数列专项训练-2025届高三数学二轮专题

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数列-2025年高考数学二轮专题

一、单选题

1.已知数列eqId76aef4cdcb5af742ce28003b7b6c8c20的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,且满足eqId69ffee847619d59c3a852562947cf20b,则eqId047dbd9ff686703cad03aa383e5fec21(   )

A.eqIdacbc6a613224461ade69362d46550474 B.0 C.1 D.2

2.已知eqId83cf38189d5cbf627d2b82ac0eb76006为等差数列,eqId034ba25825c13725931c483aa47c9363为等比数列,其中eqIde805172946282ca1176a19ed3bc53e28,则(    )

A.eqIdf6874b839b5a84246b6dfe02cdb740c3 B.eqId1af4601b786e8d9b42d811b2da0f20c0

C.eqId87e4b4809582fdddf7f3a2e84dd97b27 D.eqIdf7aa946c75c60f65b47f57c42d57b0bf

3.已知eqId08eb71ecf8d733b6932f4680874dbbf3为等比数列eqId83cf38189d5cbf627d2b82ac0eb76006前eqIdb6a24198bd04c29321ae5dc5a28fe421项和,若eqIdd96829d9df1bc318a1b8fdca8804b288,则eqIdfe343d8fe39ff80543e376846b65b240(    )

A.5 B.3 C.eqId81fb134b2b48acc99213fff6ccfee65f D.eqIdd13ce3ebd1112220c639562739f1f9d1

4.设eqId08eb71ecf8d733b6932f4680874dbbf3数列eqId83cf38189d5cbf627d2b82ac0eb76006的前n项和,若eqId2e70b6c1624e5747f851c381d38b0e31,则eqId5af1f1b7e9e20d799ee3c06b89a0611c(    )

A.3059 B.2056 C.1033 D.520

5.某厂家对其软件进行加密升级,现对软件程序中的某序列eqId4fe336cc2868f8ba1f68f7bf57180014重新编辑,编辑新序列为eqId746af321155d5070a9b7cf43abf593ea,它的第eqIdb6a24198bd04c29321ae5dc5a28fe421项为eqId2ed9925a0e08120e9d2d7846cbc45bc5.若序列eqId7dce35f78e4a3412c07f720df1844f23的所有项都是3,且eqIdf966272f7781790ff27e40db6b525253,eqIda9a4c2113fdd86f4d4fc89727ae92e07,则eqId7999465d0e871febde66296a0cbf058c(   )

A.eqId4dac452fbb5ef6dd653e7fbbef639484 B.eqId158b045c6172c4178d7aa52083e1489f C.3 D.9

6.已知等比数列eqId83cf38189d5cbf627d2b82ac0eb76006的公比eqId354efd9145bb3bd889cf0eaadbcc55f2,前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,则对于eqIdbde2576b383ae3c851529435805b3adc,下列结论一定正确的是(    )

A.eqIdf91ab5932b41914d386c7359c90f0505 B.eqId798577e78cbc4045af1acb7af358a254

C.eqId3df47fd443b150a878ece81e97e17b22 D.eqId97428489a18e94835f853eec31c14bcc

7.记eqId08eb71ecf8d733b6932f4680874dbbf3为数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和.下列说法正确的是(   )

A.数列eqId83cf38189d5cbf627d2b82ac0eb76006成等差数列的充要条件是对于任意的正整数eqIdb6a24198bd04c29321ae5dc5a28fe421,都有eqId68b93bb2c66e49ac3efaf0686d4f3815

B.数列eqId83cf38189d5cbf627d2b82ac0eb76006成等比数列的充分不必要条件是对于任意的正整数eqIdb6a24198bd04c29321ae5dc5a28fe421,都有eqId9e6cbbec0f900da8864d00e396893c98

C.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和eqId2b5e226d7c090e4083f9521563b319d3,则数列eqId83cf38189d5cbf627d2b82ac0eb76006是等差数列的充分不必要条件page number 0

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是实数eqId3b4d795709b0abcf47bceec2250f2f9b

D.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和eqIdcddbe3254149affeb78f1a8e480cda2e,则数列eqId83cf38189d5cbf627d2b82ac0eb76006是等比数列的充要条件是eqId6b108ab31cc093f03cf48ad65429889e

8.已知等差数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqId3bf81f2aaf6841f8ab298f9e2dcf2d52,公差为函数eqIda5f9b986a2884a7975fac694251d7544的最小正周期,则eqIdb6def651c9d29afc605c97e7f9f89a78之和为(    )

A.eqId8221e7bd8a72ef7d4c3ac1925ebcfaba B.eqId53adcd8cf04766b9956f60832a62458a C.eqId04f78a5284b00b95fe5ee6c61bfba242 D.eqIdc5bcb39d544fdbcbd8a53096bc1b35a4

 

二、多选题

9.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqId28de345880e4d0938e33a036b61880eb,eqIde397ffd49c0da176e2e6a1e2f749b6a1,eqIda37a59558292ad6b3d0978bfd7484990,其前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,则(   )

