福建省厦门外国语学校2024-2025学年高二上学期期末复习数学练习作业八(递推关系)

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厦门外国语学校期末复习练习作业8:递推关系

班级:                姓名:                        座号:

一、选择题

1.在数列eqId054d5a7de5684002909fe944c86227c2中,eqId77b3f6b9955e499dbdab033a38779496,eqIdc1e4d301eec54450bd5d8b768691ec82,对eqId372e6fdab89f4b96aa4eda4ce0528cfc,eqIdcca462f8b10c45d598c99829d7a6426a,则eqId39eb1fa6ddf244768efb605dc6dd050e(    )

A.eqIdf1a70d2c132a4d43a50da1cbb08f2436 B.eqId0000f6c6ad124f33b57d5474083627ff C.eqIde9819fb438d3479e89eb7f4ef97fcdac D.eqIdd2cb154a65894d87abaae67d41e43b22

2.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId8a06cfed47ac449ea045799ac7db200b,则eqId9d51ad182bd541949184738b462bbab8(    )

A.2 B.3 C.4 D.8

3.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a中,eqIdef51378d6b3048fc94aece7f1b93e1af,eqId73f752ef8d8e446ebc5d0a9f6e7bc551,则eqIdbae84e1146e947a6b86c70a640f72a29(    )

A.240 B.120 C.60 D.30

4.设数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqIdc2d3271b09324d98954c33293515c0e9,eqId2410e3e9f4bc46b79438de869018d088,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式为(    ).

A.eqIdaa4243cbecbc4ed3945f68aafcd0a2e6 B.eqId182ec321ce9241f0a436745b0dab4f54 C.eqId7c302cba96014eb29d735fb51dedcb9b D.eqId83ccd37c1ce74a91857084307f2e7248

5.意大利数学家列昂那多·斐波那契以兔子繁殖为例,引入“兔子数列”:1,1,2,3,5,8,13,21,34,55,eqId817ae81fee4d497caf4c131382708821,即eqId5e26e3b50bd54ed094cfe11895be18f6,eqId81e8d8c82c2b41ab897becfb8ffa0698(eqId9dcbbf8b034042e7bc23ec25d25fe255,eqId9286163a63004a53a7334dc742be02d2),此数列在现代物理“准晶体结构”、化学等领域都有着广泛的应用.若此数列被2整除后的余数构成一个新数列eqId93e38ecd74a24cb59da79181b95bfd3a,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的前2020项的和为(    )

A.672 B.673 C.1347 D.2020

6.已知正项数列eqId93e38ecd74a24cb59da79181b95bfd3a中,eqIdb9fb9d6c88864d84b13664c8077c40d4,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式为(    ).

A.eqIdfc9a9e13a89e4046a736231e430057e3 B.eqId245c4552fa804098945b4a058d99449a C.eqId317d7b707c8447c0b91030ab82d16239 D.eqIda9f93de80797453fa481384dc6113bc3

7.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId92478644b29a4a0e8470a8c89d31b49f项和为eqIddb5481de79c946c0a760143297d5eade,且eqIdf3aa64a34d974f0e93a6b26005e54e98,现有如下说法:

①eqId42fc4586642340278da489d4fa8d5ec9;②eqId67a39939a75747cc812549172689b877;③eqId487c5f403e2d4928bdef069c8e0e2935.则正确的个数为(    )

A.0 B.1 C.2 D.3

8.已知正项数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId50f707c14fb0414b85089344fbf2a8b7,则(    )

A.eqId6309b83b86b749b6b40acc1af57c743b     B.eqId10dd5dacac5c4d07a8930ff39323bf86   C.eqIdac5957bee30840ed9c6dabf2c0803b33 D.eqId5eaf9b9fb4884477ab830f3b3047f443

二、多选题

9.若数列{an}满足eqIdb247185f571a41fdba7ce08d6b2b0919,eqIdce0f2fa82f5c4a748beb1afdd451163a,则数列{an}中的项的值可能为(    )page number 0

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A.eqId836db6d106e440cd9e5ec0272122b7bb B.eqId0dce1f07f2a0460f80cd56ad0d9328c2 C.eqId96c7406fe9bb42d482404e87ed3f58bd D.eqId8e3ab4836a874ab593bb67a2bce00575

10.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId77b3f6b9955e499dbdab033a38779496,eqId01d07beef64e4f88aed31898009565c0,则下列结论正确的有(    )

A.eqId7ee00f20d9494a68b8920bd9eb1f0d93为等比数列                B.eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式为eqIdf37efa543ca3489cbb0b5aecfecbe210

