天津市和平区2025-2026学年八年级上学期数学期末测评模拟试卷

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2025-2026学年天津市和平区八年级(上)期末测评模拟考试

数学卷

 

一、选择题(本题共12小题,每题3分,共36分,每小题只有唯一选项正确)

1.(本题3分)“健康和平,从我做起”,下列是轴对称图形的是(    )

A.健 B.康 C.和 D.平

2.(本题3分)画出eqId15c0dbe3c080c4c4636c64803e5c1f76边eqId60ef95894ceebaf236170e8832dcf7e3上的高,下列画法正确的是(   )

A.@@@d5eaa7dc-09e1-45a4-89f6-3d3d7ea485c0 B.@@@e871bbe4-0e8f-498c-9020-d19144de3643

C.@@@3dff571e-4958-4d79-bb0e-cbbf23819464 D.@@@7bc16bba-d2eb-4cf5-8deb-8586481d7937

3.(本题3分)如图,已知eqIdacff016e041dd609c97fbd5bffd5e637,eqId54275b7e571660d0a9e0370fbfe5050b,eqIdc8832c5450a61500ccbf73d95e16f449,则eqId03902478df1a55bc99703210bccab910的长度为(   )

@@@8f3d5769-144f-4744-a94d-2dee099ea0c4

A.2 B.3 C.4 D.5

4.(本题3分)下列计算正确的是(    )

A.eqId30381aec267e21bb724620bf88c81cb5 B.eqIdb0840aadfb66da51db37b0daef0d8787

C.eqIdae21a857df2ae92301d0d629b02414d8 D.eqId7d52e52246943fdc284d499a858eb5fb

5.(本题3分)把多项式eqIdd55edb74bd1823a67c08dc56b8797e32分解因式,应提取的公因式是(   )

A.eqId61128ab996360a038e6e64d82fcba004 B.eqId294f5ba74cdf695fc9a8a8e52f421328 C.eqIdb2f7eeb06cd905c9d8a13c1c67890417 D.eqId212b97a1d6785f21e8559809efc0ea47

6.(本题3分)下列各式:eqId624ea7222a915eeccacbd749811c5a30,eqId4958156ba035c30d0e7e6acefc8d2011,eqId9d9cf5cc7d95210b7d7ac9f8be3cbb68,eqId01edb7b864a413ef387213bd39850045,eqIdae74de35eca52b5cfaa9bbc61a05fd9d,eqId11ada054c9ee5d47253ebd2ff0fe6ca1,其中分式共有(  )

A.eqId5ca7d1107389675d32b56ec097464c14个 B.eqIdb8860d9787671b53b1ab68b3d526f5ca个 C.eqIdd91e07104b699c4012be2d26160976a2个 D.eqId6f8c4c029e552954bd493b49aeab82d5个

7.(本题3分)如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId047dc9795efa99b6fb9fdf9778085dab,eqId0fffa3d9c32da53b0ea0c338012ea20c,eqIdf52a58fbaf4fea03567e88a9f0f6e37e的垂直平分线交eqId0dc5c9827dfd0be5a9c85962d6ccbfb1于eqIda0ed1ec316bc54c37c4286c208f55667,交eqIdf52a58fbaf4fea03567e88a9f0f6e37e于eqId2a30f3a8b673cc28bd90c50cf1a35281,若eqIdfaffe3765c15f53305516895aa595a9b,则eqId4cae70b8a9d2d2e96dea62c00ced04b9的长为(    )

@@@e3ca88f0-dacc-4567-af59-44b989bd3955

A.2 B.3 C.4 D.5

8.(本题3分)马扎(图①)是中国传统手工艺制品,腿交叉,上面绷帆布或麻绳等,可以合拢,方便携带,图②为其侧面示意图.若eqIda6978615637bd3febf56d23798f65306,eqIddb4df455e06db37093c8ba02b735a233,则eqId3818a2c9919d358b4c3713396093822b的度数为(    )page number 0

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@@@9351c332-ef8c-4d1f-9804-a2d8f7d197e0

A.eqIdd36581140ebac5d28438ea63b1b23b65 B.eqId2fb94bd9eb80fb9f5f02f518bb8f2211 C.eqIdad36099d4f257b472895e2c5209ea286 D.eqId68a4c9b697e3df2b5469b71d3b5e47a2

9.(本题3分)如图,eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIda69550d878381f6e8fb436e88638f070,eqId03902478df1a55bc99703210bccab910平分eqId7cbce11aa19b8bd2bf6ee5a834e005de,eqId32c38dfd14dde969702dff97ef2270f9于eqId2a30f3a8b673cc28bd90c50cf1a35281,若eqIdf6c39e82d86d4438bdef0411217762e2,则eqId85c4bdfb0db1e31e8459df1d15f9ab55的长为(    )

@@@6bfc031e-50e8-4db8-8d6e-652830c78c0a

A.4 B.6 C.8 D.10

10.(本题3分)设eqIdb6a24198bd04c29321ae5dc5a28fe421为正整数,下面是老师在投影上展示的四位同学选择一个eqIdb6a24198bd04c29321ae5dc5a28fe421的值计算eqId4b1083a141ef4038c8eb2daf080f5d4b的结果,小林很快就发现其中一位同学的计算有误,这位同学是(    )

甲

乙

丙

丁

1319

1716

2184

2730

A.甲 B.乙 C.丙 D.丁

11.(本题3分)《九章算术》中的驿站送信问题:一份文件,若用慢马送到eqIddef7f5a19d0608e6bb2ddaaea5a0c965里的城市,所需时间比规定时间多用1天;若改为快马派送,则所需时间比规定时间少用3天,已知快马的速度是慢马速度的2倍.设规定时间是x天,则可列方程为(    )

