15.2二次根式的乘除运算 练习 2025-2026学年冀教版(2024)数学八年级上册

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15.2二次根式的乘除运算 练习

一、单选题

1.设eqId44bac390720cffdc1fe9256b4c31eeef,eqId4fd9758f36baad5918da7b63ed1cfb64,则eqId4bf4cdac2c1d3be8f5ffbace5c12b91e可以表示为(  )

A.eqIda628a8c2e52476d695716fb48008f16f B.eqId7d5beb5dc5f23935bd8b90372e9959bb C.eqIdb64ae52788355b28337cb3301111939d D.eqId0a43463f220477e14f68cd390ab43248

2.若eqId770f6a5a81a8fe2986e7566721f3086d,eqId5cd51a849da8a7393cbcbb7bf2d22ad1,则下列表示eqId593bb30c53425960d6dac8544ef7011c正确的是(   )

A.eqId09905ffb3a353e3051b16bd6b72b237e B.eqIde7e68a56455072ad3cebc436febf4101 C.eqId83bd49bf887e0d7811aaea451a3d113e D.eqIdb6683513c3f444fe1a49b6b24c0f2f93

3.化简eqId5218035ed233537d55684b2b4cad86da的结果是(   )

A.eqId3f35c4a899869e8447560e6844d84365 B.eqIdfd435ed769c511f0e1ea0624e48dc721 C.eqId3cef16c6f7badd9d7f1328472e331394 D.eqIde66f936c2b57e55944846f174ab7eec6

4.若eqIded7ed40081611d37ee1e8d44cd0c210a,则eqId895c0c7fd9c7ec3c84de9f32d0ad985c中是(   )

A.eqIdb10e8abf8690e4b129466ddb918bcc94 B.eqId8af2fdf1944afebb51cb6a5e6c74aadd C.eqId95bacae35b6e16a0a33c2bdc6bc07df7 D.eqIdadbd3e8cf8325999cde03adf845d3dd0

5.下列等式不成立的是(   )

A.eqId540b2fab7ba30cd62557868c828a7e5b B.eqId3ee4aa23d24f0f7cec73d51fab8ef034

C.eqIde460f8a350f1a0ae875209187cc20df3 D.eqId209aae1a10dc6f307a8b4cabae16f57d

6.计算eqId7224411059ba11c638ab463665f5f849的结果为(   )

A.9 B.3 C.eqId8af2fdf1944afebb51cb6a5e6c74aadd D.eqId38387ba1cadfd3dfc4dea4ca9f613cea

7.用eqId2c4f5908d6a1217e493ed7586b6964dd表示不超过eqId81dea63b8ce3e51adf66cf7b9982a248的最大整数,把eqId200a5a03679565feefe2ad465c4a9c84称为eqId81dea63b8ce3e51adf66cf7b9982a248的小数部分,已知eqId2c69fe7dc2e73af588984e67726c7aaf,eqId0a6936d370d6a238a608ca56f87198de是eqId36a1b09c653185842513e24ebba60bb3的小数部分,eqId2c94bb12cee76221e13f9ef955b0aab1是eqId97add95cc99b7846691dbdd91ef0f3bf的小数部分,则eqId80463561c77a3a261417a6d9e45f4a46的值是(    )

A.eqIdf89eef3148f2d4d09379767b4af69132 B.eqId860884c0017c8bceb5b0edff796c144f C.1 D.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 E.eqId9563540452712a60d70f76cf22a868c9

8.下列运算正确的是(    ).

A.eqId9a6ad66cae04e5031c8ef2e146c9447d B.eqId302942f4319f4e7e70ce3d9c6c3cc956

C.eqIda1deb17a6641f93a15fb0812fb3780e5 D.eqId4d653afe269f3ee5d667014a5231a7b2

9.设eqId3836255bec75cd515a214213b3f4856a的整数部分为a,小数部分为b,则eqIda8bff648d780b4b720ef3f4964d8c114的值是(   )

A.6 B.eqId60cbb271baca5cd015f30e07d9eebfd8 C.12 D.eqId3dafaeda9177baa0f937f58f680de448page number 0


10.计算eqId736d6414ef9a9005139caafd2fe75720的结果是(   )

A.4 B.2 C.3 D.eqId274a9dc37509f01c2606fb3086a46f4f

11.估计eqIdd2a8870ac0dc712ecf61a62fc68e4b6a的值在(    )

A.4到5之间 B.5到6之间 C.6到7之间 D.7到8之间

12.下列运算中正确的是(   )

A.eqIdd81dbfd0868aa1126bb5e365a5176e4f B.eqId18b9dcc3861c496599f567b645a704b7

C.eqId729283841983cf07340cffbc04f02437 D.eqId78a95173d3800e086941ff99775c8ab6

二、填空题

13.设eqId7cd83f319fc5f78f83d93751ef4edcbe,eqIdd4975d31b9925734c8f8d2ae834b6d70,则eqIdda79067b13c817cf692bb715b7c1083c的值等于                .

14.计算eqIde3289b29f31d0d5a6c37179ad55c271c的结果是      .

15.eqIda14dbbc0b1ad58621137280caa4aef16      .

16.计算:eqId864301f295a0770cc55cfe91f81fbd1a      .

三、解答题

17.计算:

(1)eqId4ed3607558e9abba01ed6dd83d5d3376;

(2)eqId9e01ee3ee4530c720422988fef0d7aaa.

18.小甲同学计算eqIda6ab9936df4854fecd984712a6cf5c8c时,想起分配律,于是他按分配律完成了下列计算:

解:原式eqIdfad612e1a60ee1410da36cdffa5630b6

eqId90cfc71cbee1ac7bf3bcba1722b8da8e

eqId30308de7a18012833cd2595cf6b63e09.

小甲同学的解法正确吗?若不正确,请给出正确的解答过程.

19.先化简,再求值:eqId0224f00082b95ccb7eb9abb667eb241d,其中eqId982e022d1d403914e5820423af742aa4.

20.小路在学习了eqIdc980645685a28320d9ad1b55b77bba3c后, 认为eqId9461495fcdc7c21428fbf1245855060f也成立,因此他认为一个化简过程: page number 1


eqId958df73570a6626cdd2756933471a802是正确的.

(1)你认为他的化简对吗? 如果不对,请写出正确的化简过程;

(2)说明eqId9461495fcdc7c21428fbf1245855060f成立的条件.

page number 2


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