C.eqId93e38ecd74a24cb59da79181b95bfd3a为递增数列                   D.eqId88ef23c03cc5404f9ddfcd092ce5ed85的前eqId92478644b29a4a0e8470a8c89d31b49f项和eqId02e90e820cc847daa267dc875432aaef

11.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和eqIddb5481de79c946c0a760143297d5eade满足eqId2ad819a4060c418983e22bba66695bb0,下列说法正确的是(    )

A.若首项eqId77b3f6b9955e499dbdab033a38779496,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的奇数项成等差数列 B.若首项eqId77b3f6b9955e499dbdab033a38779496,则数列eqId93e38ecd74a24cb59da79181b95bfd3a的偶数项成等差数列

C.若首项eqId77b3f6b9955e499dbdab033a38779496,则eqId8883d88039944b25a17b8d792fae14adD.若首项eqId5cfa10abef5f4b9d9b63738fbdd3bfff,对任意eqId7d4b353d04d64315b709fbb9768a1b60,eqIde7aae36840e145a89dc0a24becae07af恒成立,则eqId70a27b6ddf6b478285353abb3b1f3741的取值范围是eqIdbe4bc64925884f98ae1daea4881aa96d

12.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId8c7c4b8d2cd5414d80d1cedee8ba88a6,eqId4910a7791b5f4d44b968bdf5b380b692(eqId3fb986269c6e480d96385f935d438389),数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId92478644b29a4a0e8470a8c89d31b49f项和为eqIddb5481de79c946c0a760143297d5eade,则(    )

A.eqId77b3f6b9955e499dbdab033a38779496       B.eqId6d774dad7f5442faba427fddd3a2e829      C.eqId639bdf1f30114fb994d5d9f85fcdba59   D.eqIde01af80d217c47dfa393efe13b4ac2d4

三、填空题

13.已知eqId77b3f6b9955e499dbdab033a38779496,且eqId5ce3b3c564034e299f8462bcdc6084da,则eqIdeedae62071f342989019a2984c7c5fe9___________.

14.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqIdd3b935d690d84f2a97a3a7c5a41423ae,且eqId77b3f6b9955e499dbdab033a38779496,eqId8c7c4b8d2cd5414d80d1cedee8ba88a6,则eqId38e7aab9632e418f8d07479b236353ec______.

15.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqIdb0f74d01dc3145ff9d6b0ed147fd68ba,则eqIdb102eb7d60b943e69780e984b5d6e108的最小值为_______.

16.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqIdc2d3271b09324d98954c33293515c0e9 eqId71a9adf926c44d4d9cdc72fe7ac7c1a8,则eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式为__________________.

四、解答题

17.已知数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId0cd6fbb2bb7c46219bccaa420b876c87为其前n项和.

(1) 求eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式;(2) 求eqId833dbc386db34a4e8f4f8d5f86afcc3f.

 

 

 

 

 

 

 

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18.在①点eqIdd209b092d60342ae979e63197b1e2ee1在直线eqIdb29dd7b6bcd348a0bac1ab0365aaa703上,②eqIdef51378d6b3048fc94aece7f1b93e1af,eqIdcfd1700abe5e464d9e03f1b0d84f8719,③eqId13580c40dcaf409ebf6c3ac9862fe034这三个条件中任选一个,补充在下面问题中,并求解.

问题:已知数列eqId2c1230a9ef5a4968be599681d676dd2b的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,___________.

(1)求eqId2c1230a9ef5a4968be599681d676dd2b的通项公式;(2)求eqIddb5481de79c946c0a760143297d5eade,并判断eqId3a79912e132a48c59e95b3edaa19ba8d是否成等差数列,且说明理由.

 

 

 

 

 

 

 

 

 

 

19.已知正项数列eqId93e38ecd74a24cb59da79181b95bfd3a满足eqId77b3f6b9955e499dbdab033a38779496,eqId12b23fc7becc4fa4938d34b300af9314,等比数列eqIdeeb4ca98872f4e6d91cea28f43fc0b63满足:eqId8b84c290f4a74f50ba9e1a3c103aa275,eqId84bb75c8cc224ea397dfe83c19d81120.

(1)证明数列eqId88ef23c03cc5404f9ddfcd092ce5ed85是等差数列,并求数列eqId93e38ecd74a24cb59da79181b95bfd3a,eqIdeeb4ca98872f4e6d91cea28f43fc0b63的通项公式;

(2)设eqId7db627832c8e412d9ea90e863f928c8c,求eqId92ed363a54bd4a8a93df9463bb3af1f5.

 

 

 

 

 

 

 

 

 

 

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