4.2等差数列(2)中午30分钟限时练-2026-2027学年高二上学期数学人教A版选择性必修第二册

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4.2等差数列(2)30min限时练

1.已知数列eqId63d471926f7b27322d90c82b9ce21d3d的通项公式eqId2f5b0c212925ac4166bcb7cf58ba6245,则数列eqId63d471926f7b27322d90c82b9ce21d3d的前10项和为(    )

A.35 B.40 C.45 D.50

2.一个等差数列共100项,其和为80,奇数项和为30,则该数列的公差为(     )

A.eqId56d266a04f3dc7483eddbc26c5e487db B.2 C.eqId4dac452fbb5ef6dd653e7fbbef639484 D.eqIdd33adb74906403b0b00fcbd9fa691d8b

3.在1和11之间插入eqId294f5ba74cdf695fc9a8a8e52f421328个数,使得这eqId9f2c1ec3153d6b86778f01cb90027029个数成等差数列.若这eqId294f5ba74cdf695fc9a8a8e52f421328个数中第1个为eqId0a6936d370d6a238a608ca56f87198de,第eqId294f5ba74cdf695fc9a8a8e52f421328个为eqId2c94bb12cee76221e13f9ef955b0aab1,则eqId22757fd981bfd153022e53b672c57906的最小值是(     )

A.eqIdd59ab85c075a09d55d69e159e4abb268 B.2 C.3 D.eqId31da7291140e430a11e2a10cc6cdefbb

4.(多选)设数列eqId63d471926f7b27322d90c82b9ce21d3d的前n项和为eqId08eb71ecf8d733b6932f4680874dbbf3,eqId8f3d2d527a8cdc81bcbaae3af3a5b50c,则下列说法正确的是(     )

A.eqId63d471926f7b27322d90c82b9ce21d3d是等差数列

B.eqId9822f367d7d625f7fcbbb19aa0242b0a成等差数列,公差为eqIdd3aab28a20b5bf47040aaec03b1eb550

C.当eqId084d365cc7ff8f3bd2db97ee45b1db17或eqId3d41b3dd8594734ce50e94fc8741ddd8时,eqId08eb71ecf8d733b6932f4680874dbbf3取得最大值

D.eqIdaf41f69faa99e847ee18d2de283542aa时,n的最大值为33

5.已知等差数列eqId62e567d7e9761951a266953c8d5042ac的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和分别为eqId478421b81927e435cbcf5acafa89efd7,且eqIdb57dfed4a26d4ef0d7cea22208fa2d98,则eqIdb4863086901be9beea78c25d48ceb460      .

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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6.在等差数列eqId63d471926f7b27322d90c82b9ce21d3d中,前n项和为eqId08eb71ecf8d733b6932f4680874dbbf3.

(1)已知eqId365e0eaa6da90cf15ce197c16e79a45e,eqId38db0637b08ba3fb6a230f8e08ba438f,求eqId5f3cf6f2bbe20a404fea41a4d2b1c4c7;

(2)已知eqIdcd16a6780c7f74c4e703632ff95e175c,求eqId05201ef79a5d5904f492845396fb5470;

(3)已知eqIdb065334d8f60c49f4bd3d9f1373fe4cd,eqId619ef41442789786a473b6ffa8e73f4f,求eqId08eb71ecf8d733b6932f4680874dbbf3;

(4)已知eqIdb065334d8f60c49f4bd3d9f1373fe4cd,eqIdc5c1344592c925b273f2cb9b9e47ebbb,eqId83529e32fa71373e2c9d53402cc0c8e9,求eqIdb6a24198bd04c29321ae5dc5a28fe421.

 

 

 

 

 

 

 

 

7.在等差数列eqId63d471926f7b27322d90c82b9ce21d3d中,eqIda71c11276ec13c22798689d836ed7f91eqId63d471926f7b27322d90c82b9ce21d3d的前eqIdb6a24198bd04c29321ae5dc5a28fe421项和为eqId08eb71ecf8d733b6932f4680874dbbf3.

