内容正文:
微专题39 直线与圆锥曲线的位置关系
[考情分析] 直线与圆锥曲线的位置关系是高考的必考内容,涉及直线与圆锥曲线相交、相切、弦长、面积以及弦中点等问题,难度中等.
典例1 已知椭圆C:+=1(a>b>1)长轴的顶点与双曲线D:-=1实轴的顶点相同,且C的右焦点F到D的渐近线的距离为.
(1)分别求C与D的方程;
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(2)若直线l的倾斜角是直线y=(-2)x倾斜角的2倍,且l经过点F,l与C交于A,B两点,与D交于M,N两点,求.
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典例2 (2022·新高考全国Ⅰ)已知点A(2,1)在双曲线C:-=1(a>1)上,直线l交C于P,Q两点,直线AP,AQ的斜率之和为0.
(1)求l的斜率;
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(2)若tan∠PAQ=2,求△PAQ的面积.
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典例3 (2022·新高考全国Ⅱ)已知直线l与椭圆+=1在第一象限交于A,B两点,l与x轴、y轴分别交于M,N两点,且|MA|=|NB|,|MN|=2,则l的方程为________.
[总结提升]
直线与圆锥曲线的位置关系中,解决直线与圆锥曲线的相交弦长、面积问题的通法是用代数法联立方程消元转化进行求解.对于中点弦问题常用“根与系数的关系”或“点差法”求解,在求解过程中,在设直线方程时,注意斜率不存在的情况.
1.(2023·雅礼中