广东省珠海市斗门区第一中学2023-2024学年高一下学期期末考试模拟题2

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珠海市斗门第一中学高一数学期末复习卷

1.复数eqId8412e932614449b5ffa3670e42c6a3a1(eqId3a7035cd4adda5d72a9fc9f9fda75995是虚数单位)在复平面内对应的点在(    )

A.第一象限 B.第二象限 C.第三象限 D.第四象限

2.已知平面向量eqId7a2f4b1178f68bd147d1a2a6acd04435与eqIdc94075193c11fe43f2396cff5a485054为单位向量,它们的夹角为eqId2d88591679796c52024d11c4de641bdb,则eqId2a035c8861e9fa9369d20d6b531d88dc(    )

A.eqIdcf298f00799cbf34b4db26f5f63af92f B.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 C.eqId2967337e3fcb228dded64ab0c41a17e0 D.eqId619096595112f0340a43b756e114dd3d

3.eqId15c0dbe3c080c4c4636c64803e5c1f76中,已知eqId2cb6362bc99fba4bcd7331db9aee922c,eqIdffe7a93172d308a58200e3c722fe1072,eqId5742b2684d00be50a66e01c9acb6b51f,则eqIdf4e9bb42376c12d7d21702ae8062b25a(    )

A.eqIda191619d261b3129a2e2b43b368375cc B.eqId792bb860c3f19bd806033132916b54b3 C.eqIdb1498771d8e55231c2969cd5f4e65fcf D.eqIde3ece506803d3968b53bc3c0e9b10346

4.已知eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1是两条不重合的直线,eqIde170f206fdbbd834aad7580c727e2cc6,eqId5b5858ee1ce52b251816757257a11c29,eqId9f435efcc7869eec21bdba1ed81dc3f5是三个不重合的平面,则下列命题正确的是(    )

A.若eqId0477d21c9b3704ca34e2a607429ea602,eqId3f3e8e3f04761b3dd23351a37f95eaaf,则eqIde18e3499b1f9307e7914d3fd1e541d9a B.若eqIda5986f2991d45fbf3578f08f27d9fd7e,eqId73f345365fe0a1986b80299f7a99a306,则eqId0477d21c9b3704ca34e2a607429ea602

C.若eqIdd35a45cfcdfbda18b089ce6698ccdbcd,eqIdb82e5d28e2e5a4790e94db2daa6a07c2,则eqIdb303b1f07604f5303aea94df7f0518e9 D.若eqId0477d21c9b3704ca34e2a607429ea602,eqId187f7895012551f2067f0b77d8df2141,则eqId057cdb4057bca398a838e868efd360f5

5.化简eqId160cd00d0edb304657466bfed4a6b9a1所得的结果是(    )

A.eqIda7ffe8515ff6183c1c7775dc6f94bdb8 B.1 C.eqIdcf298f00799cbf34b4db26f5f63af92f D.eqId860884c0017c8bceb5b0edff796c144f

6.已知eqId64c5562bd4d1b54424330cb6329cd79d,eqIdb45ba716f03748c19b7ce2f99af536ab,eqId73a0b19e69be46452425916a0fcb49c9是同一平面内的三个向量,则(    )

A.若eqIddd79264e130de60a100b001b5d45585c,eqId0b4483c17746ee5603460beda6011743,则eqId76f3e5dd4c8dbf61a7673f33d61396ac

B.若eqId64c5562bd4d1b54424330cb6329cd79d是非零向量,eqId591b482c527876b20d17464e0cbff4f9,则eqId6aa8f7351f41cbfc74f99de51c752ed3是eqId2bcf0da5679b374b3e966724179a1165的充要条件

C.若eqIdcadb456f43065bff1bf0167dcb6cd1dc,eqIdb395c26a966dcf23d4324ed43c1b914e,eqId43f40d5593a04be2752dcbcaf4e62c17,则eqId1d5e09b1502440cd196777af0434753e可以作为基底

