内容正文:
数列(4)
1.[2020·安徽省联考试题]已知数列{an}满足:{eq \f(an,n)}是公比为2的等比数列,{eq \f(an,2n)}是公差为1的等差数列.
(1)求a1,a2的值;
(2)试求数列{an}的前n项和Sn.
2.[2020·长沙市模拟考试]设数列{an}满足:a1=1,且2an=an+1+an-1(n≥2),a3+a4=12.
(1)求{an}的通项公式;
(2)求数列{eq \f(1,anan+2)}的前n项和.
3.[2020·洛阳市统一考试]已知{an}是等差数列,满足a1=3,a4=12,数列{bn}满足b1=4,b4=20,且{bn-an}为等比数列.
(1)求数列{an}和{bn}的通项公式;
(2)求数列{bn}的前n项和Sn.
4.[2020·福州市适应性练习卷]已知数列{an}满足a1=2,nan+1-(n+1)an=2n(n+1),设bn=eq \f(an,n).
(1)求数列{bn}的通项公式;
(2)若cn=2bn-n,求数列{cn}的前n项和.
5.[2020·河北九校第二次联考]已知数列{an}是各项都为正数的数列,其前n项和为Sn,且Sn为an与eq \f(1,an)的等差中项.
(1)求数列{an}的通项公式;
(2)设bn=eq \f(-1n,an),求{bn}的前n项和Tn.
6.[2020·山西省阶段性测试]设Sn为数列{an}的前n项和,已知2an+1=an,且S4=eq \f(15,8).
(1)求{an}的通项公式;
(2)若点(an,bn)在函数y=log2eq \f(2,x)的图象上,求证:eq \f(1,b1b2)+eq \f(1,b2b3)+…+eq \f(1,bnbn+1)<1.
数列(4)
1.解析:(1)解法一 ∵{eq \f(an,n)}是公比为2的等比数列,∴eq \f(a2,2)=eq \f(a1,1)·2,∴a2=4a1.又{eq \f(an,2n)}是公差为1的等差数列,∴eq \f(a2,22)-eq \f(a1,21)=1,解得eq \b\lc\{\rc\ (\a\vs4\al\co1(a1=2,a2=8)).
解法二 ∵{eq \f(an,n)}是公比为2的等比数列,eq \f(\f(an+1,n+1),\f(an,n))=2,∴an+1=eq \f(2n+1,