2.1不等式及其性质练习卷2025-2026学年北师大版数学八年级下册

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2.1 不等式及其性质 练习卷

一、单选题

1.若eqIdcb7961cbe98aac6a5fdee94582c341b4,则下列选项正确的是(    )

A.eqId750a64cbac545ad296f539b53246114f B.eqId2dd08dc3688dc64dfc58f491e9f0931b C.eqId63096e8bf975f8dfc3ed2e1aa189ed25 D.eqId4ac24f76da1470be3fd17d03812d1149

2.下列式子的变形错误的是(   )

A.若eqId1f22fec5a381ae8aca93d876e54c79de,则eqId4a1a85da14604e1ab7cd9f0c97610258 B.若eqId0c213567395973b6c767555fa550c190,则eqId1f22fec5a381ae8aca93d876e54c79de

C.若eqId7091d529281abff275ef19b9197445a7,则eqId5227ac103584a3c74d00f34264806cc0 D.若eqId43a5abe56c019ac914e1fcde1865a747,则eqId5d460a827a9d4ead2f2301d5127a318e

3.若实数eqId9e34f42b3be15518c29e3689c9fe6d6d,则实数eqIddb7bb7e4cce6269151f41af3853b4e68,eqId9dd1dbc5813e0170f59ebab4d9fe0f33,eqId27f9e0cadaf6dfd8dd819f01aefd9991的大小关系是(   )

A.eqId3c1f322806f62922efbc8127b74cbbf0 B.eqId523e226cff017279508f007761014f90 C.eqId505463900e97c03ade072d4809c5fcde D.eqId621b3cdf3c9d966de822c5cb2a493fbb

4.若eqId432d77fe5ad3032d59a237dd94c8a638,则下列不等式成立的是(    )

A.eqIdd900ca813932859200e6435fade938a2 B.eqIdfc4944e46313a7b827ad9b637cd1fd9f C.eqIdf0c628417ddc1ee8028acc40eb145834 D.eqId6a2207f7c2baed559a873092c671f0d4

5.若eqIdc6a46e678bf9d2df5ad4c782b3dc22f5,则下列不等式变形正确的是(    )

A.eqId572f468e8f9b7fae7465c2510344608d B.eqId827147c42928f59da82bc756137db0e2 C.eqIdac11bc5b29b60c7f65f466495defcf2e D.eqId168a658feda0c5c540a37a56a7a23b17

6.下列式子中,不是不等式的是(    )

A.eqIdf1b3447b7345934131ba1ed4488e52e9 B.eqId74ae32d7d2ef73fe44955e3cb30f5f41 C.eqId283eea50eb7a1adc6fd93832d813cc42 D.eqIda0650eacf302e7794473bcba4e88a150

7.下列选项中,不能用不等式表示的是(    )

A.eqIda6616da8f7c03dc5d8f1ed993d3cfa25小于0 B.eqIde2cb38f9819ea62a8c5af4f467147a6f是正数 C.eqId72850427e83ff19a24305783e080b280等于零 D.a比b大

8.贵阳某日最高气温是eqId5f2969d81e7c1cc013e2bc059ac498f5,最低气温是eqIdb19a19a3f4e5138f9f1acbfe2c4e8dff,则贵阳当日气温eqId36a1b09c653185842513e24ebba60bb3(eqIdaa088a4729226b696c536845791d4c02)的变化范围是(    )

A.eqId997e4450d9ffad99d3cb1fcc033d2347 B.eqId7aeead016b405f69e28e8da35a3ffc7b C.eqIdd0017fc68fa69824dc0c4d9561a85956 D.eqIde611732301eaef20ce8341d4fc492681

 

二、填空题

9.比较大小,用“eqId392cdb9d30684cce244bef94b8d861b9”或“eqId4ff7942da6c3fc4005256fb1458557c0”填空;若eqId7091d529281abff275ef19b9197445a7,且eqId9ff45f8b49cd6adb1ce1b6ee1ba5452a,则eqId0a6936d370d6a238a608ca56f87198de________eqId2c94bb12cee76221e13f9ef955b0aab1.

10.如果eqId9d4dd1418d682a51726ab65c18dd9b9b,那么不等式两边____________,可变为eqId66774dc471e1a5ff66abeb3a60090af4.

11.如果eqId392d68c474ffa544f6514eef5368d292的解集为eqId629507dcfdeb6866da428c4f45e2b21d,则eqId0a6936d370d6a238a608ca56f87198de的取值范围是______.

12.在下列数学表达式中:eqId7917beb7f185359cfb3e04c48ba35d68,eqId20d6fc9b90f370fbb27552876b650f8f,eqId9b384412acba251d87902ab928902f16,eqId1a2c962d59c3d67d56b905941517132c,eqId41a10eee216ae52e4b42af7a431e714e,其中不等式有________个.

13.有下列各式:①eqId7084b7c5564061fdd5d65e07f9692d90;②eqIddbfe017e21d1a4e5cf7b1fbf44fcc0ec;③eqIdf85982504c286be5478ef390dd5acd98;④eqIdd462ed4ec22e8fe51f09eb30e8792532;⑤eqId060e7930731eddbcfac592b808e9b698.其中属于不等式的有______个.page number 0

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三、解答题

14.指出下列各题中不等式变形的依据:

(1)由eqId6394f9a6cefd1bc9558e043fddeaaa16得eqId291b356ed486132abcacd5cec01b58c4;

(2)由eqId868cc7d28de7d8baf6df041e2aaf98f4,得eqIde270e5e488ded8f5eafb66f2df173692;

(3)由eqIdb3afb78f966415f634cf482461a495a4,得eqId78a45b0d8e654d12e00c6015924d37d4;

(4)由eqId8d01aa515bb937d0cd30e7f1643cd047,得eqId1d33da711e50e96568facb18cef27165.

