河南省方城县第一高级中学2025-2026学年高三迎一模数学模拟试题(四)

标签:
普通文字版答案
| 13页
| 130人阅读
| 4人下载

河南省方城县第一高级中学2025-2026学年高三迎一模数学模拟试题(四)

学校:___________姓名:___________班级:___________考号:___________

 

一、单选题

1.学校组织了“我骄傲,我是中国人”的演讲比赛.比赛规则:从eqId8b06e95b57b7a81cd81d05557a11fa92个裁判打出的分数中去掉一个最高分和一个最低分,剩余eqIdd91e07104b699c4012be2d26160976a2个分数的平均分为该选手的最终得分.已知这eqId8b06e95b57b7a81cd81d05557a11fa92个裁判给小夏同学打出的分数分别为eqId796e3e32d29652fb3ed9984c414aec35、eqIdc0538cad6b26c7238b90e664bb68c27c、eqId3d0c86435b0b5f7dabce768a0790c346、eqId2b7073684723741238b95b3b9d3b5301、eqId3d0c86435b0b5f7dabce768a0790c346、eqIde15e398a06d8ffa9071cf32c3e9e73a1、eqId6e4c1474b253f01cb4766a9e742b9dc2,则小夏同学的最终得分为(    )

A.eqIdd6d314c287aa376240f0ca41bd181f01分 B.eqId3d0c86435b0b5f7dabce768a0790c346分 C.eqId6e4c1474b253f01cb4766a9e742b9dc2分 D.eqIdc0538cad6b26c7238b90e664bb68c27c分

2.已知复数z满足eqIda91d371f5c83098ea10d089c824001b0,则eqIdb2d67321ace1e6b3be0fc0e5e8130022(   )

A.eqId8902c5c098f5f4787fcb0ca8f3e334c9 B.eqId6511a597a9367b23c0cafa716b9148ea C.eqId4b80360cbdda38f0745b998dfa872a73 D.eqIdd19ed90fa07e523db60031ab8d53e171

3.已知集合eqId6d9e80a724a8e1ecaab8bab7494faf74,eqId85481717c0e008210ff4d165b7ffafdf,则eqIdb4b9b470218359a4a47be9244980489e(    )

A.eqId43b7b75257c97af5fea4d0db68babaff B.eqId051f0c6bee647460a29070409b09db14

C.eqId81e12a49601927242c500e1e3b331112 D.eqIda7653915d4500d868bffeca544cc03b4

4.不等式eqId1acee85bd1af0603457b7744a00f1095的解集为(    )

A.eqIdb98573556bd61ba6240488177cd786bd B.eqIdad904c5a9463d27d9d15f69a82f93794或eqId1b4ddadbdc40a81d7310dd69c14f40a2

C.eqId76df9f71a5f2eb571527b90e535ad48f D.eqId197682de46d4e1ddd76437c6d56b4674或eqId1b4ddadbdc40a81d7310dd69c14f40a2

5.在△ABC中,角A,B,C的对边分别为a,b,c,若eqId73258beb2d4e2cdeb5577922404fc41b,且eqId653d9b14e37e3d60561fbd93473dab02,则角A的余弦值为(    )

A.eqId5e6486784415f3537c9a13556c05d893 B.eqId56d266a04f3dc7483eddbc26c5e487db C.eqIdd3ffd5c35bba71ea54c28622b6cf505d D.eqId4dac452fbb5ef6dd653e7fbbef639484

6.若抛物线eqIde48f28aeccf369df5980ac787e9e313f的准线为直线eqId0f85fca60a11e1af2bf50138d0e3fe62,则eqId0f85fca60a11e1af2bf50138d0e3fe62截圆eqIdf9ab11ba6b230c4309e1b899eb58daae所得的弦长为(    )

A.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 B.eqId38387ba1cadfd3dfc4dea4ca9f613cea C.1 D.2

7.已知eqId08eb71ecf8d733b6932f4680874dbbf3是等差数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和,且eqId0a735484643fd311cb1f5fb62de666fb,则eqIdae9ad4e59d7081cf19021423a984bc29(    )

A.36 B.46 C.64 D.160page number 0

试卷第1页,共1页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


8.已知eqIdeb371bd7728c6d6a16533a93924ad998为单位向量,且满足eqIdaa185cee141caef73fd24ecc84723d8a,设eqIdeb371bd7728c6d6a16533a93924ad998的夹角为eqIdc24095e409b025db711f14be783a406c,则eqId96baee807c43e1a7b7feacf142813e8b(  )

A.eqId4dac452fbb5ef6dd653e7fbbef639484 B.eqId04f55e8806a794af363e8b48d42c7e8b C.eqId24c14ff9b66f21c05e52dc3c8908c2df D.eqId7d763d0032fe54a30ea3f13a37b7b36e

 

二、多选题

9.《庄子·天下》中有:“一尺之棰,日取其半,万世不竭”,其大意为:一根一尺长的木棰每天截取一半,永远都取不完,设第一天这根木棰截取一半后剩下eqIde72adb45c60c2f63b46e65ff787302bf尺,第二天截取剩下的一半后剩下eqId3e88093a749c0d46e0ee931ecfaff925尺,…,第五天截取剩下的一半后剩下eqIdf65fc200f10b97588a0c9896277c9c64尺,则下列说法正确的是(    )

