第十四章 全等三角形 单元测试卷 2025--2026学年人教版八年级数学上册

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第十四章全等三角形单元测试卷

一、单选题(每题3分,共30分)

1.下列说法错误的是(    )

A.能够完全重合的两个图形叫全等形 B.面积相等的两个图形是全等形

C.全等形是形状、大小相同的图形 D.平移、旋转前后的图形是全等形

2.如图,用直尺和圆规作一个角等于已知角,能得出eqId7face39ae13e5ace885b20e1e1d71c4e的依据是(       )

@@@80c83979-a817-4a37-a1e3-d2aa282a77a1@@@27f6e41f-115a-4724-b5a8-48d504d0e581

A.eqIdc5a290f047f50481318d040c604d72f7 B.eqId4351a730f61bb998bab8f0b7848912d7 C.eqId9beb8b968744573e593ac28451c69729 D.eqId6720e36b02193db161c61d4017673760

3.如图,已知eqId35f22970342e5d2011554a04fe44ef96,eqId85c4bdfb0db1e31e8459df1d15f9ab55和eqId9d78abbad68bbbf12af10cd40ef4c353交于eqIda0ed1ec316bc54c37c4286c208f55667,则图中的全等三角形的对数是(   )

@@@95a2c440-6193-4373-b541-396f54378b97A.3对 B.4对 C.5对 D.6对

4.在锐角三角形eqId7bef5239ddbb0972700ce01daf9ee7cf中eqId9f08273d339dc5ddbb89aa67bb8205e6,eqId15c0dbe3c080c4c4636c64803e5c1f76的面积为30,eqIdd40b319212a7e7528b053e1c7097e966平分eqIdd39b8d91afc34e4a9b0fdbb6bafb9087交eqId60ef95894ceebaf236170e8832dcf7e3于点D,若M、N分别是eqId01633ebbf3921fe8908e159514aad7f9上的动点,则eqIdf374414357b609bc2a5fa5725ab82f11的最小值为(    )

@@@7b5a3f27-2a34-4cb5-be4a-6621c6294017A.10 B.6 C.12 D.9

5.如图所示,eqId48f9e7df9eb3f93ade03a5265d64aafb,则eqIdd5324ce5fd43c5b05e8fad764880f7b3(   )

A.eqIdc3ad1b0a76a887783392268ae203ad22 B.eqIda245ee52c2823d9554578896c4919a09 C.eqId8eb90b8c8cadeb19eaf4e2abec1ab413 D.无法计算

@@@4b311840-ee7e-4ca8-96f5-9c0876a84f756.如图,要测量河两岸相对的两点A,B之间的距离,先在eqIdf52a58fbaf4fea03567e88a9f0f6e37e的垂线eqId274cf35acb4a1748d15c39d15a9bea7b上取两点C,D,使eqId19a1bf64ba772922fe58b5322eb4bced,再作出eqId274cf35acb4a1748d15c39d15a9bea7b的垂线eqIde6e490f703eb6c9bb1278c78ebc2d661,使A,C,E三点在同一条直线上,可以说明eqIde5cb7e3776bcd9e4a16de01d3a463aff的最恰当的理由是(    )

A.边角边 B.角边角 C.边边边 D.边边角

7.下列判断正确的是(  )

A.有两角和一边对应相等的两个三角形全等

B.有一角和一条边相等的两个直角三角形全等

C.有两边对应相等,且有一角为eqIdf6b86c22b670a8e9f3896f9e8883fbbb的两个等腰三角形全等

D.有两边和其中一边的对角对应相等的两个三角形全等

@@@d31d57c1-ea56-4b60-8651-c36009d4d54b8.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId54275b7e571660d0a9e0370fbfe5050b,eqIdf1682d306c38087d9e6f7efb9cec596a,eqId03902478df1a55bc99703210bccab910是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线,延长eqId03902478df1a55bc99703210bccab910使得eqIdd2b34233772c4c26d6669499d9b1f15a,连接eqId4eedae8d316c76e3d0b451256de03fb9,则eqId03902478df1a55bc99703210bccab910长的取值范围是(   )A.eqIdf863e3893cda99d0a42b469f9b0438cd B.eqId5d995ce44e1050b4076b4dc295bf291e C.eqIdab7f502effec463bec4889245c4f09a4 D.无法确定