A.eqId01454cfeb0aa9e07975bf3a1ef86e682 B.eqId36df34f0bba0e3ac9723b4235961a2bb

C.eqId8504d89f8a8f339b80550f5e80625270 D.eqId769c86fa80ffe534b29e10d715b1d6b6

12.(本题3分)一列数eqId79ae6558e11384a40f3a338b73385ee1(n是正整数,其中eqId9fd39b02127b0b5085c2dcc7205f5a21,eqIdc3f0f405ce844313744d1ccfd222c3dd均为非零数)满足规律:从第二个数起,每一数都等于与它相邻两数之积,如eqId48934bf5d951ddda3ead111d41a2a560下列说法:

①若eqIdd70bd347c9149626acd45115ba278c1e,则eqIdc8deb9d2c4167de8878cc2661dd7d80b;

②若eqId1afd6cd079e791c95dc0ff0bab68019a,则eqId87a60302649eb940748da818199e55da;

③已知eqId213ae91d7ecf67d476a4f77a6356e893,若前3个数中任意一个为1,则M化简后的常数项为675或676.

其中正确的个数是(   )

A.3 B.2 C.1 D.0

 

二、填空题(本题共有6小题,每题3分,共18分)

13.(本题3分)若分式eqIde6f49012a861122348b7bf753e3cda54有意义,则eqId81dea63b8ce3e51adf66cf7b9982a248的取值范围为      .

14.(本题3分)如图所示的椅子,将椅子脚设计成三角形,其利用了三角形的        性.

@@@373adbefff444afeb479d46094449decpage number 1

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15.(本题3分)定义eqIdea51ce05659982daeaa3c6485a7dede1为二阶行列式,规定它的运算法则为eqId397b33ca08be9e90311c6b19de0efce1,那么当eqId9b384412acba251d87902ab928902f16时,二阶行列式eqIdbbed5d6e35fafb2ae2058f8050d3a292的值为          .

16.(本题3分)如图,已知eqIddad2a36927223bd70f426ba06aea4b45是eqIdd39b8d91afc34e4a9b0fdbb6bafb9087平分线eqIdd40b319212a7e7528b053e1c7097e966上一点,eqIdac2ef99db257cc1acb08e3a5e0006d49,eqIdcf6de7703e18a31c8081be4d2d31bb01,垂足分别是eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667,如果eqIdbc085d20368963e148712f546015835e,那么eqId5aa064ccbc61410ceab28e83d9a913c6          .

@@@c9903462-1911-4afd-baed-1902cd64b4c7

17.(本题3分)分解因式:eqIde1480f5fc2fb05bb3ab863bce90a31a6        .

18.(本题3分)如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9854baaa5fe7b28e7e443d2af3c3e9f0,eqIdc5b8b98b2f83279a49e94d9f48c5e6f2,点eqId2a30f3a8b673cc28bd90c50cf1a35281在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,eqIde1d2231c7a2875ab6d423dff3ead4069,射线eqId7aa1162d5481e2441fe5bc0d49a576b0,垂足为点eqIdc5db41a1f31d6baee7c69990811edb9f,点eqIddad2a36927223bd70f426ba06aea4b45是射线eqId9d78abbad68bbbf12af10cd40ef4c353上的一动点,点eqIda0ed1ec316bc54c37c4286c208f55667在线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e上,当eqIdbc28533be6bacfff4c46cc792603247d的值最小时,则eqId9f79997547fb75e88ad1e2c66989a4a0        .

@@@f242c47c-6f88-4dfb-9215-4d141af67259

三、解答题(本题共7小题,共66分)

19.(本题8分)分解因式:

(1)eqId6424aaacc8ed426c1785ed5731618bb9;

(2)eqId0e69ef0972b2fb94c9f48a6482ccf2cc.

20.(本题8分)先化简,再求值:eqId4d881570312b380638277cdf26cf9ab7,其中eqId8e258ab9e600435b37465092243d99f6,eqIdb86304c3e26200299a0480641525a283.

21.(本题10分)解方程:

(1)eqId166f93ca53fb67aec4da409d515c4d6f;

(2)eqId7dc03eceb3e6630b8c8d49961d6f946f.

22.(本题10分)如图,在平面直角坐标系中,已知eqId131ebfee8d3fd5d0c4d3b20012e232f8、eqId552077386ae0da5e2635d1bcce594fcc.

@@@cf74b277-94f1-42f6-95dd-d2aee258b5ab

(1)作出线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e关于eqIdd053b14c8588eee2acbbe44fc37a6886轴对称的线段eqId7bb0628cecbfc98d390e5447d52414e8,并写出eqIde7c314398e26ffc7164b82946eeb4273、eqId3953cec61ac602ce5eb59b7912352179坐标;

(2)求四边形eqIdcdcfe69b939fd1c271747fe9d37ccdf9的面积.

23.(本题10分)如图,eqId15c0dbe3c080c4c4636c64803e5c1f76是等边三角形,eqId8455657dde27aabe6adb7b188e031c11是eqIdf52a58fbaf4fea03567e88a9f0f6e37e边上一点,以eqId9d78abbad68bbbf12af10cd40ef4c353为一边向上作等边eqIdd631f45bc652539853f236952afa5bbf,连接eqId68a83fdd2ba72a2dba0b6b10bb3e06b9.page number 2

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