2025年九年级中考数学复习:全等三角形综合问题

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2025年九年级中考数学复习:

全等三角形综合问题

 

 

1.如图,点C为线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e上一点,分别以eqId60ef95894ceebaf236170e8832dcf7e3,eqId0dc5c9827dfd0be5a9c85962d6ccbfb1为等腰三角形的底边,在eqIdf52a58fbaf4fea03567e88a9f0f6e37e的同侧作等腰eqId7ac451db3443cabb204f96c31fd4a02e和等腰eqIdbbfa1a2af7e38d33634c462300df381f,且eqId0210773ea3cca829b452c3201bed4528.在线段eqId1fc56c77464a17a1e97b568762a3e2c6上取一点F,使eqIdb282c521e0f3406b61964ed80f7a56bd,连接eqId274cf35acb4a1748d15c39d15a9bea7b,eqIde6e490f703eb6c9bb1278c78ebc2d661.求证:eqId86d1125b47dec1c5e93143ee59ad862a.

@@@54565c9c-e983-454a-b915-1989cf99d106

2.如图,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId6dceb5cc71fc50f20649f6b9535fd914,点eqId2a30f3a8b673cc28bd90c50cf1a35281是eqIdf52a58fbaf4fea03567e88a9f0f6e37e的中点,连接eqIde6e490f703eb6c9bb1278c78ebc2d661并延长交eqId6b1bd1adfe4cc6566218f19970c2fd3b的延长线于点eqIda0ed1ec316bc54c37c4286c208f55667,点eqId895dc3dc3a6606ff487a4c4863e18509在线段eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,且eqId5dad09565fbe5c71a89faf94852dd2c5,连接eqId31e55e398e8520d8a36fb5a625a085b8.求证:

@@@68208cad-bc33-4717-9d5a-4369a2b126f0

(1)eqId3ac85be72fc51ef4c90de7e00c5556cd;

(2)eqId31e55e398e8520d8a36fb5a625a085b8垂直平分eqIdd004d2d115b477ade6af7ddb93db0df8.

3.综合与实践:在通过构造全等三角形解决的问题中,有一种方法叫倍长中线法.

@@@3677d3f2-f840-43ab-957b-acc7c9f4ae7d

(1)如图1,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId54275b7e571660d0a9e0370fbfe5050b,eqIdc3ad4c0ba3a6750537789844d0ec419d,求eqId03902478df1a55bc99703210bccab910的取值范围;

(2)如图2,eqId48a277db452e76240ec83ec6a2864bdd,eqId49cb6392b1f859954303066037c5f5fd,eqId2667686efccb26ac834b5d620181ba2f,D为eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,求证,eqId54fed69deeef8e1cb2cdf422dcbdf78d;

(3)如图3,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,对角线eqId989c75a3fd02e4971cab421c88de92f1相交于点E,F是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,eqId4a911ba9342ec2d17b55839cb8838d9feqId868ff1350bd72625328c85c3097cd85e,eqId9f9ff6750a4dd0f8589c4e775b102094,试探究eqIdd40b319212a7e7528b053e1c7097e966与eqId49b50357a6545cae8348e3059312f520的数量关系,并说明理由.

4.已知:如图,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,点eqIdac047e91852b91af639feec23a9598b2在eqId03902478df1a55bc99703210bccab910上,点eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3在eqId03902478df1a55bc99703210bccab910的延长线上,且eqId07e395831eddeca6f5ae769b2dfa2b4d.

@@@101851aa-abd8-4c33-a50c-31f0c3df8cc2

(1)求证:eqId405ae741a1852a47b2372b6adef9c100;

(2)若eqId2bc72673b1979d49c562aac67e8fbae5,求eqId86bfa0bbe05b01453e6ed15d74da2602的度数.

