2025-2026学年高三上学期数学期末复习自编模拟练习卷(一)(适用于江西省)

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高三数学期末复习自编模拟练习卷(一)

 

一、单选题

1.已知复数eqIdeb8811e3f17063b7a4e3794f54d0465e,则复数eqId66e9585a1da28d403536ea48b4c37a3e的虚部为(    )

A.eqIdfeab93da829a3c07a98ed41b4707967e B.eqId43f7147843dfd95d41d2dc4e158f8f88 C.eqIdd3ffd5c35bba71ea54c28622b6cf505d D.eqId9debb00d8e5555196fbc6ce38db4e838

2.已知集合eqId5b99d846b1eb8eeb2a9148367a338504,eqIdf8fc4cfcb97a8526050d45e6942852d0,eqId81e326fb6015bf96a3dd332cb3851239,则eqIdf05cc13f232fb73eaa85e6de8ff45ba3(    )

A.eqId99128d02f8c3420a5fd5091358e4cd06 B.eqId472fa47c4794990274f0c1eca7b1087f

C.eqIdf02ce2714f7fea433de077d91ae96853 D.eqIdd1a768ae955534c98caa4e28a9fb50fa

3.已知双曲线eqIda5ec7fa23be9cbe9a50607ea6bc8a4ff的一条渐近线方程为eqIdb2bdeeb6f5e38e3464c357d00839a6ce,则该双曲线的离心率为(    )

A.eqId2967337e3fcb228dded64ab0c41a17e0 B.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 C.eqIdd91e07104b699c4012be2d26160976a2 D.eqId5ca7d1107389675d32b56ec097464c14

4.函数eqId8ef7e3345f243d09ad4355defbef6fdf的图象的对称中心不可能是(    )

A.eqId22e0fb0c1fe0b09e6484d75c949674d3 B.eqIdb9b2b096238bd6eac8cd1ab2c4348fb9 C.eqId18b212e0d4339cbd3d236a807547ebf6 D.eqId6d9241d8aacd119d93c359d7286eeff0

5.已知函数eqIdbe1ce3f01e2b6364f9a9fdaf197d5e29是定义在eqId7999f80a1fa43cb687f8ef8a551f8040上的奇函数,且eqIddddd9a2b1c9ee37a5c36278209fe93fb则eqIdd8c44924ea61cc28dd4dae1b6eb2bebb(    )

A.2 B.7 C.10 D.17

6.已知eqId6569e50f43b3d8645652ecc13b62066e,eqId1bf5fa8a3b350156537f72c11cbf5485,则eqIde9afc7bfbc67ff08ae5380508d9ca746(    )

A.eqId61128ab996360a038e6e64d82fcba004 B.eqId5ca7d1107389675d32b56ec097464c14 C.eqIdb8860d9787671b53b1ab68b3d526f5ca D.eqIdd91e07104b699c4012be2d26160976a2

7.已知圆eqId4b9cc872b38a55f06ed1d30634b1b36a上到直线eqId7202181091999688e52fbb3c005ada90的距离为1的点有且仅有2个,则r的取值范围是(   )

A.eqIdab1242ec96ac54e2fd418988d5190a88 B.eqIde2ce2f5e22175e3ff8ab5e0afca58f9c C.eqIdfbf9092450a83b2dff5d0c65eb6b1e7c D.eqId870ebc2f7aabb028024894568d749934

8.已知对任意的正数eqId81dea63b8ce3e51adf66cf7b9982a248,不等式 eqIdaff81135194b51b105b6ed925ad388f6 恒成立,则正数eqId0a6936d370d6a238a608ca56f87198de的最大值为(     )

A.eqId041a7c8fc017f596542c5e6ec7d1c40b B.eqId2bf46272a49bb464438193adc2dfb083 C.eqId3a639ad33a565c8c522064ecc6e17868 D.1

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二、多选题

9.如图,在正方体eqId6e09725691ee7851f54c0dee86b2bf55中,eqId2a30f3a8b673cc28bd90c50cf1a35281为eqId394c5d2f55221975503be8aa18022480的中点,eqIda0ed1ec316bc54c37c4286c208f55667为eqIdf66fb71b75b63594ebeeeebd1963eed5的中点,下列结论中,正确结论的是(   )

@@@69ee02b9-6bd6-47bd-9af4-390a268ff32a  

A.异面直线eqId49b50357a6545cae8348e3059312f520和eqId83c09eec4e14a861af83d7828797d176所成的角为eqIdf1e5fa72f2878b476bc57f0df12d6555

B.eqId06222ee533c2484ab25321a6abbf98cb平面eqIda211ad5a06b505b8365a62c1946f3cb7

C.eqIdddc8d7854010461e187f817b81e3f351

D.直线eqId6a22d6b860f06fe23618b0d3de6768fa平面eqId34be4e71cabf458f17a6cd7f24bc70af

10.已知抛物线eqIdc5db41a1f31d6baee7c69990811edb9f:eqId7089148c36cb3c39af71de653756396a的焦点eqIda0ed1ec316bc54c37c4286c208f55667与椭圆eqId4fdd1989149897babe496145a3812e49的右焦点重合,过eqIda0ed1ec316bc54c37c4286c208f55667的直线交eqIdc5db41a1f31d6baee7c69990811edb9f于eqId5963abe8f421bd99a2aaa94831a951e9、eqId7f9e8449aad35c5d840a3395ea86df6d两点,过点eqIda0ed1ec316bc54c37c4286c208f55667且垂直于弦eqIdf52a58fbaf4fea03567e88a9f0f6e37e的直线交抛物线的准线于点eqIdac047e91852b91af639feec23a9598b2,则下列结论正确的是(    )

