7.1.1 两条直线相交 同步练习 2025-2026学年人教版七年级数学下册

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7.1.1两条直线相交 同步练习

一、单选题

1.下面四个图形中,eqIdd5b69d40b75d582c4b8ffa2369af1d41与eqId9d57899ad4774aed9ccc7bd23db72153是对顶角的是(    )

A.@@@163b10fc-29ab-4ee2-8dca-f4af6194e1c6 B.@@@c6238e7b-ffa2-47aa-bd80-578cd00d8b24

C.@@@35da0f2b-a96f-4cd2-aa08-66390d215591 D.@@@cd5631f4-1a17-4143-9d53-3d4ea26ca418

2.下列四个图形中,eqIdd5b69d40b75d582c4b8ffa2369af1d41和eqId9d57899ad4774aed9ccc7bd23db72153是邻补角的是(    )

A.@@@02b671c3-3ad3-42c9-a7f7-af4c171a1f56   B.@@@bf39f36f-66ef-4705-9f6c-e3cdd0c96db9  

C.@@@6eccb85a-55a3-4265-bf2e-5b604cdc1990   D.@@@ec203c01-426e-40e9-a7cc-e13dbd092785  

3.如图所示,已知直线eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId9d78abbad68bbbf12af10cd40ef4c353相交于点eqId1dde8112e8eb968fd042418dd632759e,eqIda299d2b999568e80be8005565ba209a4平分eqIddc9f91270ddbe1cf3c1362e1b95aee14,eqId6cad4595d5352b2884568a59d8d766a4平分eqIdd0e1e2a60c37ebc303d4fc2bf3d6a234,eqId66c2ca2ee2a993b27c0e40b030f65cdf,则eqId778d3556c2454a733a15629af5c2444f的度数为(    )

@@@f03f5602-7f7a-4281-84d4-2c566acf4a7b

A.eqIdd6c858ffdfa9cf878ee3ccc2bbcfca28 B.eqId6ee6e9272380b8f02c3f1e6eb3e97036 C.eqIda7b398c95494eddc79939f16e66cf4da D.eqIdc02b54dc6b3e1bb6544f47d4c8743fcf

4.如图,点O在直线eqIdf52a58fbaf4fea03567e88a9f0f6e37e上,eqId109ef96c8618eeaaf6a679940e195a7c.若eqIdbe089053abcaa85ca478f091a548b3a1,则eqIddc9f91270ddbe1cf3c1362e1b95aee14的大小为(  )

@@@5b96ffa2-94b7-4be6-855e-11d0adf0a49c

A.eqId76c12e76fbd84eeec721386bd3b04cc4 B.eqId0aee6e4e9350a2665df8597ff8045bbd C.eqIdf6b86c22b670a8e9f3896f9e8883fbbb D.eqId79a97bb4dcfab4ec7539bc783d563c49page number 0

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5.如图,有一个破损的扇形零件,利用图中的量角器可以量出这个零件的圆心角的度数,依据是(   )

@@@e7fdcade-e7cb-4b4f-a051-e448399f61a8

A.同位角相等 B.对顶角相等 C.内错角相等 D.同旁内角互补

6.如图,直线eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId9d78abbad68bbbf12af10cd40ef4c353相交于点O,eqId92ffc9ad0f1c482d721294cc4768cb04,则eqIddc9f91270ddbe1cf3c1362e1b95aee14的度数是(   )

@@@818b71c7-8767-4553-9701-9b470d12af95

A.eqIdd36581140ebac5d28438ea63b1b23b65 B.eqId2fb94bd9eb80fb9f5f02f518bb8f2211 C.eqIdad36099d4f257b472895e2c5209ea286 D.eqIdbe6a6301878fed2a01413020b27310a5

7.若eqIdd5b69d40b75d582c4b8ffa2369af1d41 与 eqId9d57899ad4774aed9ccc7bd23db72153 相等且互补,eqId605f2976297a0deaa1602ef09d6a5afa与eqId9d57899ad4774aed9ccc7bd23db72153是对顶角,则eqId605f2976297a0deaa1602ef09d6a5afa的一半是(    )

A.eqIdf6b86c22b670a8e9f3896f9e8883fbbb  B.eqId79a97bb4dcfab4ec7539bc783d563c49  C.eqIdbe6a6301878fed2a01413020b27310a5  D.eqId391479c151307826c9765a47a5f10503

8.若两条直线相交所成的四个角中,有两个角分别是eqId5fac819fa15b441d3bf4a519f45cefb5和eqId794dd52563aea9b9deca8e8afd37e122,则x为(   )

