数列综合专项训练-2025届高三数学二轮专题复习

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数列综合专项训练-2025届高考数学二轮复习

一、单选题

1.已知eqId08eb71ecf8d733b6932f4680874dbbf3为等比数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和,且eqIdb065334d8f60c49f4bd3d9f1373fe4cd,则“eqIda9875b5a21e007035dbf079af4617d3b”是“eqId2f5b78d8869e45eb2baf7422155a0992”的(    )条件.

A.充分不必要. B.必要不充分. C.充分必要. D.既不充分也不必要.

2.已知等差数列eqId83cf38189d5cbf627d2b82ac0eb76006的公差eqId30a50b23570153151e6a375bcf8fbdab,则eqId06654677d4f06f1e588a3a5189fd95e8的最小值为(    )

A.1 B.eqIdcf298f00799cbf34b4db26f5f63af92f C.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 D.2

3.在复平面内,eqId04741b92c01e21293d2fb40df5b52844对应的点位于(    )

A.第一象限 B.第二象限 C.第三象限 D.第四象限

4.数列eqId57ef6d44448092ebdb9e4a49d866a749满足eqId9de3833f5a970216ac2d7ef7a62cdbf3,若数列eqId57ef6d44448092ebdb9e4a49d866a749单调递增,则实数eqId0a6936d370d6a238a608ca56f87198de的取值范围为(   )

A.eqId9006ed5e53e4637fbacec7832dfe2146 B.eqIdc2e88ebfb5c0d6cce558b515be06404d C.eqId5265d99095b635f62c7915298ec0e963 D.eqId3654254401fc902c3cb4912969f21f88

5.已知数列eqId359b048cd64e08ea535f840c39d718b5满足eqId0991aa44e1f79015ce512320af82bf37,某同学将其前20项中某一项正负号写错,得其前20项和为372,则写错之前这个数为(   )

A.eqIdebbfdbcb4d514daa81d6d039bbb29044 B.eqId734161e5ba37cffb31803828c2ad3d28 C.100 D.eqIde223c6bc28ad8eeac351eb8f2e25f877

6.设无穷数列eqId76aef4cdcb5af742ce28003b7b6c8c20满足eqId94e67fe320357a5de9f10b14983a7c13,则()

A.存在eqId9bd0a75175e14e506f7463f8e513450e,eqId76aef4cdcb5af742ce28003b7b6c8c20为等差数列 B.存在eqId9bd0a75175e14e506f7463f8e513450e,eqId76aef4cdcb5af742ce28003b7b6c8c20为等比数列

C.存在eqId9bd0a75175e14e506f7463f8e513450e,eqId76aef4cdcb5af742ce28003b7b6c8c20为递减数列 D.存在eqId9bd0a75175e14e506f7463f8e513450e,eqId76aef4cdcb5af742ce28003b7b6c8c20为递增数列

7.设函数eqId09f86f37ec8e15846bd731ab4fcdbacd满足:eqIdf70e0db0174a2c05b28fb6d0c2508778,都有eqIda1c38a21483a2dc328d2e0b1d1b62599,且eqId3587ff064f9af01371279ab75d22116c.记eqId695950fe16f7972182bd2d0864e12feb,则数列eqIdaf869fd5762c9fa9a40dfc2371bf4240的前10项和为(    )

A.55 B.45 C.eqIde9d7ff5092d0e78bb8fe27851083e67e D.eqIde708e3af53e52b956326036304c90f27

8.等比数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqId5bef7b438f39fe0c377a55bdd8a8c6f6,记eqId2fe94a4da73270a6cd90b94b2ffdddfa,则数列eqIdde777c4e44546bcfe26ad5b6bb418052(  )

A.无最大项,无最小项 B.有最大项,有最小项

C.无最大项,有最小项 D.有最大项,无最小项

 

二、多选题

9.数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,已知eqId812e60d54da9fba25d00bc0e2cc520a2,则下列结论正确的是(    )