(1)求数列eqId63d471926f7b27322d90c82b9ce21d3d的通项公式;

(2)求eqId08eb71ecf8d733b6932f4680874dbbf3取最大值时eqIdb6a24198bd04c29321ae5dc5a28fe421的值;

(3)设eqIdf50f660146107d2c941da9981db65bb5,求eqIdf1ae9a3b0b7aeb1545b65d91aa371b3c.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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答案

1.已知数列eqId63d471926f7b27322d90c82b9ce21d3d的通项公式eqId2f5b0c212925ac4166bcb7cf58ba6245,则数列eqId63d471926f7b27322d90c82b9ce21d3d的前10项和为(    )

A.35 B.40 C.45 D.50

【答案】C

2.一个等差数列共100项,其和为80,奇数项和为30,则该数列的公差为(     )

A.eqId56d266a04f3dc7483eddbc26c5e487db B.2 C.eqId4dac452fbb5ef6dd653e7fbbef639484 D.eqIdd33adb74906403b0b00fcbd9fa691d8b

【答案】D

【解析】设等差数列的公差为eqId5c02bc0c74292b1e8f395f90935d3174,则由条件可知:

数列的奇数项之和为eqId09bd35eb7d2a5878876fd73e24af9792,①

偶数项之和为eqIdcc43a8327cbe88d1f7023c71218515fd,②

由②-①,得eqIdd2143b1636e638d26c2a78b08879df09,所以eqId56fbe14f8ef4baea799640bd3bdccd58,即该数列的公差为eqIdd33adb74906403b0b00fcbd9fa691d8b.故选:D.

3.在1和11之间插入eqId294f5ba74cdf695fc9a8a8e52f421328个数,使得这eqId9f2c1ec3153d6b86778f01cb90027029个数成等差数列.若这eqId294f5ba74cdf695fc9a8a8e52f421328个数中第1个为eqId0a6936d370d6a238a608ca56f87198de,第eqId294f5ba74cdf695fc9a8a8e52f421328个为eqId2c94bb12cee76221e13f9ef955b0aab1,则eqId22757fd981bfd153022e53b672c57906的最小值是(     )

A.eqIdd59ab85c075a09d55d69e159e4abb268 B.2 C.3 D.eqId31da7291140e430a11e2a10cc6cdefbb

【答案】C

【解析】由题可知,eqId8884c348ee8650787e7808cc56c19a8a,

所以有eqIdff198ab5147660b1635194e4cdb220f6,

当且仅当eqId9faf30ec956899ba79996c3ef78f1308,即eqIdb8a1d98ec7fd447ebedabe8d342e4aa0时等号成立,

此时eqId632244ea6931507f8656e1cc3437d392满足eqId71740b2dde45b38332dd93c46c827503,eqId972592728257d4ed956be1c5f3a097f3,所以eqId22757fd981bfd153022e53b672c57906的最小值是3.故选:C.

4.(多选)设数列eqId63d471926f7b27322d90c82b9ce21d3d的前n项和为eqId08eb71ecf8d733b6932f4680874dbbf3,eqId8f3d2d527a8cdc81bcbaae3af3a5b50c,则下列说法正确的是(     )

A.eqId63d471926f7b27322d90c82b9ce21d3d是等差数列

B.eqId9822f367d7d625f7fcbbb19aa0242b0a成等差数列,公差为eqIdd3aab28a20b5bf47040aaec03b1eb550

C.当eqId084d365cc7ff8f3bd2db97ee45b1db17或eqId3d41b3dd8594734ce50e94fc8741ddd8时,eqId08eb71ecf8d733b6932f4680874dbbf3取得最大值

D.eqIdaf41f69faa99e847ee18d2de283542aa时,n的最大值为33

【答案】ACDpage number 2

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