A.eqIdcc847b94ecaaa156770fdf3a24ca5d5e

B.eqIdc43f3f5127aca01b8bc4b8dd81476198的最小值为2

C.eqId20a5e0a51c9e14fb246b0ba0b231c1e3的面积为定值

D.若eqIdac047e91852b91af639feec23a9598b2在eqId81dea63b8ce3e51adf66cf7b9982a248轴上,则eqId20a5e0a51c9e14fb246b0ba0b231c1e3为直角三角形

11.设函数eqId09f3b9023eca688dad3279fe8c569238,则(    )

A.当eqIdf22a4a0dd7307a1323d25331e60782d8时,eqId4c019b4fdb615a30645421e3af6ab1d8 B.当eqId8e258ab9e600435b37465092243d99f6时,eqId4ce3fb3b66987dc7cbe9ce89fffb6c33

C.当eqId6b108ab31cc093f03cf48ad65429889e时,eqId97d74aaf17733bb3aea3ea79c70fcd9c D.当eqId0b550ee821ee1838384835e81fc34b67时,eqId97d74aaf17733bb3aea3ea79c70fcd9c

 

三、填空题

12.设函数eqIdd0f845d20944d994b0f4265a863d211f在R上可导,且eqId4fe7d5809da02c15a43a0e9a898b9086在图象上的点eqId150e8e4ca6aa729a72a6a17c36b8ebfe处的切线方程为eqIdfceb9eb57ca36db386ffafeda213599c,则eqId6225b169b46168aee48cdfb6dbf36575的值为          .page number 1

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13.已知等比数列eqId83cf38189d5cbf627d2b82ac0eb76006的公比eqId58f45f5bc7c648c0e8924b4fa7b1ad08,前eqId5ca7d1107389675d32b56ec097464c14项和eqIdf53336b8da6b325a9fe6662facc798d3.函数eqId8a4cef456013557a296742756f5202d8eqId1b75e002e4638ee2dd6cfb414adb050c在eqId24db7b603aebdee8e298d1fe49c848e1处取得最大值,且最大值为eqId6c1ccc6c74b8754e9bcbb3f39a11b6f1,则函数eqId4fe7d5809da02c15a43a0e9a898b9086的解析式为      .

14.有4个相同的球,分别标有数字2,0,2,5,从中有放回地随机取4次,每次取1个球,并记录每次取出的球上的数字作为结果.记eqIdf022950e0faa45b617d497b01b5292b9为结果中数字2,0,5各出现次数中的最大值,则eqIdf022950e0faa45b617d497b01b5292b9的数学期望eqIde4ee23f759c001f011b4d4cbaaaa07ff       .

 

四、解答题

15.某研究机构为了了解各年龄层对高考改革方案的关注程度,随机选取了eqId90dd550e1ad9bbf01687ffb4aab788ec名年龄在eqId76c846ba76b02bd92ab67a2ee6cdcf12内的市民进行了调查,并将所选市民的年龄情况绘制成如图所示的频率分布直方图(分第一~六组区间分别为eqId895b9f3df5efc5da06b61a94c1ecd7c7,eqIdea4a14279265fd731e467387ee649ef0,eqIdefe443f2d4acd8417bf0d75f299fe4d5,eqId8fbe6471715aea341f83bddbf7b0e68e,eqId74fec878623fb050bf545f23504201e7,eqIdb15622108dc7663661e40c46fd488125).

@@@57636faff86e49a79019b13e7bfb192f

(1)求选取的市民年龄在eqId74fec878623fb050bf545f23504201e7内的人数;

(2)研究人员从eqIdefe443f2d4acd8417bf0d75f299fe4d5,eqId8fbe6471715aea341f83bddbf7b0e68e两组中用分层抽样的方法选取了eqIdd91e07104b699c4012be2d26160976a2名市民准备召开座谈会.现在要从这eqIdd91e07104b699c4012be2d26160976a2人中选取eqId61128ab996360a038e6e64d82fcba004人在座谈会中作重点发言,求作重点发言的eqId61128ab996360a038e6e64d82fcba004人中至少有eqIdbdaa19de263700a15fcf213d64a8cd57人的年龄在eqId8fbe6471715aea341f83bddbf7b0e68e内的概率.

16.在数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqId478565573c6f43aa4427f78ae8242680,且eqId279a59ddbb4b5d44f3b1d1f6d2fc6dd7.

(1)求数列eqId83cf38189d5cbf627d2b82ac0eb76006的通项公式;

(2)在数列eqId83cf38189d5cbf627d2b82ac0eb76006中,满足eqIdbcfc6465f763b99fea857f66141526db(eqIdf0a532e15e232cb4b99a8d4d07c89575为正整数)的项有eqId233427826eb2233641fc3a9805f6d206项,求数列eqId8dcb1ddb73e4087f8cfcc40eead8b893的前eqIdf0a532e15e232cb4b99a8d4d07c89575项和eqId3a996c4e29bcc381353e072eb04c11b0.

17.如图,在三棱锥eqId63397cda22cb1fad59cf966dfb588643中,eqIdccd4fd4b7a4d6b8ca0c5827c055a9ce7底面eqId7bef5239ddbb0972700ce01daf9ee7cf,eqId45acdbac251ca6b76a166c1242e71df9,eqId0b80ee363635d73f601654339028daec,eqId0c14a66ed4bd66df65bc42c4ac1ed15c.求证:平面eqId78a3fd5284e160896f07ce367645fd04平面eqId1e582d73b96ba649378379c3074d506d;page number 2

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