内容正文:
南平市2022—2023学年第二学期高一期末质量检测
物理试题
高一物理试卷 第1页 共6页 高一物理试卷 第2页 共6页 高一物理试卷 第3页 共6页
甲
m
钉子
O 0.2
4
8
12
E/J
t /s2 2
0.4 0.6 0.8 1.0
高一物理试卷 第4页 共6页 高一物理试卷 第5页 共6页 高一物理试卷 第6页 共6页
A B
O1
R
C
O2r
D E
C B
L2 L1
A
h
h螺旋滑道
水平滑道 倾
斜滑
道
O
南平市2022-2023学年第二学期高一质量检测
物理参考答案(定稿)
1、 单项选择题:本题共5小题,每小题4分,共20分。在每小题给出的4个选项中,只有一项符合题目要求。
1.A 2.C 3.D 4.D 5.B
2、 多项选择题:本题共5小题,每小题4分,共20分。每小题有多项符合题目要求,全部选对得4分,选对但不全的得2分,有选错的得0分。
6.CD 7.AC 8.AD 9.BC 10.AC
三、非选择题,共60分,考生根据要求答题
11.(每空2分,共4分);。
12.(每空2分,共4分);。
13.(5分) (1分);切线水平或水平(1分);是(1分);98(2分)。
14.(7分)(1分);(2分);0(2分);(2分)。
15.(10分)解:
(1) 将弹珠水平弹出时做平抛运动,有:
························①(1分)
·························②(1分)
由①②解得:·················③(1分)
(2) 调整初速度,再次将弹珠水平弹出时,有:
························④(1分)
························⑤(1分)
························⑥(1分)
······················⑦(1分)
由④⑤⑥⑦解得:··············⑧(1分)
·······················⑨(1分)
解得:·····················⑩
故弹珠速度的方向与水平方向的夹角为·········⑪(1分)
16. (12分)解:
(1) 当游客刚滑上倾斜滑道时,有:
······················①(2分)
解得:····················②(1分)
(2)
当游客刚滑上倾斜滑道时,设倾斜滑道倾角为,在A点:
·····················③(2分)
····················④
解得:·············· ··⑤(1分)
(3) 当游客从O点滑到C点时,有
·············⑥(2分)
其中:····················⑦
解得:···················⑧(1分)
因在倾斜滑道上做匀减速运动,故:···⑨
解得:·····················⑩(2分)
其中:·····················⑪
由⑧⑩⑪解得:··················⑫(1分)
17. (18分)解:
(1) 小车恰好过C点时,由重力提供向心力得:
························① (2分)
由功能关系得:
····················②(2分)
由①②解得:J·················③(1分)
(2) 假设小车恰好过C点时也能过D点,则有:
··················④(2分)
解得:···················⑤(1分)
由于,小车能过D点,假设成立,过D点的最小速度⑥(1分)
在D点,由牛顿第二定律得:
·····················⑦(1分)
解得:···················· ⑧
由牛顿第三定律可得压力大小:,方向竖直向下 ⑨(2分)
(3)
①当小车恰好到圆心等高处时,有:
······················⑩(1分)
解得:··················⑪ (1分)
②当小车恰好停在水平轨道DE的E点时,有:
···············⑫(1分)
解得:··················⑬(1分)
故锁定时弹射器的弹性势能Ep的范围为:或⑭(2分)
注:计算题解答过程用其它方法解得正确答案同样给分。
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