A.eqIdf82feb0b57e12f855db8c254c5ddad65 B.eqId392b9095013eede74a17ac7928c40167 C.eqIdd97c6c5a8ff159a689e10f3f643f2fe8 D.eqId3ee92298a0a93de40f051e1bfbafdb95

10.设等比数列eqId83cf38189d5cbf627d2b82ac0eb76006的公比为eqId9aa8a716a31b0f51b70fdf9bdb257909,前eqIdb6a24198bd04c29321ae5dc5a28fe421项积为eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3则下列结论正确的是(    )

A.若eqIdcbf33fa80f738ef4835551cafa830bf6,则eqIdd8c1749b1460d5ca5c919ce3aa75a008

B.若eqIdcbf33fa80f738ef4835551cafa830bf6,则eqId21bd954305e1c06584478749c33d1104

C.若eqIdb065334d8f60c49f4bd3d9f1373fe4cd,且eqId4ccdc17b603871d20843ffccca2df0ae,则eqId26d9b6c86435e0ceff94d8ad1cd03737

D.若eqId0358628df0a891ee9d868c3738f3a32d,且eqId0e9f09de7212a10ef7182e9dceac856e,则数列eqId034ba25825c13725931c483aa47c9363的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId5ff46490964d3559dbda1d03134bf96e

11.已知在首项为1,公差为eqId90bfe21c96489cb30c544d49ddb4c1c8的等差数列eqId83cf38189d5cbf627d2b82ac0eb76006中,eqIdf0dda391f51b090fb65d2a0fe359f5f0是等比数列eqId034ba25825c13725931c483aa47c9363的前三项,数列eqId83cf38189d5cbf627d2b82ac0eb76006的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3,则(    )

A.eqId09f2572192cc7ca046e9a3155ef3e56a B.eqId77474f4844152b70551678308b122f96

C.eqId4dea1dd4ffcb4cf0697ca43079f6a1f2是公差为3的等差数列 D.eqId5e7ffb3d891649630b77d597be24b529

 

三、填空题

12.已知eqIdb3c65edad25ddd666cdce0d7e5afefc9,“eqId5963abe8f421bd99a2aaa94831a951e9、eqId7f9e8449aad35c5d840a3395ea86df6d、eqIdc5db41a1f31d6baee7c69990811edb9f成等差数列且eqId79b01adc561735ff5be9bb97266918f2、eqIdc8e5d4f93699f8dcffb0e7840ca5597e、eqIdc32e2f2d7147cf1699fbfdef9cf4af74成等比数列”是“eqIdb3c65edad25ddd666cdce0d7e5afefc9是正三角形”的               条件.

13.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006为等差数列,数列eqId034ba25825c13725931c483aa47c9363为等比数列,且eqIdebaf2a2590bb84d646957f913d78f6dc,eqId34308d5ee137e0e442fa70f4642a80ca,若eqIddf30873d6e82ed67234ba6777b64cf90,则实数eqId36a1b09c653185842513e24ebba60bb3的取值范围为      .page number 1

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14.已知数列eqId83cf38189d5cbf627d2b82ac0eb76006满足eqIdb065334d8f60c49f4bd3d9f1373fe4cd,且对任意eqIde167b43045b3297248e334c41c621b8f,有递推关系式:eqIda96af0e3f78d9e61e2e002ec2e106e5e,定义数列eqId034ba25825c13725931c483aa47c9363为eqId9b35b20d625d7ec24531a0a6619f7683,则eqIda2745013a3442de12bdfc8c192dd9c7e          .

 

四、解答题

15.投掷一枚均匀的骰子,每次掷得的点数为1或2时得1分,掷得的点数为3,4,5,6时得2分;独立地重复掷一枚骰子若干次,将每次得分相加的结果作为最终得分.

(1)设投掷2次骰子,最终得分为eqIdf022950e0faa45b617d497b01b5292b9,求随机变量eqIdf022950e0faa45b617d497b01b5292b9的分布列与期望;

(2)设最终得分为eqIdb6a24198bd04c29321ae5dc5a28fe421的概率为eqIdbf83e20035c3afd6d26ebfd53d768a70,证明:数列eqIdd8e5134f738fa09b1c307fe7612a4022为等比数列,并求数列eqId8c5a325806df1a1c3e7ce609fe99085f的通项公式.

 

 

 

 

 

 

 

 

 

 

16.已知正项数列eqId76aef4cdcb5af742ce28003b7b6c8c20的前eqIdb6a24198bd04c29321ae5dc5a28fe421项的和为eqId08eb71ecf8d733b6932f4680874dbbf3,且eqId0e6c763e79238dba3da6a49812febbbf.

(1)求eqIde097c8d4c948de063796bd19f85b3a9a,eqId1e0bd63f55069a3bc870915010b39225;

(2)证明:eqIde2323ea8c1194123755bfff0436d4670是等差数列;

(3)求数列eqId59b0475f5bd564684191bdce7696150c的前eqIdb6a24198bd04c29321ae5dc5a28fe421项的和eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c.

 

 

 

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