5.生活中的数学:某校计划为初一学生暑期军训配备如图1所示的折叠凳.page number 0

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@@@7921e4cf-edc4-4dc7-b945-47e23b4e4cbc

(1)这种折叠凳坐着舒适、稳定,这种设计所运用的数学原理是三角形的____________性;

(2)图2是折叠凳撑开后的示意图(木条等材料宽度忽略不计),其中凳腿eqIdf52a58fbaf4fea03567e88a9f0f6e37e和eqId9d78abbad68bbbf12af10cd40ef4c353的长相等,eqId1dde8112e8eb968fd042418dd632759e是它们的中点.为了使折叠凳坐着舒适,厂家将撑开后的折叠凳宽度eqId03902478df1a55bc99703210bccab910设计为eqId3668a3f3ce5b8a272ad92c2ebd233f5a,则由以上信息可推得eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的长度也为eqId3668a3f3ce5b8a272ad92c2ebd233f5a,请说明eqIde8d2530e7023b2345c651e8f53629ff1的理由.

6.如图,已知:eqId52d66e2111f4ba89416cade42abb3ebe,eqId6dceb5cc71fc50f20649f6b9535fd914,eqIdd8ce1475f537b4ad21775bfaa16daa0c.

@@@5c3aee89-de6e-4f84-b9f8-0a66aff93dec

(1)求证:eqId2e2758611194cb0a19d367c8ebbddd70.

(2)若eqId7cb6ca11c8c7d9e7d5b926dc6399ee58,eqId4a4ea05b01791557d956302f18160130,求eqId49b50357a6545cae8348e3059312f520的长.

7.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId8455657dde27aabe6adb7b188e031c11为eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,eqIdbffd657e48b15b9b54a55817e2c26b22交eqId7cbce11aa19b8bd2bf6ee5a834e005de的平分线eqId68a83fdd2ba72a2dba0b6b10bb3e06b9于eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIdab00e0cff0876c4183a47f1272cf9928于eqIda0ed1ec316bc54c37c4286c208f55667,eqId827beb23a9fe02a8b588645bcb82ce67交eqId60ef95894ceebaf236170e8832dcf7e3延长线于eqId895dc3dc3a6606ff487a4c4863e18509.

@@@f3af095d-c797-4513-a2fe-195eceb4ca77

(1)求证:eqId8fb65161f9508867ed7847606781fa7e.

(2)猜想eqIdf52a58fbaf4fea03567e88a9f0f6e37e、eqId60ef95894ceebaf236170e8832dcf7e3、eqId6aa2b5e09f8ec785c59900a529390a02的数量有什么关系?并证明你的猜想;

(3)若eqIde1cd4a1c8087ef697d82b321a3331211,eqIddafddfd80f69337909f6eac0f0dbfd59,则eqId9f79997547fb75e88ad1e2c66989a4a0________eqId9efa9fbcfb9595e2f031aa691db4564b.

8.如图,四边形eqId5cb3f9a5da641be35117fd35ba07a6aa中,eqIdc220eadc312101e2fb89dfe920f7b30d,eqIdd8ce1475f537b4ad21775bfaa16daa0c,eqId03687d97d61b4a7cecbb73f2a6604212,

@@@ae55cac6-626a-4ba4-bfb0-a2c2b1742bdf

(1)求证:eqId9d99bb3ab66b8884bf23cffe1bddcb33;

(2)求证:eqId82636b87f9b3636cd55d0af11ad4cc39;

9.如图,点eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667在eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,eqIdabc14f568922b9c36a9af4cd20116e82.

@@@40a99c42-64ab-47a5-9c3c-5fc938b1c171

(1)求证:eqIde153e07a91c773708d981b1d18bbacf8;

(2)连接eqId68a83fdd2ba72a2dba0b6b10bb3e06b9,若eqId7b09659e3eaf2a3e4f2c1be459eb62ee,eqId2d4d00b86b2f067b902baf6e52f0faab,eqId48a277db452e76240ec83ec6a2864bdd,求eqId9fd2f170b469893461de5807ccd2cf45的度数.page number 1

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10.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId60d9142db4dd2ef151bf3d4a63afb61e,eqId3570a95f68349fcd9417fcda62e78e7e,点D是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的一点,连接eqId03902478df1a55bc99703210bccab910,将eqId03902478df1a55bc99703210bccab910绕点D顺时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到eqIde6e490f703eb6c9bb1278c78ebc2d661,作eqId58cc90fee532e50d319081d571410421交eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的延长线于点F,连接eqId4eedae8d316c76e3d0b451256de03fb9.

