24e7c89879bb5b999cf2,若eqId07dd741bc3f02d8552afbcf63fba4fb6,则点eqIdc5db41a1f31d6baee7c69990811edb9f到eqId68a83fdd2ba72a2dba0b6b10bb3e06b9边的距离为    .

@@@3118d7ee-12f3-4c3b-9062-a0710610cdfd  

三、解答题

14.如图,在eqId5138a9f70d5e8b0580e30fef6eb7baef中,eqIdd40b319212a7e7528b053e1c7097e966是它的一条对角线,过A,C两点分别作eqId53c51c25b65a37b676ae3c3b71c29f9b,eqIdaac18b0388014ae20b2add2975ef56aa,E、F是垂足,求证:eqId86d1125b47dec1c5e93143ee59ad862a.page number 2

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