5.2二元一次方程组的解法同步练习2025-2026学年北师大版八年级数学上册

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北师大版八年级上册数学5.2二元一次方程组的解法同步练习

 

一、单选题

1.用加减消元法解方程组eqIdd7db4e68f0bbc92fdeeeb958df21351b,下列解法错误的是(   )

A.eqId1c354a9337b9832c574a25e956cbff63,消去eqId81dea63b8ce3e51adf66cf7b9982a248 B.eqId8663715d70c74ad7cdbec84ed795602a,消去eqIdd053b14c8588eee2acbbe44fc37a6886

C.eqIdb2c0dc4c31d7248cb1e4d8f12cd5a060,消去eqId81dea63b8ce3e51adf66cf7b9982a248 D.eqId625e76ffcee9ce946b034e25e56d8595,消去eqIdd053b14c8588eee2acbbe44fc37a6886

2.若方程组eqId2c93cdcc8f8ade321353f8653d8ad318的解中eqId577acd6358411eb7a76bea90422519ca,则k等于(   )

A.2024 B.2025 C.2026 D.2027

3.把方程eqId19556a290cd4e98e84b584d30f466614写成用含eqId81dea63b8ce3e51adf66cf7b9982a248的式子表示eqIdd053b14c8588eee2acbbe44fc37a6886的形式,正确的是(    )

A.eqIdb2a8f934d2252fddd69a464d27c392f9 B.eqId18578107f6a1ce8052be8b932dd5068f

C.eqIdad0e65f64902f57402d44bb514d43dd0 D.eqIdcced16747e6040679b6a209f8a24cd6e

4.用代入消元法解二元一次方程组eqIdaa527906441f1188d12c160185a49a57时,下列对方程①的变形正确的是(    ).

A.eqIdca522e106992089596171be15227409b B.eqIdb98e940956e5b75434bbba0ea05159b2

C.eqId66d6e08526a91f8dfd160e7da2f92a3a D.eqId62bb6b1f74b03f2afd51ffb6800df5ba

5.若方程组eqIdcc4db1c5508683ac4985af3e7b3c77c4和eqIdd724a96e95386a00a493adc4adbb66a9同解,则a的值是(   )

A.2 B.3 C.4 D.不存在

6.小明在解关于eqId9b0fffbec1fe851795dfdd448bf0d165的二元一次方程组eqIdd1e85e4163f973bb06cba4c9dfd4b585时,不小心滴上了墨水,无法做题,老师告诉他这个方程组中eqId81dea63b8ce3e51adf66cf7b9982a248的值为3,则●和eqIdd053b14c8588eee2acbbe44fc37a6886的值分别为(    )

A.2,2 B.2,eqIdf89eef3148f2d4d09379767b4af69132 C.8,eqIdf89eef3148f2d4d09379767b4af69132 D.8,2

7.在解关于eqId9b0fffbec1fe851795dfdd448bf0d165的二元一次方程组eqIde9609fe02fb24d211a15cbe16afeafe4时,若eqId6ba994343f920318c01ee880ccb1da18可直接消去未知数eqIdd053b14c8588eee2acbbe44fc37a6886,则eqId294f5ba74cdf695fc9a8a8e52f421328和eqIdb6a24198bd04c29321ae5dc5a28fe421满足的条件是(    )page number 0

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A.eqIdb0a4480988244a9d04ec293975db2cc0 B.eqIdd73552080b72be89317eb60e9bef76c0 C.eqId087c617ff25126d2cd6428b2cd62ff47 D.eqId5f371d431b6c91972b742c426c8a81ef

8.若eqId869e22403ef71489a1476aa8aa324755,则eqId35bdc9387f534c34ddc2b23b9114959a的值为(    )

A.eqIdacbc6a613224461ade69362d46550474 B.1 C.eqId57a753e86f7c4d34f73d025446b3fc73 D.eqId92a32f87a6b136d9b5f037d52cdf546a E.2023

9.已知方程组eqId44f30285caaeff58a56dd0bbe65cb4e0的解是eqIdbdadadd408db71ac29a852a8c4a2841f,则方程组eqIdbd06a0c360a14c06700dd7e244f2909c的解是(    )

A.eqIdbdadadd408db71ac29a852a8c4a2841f B.eqIdba9c835d6bc65d3456846e19eb8b9a84

C.eqId7aa236b0fe60547f5d46270e31bb305d D.eqId9b5f4037eea47f20bfa1b7b009bdde16

10.已知a、b为常数,关于x的方程eqId9bdb78170d6301ee07f04235de579c61,无论k为何值,它的解总是1,则eqId1d8d46eada13011509b4b6da5bce1893(    )

A.26 B.eqIdfc39e77a96abe054351f5937a44dec82 C.13 D.以上都不对

 

二、填空题

11.已知eqId9b0fffbec1fe851795dfdd448bf0d165满足方程组eqId6b5d1f4543a39249944ef8efaaa88f68,则代数式eqId5113986d9507fc5015e71989831c128b                .