@@@e18686ef-75b5-46ae-b2f2-1a40dab89e0b

(1)求证:eqIdf5718f0efe0c2c7cb17331165806bd80

(2)若eqId9bdd2c73b7d7de9c4fc498068e6da329,求:eqId3869e8cb0fe2d7c477edd3e01116af41的值.

11.阅读下列学习内容:

@@@a5087e01-a1c2-4472-bf2b-edb60d18c805

(1)如图1,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2e735a28578ba191da6d4f3b0f8e8729,eqId9eee296a7d9fba487f1485c61580196f,eqIdb81939c1f23fa5fb48a3a270bbf52d60,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667分别是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上的点,且eqId4a9eb456c912e01458c19b06e83a5c9d,探究图中线段eqId85c4bdfb0db1e31e8459df1d15f9ab55,eqId49b50357a6545cae8348e3059312f520,eqId00bab17635a999236e8d2e35017a208d之间的数量关系.

探究思路如下:延长eqIdccaee8f228ff24e7c89879bb5b999cf2到点eqId895dc3dc3a6606ff487a4c4863e18509,使eqId28e9f8f8598ffafaf6168f64799c8b9b,连接eqId77a7e4a6765ce78b05ee97764771e01f.

eqIdc38743ad48b33f111650ba8cd02da335

eqId64249babb27dc83c25d100861ec22d49

eqId9de0f57e01bd843ac9977f8c1a68ea21

则由探究结果知,图中线段eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqId49b50357a6545cae8348e3059312f520、eqId00bab17635a999236e8d2e35017a208d之间的数量关系为_____.

(2)根据上面的方法,解决问题:如图2,若在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2e735a28578ba191da6d4f3b0f8e8729,eqId173904239da66b7bef7cb1d997cc40ed,eqId2a30f3a8b673cc28bd90c50cf1a35281、eqIda0ed1ec316bc54c37c4286c208f55667分别是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上的点,且eqId2a6aef04eceb608a7a2cfc3e566f9e8b,上述结论是否仍然成立,并说明理由;

(3)如图3,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqIdda37579f60ddb7078d91091b64194fa7,eqId5f0c1a666b83161c1dde0e8deb7466e1,点eqIdac047e91852b91af639feec23a9598b2、eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3分别在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1、eqId9d78abbad68bbbf12af10cd40ef4c353上,且eqIdb4794cf7c57bdd4825d9e6615e2527a4,若eqIdfb909eaf6572dc2a0cac7557cb91d2cd,eqId1c2e14551ec5c30da3ccc60eeeb3049a,请求直接写出eqId411461db15ee8086332c531e086c40c7的长度.

12.如图1,在等边eqId15c0dbe3c080c4c4636c64803e5c1f76中,点eqId8455657dde27aabe6adb7b188e031c11,eqId2a30f3a8b673cc28bd90c50cf1a35281分别是eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId60ef95894ceebaf236170e8832dcf7e3上的点,eqId3eac6f98ed81727dc5f6699ea5117fff,eqId85c4bdfb0db1e31e8459df1d15f9ab55与eqId9d78abbad68bbbf12af10cd40ef4c353交于点eqId1dde8112e8eb968fd042418dd632759e.

@@@b604fb5a-90a0-48c6-bfd1-99e93b4b5c17    

(1)求证:eqIdf5e15185ad47818310266ab6b85e117f;

(2)如图2,以eqIdbdc93e193fad261689949a52819753f0为边作等边eqId20bb77c849e0ce2a7d06ff0ca900fb28,eqId6aa2b5e09f8ec785c59900a529390a02与eqIdaaf1438142deeac876fc7dc50552e552相等吗?并说明理由;

(3)如图3,若点eqId895dc3dc3a6606ff487a4c4863e18509是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,连接eqIde2c3d2cba96f6f03520c0b3f6e4da03e,eqId59faf75f0c95312e556ae905b3ff5b87,判断eqIde2c3d2cba96f6f03520c0b3f6e4da03e与eqId59faf75f0c95312e556ae905b3ff5b87有什么数量关系?并说明理由.page number 2

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