@@@101fcf49-cafd-4bf5-9209-3d5b1cc81cf99.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId45acdbac251ca6b76a166c1242e71df9,eqId3570a95f68349fcd9417fcda62e78e7e,eqId8455657dde27aabe6adb7b188e031c11是线段eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上一点,连接eqId03902478df1a55bc99703210bccab910,过点eqId5963abe8f421bd99a2aaa94831a951e9作eqIdb8b1472e121da0ae5550329cfda5f0a2,且eqIde30e50e094cd2849e38859b36aad0b0c,连接eqId1fc56c77464a17a1e97b568762a3e2c6交eqIdf52a58fbaf4fea03567e88a9f0f6e37e于点eqIda0ed1ec316bc54c37c4286c208f55667,若eqId8c23150a27afe4050060d5dc14dcdc5b,eqIda675e83059001956c22462a86d903f19,则eqIdf52a58fbaf4fea03567e88a9f0f6e37e的长度为(   )

A.8.3 B.8.5 C.8.7 D.9.1

@@@fa19d949-34d5-4932-8225-e4635cef393110.某镇政府为促进旅游发展,准备在三条公路围成的一块平地上修建一个度假村,如图所示.要使度假村到三条公路的距离相等,这个度假村应修建在(    )

A.eqId15c0dbe3c080c4c4636c64803e5c1f76三条高线的交点处 B.eqId15c0dbe3c080c4c4636c64803e5c1f76三边垂直平分线的交点处

C.eqId15c0dbe3c080c4c4636c64803e5c1f76三条中线的交点处 D.eqId15c0dbe3c080c4c4636c64803e5c1f76三条角平分线的交点处

二、填空题(每题3分,共18分)

11.如图,eqIdb50834e39c4e028e0fc303b94d571923,eqIdb79dd200766db27fb90d6bd1992cf658和eqId8cdd9f345915ae742ed3dcd3f9678264是对应边,eqIdabdc311a6ecc2c46403435f8047dff0d则eqId66b05714b8620eba2f56084a91442533      度.

12.如图,已知点A,D,C,F在同一条直线上,eqId0a510a3eb906b3ef0760b0d1723d11ae,eqId7da8fe8f5f8a3f17561d70652ad1172a,要使eqId1ca10806fc8c3c3efd6859f526b76900,根据eqId6720e36b02193db161c61d4017673760还需要添加一个条件是      .

13.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId2e743364593560434ef87c60337a33e0,eqIde967618e5e460a01eace529852292567,则eqIde7d19f963f7c803bcfcbb265ec6d4304的度数为      .

14.王师傅不小心将一块瓷砖摔碎了,摔成如图所示的三块,现要去瓷砖生产厂切割一块完全一样的瓷砖,只需携带         即可(填“①”“②”“③”).

15.如图,eqIdd40b319212a7e7528b053e1c7097e966是eqIddd967903ed5a6f640a5b801ec8be0070的角平分线,eqId305a88d4e0249bd16d48eda01331d2d4,eqId57ebb33adb2310a6e03918761e68204a,那么eqIdab2a2834d80ff574e79eae8ca8d4e94f与eqId73636989e83905f8800a865c2b608c43的面积之比为      .

@@@93d27311-3f69-4071-a605-656f222be7a0@@@71dd4058-1474-427e-b7d5-4fa6dd51a846@@@25ddbf4c-9129-4157-b30b-54297f415f1d16.如图,点O在eqId15c0dbe3c080c4c4636c64803e5c1f76内,且到三边的距离相等,eqId7661d8b8cc71e4261a3c32504377ac76,则eqIdd22df2977de56cc69be0c1e847653d7a的度数为          .

@@@2a723382-d2e4-4dec-920a-d713f16c39ff@@@ff670d2c-0cac-4672-a23f-3901964c66aa@@@f22c0d39-5956-4239-8221-9048d0a3a1fa

   11题            12题               13题         14题               15题          16题

三、解答题(10个小题,共72分)

17.(6分)(1)用尺规作一个角等于已知角的依据是______;

(2)尺规作图(不写作法,保留作图痕迹):如图,已知eqId6d7b2fe01a33c4825f9974ed9663a99c及eqIdae7a3e520a16d4fdd73c4e6a4ce7be0e边上的点eqIdc5db41a1f31d6baee7c69990811edb9f,过点eqIdc5db41a1f31d6baee7c69990811edb9f作射线eqIda6b41d4070854edfaa24071137b314cb,使eqId0a6344bc3dded8f8aaf2e7a359ddddea.