15.先阅读下面的解题过程,再解题.

已知eqId2b21208364124b5c477b2ff8df1c2e8f,试比较eqIdefb8b4afc934829f7d2d9608da77a903与eqId558e50a8ada99e02f870e6c7a7e2fe29的大小.

解:∵eqId2b21208364124b5c477b2ff8df1c2e8f,①

∴eqId806463f4e66b4b5cfaf397b2c4067c34.②

∴eqId0c359c59e0b3ff0915d2d5db54112ae8.③

(1)上述解题过程中,从步骤________开始出现错误(填写序号);

(2)请写出正确的解题过程.

16.果农通过网络直播宣传,使物美价廉的水果畅销全国各地eqIdc90282d4a37c9a20620d4bbb0c263cae粉丝小级想在直播间购买凤梨和山竹,凤梨每箱eqId0a6936d370d6a238a608ca56f87198de元,山竹每箱eqId2c94bb12cee76221e13f9ef955b0aab1元,eqIdc6a46e678bf9d2df5ad4c782b3dc22f5.为了方便快递,直播间要求一单需买两箱,且整箱购买.小级决定在直播间下一单.

(1)若小级一单买了eqId61128ab996360a038e6e64d82fcba004箱凤梨,则需花费eqId30f6ae805e69e5c04728f976047dad58______元;若他一单买了凤梨和山竹各eqIdbdaa19de263700a15fcf213d64a8cd57箱,则需花费eqId8b54e384a072508d4754e0f1636f8f66 ______元.

(2)比较eqId54015ff5b49e3283901da1291b6b921d与eqId46f6872ffb1934339c53c2c2282d5889的大小,并用不等式的基本性质说明理由.

17.根据下列数量关系写出不等式.

(1)x与5的和的eqId71761bf8d19bf3deacbc9fd434a0c4a1不大于eqIda67312d6fbde2db992b25a11f4ec102b;

(2)m除以4的商加上3至多为5;

(3)a与b两数和的平方不小于3.

18.用不等式表示下列问题中的数量关系:

(1)长为a、宽为eqId564a3336ddeba347978fee32ffb16631的长方形的面积小于边长为eqId83666674f1111c699d7c5f7b792e0285的正方形的面积.

(2)一辆40座(不含司机座位)的公交车内载有乘客x人,到某一站停车时下车2人,又上车a人,车内仍有空余座位.

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《2.1 不等式及其性质 练习卷》参考答案

1.C

【分析】利用不等式两边加(或减)同一个整式,不等号方向不变的性质判断各选项即可.

【详解】解:eqId76c2bb7be2e9410a16502268fd4c67be选项,左右加减不同的数,不满足性质,举反例eqIdbc304a55feec5d8312d3082f1bb91a23,eqId38c9d7f7f9a3e9ec476f5cf7fda97c88可得eqIdb756ec0993d48c2d292065bef1e2f519,eqId322cf5b4b35105ca441397dccf2e3a66,eqIdba4aacd94cff63249847792994c45085,选项错误;

eqIdc14c6709d2a04863cacdee618b20613e选项,不等式两边同时加eqIdda971671378e8d40e15f5ef0b6e41467,不等号方向不变,可得eqId2e1051296813c49d4f940bc496fa5fc4,选项错误;

eqId7f015ed8e497b4394053ddd19683a98f选项,不等式两边同时减eqIdda971671378e8d40e15f5ef0b6e41467,不等号方向不变,可得eqId4ed77508b54257158c20a3a99190d77a,选项正确;

eqId7909220d1db380634534190b662ee0a7选项,不等式两边同时减eqIdb6a24198bd04c29321ae5dc5a28fe421,不等号方向不变,可得eqIdd3dd59c7b9f7ab0fc32284d954467095,选项错误.

2.D

【详解】解:A、eqId1f22fec5a381ae8aca93d876e54c79de,两边同时加eqIdda8280bdbac2fa4e050c6ac329f30446得eqId4a1a85da14604e1ab7cd9f0c97610258,变形正确.

B、等式eqId0c213567395973b6c767555fa550c190中,分母eqId294f5ba74cdf695fc9a8a8e52f421328不为eqIdc95b6be4554f03bf496092f1acdfbb89,两边同乘eqId294f5ba74cdf695fc9a8a8e52f421328得eqId1f22fec5a381ae8aca93d876e54c79de,变形正确.

C、∵eqIdd37660096fb35820bc02bb27d58195fc,

∴eqId11ff050e8101751af6b5cf052e25c410,

∵eqId7091d529281abff275ef19b9197445a7,

∴eqId5227ac103584a3c74d00f34264806cc0,变形正确.

D、当eqId3b4d795709b0abcf47bceec2250f2f9b时,eqId8a00de2c7f4179d80ddac6ae626ad1cd,此时eqId0fb90f79bcd0002af53541bee7f3043c

∴eqId43a5abe56c019ac914e1fcde1865a747不能推出eqId5d460a827a9d4ead2f2301d5127a318e,变形错误.

3.B

【分析】本题考查学生对利用不等式比较大小的方法的灵活使用情况,利用作差法分别比较即可.

【详解】解:∵eqId9e34f42b3be15518c29e3689c9fe6d6d,

eqId679c4d5dbfe44381c260764111c748db,

eqIde354ddec2a1796ee496131a6b72974e1,

eqId8b699ba761ed091c2eead91854883be3,eqIdd1e69a88ab23567a67b96dcc878eecef,

而eqId81986c73a4772602e9c6c578dc62e6fb,

eqId861f9e3fa1090d55469280d52aeb423f,

eqId6c8a452308c1b5e0c66935872f64ede5,

故选:B.

4.Dpage number 2

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