内容正文:
高三数学(理科)答案 第 1 页 共 8 页
2017~2018 学年度第一学期期末考试
高三数学(理科)参考答案及评分标准 2018.1
一、选择题:本大题共 12 小题,每小题 5 分,共 60 分.
DDBA BCCD BDAA
二、填空题:本大题共 4 小题,每小题 5 分,共 20 分.
13. 5 14. 1 15. 4 16. (−∞ , 2 ]−
三、解答题:本大题共 6 小题,共 70 分.解答应写出文字说明、证明过程或演算步骤.
17.(I)解: 2
1
( ) sin sin cos
2
f x x x xω ω ω= − −
1 cos 2 1 1
sin 2
2 2 2
x
x
ω
ω
−
= − − ························································· 2 分
1
(sin 2 cos 2 )
2
x xω ω= − +
2
sin(2 ).
2 4
xω
π
= − + ······································································· 4 分
可见, max
2
( ) .
2
f x = 由题意,
2
.
2
m = ······················································· 5 分
由题意,函数 ( )f x 的周期为π ,因此
2
.
2ω
π
= π 解得 1.ω = ···························· 6 分
(II) 由(I),得
2
( ) sin(2 ).
2 4
f x x
π
= − +
由2 2
2 4
k x
π π
π − +� 2
2
k
π
π +� ,k ∈ Z, ·························································· 8 分
得 .
8 8
k x k
3π π
π − π +� �
所以, ( )f x 的单调递减区间为[ , ]
8 8
k k
3π π
π − π + , .k ∈ Z ·························· 10 分
注:1. 不出现k ∈ Z,扣 1 分; 2. 减区间写成开区间,不扣分.
18. (I)解法一:由题意, 2 =3 0+4 1=4a × × , 3 =3 4+4 2=20a × × .
设 n nb = a nλ µ+ + ,则 1b = λ µ+ , 2 4 2b = λ µ+ + , 3 20 3b = λ µ+ + .······ 3 分
由题意,知数列{ }nb 是公比为3的等比数列,所以有
4 2 = 3
20 3 =3 4 2
λ µ λ µ
λ µ λ µ
+ + +
+ + + +
( ),
( ).
··········································································· 5 分
解得 =2λ , =1µ .经验证, =2λ , =1µ 符合题意. ········································· 6 分
高三数学(理科)答案 第 2 页 共 8 页
解法二:由题意, 1 ( 1) 3( )n na n a nλ µ λ µ+ + + + = + + , ······································· 3 分
即 1 3 2 2 .n na a nλ µ λ+ = + + −
又 +1 =3 4n na a n+ ,所以2 4λ = ,2 0.µ λ− = ··············································· 5 分
解得 2λ = , 1.µ = ·························································································· 6 分
(II)由(I),知若设 n nb = a nλ µ+ + ,{ }nb 是首项为3,且公比为3的等比数列,
故
13 3 3n nnb =
−× = ,即 2 1 3nna n =+ + ,故 3 2 1
n
na = n− − .···················