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18.(5分)如图:eqId15c0dbe3c080c4c4636c64803e5c1f76和eqId72cb97395ebc5ee1b212afb7a97b985c中,eqId554c9ef781166cc11d9be2268e946764;试说明eqId1ca10806fc8c3c3efd6859f526b76900.

@@@70d70913-0f65-47de-b725-ebcd7197b6d0

 

 

19.(5分)如图,已知eqIdf9b79c80cc81b5446dfac3ee97b03c03相交于点eqId1dde8112e8eb968fd042418dd632759e,且eqId718af018a120478c11db2d405d393c8c.求证:eqId0866e1551b61074ca8e61261ecd1f9dc.

@@@dc1c3362-899d-4622-beda-96e9e0191a2c

 

 

20.(8分)如图,已知eqId07ad1e4732310d4f11ec0dbf17fdb56b,eqId9ff439a446238f75c3f184e4f8dfe137,eqId7159d113d1301b49171e736384f00131,

@@@5c9be579-abc1-44e1-9e80-8748fdd15f55

(1)求证:eqId7cbc4f960f46cec54b1a5974536bae53

(2)若eqIdb0eadd973f328e0444d29e5d11e930aa,eqId991a7d4d806d9c3a2e2ddd9551e897e0,求eqId51fa3bd80b5c8f4442007a1b0a42238f的度数.

 

 

21.(5分)如图,eqId53c51c25b65a37b676ae3c3b71c29f9b,eqIdaac18b0388014ae20b2add2975ef56aa,垂足分别为eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667,eqId03687d97d61b4a7cecbb73f2a6604212,eqIdd8ce1475f537b4ad21775bfaa16daa0c,求证:eqId9d99bb3ab66b8884bf23cffe1bddcb33.

@@@70c9908c-6a56-49a7-a127-55726500d072

 

22.(6分)如图,已知eqIdb0fff774b4b0087a6f304ce930d359be,eqIde35e605f50c4f13ddf63c2466e802e4c.

@@@86074b91-d578-42cc-b387-7341e8493849

求证:

(1)eqIde153e07a91c773708d981b1d18bbacf8;

(2)eqId56d4ea87a0837c4eee99c8b5ba6ec977.

23.(5分)已知:如图,点A、F、C、D在同一直线上,点B和点E分别在直线eqId88929f4ba0851730d5f941d426b87548的两侧,且eqId02da875ca9f32c1c6a31667f44fede23,eqId74ccd4102948986b0ec3d8f0b6a30468,eqId193896446a1812185273761079009fc6.求证:eqIdb725365073c86b1163117e3fa8a92f02.

@@@c6f9acb0-4567-4201-95d1-083e8b8787c7

 

 

24.(5分)王明家所在的小区有一个池塘,如图,A,B两点分别位于该池塘的两侧,池塘西边有一座假山D,在eqIdb3182db896bc2462331796e2a6108363的中点C处有一个雕塑,王明从点A出发,沿直线eqId60ef95894ceebaf236170e8832dcf7e3一直向前经过点C走到点E,并使eqIde03ca3e334c5290ab28b4b4a883c90c8,然后他测量点E到假山D的距离,得出eqIde6e490f703eb6c9bb1278c78ebc2d661的长度就是A,B两点之间的距离.试说明王明这样做的根据.

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25.(7分)如图,已知eqId7f9e8449aad35c5d840a3395ea86df6d、eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIdc5db41a1f31d6baee7c69990811edb9f、eqIda0ed1ec316bc54c37c4286c208f55667在同一条直线上,eqId0a510a3eb906b3ef0760b0d1723d11ae,eqIdcd81adb13f5a7550b0f94f770900a613,eqIdf805768a5ffaf8bdfa4bc3b680aafdc9,eqId60ef95894ceebaf236170e8832dcf7e3与eqIde6e490f703eb6c9bb1278c78ebc2d661交于点eqId895dc3dc3a6606ff487a4c4863e18509.

