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绵阳南山中学 2020 年高一新生入学考试数学试卷
参考答案及评分标准
一、选择题(每个小题 5分,共 60 分)
题 号 1 2 3 4 5 6 7 8 9 10 11 12
选 项 A C B A C D A D C B D B
二、填空题(每个小题 5分,共 20 分)
13. 6 14. 216
15. 1或 2 16.
25
36
a
三、解答:(共 70 分)
17.解(1)原式 4 3 3 3 5 1 4 3 ····················································· 5分
(2)原式
4 4
1 1
x
x x x
············································································· 9分
把 5 2x 代入得原式 4 4( 5 1) 5 1
5 1 ( 5 1)( 5 1)
·······························10 分
18.解(1)∵总人数
30 200
0.15
(人)
∴ 200 0.45 90m , 60 0.3
200
n .……………………………………………2分
(2)由(1)的计算知 70 至 80 分段的人数为 90 人,………………………3分
90 至 100 分段的人数 200 30 90 60 20 人,
补全条形图如下图所示:
……………………………………4分
(3)比赛成绩的中位数落在:70~80分 …………………………………5分
(4)恰好抽中获奖选手的概率为:
60 20 2
200 5
. …………………………6分
19.解(1)由
bk
bk
3
21
,解得
3
5
3
4
b
k
,所以
3
5
3
4
xy ································3 分
5( 0)
4
C , , 5(0 )
3
D , .在Rt△OCD 中,
3
5
OD ,
4
5
OC ,···································5 分
∴ OCDtan
3
4
OC
OD
. ·········································································6分
频数
120
90
60
30
0
分数(分)90 1008060 70
20
2
(2)取点 A 关于原点的对称点 (2 1)E ,,则问题转化为求证 45BOE .
由勾股定理可得, 5OE , 5BE , 10OB ,∵ 222 BEOEOB ,
∴△EOB 是等腰直角三角形.∴ 45BOE .∴ 135AOB ° …………………12 分
20.解(1)设改造一所 A类学校和一所 B类学校所需的改造资金分别为 a万元和b万元.
依题意得:
2 230
2 205
a b
a b
·····································································2分
解之得
60
85
a
b
··················································································· 3分
答:改造一所 A类学校和一所 B类学校所需的改造资金分别为 60 万元和 85 万元
········································································································4分
(2)设该县有 A、 B两类学校分别为m所和 n所.则
60 85 1575m n ···············································································5分
17 315
12 12
m n ················································································6分
∵ A类学校不超过 5 所 ∴ 17 315 5
12 15
n ≤ ∴ 15n≥
即: