第二章一元二次函数、方程和不等式专练【六大考点】-2025-2026学年高一数学上学期人教A版必修第一册

| 10页
| 163人阅读
| 0人下载
知识分享小店
进店逛逛

第二章一元二次函数、方程和不等式【六大考点】

2025-2026学年高一数学上学期人教A版2019必修第一册

考点导航

【考点一】作差法比较不等式大小

【考点二】由已知条件判断不等式是否成立

【考点三】由基本不等式求和的最大值

【考点四】由基本不等式求和的最小值

【考点五】基本不等式1的求值问题

【考点六】二次函数与一元二次方程、不等式

 

跟踪训练

【考点一】作差法比较不等式大小

单选题

1.若eqId947f01e7b7ddc07f84d112b706815239,eqId5d5cae5b24aff2697ed3c90fc7cbc9e5,则(    )

A.eqIdc6a46e678bf9d2df5ad4c782b3dc22f5 B.eqId3798d6c2e5eac9c1d8b044efd5081acf C.eqId432d77fe5ad3032d59a237dd94c8a638 D.eqId1132de2e8913dba9c5cc2396ecb09fcf

2.已知eqId4229ff635926a635340df51dc6a0eec4,则eqIdac047e91852b91af639feec23a9598b2与eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3大小关系是(    )

A.eqId9f8f97cf2fc2d0676d6df01ff9759611 B.eqId1ba84caf91202df9aca6302e6860f82e

C.eqId6208895c0e3f31fcc437d2dfc5d18b9e D.eqId0c3e9740f1cdda4ee24958381be9117f

3.已知eqId2c94bb12cee76221e13f9ef955b0aab1克糖水中含有eqId0a6936d370d6a238a608ca56f87198de克糖(eqId2d100c22435a23e017cfe6f535379d3c),再添加eqId294f5ba74cdf695fc9a8a8e52f421328克糖(eqId58b140e221ddf537b8964fff8557cca0,假设全部溶解),糖水变甜了,将这一事实表示为一个不等式(    )

A.eqIdf57c5d9f81a99471e74b7bc4eb06291d B.eqId1771553568f7bf99c367f06754d708cc

C.eqId8009298a2cfffe742a7f7a072471cb01 D.eqId4e943e44d51de25b3e47c62ac7493cbd

4.两人共同参加一个游戏,游戏规则如下:其中一人在集合eqId209f058a1784e1404d160cbce95c9302(eqId08115d6d9f876dea921a4d32260ff1fb,eqId061813f1ec633c5c4c393c4de7938322且eqIda11a069688e4c797fcf527eab15afa82)中任取2个元素并求和,剩下2个元素给另一个人并求和,和大者为胜.则先取者取下列哪2个元素能够保证先取者必胜(    )

A.eqIdd800f03de80068a1172beac3a2c75587,eqId1084e900dbaa663060019c3723d74d3b B.eqIdd800f03de80068a1172beac3a2c75587,eqId69f9277e5bbe16c4a6f220bae0039b33 C.eqIdd800f03de80068a1172beac3a2c75587,eqId02d8026e7e56b5a88c2bb9347c9d204d D.eqId1084e900dbaa663060019c3723d74d3b,eqId69f9277e5bbe16c4a6f220bae0039b33

【考点二】由已知条件判断不等式是否成立

5.若a>b,c>d,则(   )

A.eqId3c22b9d08cf536bbb76bce1b0f135772 B.a-c>b-d

C.a-d>b-c D.ac>bd

6.已知eqIdbaca30d4248a82988890bd032d159b25且eqId432d77fe5ad3032d59a237dd94c8a638,则下列不等式一定成立的是(    )

A.eqId0cb54b1b3617ebc502cb44194cbcd1dc B.eqId26f7c54faca6eac8af5309942062058d

C.eqIdd3af1ae042c55e9a09d4ef1fbecb49fa D.eqId681f8d91b64433d0cb2a1b5bc14b1d0b

7.若eqIdbaca30d4248a82988890bd032d159b25,则下列命题正确的是(   )

A.若eqIdc6a46e678bf9d2df5ad4c782b3dc22f5,则eqId1b0a0d270919adc01448dc0441bb946f B.若eqId3c22b9d08cf536bbb76bce1b0f135772,则eqId432d77fe5ad3032d59a237dd94c8a638

C.若eqId7aa8950fa963eedb948d6a57871478cc,那么eqId522ea2b031666780e551b93fe8ca4cff D.若eqId5a0c4c098615c6bc7e6dcf72e5b5201a,则eqIde1a4044632f02f68d0e94fa859701d04

8.已知eqId497d269c30eec393e3f0e877ddbe2983,则(   )

A.eqId66f00cfcbd5f96bab94e532a2e79204e B.eqId906e97540d6920dc910fbaa11bb78616 C.eqIdf781c98463b67a7c4520078a1c13698d D.eqId13132d3a1cd28b08273a46bf7473973c

【考点三】由基本不等式求和的最大值

9.已知eqId16e482dd69ac1cf7f06552fdf25a217c,则eqId8ae47008eb71803df928ae0855009467取最大值时eqId81dea63b8ce3e51adf66cf7b9982a248的值为(    )

A.1 B.eqIdc34e01955f8c8fe2f0041b35d8d602a7 C.eqIdcf298f00799cbf34b4db26f5f63af92f D.eqId40822dc70f1fbe57e09b4bf918c8ffa7

10.已知eqId08115d6d9f876dea921a4d32260ff1fb,则eqId0b909fb303838806743aa4ee42c0d6d9的最大值为(   )

A.0 B.1 C.2 D.3

11.已知eqId7326ea56be82bd616fec7e6aa3c884c8,若eqIde3bea0b189624762514410b65e5f2ad3恒成立,则实数eqId2c94bb12cee76221e13f9ef955b0aab1的取值范围为(   )

A.eqId27d07eba2026e5e216922bf41f61a27d B.eqId6f5050979ea2cc2f157b81cda8470872 C.eqIdafa482d7bcaa385bfc3548b42a4bfb60 D.eqIded1a65d88f9823d49da8f3b96ea9ec6f

12.已知eqId05105dedcaa0c71dae06729996a4e77a,则eqId18f0281e6bbdbe08beeccb55adf84536的最大值为(    )

A.eqId8b2a698891d42c70b597f0da4f215f09 B.eqIda4b8503f4706b8321e4e79a87eadea84 C.eqId533a7b702ada1dd80123e4041271d521 D.3

【考点四】由基本不等式求和的最小值

13.已知eqId5e02fa0e0fe2363c0e2b4df46a60ba32,则eqId56e429ab022bfd118b598598ad26f97f的最小值为      .page number 0

第1页 共2页          ◎          第2页 共2页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


14.已知eqId1a14c388e1e2e5a2ff1ccf6caffbee0d均为正数,则eqId62b67971d1ecbf64e25e9df6bab4a027的最小值为      .

15.已知eqIdbba2cbab39c33dc800c6b970c69b5c58,则eqIdd7caf4941cec03d0730041ba6bf7c14e的最小值为      .

16.若正数eqId15a75358a62ded39903d5fe67eb14f53满足eqIdb8d65e4902acac49cf0cfb53587354a0,且eqId6f29d5f376c75c41ae6af0c8a8565449的最小值是16,则eqId0a6936d370d6a238a608ca56f87198de的值为      .

【考点五】基本不等式1的求值问题

17.已知eqId94440d3e4c073f94f2b266ff99d50e74,eqId67ca5fd57c2c2fcc3c7a574fdd1467d9,且eqId3de6fcb38854c3d2dd97be5793c61952.

(1)求eqId18f0281e6bbdbe08beeccb55adf84536的最小值;

(2)证明:eqId16237160b44f2be61b244314ea663fe1.

18.已知eqId69ee6696dee035519e1ba7fb78269830满足eqIdda4611011375960ede327251150729f7.

(1)求eqId9801c685f18870a41612ee2520a34bdd的最小值;

(2)若eqIdbca2a639ff931cbb3cb009eeb05c8cc7恒成立,求eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围.

19.已知正数eqId81dea63b8ce3e51adf66cf7b9982a248、eqIdd053b14c8588eee2acbbe44fc37a6886满足eqIdb45900deae0489e87fe448948e8091c4.

(1)求eqId6f29d5f376c75c41ae6af0c8a8565449的最大值;

(2)求eqIdcd31dc2d0967db352574381d66d33fc0的最小值.

20.已知eqIdd7561672145e37fe20547e2f24baff6a,求证:

(1)eqId2129e8ec4f374ae282fb9785461a64c7;

(2)eqId978d9541cfb6588638b1b371db89248d.

【考点六】二次函数与一元二次方程、不等式

21.已知二次函数eqId51b245a740a439a6d5fedeba7e2e0d7a.

(1)若eqIda71baf6217604517fd98fa97d0f55b43的解集为eqId437c2f42c458dc35f46193e303febf00,分别求a,b的值;

(2)解关于x的不等式eqId70d5caeed374d705a39e564872a24717.

22.已知函数eqIdd3d26e75e0fbd30738447c91a15e119f.

(1)当eqIdcf0086b054ef120408acac806a1b1318时,求不等式eqIdd462ed4ec22e8fe51f09eb30e8792532的解集;

(2)求不等式eqIdd462ed4ec22e8fe51f09eb30e8792532的解集;

(3)若不等式eqIdd462ed4ec22e8fe51f09eb30e8792532的解集中恰有三个整数解,求实数eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围.