D.若eqId64c5562bd4d1b54424330cb6329cd79d,eqIdb45ba716f03748c19b7ce2f99af536ab,eqId73a0b19e69be46452425916a0fcb49c9两两的夹角相等,且eqIdc7958a6bddd1d578bbd6fbcb92e3f6a3,eqId404067afb19bd74f447a6c0c832af1da,eqIda1a1fa7538549bf04c02a09ead1745ed,则eqIdfb8832c8d6d8f4fc09e98fc4bcdfa626

7.在eqId15c0dbe3c080c4c4636c64803e5c1f76中,若eqId8e258ab9e600435b37465092243d99f6,eqId43b86d43790babcdbbdc03493ee70928,则eqId15c0dbe3c080c4c4636c64803e5c1f76面积的最大值为(    )

A.eqIdadbd3e8cf8325999cde03adf845d3dd0 B.eqId38387ba1cadfd3dfc4dea4ca9f613cea C.eqId0f2c06207565e9fa6a288a788e4ab2fd D.eqIdab46ea0cba2d06283fae3d864a2329e0

8.eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIdc2b5a6afe917b7468cc8b1e10e133afe,若对任意的实数eqId2c89d0494abea7465def0c9d74319335恒成立,则eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边的最小长度是(    ).  

A.eqIdd4056761b8f826eeb6ad8c9a151d3c9c B.eqId30b12efb03327f461e868b2ea433f9b0 C.eqIdde31a7b108b0fdc888133f701e7c79b3 D.eqId9b91d650c2fc1a741fabdb333b09aeb6

二、多选题

9.下列说法正确的是@@@82f208dfc82c4f6e9826327cdd3673ef(    )page number 0

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A.在eqIde428e7a09732be85c1224e9c8f6a71c5中,若eqIdc3e187e1473e72c646dd997f2da29e40,则eqId5c029618cf11f31cf131e7103f03e183

B.若eqId6ed1148f2b32477ca7f5f81cb892ca00,eqId89d500af0ca164f4f04b67a080ba6189,eqId60de99e211b7c60ef4ebce335e606536,则eqIde428e7a09732be85c1224e9c8f6a71c5有两解

C.若eqIdcc126eec669e84f271784a8119c08b52,则eqIde428e7a09732be85c1224e9c8f6a71c5一定是等腰三角形

D.若eqId922bdf3d59bc6080949dbcf274e49719,且eqId84b361b78d33b57638661cd683cb9ed3,则eqIde428e7a09732be85c1224e9c8f6a71c5为等边三角形

10.把函数eqIdaa7f9b35017daa8b524c5717a355834a的图像向左平移eqId2d88591679796c52024d11c4de641bdb个单位长度,再把横坐标变为原来的eqIdf89eef3148f2d4d09379767b4af69132倍(纵坐标不变)得到函数eqId4669810732b633b60dbeaf0bf57204f6的图像,下列关于函数eqId4669810732b633b60dbeaf0bf57204f6的说法正确的是(    )

A.最小正周期为eqId86ebba6ed1add0fe647c0226614b9290 B.在区间eqId24cea33d22c544df18a2533e94e2dbd4上的最大值为eqId860884c0017c8bceb5b0edff796c144f

C.图像的一个对称中心为eqId95228c66257fdb082fbc371d06c1c6e8 D.图像的一条对称轴为直线eqId720091d877ca5e2837b0f410fb99631d

@@@29a75eaf76744c938478290a714b892d11.如图是一个正方体的侧面展开图,eqIdf9fd93a869fbf0658083aec7c24cda71是顶点,eqIdfbdb21011ea821b91d539cb763aac649是所在棱的中点,则在这个正方体中,下列结论正确的是(    )

A.eqId274cf35acb4a1748d15c39d15a9bea7b与eqId68a83fdd2ba72a2dba0b6b10bb3e06b9异面        B.eqId1c8ccd4181f956f6e0140bf0ab8f0716平面eqIdb4eb7e9ad5486cf1c5e506b20c5469e8

C.平面eqIde5e7a3d6eadcf4e7be0c6ba280c11c64平面eqId7abd284f76d9f5769bc189508ce2572b

D.eqIde6e490f703eb6c9bb1278c78ebc2d661与平面eqId7abd284f76d9f5769bc189508ce2572b所成的角的正弦值是eqIdbf31876698721a199c7c53c6b320aa86

三、填空题

12.若复数eqIdff223d1413b0bfc6be8bf39b968b35ad为纯虚数,则实数eqIda6c57bbef89a37f1a3808c0ceeac0c22      .