A.40 B.80 C.40或80 D.60

9.如图,eqId1dde8112e8eb968fd042418dd632759e为直线eqIdb79dd200766db27fb90d6bd1992cf658上一点,eqIdd8cc88685997c7586d1d4bf75a055433,OE平分eqId9fed1f57a835af4e9022e27603d12d31,OG平分eqIdd22df2977de56cc69be0c1e847653d7a,OF平分eqIddc9f91270ddbe1cf3c1362e1b95aee14,下列结论:①eqId091f651d3a16b77ec8f154035995d2d9;②eqId4cbee6d5731d6f4bb1e4f2ba3d89b7dc与eqId843adec8fba1741ccb81a9017cfb815f互补;③eqId506a911b6ce256f767b37a5f08c82e87;④eqIdc67e4dd4663f098638fc9cf2bb05b140,其中正确的有(  )

@@@9fce9a0d-1846-410a-9d49-0324c1c0a0b1

A.①②③ B.①②④ C.①③④ D.①②③④

 

二、填空题

10.泰勒斯被誉为古希腊及西方第一个自然科学家和哲学家,“两条直线相交,对顶角相等”page number 1

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就是泰勒斯首次发现并论证的.如图,七年级数学课堂上论证“对顶角相等”时,进行了如下推理:因为eqId1d1717b5311ed602f1730e86d9322647,eqIddf4d67aa2a39c15abaa0cbc09432f1fb,所以eqIde50ce9ef89a466df68124a1dccff5663.其中,得出eqIde50ce9ef89a466df68124a1dccff5663使用的依据是      .

@@@a8e3dbc3-2733-4ad6-9ad2-84f40d45e5e2

11.如图,直线eqId31675fb9b93a97d1253c7d1cb537a764交于点O,射线eqId37a0397c811fe80c80ecd5b871201987平分eqId9fed1f57a835af4e9022e27603d12d31,eqId75c6c9189ed2a22089c12e0093949aeb,则eqId4c9de708d1544ebe0b82e7e6e2102382的度数为      .

@@@1a83b2ae-a955-4513-b0f2-96fc9805bf3a

12.若eqId780d8fd6c6c1deeeb45e15f639719e02与eqId15417741fba20d681ab4414b07339099是对顶角,eqId780d8fd6c6c1deeeb45e15f639719e02的补角是eqIda6c0927afc571a7c966c98192040979e,则eqId15417741fba20d681ab4414b07339099的余角的度数为          .

13.如果两条直线相交形成的四个角中,较大的角度为eqIdcef5188670b78eecf710cdf8d080462f,那么这两条直线的夹角是      度.

14.如图,直线eqIdf52a58fbaf4fea03567e88a9f0f6e37e、eqId9d78abbad68bbbf12af10cd40ef4c353相交于点eqId1dde8112e8eb968fd042418dd632759e.已知eqId5314ff3271c227f25ea513fa489fb375,eqIda299d2b999568e80be8005565ba209a4把eqId9fed1f57a835af4e9022e27603d12d31分成两个角,且eqIdd1861d52204ad36b1aa26e4ce1a995f0,将射线eqIda299d2b999568e80be8005565ba209a4绕点eqId1dde8112e8eb968fd042418dd632759e逆时针旋转角eqId335c1d4db7d83b1271c2d6ff87a24b6f到eqId6cad4595d5352b2884568a59d8d766a4,若eqId5bf4f48dc6647ecdaa62da83f099c678时,eqIde170f206fdbbd834aad7580c727e2cc6的度数是           eqId83873a9d782f2588c5eedbfe73f9bc2f.

@@@7c71ab30-c434-415a-9692-40e19e325147

15.已知直线eqIdb5c4cd264c97c1f261229925cc5a6761相交于点eqId1dde8112e8eb968fd042418dd632759e,点eqId2a30f3a8b673cc28bd90c50cf1a35281在eqId42e7b8a59f8d66176463f3d71f882a26内部,作射线eqIda299d2b999568e80be8005565ba209a4.

@@@07cc023f-46ff-43e0-96a6-424b5b24a119

(1)如图①,eqId72bbf7218e8ea804f152815d38a685ce,则eqId021bc0ff7e36c9d6d70ddd2e51e8c04c       eqId83873a9d782f2588c5eedbfe73f9bc2f;eqId4741d75d168a29c433a76d177deb8583       eqId83873a9d782f2588c5eedbfe73f9bc2f;page number 2

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