第5练 A卷(1完形+2阅读)-2022-2023学年高一英语上册【经纶学典】学霸组合训练(五合一)

Researchers,improve our health呼应played29,A根据上文“In fact,.she has been2144.troubles考查主谓一致和时态。句意：每当 an important part。.故E选项“研究表明，善 soup to Canberra's homeless people for 38 有事情困扰我们时，我们可以先用笔记本记 举可以改善我们的健康。”切题。故选E项 years'”可知，她开始为做汤准备原料。故选 下它，然后查阅我们的词典。在whenever引 I7.D根据上文“Oliver Curry is the research A项。 导的时间状语从句中，陈述客观事实用一般 director at Kindlab,a non-profit organization." 30.C根据上文Stasia Dabrowski的善举及常识 现在时表示将来，主语something为不定代 可知，选项承接上文，说明非营利组织的目标 可知，Stasia Dabrowski的善举应是获得多方 词，谓语动词应用第三人称单数。故填 是什么。故D选项“它的目标是教育和鼓励人 人士的帮助，在他们的帮助下，她的工作得以 troubles. 们选择善良。”切题。故选D项。 继续。故选C项。 45.of考查介词。句意：总之，我认为用英语记 18.A根据下文“University of London psychologist 3l.B根据下文“because of her kind action.But 日记对提高我们的写作能力是很有用的。这 Anat Bardi studies value systems in people... it is not what she is after.”及常识可推知，因 里be of use等同于be useful,表示“有用的”。 to pick the most important,kindness won." 为善行她获得好多荣誉，但这不是她的追求 故填of。 可知，选项在说明善良胜过其他价值观。 故选B项。 V.读后续写 prize kindness over other values呼应 32.D根据语境及她施汤这件事可知，她总是喜 One possible version: kindness won。故A选项“其他研究表明，许 欢帮助他人。故选D项。 The next morning,I woke up with the 多人看重善良胜过其他价值观。”切题。故选 33.A根据上文“She is always loving32 sound of someone knocking at the window.To A项 people..”可知，有人依靠她，她正好也喜欢帮 my excitement.I could recognize a friendly face I9.C根据上文“In one experiment.,asked a 助别人。故选A项。 of a policeman through the window and I realized different group to do three acts of self- 34.C根据上文“It's a pleasure,because I I was saved.After a brief check on my physical kindness..”可知，选项承接上文，应是举例说 know somebody is 33 me,'said Stasia." condition,the policeman quickly sent me to a 明可做的善举。故C选项“这些行为可能很 可知，有人依靠她，她觉得自已有用。故选 nearby hospital.Luckily,the doctor said the 小，比如为某人开门。”切题。故选C项。 C项。 injury on my leg was not serious and suggested a 20.F根据上文可知，上文说明了善良在情感上 35.B根据上下文逻辑可知，上文解释了原因， good rest in the hospital.After getting enough 的益处。结合下文“Sonja studied a group of 空处应使用why,表达“原因”之意。故选 sleep that night,I felt much better and I was people...more acts of kindness had less inflammation B项。 ready for my next trip.