[]山东省枣庄市2018-2019学年高二下学期期末考试数学试题（图片版）

$$ 高二数学答案 第 1 页 共 7 页 2018～2019学年度第二学期质量检测 高二数学参考答案及评分标准 2019.7 一、 单项选择题：本大题共 10小题，每小题 4分，共 40分. BCBC DDAB BC 二、 多项选择题：本大题共 3小题，每小题 4分，共 12分. 11．BD 12．BCD 13．BC 三、填空题：本大题共 4小题，每小题 4分，共 16分． 14． 6 2 4 + − 15．3 16． 13 17． 448− 3280 四、解答题：本大题共 6小题，共 82分． 18. （1）解： ( ) 3 cos sinf x x xω ω= + ······································································ 2分 3 12( cos sin ) 2 2 x xω ω= + 2sin ( ) 3 xω π= + ． ·········································································· 3分 由题意，最小正周期 2 4 8T = × = ，····························································· 4分 所以 2 8 4 ω π π = = ．所以 ( ) 2sin ( ) 4 3 xf x π π= + ．········································· 6分 由 2 2 2 4 3 2 xk kπ π π π− + π + + π � � ， k ∈ Z， ················································· 7分 得 10 28 8 3 3 k x k− + +� � ， k ∈ Z． 所以 ( )f x 的单调递增区间为 10 2[ 8 , 8 ] 3 3 k k− + + ， k ∈ Z． ························· 8分 （2）因为 0 6( ) 5 f x = ，由（1）知 0 0 6( ) 2sin ( ) 4 3 5 xf x π π= + = ，即 0 3sin ( ) 4 3 5 xπ π + = ． ······································· 9分 因为 0 2 14( , ) 3 3 x ∈ ，所以 0 3 2 4 3 2 xππ π π < + < ． 从而 20 3 4cos( ) 1 ( ) 4 3 5 5 xπ π + = − − = − ． ··························································11分 所以 00( 2) 2sin ( )4 2 3 xf x π π π+ = + + 高二数学答案 第 2 页 共 7 页 0 π π2cos( ) 4 3 x = + ······································································ 13分 42 ( ) 5 = × − 8 5 = − ．···································································· 14分 19.（1）估计7岁到8岁不玩手机游戏的儿童中注意力集中的概率为 40 2 60 3 = ． ········ 6分 （2） 2 2 ( ) ( )( )( )( ) n ad bcK a b c d a c b d − = + + + + 2110 (20 20 30 40) 50 60 50 60 × × − × = × × × ·········································