3.3整式的加减(3)同步练习2025-2026学年苏科版数学七年级上册

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3.3整式的加减(3)同步练习

1.已知eqId2a37bcd996a5b644cb3b51efd699a383,若eqIdc8a5c853d53db09aa185ef80c34b6791,则整式eqIddad2a36927223bd70f426ba06aea4b45为(   )

A.eqId5fb308b8b1c16d719254e64e9b621502 B.eqId07ebc90e13177fceb829621bde3e26be C.eqId227b4d6e873a51613c36db45e031cadc D.eqIdb55ddb538dd65b167209687f093365c0

2.已知某三角形的第一条边的长为eqId824ee6d5f875bc94b5b4d544525e867b,第二条边的长比第一条边的长多eqId3dc7a801e2d2fe2dffe6e8aa3e2178ce,第三条边的长为eqIde5cd6dcbca4400121e022fb734b4e732,则这个三角形的周长用代数式表示为(   )

A.eqId3d509c2c9233055a31b16471e6d61945 B.eqId28dc11b20073a4e583405b41c40d9c9e C.eqId86fb71437601c83c4ccd0bcfb70c9163 D.eqId47808c8aa5fa4dc7e32c37138927db9a

3.已知eqIdcf4134a66e2f8bc4f0af9c45860b54d9,eqId066c1afd0b148f086d178beb0d3c22bd且x与y互为相反数,则eqId6ce69cd33d105ce280170f0cd0513026等于()

A.6 B.4 C.2 D.0

4.合并同类项eqIdecc00d333b395d62c4cceb54770d62cb的结果为(  )

A.eqIdc95b6be4554f03bf496092f1acdfbb89 B.eqIdbdaa19de263700a15fcf213d64a8cd57 C.eqIdf5a4e88f1da6d931ea32a25af1789a54 D.以上答案都不对

5.老师在黑板写了一个正确的演算过程,随后用手掌捂住了如图所示的一个二次三项式,形式如图,@@@73aadc7a-0c52-49f7-9e4b-09af15d0dd71eqId4bf597350ed8fc616d159f26d520bd57,则所指的二次三项式为(   )

A.eqId0dec799a3bb61e0b5b971ba2cbb43b34 B.eqIdffc46f0afda72111b61d5d6a102ca922 C.eqIda0b3dba7f2cde2ccec6cff21b8cdf04c D.eqId81843351cfa63bb76c9f39aa96434283

6.若eqIdd612076d1856736e6e49ebd0c8ee8eee,eqId442858e4982f95899efdffb8c1661a1e,则A与eqId772562a411cb35b12e8a5878ddaa9de1的关系是(   )

A.eqIdad93f7804b74fbad3d810136f974167f B.eqIdd501ea15e9fb0110880b0af602e7821c C.eqId5a2264c134952d41fb9bcb90e6c72c83 D.无法确定

7.已知eqId22133beb7f3f27717907afa81c2cbf56,那么代数式eqId1d0134fad5d494b2021d7be2c5f7b856的值为(   )

A.eqIdacbc6a613224461ade69362d46550474 B.eqIdc7eb3b5ab19d97f6c7df36294ccc3674 C.eqId274a9dc37509f01c2606fb3086a46f4f D.eqId3edbd40e04e2a943051fa83d6e511add

8.减去eqId1f5a8eac848f5075a0cdf46026e5bc40等于eqId1d9547e9db0979f783283b430b973822多项式是(    )

A.eqIde6b6307c9af4a7bbf2982256e548adf2 B.eqId79828431d4d53a38863a8a52acb34718 C.eqId5fa642f8470c4dfc6324d64d60bb5ce4 D.eqId39827f7f7658a4ad0c64a3612394905e

9.要使eqId9ad6b3ec841867ae378df5a681ce3d03的化简结果为单项式,则括号内的整式可以是(     )

A.eqIdc8cc0b4997cae4d8aec791a1d3923314 B.eqId14497026bf87b50a6657c0d5b8dd6f12 C.eqId432bb0bd2aba66e57f19a855f92d15c4 D.eqId87594f95cad4287b2bcf52ac922df37d

10.已知eqIde5178895b1b7670ea686100801de433f,eqId9bfb496f194a5404fd81b297ce39f46d,则eqIdc4329a509a13ab537d19ae98f509fcc3的值为(  )

