2.5有理数的乘法与除法(3)同步练习2025-2026学年苏科版数学七年级上册

| 12页
| 62人阅读
| 2人下载

2.5有理数的乘法与除法(3)同步练习

1.计算eqIdf40859a0452857dc7a79b7026a8f94c1的结果等于(   )

A.eqId81fb134b2b48acc99213fff6ccfee65f B.3 C.eqIdf30d314a642667fef559032264647366 D.eqId4dac452fbb5ef6dd653e7fbbef639484

2.下面算式错误的是(  )

A.eqId283a817c012809099736bdb4bfc03582 B.eqIdb6225aea547aab9c2fb97f64e8bc7982

C.eqId14c6762a35f45f78d9873d699bc9e40c D.eqId1cb64cd71c683aa05318c855a9b9e050

3.实数a,b在数轴上的位置如图所示,下列结论正确的是(    )

@@@23c1c1a1-06a6-4018-a92f-892e9e61db8c

A.eqIdbd039882414ced3cd59d7a4d5ec76f35 B.eqIdc07e06bc34732528a4a765458fd0e193

C.eqId51c42a01a86c30cc7ef326f4ea2dabf3 D.eqId99e25e52343ede4373bc599876cce2fb

4.若eqId2337a014613815d22747aa98f19b5297,则“eqId895c0c7fd9c7ec3c84de9f32d0ad985c”内应填的实数是(    )

A.eqId274a9dc37509f01c2606fb3086a46f4f B.eqId3389f53711264b0acba3ba6019f8b908 C.eqIdf89eef3148f2d4d09379767b4af69132 D.2

5.根据有理数除法法则,计算eqId0f382b9ee8f1ef379fd67503a62493e1过程正确的是(   )

A.eqId5ec42f6f0172f5614181a864f8846e67 B.eqId6bb88dc6b48cf31ed62caf212e3ead7d C.eqIdc6f3b7cf31f4ff1d37fc61d8b040203c D.eqIdffb40fd4a04a3018475e9af81239549e

6.用运算符号“eqId4d4cd9a7068de096606d1ab991f5e6da、eqId4bfc339cf6dd66599db64fa3fa44e608、eqId2468403b3eba9e40bfa36f464e927738、eqId09052719a6d55df23d74d8e3956257ea”填入“□”中,运算eqIddfda5c2e2a5a25a9c4a6c6d5ab19600d结果最大是(    )

A.eqIdd13ce3ebd1112220c639562739f1f9d1 B.eqId01317332a203c898536b1d0459f51d23 C.5 D.6

7.我们规定eqIde46f0a53b974a67679c31d84ec14412f,则eqId8946f7622d3a7371ec019e68098741ae(   )

A.eqIdacbc6a613224461ade69362d46550474 B.1 C.eqIdc7eb3b5ab19d97f6c7df36294ccc3674 D.eqIdd33adb74906403b0b00fcbd9fa691d8b

8.已知eqId4fc0442b276aefefadb3f1e6397a1b15,且eqId2b21208364124b5c477b2ff8df1c2e8f,则eqIdd4e7bf9200b351a259ddfc6c0266129d的值是(   )

A.6 B.eqId39fa8414146b94d4b04cd4ca6f4ef93c C.eqId5e6486784415f3537c9a13556c05d893 D.eqIda8101b5248dac98505d53248879bae30

9.某同学在计算eqId6f3afeeee11e2b54d7b84a1073349b6c时,误将“eqId09052719a6d55df23d74d8e3956257ea”看成“+”而算得结果是eqId81fb134b2b48acc99213fff6ccfee65f,则eqId6f3afeeee11e2b54d7b84a1073349b6c的正确结果page number 0

 

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


是     .

10.若eqId0b916db65bdc27c65ff9f13bf9ebe789,eqId24f11f9a566e6976ce6044000a7540f1,eqId611b888fda081f18075b7dd1b6e813d8,则a,b,c的大小关系是       .

11.在数字6、eqId3edbd40e04e2a943051fa83d6e511add、5、1、eqId274a9dc37509f01c2606fb3086a46f4f中抽取两个数相除,所得的商最小是      .

12.计算:eqId966f441cbe6eccebf7dcd52d08d9cf32

 

 

13.计算:

(1)eqIdde2edf9029692a808541e2c3868651ec;                       (2)eqIdf163d7299b96c2a58cea2f9d8ffc8285;

 

 

(3)  eqId95b5424c947f533ddb60bd78d26e3a78;                       (4)eqIdba92c3f1bc6fd7f3fc1f1eeb5a889121.

 

 

14.计算:eqIdc22f8fb6d9f597fd37032c1170ff9dce.

 

 

15.计算:

(1)eqId88b40cd070c8df8666ba66f90a232d31;                    (2)eqId346a16350bf7c312aef329da79b542aa.

 

 

 

16.阅读下列材料:

计算:eqIdd0a2ebf70c134509fd4e6542213a7613

解法一:原式eqId07005923947d995eaa7aef6953c90fe0page number 1

 

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


解法二:原式eqId0e16ee1bc40b469639ac01d5fa145b8f

解法三:原式的倒数eqId30e28679403e9fb41091b89fb4c70620

所以原式eqId02c55abb63905eff674ece37c47632d2

(1)上述得到的结果不同,你认为解法 是错误的

(2)请你选择合适的解法计算:eqId891d6f24771cfc6d88fb9a8053289d7c

 

 

 

 

17. “分类讨论”是一种重要数学思想方法,下面是运用分类讨论的数学思想解问题的过程,请仔细阅读,并解答题目后提出的两个问题.

例:三个有理数a,b,c满足eqId73c21bd0bd90a89b7ff5ac0eacf612a5,求eqId61787354fdcb8a3daa0235f736e08e30的值.

解:由题意得:a,b,c三个有理数都为正数或其中一个为正数,另两个为负数.

①当a,b,c都是正数,即eqId94440d3e4c073f94f2b266ff99d50e74,eqId67ca5fd57c2c2fcc3c7a574fdd1467d9,eqId8cec12441802f71e803efaf2c62ee588时,

则:eqIdeaf5fa06d81677ce21cb27f4185fb6df;

②当a,b,c有一个为正数,另两个为负数时,不妨设eqId94440d3e4c073f94f2b266ff99d50e74,eqIde3a915c1a8a9304aeb307d130faaeb15,eqIdf75807858b7804a1ad2039c41f323a18,

则:eqIdfcc1daacf5f5ded90c3f11f05ce2c893,

综上述:eqId61787354fdcb8a3daa0235f736e08e30的值为3或eqIdacbc6a613224461ade69362d46550474.

请运用分类讨论的数学思想方法解答下面的问题:

(1)已知a,b是有理数,当eqId9eae9ba258299eb489b490594397e23c时,求eqIdf915ea63b69f1bcddbd60c350bdcd6e2值.

(2)已知a,b,c是有理数,eqId9e56f4504e0f80fd031c8b5f41832e03,eqId73c21bd0bd90a89b7ff5ac0eacf612a5,求eqIdccc396b18994077ea05d392c24395cff的值.

 

 

page number 2

 

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


由于学科网是一个信息分享及获取的平台,不确保部分用户上传资料的 来源及知识产权归属。如您发现相关资料侵犯您的合法权益,请联系学科网,我们核实后将及时进行处理。