@@@4a2ea334-9bf9-4ec2-8156-c81966d1cba4

(1)求证:eqId1ca10806fc8c3c3efd6859f526b76900;

(2)若eqId41bef89ac0dd5ae192cd9c7222d5041b,eqId1612dbaf3d93e619356063b3f569ae4a,求eqId16a8e30f70325b5b14851b9377107ab8的度数.

 

 

 

 

 

 

26.(8分分)如图,eqIde742966e3711cfa53dce04022acf4bcc的边eqIdf52a58fbaf4fea03567e88a9f0f6e37e和eqId13668f033d00acfc366f7e47949c4462的边eqId9d78abbad68bbbf12af10cd40ef4c353在同一条直线上,eqId15d3439583c11f5713a23311c2b3faed,eqId60b333110550208ffce4ec642f78075f

@@@db3df4ee-3063-4efd-aad1-f2794fab0cae

(1)求证:eqIde845bd4553b79d60f4a163aeb7aa1f3b;

(2)若eqId1bc6cfc2eafb07d6f690da4d5ca5a754,求证:eqId6ff56ea00ca90825f3d95809de24f639.

 

 

 

 

 

 

 

 

 

27.(12分)综合与实践

【问题重现】

义务教育教科书数学八年级上册《第十一章三角形》中我们学过了三角形中线的定义、画法、性质等.下面是一道关于三角形的中线有关问题:

如图1,eqId9d78abbad68bbbf12af10cd40ef4c353是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId5a3d296e0d7154a170cb7d3ae42989b0,eqIda4a88b719166fcc1431f876bc8c5656c,求eqId9d78abbad68bbbf12af10cd40ef4c353的取值范围.

问题解决思路:延长eqId9d78abbad68bbbf12af10cd40ef4c353到eqId2a30f3a8b673cc28bd90c50cf1a35281,使得eqIdd0fa1aa5a7a5bb172ed4603f17c8b2c6,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,可证eqId8dbf220691e9f8761295b5e8ab91c81c(相当于将eqId8a4a514e2e338c6fa31c9938624a4a71绕点eqId8455657dde27aabe6adb7b188e031c11顺时针旋转eqIdbfe639eab78eafd2d40ea70aa5d3f21d得到eqIdb96715995549e5e48494101570bb3bb8,把eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId60ef95894ceebaf236170e8832dcf7e3,eqId43079c1ad97e746d9cec11ee6918e888变换到eqIdfd0c32d9f3badb7e51233dd39a39fbb3中,利用三角形的三边关系可得eqId04f2544586d276a932812fb1c3d1441e,所以eqId59ca56dad26087d82bf8dc3e266b9691.根据上面信息,解决下面问题.

【问题变式】

如图2,点eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667分别在eqId15c0dbe3c080c4c4636c64803e5c1f76的边eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId9abaeba15f3abdd877bc701af52c5cd9上,eqId8455657dde27aabe6adb7b188e031c11是eqIdf52a58fbaf4fea03567e88a9f0f6e37e边上的中点,eqId3efffb3e6a571832b723b3c5795b8e8c,连接eqId49b50357a6545cae8348e3059312f520.

(1)求证:eqIdad4a7f99e7ebbfeeaaad687bc80f6e14;

(2)当eqId7e3262fc038bbec5e7c8cc47df08bef7时,猜想线段eqId49b50357a6545cae8348e3059312f520,eqId6aa2b5e09f8ec785c59900a529390a02,eqId85c4bdfb0db1e31e8459df1d15f9ab55之间的数量关系,并证明你的猜想;

【问题拓展】

(3)如图3,四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqIdc5b5b8f11879d32fe6b8388582dfe955,eqIda651eb577dbada1f29590e558d6f9fa2,eqIdc5b0382c28547d3834ca71f3f0677695,点eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667分别在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f的边eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId03902478df1a55bc99703210bccab910上,且eqId11872bd228050e0af8764dfa77394341,连接eqId49b50357a6545cae8348e3059312f520.探索线段eqId49b50357a6545cae8348e3059312f520,eqId2319a01218514917e446dfc807a625ff,eqIde6e490f703eb6c9bb1278c78ebc2d661之间的数量关系并证明.

        @@@fd7f8353-3f6d-4116-af9e-f27308458d67

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