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宁夏高一期中数学试卷
参考答案及评分标准
一、 选择题(本大题共 12 小题,每小题 5 分,共 60 分)
1.C 2.C 3.B 4.A 5.D 6.D 7.B 8.C 9.B 10.C 11.B 12.B
二、填空题(本大题共 4 小题,每小题 5 分,共 20 分)
13. {x|x≥1 且 x≠5} 14. [−2,3] 15. 2 16. [60,100]
三、解答题(共 70 分)
17.解(1)∵B={x|x>2};
∴∁UB={x|x≤2};
∴(∁UB)∪A={x|x≤3};·················································(5 分)
(2)∵C∩A=C,
∴C⊆A;·····························································(7 分)
∴ ;
∴1≤a≤2,·························································(9 分)
∴实数 a 的取值范围为[1,2].·········································(10 分)
18.解:(1)g(x)=f(x)+a2x=x2+(5﹣6a+a2)x+a﹣2 为偶函数,
则 5﹣6a+a2=0,
解得 a=1 或 a=5····················································(5 分)
(2)∵f(x)对称轴为 ,又(1,2)内是单调函数,
∴ 或 ,············································(8 分)
解得 或
∴a 的取值范围为 .····························(12 分)
19.解:(1)原式= ;·······(6 分)
(2)原式=4+4+2lg5+lg2·(2﹣lg2)+(lg2)2
=8+2(lg2+lg5)
=8+2
=10.······························································(12 分)
20. 解:(1) ∵幂函数 f(x)=xa 的图象经过点(2, ),
∴2a= ,····························································(2 分)
解得 a= ,
∴幂函数 f(x)=𝑥
1
2=√𝑥(x≥0);·······································(6 分)
(2)由(1)知 f(x)在定义域[0,+∞)上单调递增,
则不等式 f(1+a)>f(3﹣a)可化为
,
解得 1<a≤3,························································(10 分)
∴实数 a 的取值范围是(1,3].·········································(12 分)
21.解:(1)由题,得△=(m+3)2+4m>0,
解得 m<﹣9 或 m>﹣1,················································(3 分)
∴m∈(﹣∞,﹣9)∪(﹣1,+∞);······································(4 分)
(2)∵m>0,所以对称轴 ,····································(6 分)
当 ,即 m∈(0,1]时,函数在[0,2]上单调递减,
故当 x=2 时,取最小值 2m﹣7;··········································(9 分)
当 ,即 m∈(1,+∞)时,函数在[0,2]上先减后增,
故当时 ,取最小值 .···································(12 分)
22. 解: (1)∵f(x)+f(﹣x)=0
∴f(﹣x)=﹣f(x),即 f(x)是奇函数.·································(2 分)
∵f(x﹣1)=f(x+1),∴f(x+2)=f(x),即函数 f(x)是周期为 2 的周期函数,
∴f(0)=0,即 b=﹣1.···············································(4