13.在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId047dc9795efa99b6fb9fdf9778085dab,eqIde65a3e478bb87d094e3a0af30dd10ae8,点eqIddad2a36927223bd70f426ba06aea4b45在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,则eqId8c6f6018cd03014f32e020d2bcadd9b0的最小值为        .

14.已知正四棱台的上、下底面边长分别是1和2,所有顶点都在球O的球面上,若球O的表面积为eqId7d80f16c3278cd252725625dcf253cda,则此正四棱台的侧棱长为          .

四、解答题

15.已知向量eqId81f4dcf415977dea53f52a85b6b82136,eqIdf27481c3e3f0a647379ecd926e616ec2,向量eqId73a0b19e69be46452425916a0fcb49c9满足eqIdda1c5bcaa260128e281a12f6ef6aacbc,且eqId2afff6080f14570f2a54b79cdfdeee83.

(1)求eqId73a0b19e69be46452425916a0fcb49c9的坐标;(2)若eqId73a0b19e69be46452425916a0fcb49c9与eqIdba2b0627ff70b02aa16b007dc41794dc的夹角为钝角,求实数eqIddf64046e91b047037f19e4032e3b6de3的取值范围.

 

 

 

 

16.已知向量eqIdca1ceb88aa6d0e5964f77a543326efcc.page number 1

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(1)求eqIdb9b87f4ef298bdeebf59a0d850aff72c的值; (2)求eqId4fe7d5809da02c15a43a0e9a898b9086图象的对称轴方程; (3)若eqIdbb48434bdcafb5e084fc0b6396cb9469,求eqId4fe7d5809da02c15a43a0e9a898b9086的值域.

 

 

 

 

 

17.记eqId15c0dbe3c080c4c4636c64803e5c1f76的内角eqId5963abe8f421bd99a2aaa94831a951e9,eqId7f9e8449aad35c5d840a3395ea86df6d,eqIdc5db41a1f31d6baee7c69990811edb9f的对边分别为eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183,eqId15c0dbe3c080c4c4636c64803e5c1f76的面积为eqIdcf231f8f86fb922df4ca0c87f044cec3.已知eqId9ab4140b024c549f700bea7875a772b4.

(1)求eqId7f9e8449aad35c5d840a3395ea86df6d;(2)若点eqId8455657dde27aabe6adb7b188e031c11在边eqId60ef95894ceebaf236170e8832dcf7e3上,且eqId32aec98e4b02f753c005ea1de0f96ce8,eqId8d5e30f37c5be1b607c71e214a679624,求eqId15c0dbe3c080c4c4636c64803e5c1f76的周长.

 

 

 

 

 

@@@898eb75b-cd41-4533-91ab-2797cdda981918.如图,已知四棱锥eqId0585b6c0f156eecf9662b9846d4eb693的底面ABCD为梯形,eqId10df84d553a8826a7ce9bff4bf0d95b9,eqIdfebdb95e8536e7000ad25c4ce1207665,eqId2e921f46d90e43f4517c55832b6280f9,eqIdfcd0ced286a0fbc7e4862f8147264277,eqId7df793f5dac174bc71bd1e82bbf5732b,直线PA与底面ABCD所成角为eqId15615de1a6df206dbd081251f676578e.

  (1)若E为PD上一点且eqIdafcbbbe350b38381d1999e2886d45f0e,证明:eqId30067b7b236d17af8a462f96a58d11bd平面eqId4c66d99a6a8415ddad22bbed33b64cfb;

(2)求二面角eqIdc911b404bbb8f8d5f1470585fa31ad97的余弦值.

 

 

 

 

 

 

 

 

@@@bc8f20ba-9fa0-47d5-a1c2-3c76ee96d28319.如图,树人中学在即将投入使用的新校门page number 2

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