A.eqId83cf38189d5cbf627d2b82ac0eb76006为等差数列 B.eqId83cf38189d5cbf627d2b82ac0eb76006可能为常数列page number 0

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C.若eqId83cf38189d5cbf627d2b82ac0eb76006为递增数列,则eqId2f0d68648b10fce54dfc19c5ee60086d D.若eqId846fa57d92d6ad44d6a0cafad1e71ed4为递增数列,则eqIdfc329b32ecf0f0532d09a8a21343e8cb

10.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和eqId986d4064de58f1d10cca945fea07fbc3,则下列说法正确的是(   )

A.eqId214dee809f57005561c9768885d2cffa B.eqId08eb71ecf8d733b6932f4680874dbbf3取最小值时eqIde45cf86650443d1b86c79b1e3edc7e5c

C.数列eqIdd1705cd1b7eb5de318f6f140bbefaa16是等差数列 D.eqIdcc797990ed5e3bb683d5086f62b41668

11.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006满足eqIdb065334d8f60c49f4bd3d9f1373fe4cd,eqId9652f65b28e2032c0cbc2a9649db4f51,且eqIdb60899b44b22e227cc912a751032b76e,若记数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项的积为eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c,eqId5e90fb7da7229162b501f7dcdbf6b3ec,eqId034ba25825c13725931c483aa47c9363的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,则下列结论正确的是(   )

A.数列eqId034ba25825c13725931c483aa47c9363是等比数列        eqId03bfe30380decb4ba3f9a6b0598ed922 B.eqId5b75dbb20178da2eec9ff11a9c74e841

C.当eqIdb6a24198bd04c29321ae5dc5a28fe421为奇数时,eqIdee2111f68ffdb8d03d62a3b4e60be485 D.当eqIdb6a24198bd04c29321ae5dc5a28fe421为偶数时,eqId2830887a32a349e6d370f548b950f2ae

 

三、填空题

12.从分别标有数字2024,2025,2026的三张卡片中随机抽取一张,记下数字后放回,再随机抽取一张,记下数字后放回,以此类推,抽取eqIdb6a24198bd04c29321ae5dc5a28fe421次后,记下的eqIdb6a24198bd04c29321ae5dc5a28fe421个数字之和为奇数的概率为      .

13.已知函数eqId7dc1d4dfe9b98c934cb60526c8e36074的导数为eqId6a4b04824a308519a61318a82aa97a05,函数eqId4fe7d5809da02c15a43a0e9a898b9086的“牛顿数列”eqIde976c0663fa749ca749f99842d21ca03满足eqIdf5fe55a14cbd928ab78d3856ec88f71b,若eqId87a60302649eb940748da818199e55da,则eqId9e7ad31dd3397f7d2830182a8d309289          .

14.在数列eqId83cf38189d5cbf627d2b82ac0eb76006中,已知eqIdf7bab423942f5e4d37c150ccfaf9f055,则eqId83cf38189d5cbf627d2b82ac0eb76006的前10项和为         .

15.数列eqId76aef4cdcb5af742ce28003b7b6c8c20的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,若eqId039e4fe671d61e59b96ee525c9df43e8,当eqId96abfe2da27a63e6affb19a0c80236d9为偶数时,eqIddcd4ac585f99d00780dbf53b60ccc5b0,当eqId96abfe2da27a63e6affb19a0c80236d9为奇数时,eqId41b60dd4692d64793b2880a5ad18ad48,则eqId554e6c461ccc5aa3093c524aa528a4e2          .

16.已知eqId76aef4cdcb5af742ce28003b7b6c8c20为等差数列,eqId08eb71ecf8d733b6932f4680874dbbf3为其前n项和.若eqId4de3b8a8deded91083026e63687fa4fd,则公差eqId7c98c59cd4749afdd21e73529fc84323      ,数列eqId3ae17135935407a64d92c9f8871eba78的前5项和为            .