12.若直角三角形的两条直角边长eqId9b0fffbec1fe851795dfdd448bf0d165满足方程组eqIda067ff7ba0a57bf7ab1f38172da1480a,则这个直角三角形的周长是        .

13.在数轴上,点 A 表示的数是 a,点 B 表示的数是 b,且eqIdcb730d079f803d1367f183b07b2798fe,若eqIdf22a4a0dd7307a1323d25331e60782d8,则 b 的值为      ;若点 A 在点 B 左侧,且eqId4a7dbc702617c765a573961953cc0901,则 eqId380bbacf854e30e2e747fc286d2b9997       ,eqId5ccd4162c7d09f970cb77cadacdbe521       .

14.若eqId3a97b026a8d9122e23823c560beb53bc与eqIddca753395578b2b81c9d80d76c6eb26b的和是单项式,则eqIde59eda562882c2656d85759e99766674的值为       .

15.已知关于eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886的二元一次方程组eqId81d64e4cddb2e259ef23496d6d3b5d29,给出下列结论中正确的是        .

①当这个方程组的解eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886的值互为相反数时,eqIdf22a4a0dd7307a1323d25331e60782d8;②当eqId0b550ee821ee1838384835e81fc34b67时,方程组的解也是方程eqId40125ac27906362215d1a32be1898dba的解;③无论eqId0a6936d370d6a238a608ca56f87198de取什么实数,eqId1cf99adccc80f28343fedd8d0aad7429的值始终不变;④若用eqId81dea63b8ce3e51adf66cf7b9982a248表示eqIdd053b14c8588eee2acbbe44fc37a6886,则eqId302f4bff9fb902e2068b825a04335277page number 1

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三、解答题

16.解下列方程组:

(1)eqId49657ee21b0e49b4697bd24a981ec419;

(2)eqIdebf2a117bf9d1db95dff52a754bb9186.

17.解方程组:eqId1e4f48ba05dcc97fdae99cdfc8dab457下面是马虎的解答,你认为他的解法正确吗?若不正确,请给出正确解法.

解:方程①去分母,得eqId078dcd8c8f954376d01751d3f926868e,即eqIdf2c340791fb301e9cde397e4a05b3750.③

③+②,得eqIdc6a399c91d31a88ea469d4335c19f47f,解得eqId08ba826ef7428025a72f27a90f075576.

把eqId08ba826ef7428025a72f27a90f075576代入②,得eqIdce9d768ca7f9aa9b1f766a3db2f6090c,解得eqIdcf6c43474eae23759a141ae2315089c9.

所以原方程组的解为eqId7202c0b7f43226ec9d38687c6ef44c94

18.对于任意的有理数eqId1d5e806433a8e6e9dafcee9807519d7b,我们规定:eqIdb0c8894e0b37af5da23a1c1bffb32017,根据这一规定,解答以下问题:若eqIdd708cb763716467219215cdc0782c0a6同时满足eqIdef8df886472711f63d324a6886d65c79,求eqId0c4ac0baac097ee2e7275582ab55a48e的值.

19.已知eqIdab1ced59568a703a190f837621e887ce和eqIdd0ce8f5c1803be4481adfaa7fc25e220是关于eqId9b0fffbec1fe851795dfdd448bf0d165的二元一次方程eqId25475fcf7f797ff05cd630ba2dec5521的两组解.

(1)求eqId632244ea6931507f8656e1cc3437d392的值.

(2)在(1)的条件下,eqIdb18e5ce51c600db6c9b76b3120ab4b88的值是 ;在(1)的条件下,若eqId9b0fffbec1fe851795dfdd448bf0d165是方程eqId25475fcf7f797ff05cd630ba2dec5521的一组解,则eqId8de6bd4153848314b169e7076b75615e的值是 .

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