第4章整式的加减单元检测常考题型提分训练卷 2026-2027学年人教版七年级数学上册

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第4章整式的加减单元检测常考题型提分训练卷人教版2026—2027学年七年级数学上册

总分:120分   时间:90分钟

姓名:________    班级:_____________成绩:___________

考卷信息:

本卷试题共20题,单选10题,填空4题,解答6题,满分120分,限时90分钟,本卷题型针对性较高,覆盖面广,选题有深度,可量化学生的掌握程度!

一.单项选择题(每小题4分,满分40分)

1.下列运算,结果正确的是(     )

A.eqId28d18469b0186854fc4b39094650f622 B.eqId9978627e36105930b91bc3a219c7f78a    C.eqId60a6e37d14156d2555d4bb1bb638010c D.eqId77b0a24a0ee74f03a1f0183ceb281fac

2.下列选项中是同类项的是(     )

A.eqIda025f648f3051e60bb8924dc0bfb313f与eqIdad0146c75af51ec88de9f9f2a3fa117a B.eqIdd76edcaf6e7b5608661a3d1bcdd822b4与eqId29468c2e3d73a10c7b46ca5b6dff5982

C.eqId81dea63b8ce3e51adf66cf7b9982a248与eqId6c1d2e5599453f8d4c04369bc8f79962 D.eqIdfaa948502996e729830dbd10e15313ce与eqId101f3b0169578a0607831e246af58727

3.与eqId11a42b93260c4334e09817890a5ebe0a相等的整式为(     )

A.eqIdbd19ab20f4bdd02bfce0d45c654cc7c1 B.eqIdbd4b13c3cb3d33470269907393c32c83 C.eqId07eecfc97e2ecc13d515d10f9123127f D.eqId08b709be04e86cd3615204952fb83fcb

4.若eqIdb3465a833f5b6b71e7b67a426b9872c5,eqId78866ea635f38545bca721b65af19884,且eqIdadc1e5814684904a9aca03678acf0ad5,那么eqId20d6fc9b90f370fbb27552876b650f8f的值是(    ).

A.eqId274a9dc37509f01c2606fb3086a46f4f或4 B.2或eqId3edbd40e04e2a943051fa83d6e511add C.2或4 D.eqId274a9dc37509f01c2606fb3086a46f4f或eqId3edbd40e04e2a943051fa83d6e511add

5.以下是一组按规律排列的单项式:eqIdda971671378e8d40e15f5ef0b6e41467,eqId9202728e1638c038fbac0366f6a3fed0,eqId2446194c7bde4b1e81f7056f658bb356,eqId3044ef79a2b3ef3d85d5c1ba3fe2288b,eqIddaa5e9bd516f6282483b92cfe6074623其中第eqIdb6a24198bd04c29321ae5dc5a28fe421个单项式是(     )

A.eqId307f89291689cc9c5d531b43cbcf3309 B.eqId45fdaa75e5aae4db800b062f5374d79d C.eqId3d14a2a6f8f43ee9a44d68c1027338d0         D.eqId359fa75644ce7ca5b3c9e51c11cfdf06

6.下列说法正确的是(     )

A.eqIdc3219245493e321d3e0e6180f3e7cf16与eqId529e97b5b7c237c464248b10755547c9不是同类项 B.eqId78db83a3fbad2a4732e9ecc196521d46不是单项式

C.eqIde0c0adbbd84df799d851d0e803d09c2c是一次二项式 D.化简eqIdf7cb37c074d9befabd2146135ae2870b的结果是eqId78db83a3fbad2a4732e9ecc196521d46

7.一个多项式与eqId61f9b180e9be7407497331ab01eef9ef的和是eqIdfa54d2a1b192048f8de9f66f0e14a1c1,则这个多项式为(     )

A.eqId649e1db268573bde86da7f123ef1d013 B.eqId8aabdc8835420fedbf023c919d0f21b8 C.eqId33e22e53abf575ea36b5a6b9c73dfab7   D.eqId53e85e08e2a764c9a0cec96d3fe6d59b

8.已知eqIdd90d7f054e8f0346479e1999622f11cf是有理数,eqId9e56f4504e0f80fd031c8b5f41832e03,eqId73c21bd0bd90a89b7ff5ac0eacf612a5,则eqId23953452aa76eaf222597f5d925e6ecc(     ).

A.3 B.eqId81fb134b2b48acc99213fff6ccfee65f或eqIdbdaa19de263700a15fcf213d64a8cd57 C.eqIdacbc6a613224461ade69362d46550474 D.1

9.如图,已知eqId5963abe8f421bd99a2aaa94831a951e9、eqId7f9e8449aad35c5d840a3395ea86df6d、eqIdc5db41a1f31d6baee7c69990811edb9f、eqId8455657dde27aabe6adb7b188e031c11在数轴上表示的数分别为eqId0a6936d370d6a238a608ca56f87198de、eqId2c94bb12cee76221e13f9ef955b0aab1、eqId071a7e733d466949ac935b4b8ee8d183、eqId5c02bc0c74292b1e8f395f90935d3174且满足eqId64e0aa0c32420a979308a68c3ec525e9,eqIda489fb10783de3c6b50dffd87059c146,则eqIde6bb99e2251df1777c5288d603170bd2的值为(     )

@@@187e4f6b-b87c-4826-976f-a6f98929247e

A.eqIdacbc6a613224461ade69362d46550474 B.0 C.eqId8ec818fc0754296163206e1e8870f9e6 D.1

10.如果eqId05cc4e11ed217a955c89cc351ee73bd7是关于x,y的四次三项式,那么eqIda6c57bbef89a37f1a3808c0ceeac0c22(     )

A.eqIdacbc6a613224461ade69362d46550474 B.eqIdacbc6a613224461ade69362d46550474或3 C.3 D.eqId81fb134b2b48acc99213fff6ccfee65f

二.填空题(每小题5分,满分20分)

11.已知eqIdd517c7b7bfd6b21cfd5e0d35a58e77aa,则代数式eqIdac379bb4535e1fe45274c16a903612ce的值为________.page number 0

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12.若eqId33ad29829073ac55640b4fcb5ac0d15e,则eqIdc2b84299f0bef4b1f3796c21a914a2a6___.