 

四、解答题

17.已知等比数列eqId83cf38189d5cbf627d2b82ac0eb76006的首项eqId9a086dd951924fd2a094fc1d4da4341d,公比eqIdbc66617bfdbad40a2b74f23b7addefb2,在eqId83cf38189d5cbf627d2b82ac0eb76006中每相邻两项之间都插入6个数,使它们和原数列的数一起构成一个新的等比数列eqId034ba25825c13725931c483aa47c9363.

(1)求数列eqId034ba25825c13725931c483aa47c9363的通项公式.page number 1

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(2)记数列eqId034ba25825c13725931c483aa47c9363前eqIdb6a24198bd04c29321ae5dc5a28fe421项的乘积为eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c,试问:eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c是否有最大值?如果有,请求出此时eqIdb6a24198bd04c29321ae5dc5a28fe421的值以及eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c的最大值;若没有,请说明理由.

 

 

 

18.设eqId08eb71ecf8d733b6932f4680874dbbf3为数列eqId83cf38189d5cbf627d2b82ac0eb76006的前n项和,eqId0704f453b2de48d36911f7db496bbf82时,eqId7c6170394bb75941b7408429407c83e3,已知eqId832f85c54573606edb20710a8e8ccbd7.

(1)证明:数列eqId40dc43b8d11d5462e4b525dd7b03bcfc为等比数列;

(2)求数列eqId83cf38189d5cbf627d2b82ac0eb76006的通项公式;

(3)若不等式eqIda44670836f4734977a9287175998ae55对任意正整数n都成立,求实数eqIddf64046e91b047037f19e4032e3b6de3的最小值.

 

 

 

19.已知等差数列eqId76aef4cdcb5af742ce28003b7b6c8c20满足:eqId039e4fe671d61e59b96ee525c9df43e8,且eqId2a18556fda4a825861f1170cdeb059ff成等比数列,数列eqId76aef4cdcb5af742ce28003b7b6c8c20的前n项和为eqId08eb71ecf8d733b6932f4680874dbbf3.

(1)求数列eqId76aef4cdcb5af742ce28003b7b6c8c20的通项公式,前n项和eqId08eb71ecf8d733b6932f4680874dbbf3;

(2)是否存在正整数n,使得eqId629ebe5a62685ba4efbc30e7e0cae4d6?若存在,求n的最小值;若不存在,说明理由.

 

 

 

 

 

20.对于数列eqId83cf38189d5cbf627d2b82ac0eb76006,若存在eqId3e9efb6ee2c5ca85c9f811de30815c73,使得eqId93590334e934816ef9b6323adbbbeb4f或eqIdad936f17d517a94918aea38d0fd45968,称eqId50a272adba0f1120109824440f0e252c为eqId83cf38189d5cbf627d2b82ac0eb76006的拐点值,eqId2c05b9832b09731a574d4a4adf7448de为拐点.若eqId93590334e934816ef9b6323adbbbeb4f,则eqId2c05b9832b09731a574d4a4adf7448de为上拐点,eqId50a272adba0f1120109824440f0e252c为上拐点值;若eqIddd16e3f90bb92de4fe1cf62b71ca67d9,eqIddd16e3f90bb92de4fe1cf62b71ca67d9,则eqId2c05b9832b09731a574d4a4adf7448de为下拐点,eqId50a272adba0f1120109824440f0e252c为下拐点值.

(1)写出数列eqId38b1d129fbc66f5ebe7f8a8fa3cae8f6的所有拐点;

(2)若数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08888d1e5fbc11511ae1ae6b76a67f66,且eqId1879857322ba3d93ccb1a9a94a106cd6.

①求数列eqId846fa57d92d6ad44d6a0cafad1e71ed4的拐点;

②已知eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3是数列eqId83cf38189d5cbf627d2b82ac0eb76006的拐点,当eqId1563da7b0f046a469476668a3686e8f9时,在eqId2fda57f23706517a3b7c02218a1dbcef中任取两个不同的数eqIdc639c7e5f1e7e7ee5d5ee2f30b155bb0,记eqIdd513f3181a48f6f0cfb9ef7175914643的概率为eqIdb1010846eeec6c9da29640f5aa3f8738,求page number 2

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