A.eqId2b3156bbf9cf6a9d4a24681e5ada0c75 B.eqId28de345880e4d0938e33a036b61880eb

C.eqIdca44c57f58b69b5189d55d6798309432 D.eqIde698d4c7e63b92729e64a5c590c44997

10.已知函数eqId392d1490e2d093f93ad84eab802b88f4,则下列说法正确的是(    )

A.若eqId859458471c86ae39e0cc42d2d960d03e,则eqId0ab31ba45a13c09b7cde61c6946fe6c7

B.eqId3ecde310a05c8e8b885c197e326729ac的图象关于原点对称

C.若eqIdea96605a82e3e1e4271e93b2b80f392a,则eqId0e2f24b4fa5308650a244d954f78f09b

D.eqId3771fb87395071eb7f1684bea1b562d9,都有eqIdbf56704d5f06246899f836b30eb4f611成立

11.已知向量eqId70c6e073d481970c1f963a5b8f2a323e,则下列结论正确的有(   )

A.若eqId460e5ba67828c57daf2edb497fb52e56,则eqId01c2cf8a7d1a0eb01c42c34e1dd08dce

B.若eqId8bf21fef3026cfe445a855c94cab5c84,则eqIda25f975b10c060e996476704394c63ec

C.若eqId64c5562bd4d1b54424330cb6329cd79d与eqIdb45ba716f03748c19b7ce2f99af536ab的夹角是eqIdac1a63ab608517bb10aa036783dfb51f,则eqIddd4b22366f95ab9de62c1d22d14fa2ff

D.若eqId64c5562bd4d1b54424330cb6329cd79d与eqIdb45ba716f03748c19b7ce2f99af536ab的方向相反,则eqIdb45ba716f03748c19b7ce2f99af536ab在eqId64c5562bd4d1b54424330cb6329cd79d上的投影向量坐标是eqIdd44dde017449fa39148f09c0676f0bf6

 

三、填空题

12.已知向量eqId6ff8bc156edb0480a32e974f3c9cae1d,则eqIdd07581a5a6afb73b4995e0fed76ac021          .

13.若函数eqIdd275fbb3ee5cd1177ca5a2ceecbbef0f在eqId2628e2dd7a988cc80530e739c22b2280上可导,eqId0737ec7778d36d0c14e2759e804e2785,则eqIdd0c26e3bc2f7e06ea5068d75d4b1ab4f          .page number 1

试卷第3页,共2页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


14.如图,在四面体eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId67d822262ff00915910e5b87d81ad1ba,eqId7d97dc3b752832906de41447bb58a341,eqId9e52a8f07834cbbbe4224962672fbbb2两两垂直,eqId8c6e31fa088253d9894b0e71e6c39fd7,以eqId8455657dde27aabe6adb7b188e031c11为球心,eqIdbdaa19de263700a15fcf213d64a8cd57为半径作球,则该球的球面与四面体eqId411b38a18046fea8e9fab1f9f9b80a5f各面交线的长度和为   .

@@@4a4d994b-d448-491d-8fc8-063143cb25a9

 

四、解答题

15.(1)已知椭圆的对称轴为坐标轴,离心率eqId16a6f11bccb89077aff12e0d1d2b88df,短轴长为eqIda46fd58e40935064129c4676ec310791,求椭圆的方程;

(2)已知椭圆的两焦点为eqId462a41b26eccbc6cf4325e735e34fad4,点eqIddad2a36927223bd70f426ba06aea4b45在椭圆上,若eqId33d776753746914c2410a3946c357f35面积的最大值为12,求此椭圆的方程.

16.如图,在直四棱柱eqId6e09725691ee7851f54c0dee86b2bf55中,底面eqId411b38a18046fea8e9fab1f9f9b80a5f为菱形.

@@@af09e6c4-b10d-4bfe-8396-c67635c08a68

(1)证明:eqId417104247ce266ae42c3a9860f387272.

(2)若eqIdcdb2dd10731b99c0f4f89ee957f8a239,eqIde46571701ccaa18d3c844ab99ee6c30e,eqIde8d927585a17c2e98ef7d5a9589a26ac,二面角eqIdc2ead078d0c9a22439c512767bf3d4c7为eqIdc24095e409b025db711f14be783a406c,求eqId67dbce6d654dd35a89cdc914c545d366.

17.已知函数eqIdf9c0b46e9b09d052d433de10dcf2857e.

(1)当eqId8e258ab9e600435b37465092243d99f6时,求曲线eqId51c530f4b7491b95acb8ce3eef9aa09d的在点eqId9b384412acba251d87902ab928902f16处的切线方程;

(2)若函数eqId4fe7d5809da02c15a43a0e9a898b9086在定义域上恰有一个零点,求a的取值范围.

18.某商场推出购物抽奖促销活动,活动规则如下:

①顾客在该商场内的消费额每满100元,可获得1张奖券;

②每张奖券可以进行1次抽奖活动,即从装有4个白球、2个红球的盒子中,随机摸取1个球(每个球被摸到的可能性相同).奖励规则:若摸出白球,则没有中奖,摸出的白球放回原盒子中,本张奖券抽奖活动结束;若摸出红球,则中奖,获得礼品1份,且摸出的红球不page number 2

试卷第4页,共2页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


由于学科网是一个信息分享及获取的平台,不确保部分用户上传资料的 来源及知识产权归属。如您发现相关资料侵犯您的合法权益,请联系学科网,我们核实后将及时进行处理。