23.不等式eqId4b6d03dfc5b4ce38e17403b3b49fdc15对一切实数eqId81dea63b8ce3e51adf66cf7b9982a248恒成立的eqIdf0a532e15e232cb4b99a8d4d07c89575的取值集合为eqId5963abe8f421bd99a2aaa94831a951e9,集合eqId001213ef7e78dd70c3aeecaa814bc15c.

(1)求集合eqId5963abe8f421bd99a2aaa94831a951e9;

(2)若“eqId6ed006b944ea64f970fee46e2f558467”是“eqIde23af61cd402b3789af2401bde9cbefe”的充分条件,求实数eqId294f5ba74cdf695fc9a8a8e52f421328的取值范围.

24.定义关于eqId9b0fffbec1fe851795dfdd448bf0d165的新运算:eqIdaa1a37567a7bc540d7e0a97fbe934f19,其中eqIdfacb614b80fe55a92062092617eff633,eqId632244ea6931507f8656e1cc3437d392为非零常数.

(1)当eqId7c8b43558e99a0a04f6cd28f10caded9,eqId4ad277c33752b5d7cb6cf8bd15119a29时,求eqId632244ea6931507f8656e1cc3437d392的值;

(2)当eqId52addf4882f63a7215632bf4109d9bc8时,求不等式组eqId7fbf0026fcfa2a2de5166223636328ab的解集.

page number 1

第3页 共2页          ◎          第4页 共2页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


 

学科网 zxxk.com学科网 zxxk.com

《2025-2026学年高一数学上学期人教A版2019必修第一册第二章一元二次函数、方程和不等式【六大考点】》参考答案

题号

1

2

3

4

5

6

7

8

9

10

答案

C

C

D

C

C

D

B

C

C

C

题号

11

12

 

 

 

 

 

 

 

 

答案

A

B

 

 

 

 

 

 

 

 

 

1.C

【分析】利用作差法可得出eqId632244ea6931507f8656e1cc3437d392的大小关系.

【详解】因为eqId169ed0ec07eee65b9834898bba91a006,所以eqId432d77fe5ad3032d59a237dd94c8a638.

故选:C.

2.C

【分析】利用作差比较法求解.

【详解】因为eqIdbf6661e97c8d23449d439f96cddc0999,

所以eqId6208895c0e3f31fcc437d2dfc5d18b9e.

故选:C.

3.D

【分析】糖水变甜,表示糖的浓度变大,即eqId4e943e44d51de25b3e47c62ac7493cbd.

【详解】这一事实表示为一个不等式为eqId4e943e44d51de25b3e47c62ac7493cbd.

证明:eqIdac64ad0a3579c38eb82e2a2a595fe029,eqId58b140e221ddf537b8964fff8557cca0

eqIdeaf63b55ae438a093920adaba129ce5b

eqId1e1036936144dfc1601ca00ca9d1023a

又eqIdac64ad0a3579c38eb82e2a2a595fe029,eqId58b140e221ddf537b8964fff8557cca0,

eqId90ccea72b158136e29b8126adaf3274f,eqId0c2350a63e3856f837413a45ff007c25即eqId09cae6ea09fada99f6be81a6f35d80d1,

eqIda3c22a98c8f2fa3da8c42383adf83ba1即eqId4e943e44d51de25b3e47c62ac7493cbd.

故选:eqId1f0b669ef4514f24ee09adeff7f41238

4.C

【分析】利用作差法逐项判断.

【详解】若先取者取eqIdd800f03de80068a1172beac3a2c75587和eqId1084e900dbaa663060019c3723d74d3b,

则eqId88aa59b7f4c2251803846bdd86424b18,

根据eqId08115d6d9f876dea921a4d32260ff1fb,eqId061813f1ec633c5c4c393c4de7938322且eqIda11a069688e4c797fcf527eab15afa82,不能确定大小关系,A错误;

若先取者取eqIdd800f03de80068a1172beac3a2c75587和eqId69f9277e5bbe16c4a6f220bae0039b33,

则eqId2e50aaf12cfc197bf641cab16ff85e82,

根据eqId08115d6d9f876dea921a4d32260ff1fb,eqId061813f1ec633c5c4c393c4de7938322且eqIda11a069688e4c797fcf527eab15afa82,不能确定大小关系,B错误;

若先取者取eqIdd800f03de80068a1172beac3a2c75587和eqId02d8026e7e56b5a88c2bb9347c9d204d,

则eqIdc8a6111456d097e089c921e3b39a24b3page number 2

答案第1页,共1页

学科网 zxxk.com学科网 zxxk.com学科网(北京)股份有限公司


由于学科网是一个信息分享及获取的平台,不确保部分用户上传资料的 来源及知识产权归属。如您发现相关资料侵犯您的合法权益,请联系学科网,我们核实后将及时进行处理。