13.对于三个非零有理数a,b,c,那么eqIdf66c57ebe84fb2b897be3364f5c323e0____________.

14.如图,这是2026年1月的月历,其中“eqId0b68df477b3ee45ac0f725db00d465a1”形、“eqId0c88d9142df6ba8e43c1a93bd04a1362”形两个阴影图形均覆盖四个数字,它们在框内可上下左右移动,可重叠.设“eqId0b68df477b3ee45ac0f725db00d465a1”形阴影图形覆盖的最小数字为eqId0a6936d370d6a238a608ca56f87198de,四个数字之和为eqIdac047e91852b91af639feec23a9598b2;“eqId0c88d9142df6ba8e43c1a93bd04a1362”形阴影图形覆盖的最小数字为eqId2c94bb12cee76221e13f9ef955b0aab1,四个数字之和为eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3.若eqId3dab51a55918da45b38648c3eaa88065,则eqId3ae0f8520349250a31be6d58542ef2d9的最大值为________.

@@@2d088bf0-20d8-4ac5-95b2-34c9ed49ba5c

三.解答题(共6小题,总分60分,每题须有必要的文字说明和解答过程)

15.先化简,再求值:eqIdd119a2dd78b1c22dc48cb5639582979e,其中eqId8e258ab9e600435b37465092243d99f6,eqIdb86304c3e26200299a0480641525a283.

 

 

 

 

 

 

 

16.按要求完成下列各题:

(1)已知eqIdae80131e0591efa4c612a56191723066,eqId7ca0bf6f3a69dc2dec1f3d5275b69982,且eqId4eff0953a7bcb8f4dc02acb81b549942,求eqId72850427e83ff19a24305783e080b280的值.

(2)已知eqId58e23117608becdb000a9812d7fe9821,eqId2549b7ae6b1632f12121f6c59e70384f,且eqId2b21208364124b5c477b2ff8df1c2e8f,求eqId059d6df06a5b85848dc4fa33327f8e07的值.

 

 

 

 

17.有理数eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1,eqId071a7e733d466949ac935b4b8ee8d183在数轴上的位置如图:

@@@98bca803-c72d-4695-844d-549d1038fe87

(1)判断正负,用“eqId392cdb9d30684cce244bef94b8d861b9”或“eqId4ff7942da6c3fc4005256fb1458557c0”填空:eqId9db8d3facff8f90f28a936fc5b3ab878______0,eqId20d6fc9b90f370fbb27552876b650f8f______0,eqIda8409329b550296446a936d97c491ca9______0;

(2)化简:eqId4cfdc883779bcdf35d6f6dcac20bf283.

 

 

 

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18.定义:将图①中的长方形纸片剪成eqIdbdaa19de263700a15fcf213d64a8cd57号,eqId61128ab996360a038e6e64d82fcba004号,eqId5ca7d1107389675d32b56ec097464c14号,eqIdb8860d9787671b53b1ab68b3d526f5ca号正方形和eqIdd91e07104b699c4012be2d26160976a2号长方形.

@@@9520cdb7-d4b2-4182-ab71-475598a92d62

(1)设eqId5ca7d1107389675d32b56ec097464c14号正方形的边长为eqId0a6936d370d6a238a608ca56f87198de,eqIdb8860d9787671b53b1ab68b3d526f5ca号正方形的边长为eqId2c94bb12cee76221e13f9ef955b0aab1,求eqIdbdaa19de263700a15fcf213d64a8cd57号,eqId61128ab996360a038e6e64d82fcba004号正方形的边长分别是多少?(用eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1的代数式表示)

(2)若图①中裁剪前长方形的周长为eqId332e71982612ea86c28b9f2054b1045c,试求eqId5ca7d1107389675d32b56ec097464c14号正方形的边长;

(3)在(2)的情况下,若将这五个图形按图②的方式放入周长为eqId17e85c53a287e873f35c9ca64972023c的长方形中,求阴影部分的周长.

 

 

 

 

 

 

 

 

19.“整体思想”是初中数学一种重要的思想方法,它在代数中应用较为广泛.如已知eqId254aebe3ef7eabdf41e46c1cd857c705,求eqId833ec375a625906c5a0d18dd6c20da48的值.根据已知条件我们虽无法直接求出a与b的值,但可以将eqId891007ba7625f47b096a69dc8726e846看作一个整体,其值即为2,而eqId181ab0af5304e130073b3810c3cffdca,将eqId254aebe3ef7eabdf41e46c1cd857c705整体代入,即可求得eqId7cdec5dc8d345080a0a00c7f54f94976.

(1)已知eqIdfa29827b7608fafe15bc4174be30a879,则eqId442910d7cab67a25fbaefa01623dca54______;

(2)若eqId2a508d7e1d5b2e11cc26dadce5d44fde,求eqIdea5f6c52a19c0f3fcf906e27131e792d的值;

(3)设多项式eqId69def3da142e831f32cee31271489a76,eqIdfb0c88183f51b688314d4b7de15c76ad,eqId9c0731a7cc2ce607c4779d20b40c864f,若eqIda551563a3f2c6b5f3c966b6ed146d94b的结果与x的取值无关,求eqId0466d19eebba7c8031bbc76772f92bb5的值.

 

 

 

 

 

 

 

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