内容正文:
7.解:(1)5ab-7a22-8ab+5a2)-ab
7.解:(1)(3a-2)-3(a-5)=3a-2-3a+15=13.
(4)-(3a2-4ab)+[a2-2(3a2+2ab)]
做3个乙型窗框需要塑钢3(2x十2y)米,
=-4ab-2a2b,
(2)2m+(m+n)-2(m+n)
=-3a2+4ab+a2-6a2-4ab
所以共需要塑钢5(3x+4y)+3(2x+2y)
当a=-2.h=-时,原式=-4×(-2)×(-2)-2X
=2m十m十n-2n-2n
=-8a2.
=15.x+20y+6.x+6y
=一
5.解:(1)(x3-2x2十x-4)十(2x2-5x十6)
=(21x十26y)(米).
(-2驴×(-合)-4-2=-6
(3)(4a2b-5al)+[-2(3a2b-4a)]
=x23-2x2+x-4+2x3-5.x+6
答:共需要塑钢(21x十26y)米
=4a2b-5a+(-6a2b+8ab)
=x2+2x2-2x2+x-5x-4+6
(2)2x2+xy+3y2-x2+xy-2y2
=4ab-5ab:-6a2b+8ab2
=3x2-2x2-4x+2;
第2章章末复习
=x2+2xy+y2,
=-2a2b+3a.
(x2-2x2+x-4)-(2x3-5.x+6)
当x=2y=1时,
中考演练
D素养培优练
=x2-2x2+x-4-2x3+5.x-6
原式=22+2×2×1+12=4十4+1=9.
1.c
8.解:原式=2r2+mx-y十3-3x+2y-1+mr
=x2-2x3-2x2+x+5.x-4-6
D能力提升练
=-x3-2x2+6.x-10.
2.)g×(1+名)=2-6
8.C9.A10.A11.1
=(2+r+(m-3)x+y+2.
(2)由题意,得
12.解:(1)3a2b+1-8ab-a2b+11ab-5
因为该式的值与x的取值无关,
3A-B
(20号×(1+)=2-日
=(3a2b-a2b)+(-8ab+11ab)+(1-5)
所以2十n=0,m-3=0,
=3(4x2-4xy十y2)-(x2+xy-5y2)
=(3-1)a2b+(-8+11)ab-4
=12x2-12xy+3y2-x2-xy+5y2
r+(-1)
=2a2b+3ab-4.
所以n=一2,m=3,
=11x2-13.xy+8y2
3.2n+1
(2)3(x-y)2-7(x-y)+8(x-y)2+5(x-y)
所以(m十2n)-(2m-n)
4.B5.C6.D7.48.89.110.711.2011012.D
=[3(x-y)2+8(x-y)]+[-7(x-y)+5(x-y)]
=-m+3n
6.C7.15
=-3+3×(-2)
8.解:(1)原式=2a2-1+a-2a+2-2a
13.解:-(3a2-4a2-4ab)+[a2-2(2a2+2ab)]
=(3+8)(x-y)2+(-7+5)(x-y)
一9
=-a+1,
-3a2+4a2+4ab+a2-4a2-4ab
=11(x-y)2-2(x-y).
=-2a2.
(3)12a'be+9abe2-15a'be2-abe2 +2a2bc-a'be"
第2课时添括号
当a=-12时,
原式=12+1=13
14.解:x2-3(2x2-4y)+2(x2-y)
=(12a2bc+2a2bc)+(9abc2-abc2)+(-15a2bc2-a2bc2)
D知识梳理
(2)原式=3x2y+6.xy+2x2y-4xy-5.xy
=x2-6.x2+12y+2x2-2y
=(12+2)a2br+(9-1)ab2+(-15-1)a2b
(1)不改变(2)改变
-3.x2+10y.
=14a'bc+8abe2-16a'bc2.
=2xy,
D基础巩固练
当x=1,y=-1时,
13.解:根据题意,得4、
1.A2.C3.D4.C5.n-3
当x=一2y=方时,
原式=2×1×(-1)=-2.
D能力提升练
D能力提升练
原式=-3×(-2)2+10×=-3×4+2=-10.
所以m=42,n=土
6.D7.D8.D
9.A10.411.-3.x+15y
9.-2
15.解:(1)A区显示结果为
因为mm=-1,所以m=4,n=一,
12.解:由题意,得
10.解:(1)-3x+52-4r-3=+(-3x+5.x2-4x-3).
25+a2+a2=25+2a2.
2A-(3B-[A+2(B-A)]
(2)-3x+5.x2-4x-3=-(3.x-5.x2+4x+3).
B区显示结果为
所以原式=--(-1)-3×(1-4)-×4-11
=A-B
(3)-3.x+5.x2-4.x-3=-3.x+5.x2-(4x+3).
-16-3a-3a=-16-6a
(4)-3x+5.x2-4x-3=-3