A.eqIdd13ce3ebd1112220c639562739f1f9d1 B.eqIdacbc6a613224461ade69362d46550474 C.eqIdbdaa19de263700a15fcf213d64a8cd57 D.eqIdd91e07104b699c4012be2d26160976a2

11.下列各题去括号不正确的是(  )page number 0

 

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A.eqIda8374c681d982bdda300232a9ef10888

B.eqIdbead56f587a65de445a9d678761c80e0

C.eqIdb8f2a0ff112465f7641fbeee06b26f90

D.eqIdd0b74dbece3e82b541c80cd580352c81

12.下列代数式添括号正确的是(   )

A.eqId02e590be86f004957929b475165479ff B.eqId5d6a34087e4cdb65870f6c990a344b69

C.eqId19fe6fc0769948a1108008accc426bc8 D.eqId4dda73068f369e25699c8eddc6e01b6d

13.已知eqIdc0604a62cdfff465add11b9f4372dc46,eqId1344330bd0b375aa03ea9c1540ccf28d,则代数式eqId515ab61e0d9a4d531e4071490d2f0f0f的值是(  )

A.eqId4b837fd9c52f60bfb3b6852733abc790 B.eqId46be7581dbbccda50e5d5cd18056ddea C.eqId4b7f27ebcef70a3ebbbe8d2e53ea0896 D.eqIdea1834490aacbee800ed5721312f4be1

14.化简:

(1)eqIdfe534ca2a0003bc380c23c9ad1598635;               (2)eqId1450d1122de2b117646f70c5a8c82633;

 

 

(3)  eqIdc9c80d1243499debc9994bbf5e9d5272;                  (4)eqIdb57070050e158aa586947bf3e38241d9.

 

 

15.已知:eqIdfee25437077e46e1663ea7a814763ec2,eqIde8a43ddf8c10b07d5122635dcd9b4eee.若eqIde13c8573cf2fff14ab3c22a56536d8e1的值与eqId81dea63b8ce3e51adf66cf7b9982a248无关,求eqIdd053b14c8588eee2acbbe44fc37a6886的值.

 

 

 

16.(1)填写运算依据:

eqId4111156ae3b2c6f02efc11e2fad8991f

第一步:eqId7959b5559907d13169df70a57a365123            (    )

第二步:eqId1b7bb2fae7882c8a286d17db2dbef136    (    )page number 1

 

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第三步:eqId3b5c2b6f0155877be53d7bba4735317c        (    )

第四步:eqIdbbd6de79b8c8a125bdffbe9f46dc8114

(2)先化简,再求值:eqId017cf3eca3c8249365a2f4309dd0208b,其中eqId94376e3e25de7fa4e506d40446b22ffc,eqIdeb70fdf064b9193e506ca43f4672af56.

 

 

 

 

17.下面是小岩整式化简的过程,请认真阅读并回答问题.

eqId1ab96e6267822419cb8fb3ad58e00db0

eqId61209594e475364a43990959c274f53a········第一步

eqId98b110816b9bda1700c387523acddd87·········第二步

eqIdb0f73342445b6879cf26cd033523787f. ··············第三步

(1)第一步的依据是_______________________________;

(2)小岩的化简过程从第____步出现错误,出现错误的原因是______________________;

(3)请写出正确的化简过程,并计算当eqIdc13e31ee9bc0d8b6fa6a88a7e81e5699,eqId6862dd3c43647ce7d7935a7d205b54d2时该整式的值.

 

 

 

18.数学中,运用整体思想方法在求代数式的值中非常重要,例如:已知,eqIdab12b3b809f7379519776a5771a6acf0,则代数式eqId67202b95c9625a411182621dbea0495c.请你根据以上材料解答以下问题:

(1)若eqIdb79c0a3fa83f863a4edec7ce2f29c669,则eqId86c931162260920ca2464393d9a9bb42 ;

(2)若代数式eqIdab08bee8084a3c4a92d1d13e4963ee08的值为10,求代数式eqIdcef7fd3a02cdb6121f320a2602d9b951的值.

 

 

(3)当eqId2600a54b7bf3f79aaec7d49a47f6b4d2时,eqId7d087bc1d118b5d465d5a951a13a41bd的值为9,当eqId15d2b01f86fb5a373af6b089cf3d891b时,求代数式eqId67ab8b89ca3f961ca74753139deb9c36的值.

page number 2

 

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