第九章平面直角坐标系含参问题 2024-2025学年人教版七年级数学下册

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新2024人教版七年级下册第九章平面直角坐标系含参问题

一、各象限坐标符号

1.在平面直角坐标系中,点eqIdaa39c785e9adf9ef1f97553ece0354fe一定在第      象限.

2.已知点eqIdaee82283f06cedef32eb15b87964f5d2在第三象限,且eqIdb2bf04745abf8e0bbfc2f2bc7bf39a32,则点eqIddad2a36927223bd70f426ba06aea4b45的坐标是(  )

A.eqId3e0b78171a4d834a3c1fd9a484bd2e2f B.eqIdbf6429442381aa4ee5cf39b972ede0a9 C.eqId601b6e8e0de5e22fb87f5ecac715c5e0 D.eqId120ad1042106887e2916cfe6fd174890

3.若第四象限内的点eqIdaee82283f06cedef32eb15b87964f5d2满足eqId342e44ab6b4cb9a16afa2804fad04d21,eqId1e6583f77adaadd380376a15ef1eabcd,则点P的坐标是      .

4.已知点eqIdeefeafbae284422e21fa16721f0b9839在第四象限,求a的取值范围.

 

 

 

 

二、在坐标轴上

1.在平面直角坐标系中,若点eqId2e166e296dba4c61f5474d3fde441d56在eqId81dea63b8ce3e51adf66cf7b9982a248轴上,则eqId0a6936d370d6a238a608ca56f87198de的值为(    )

A.eqIdbdaa19de263700a15fcf213d64a8cd57 B.eqIdc95b6be4554f03bf496092f1acdfbb89 C.eqId274a9dc37509f01c2606fb3086a46f4f D.eqId61128ab996360a038e6e64d82fcba004

2.点eqId957387ba74ea32c669433e60128b6eb1在直角坐标系的y轴上,则P点坐标为      .

3.在平面直角坐标系中,点eqIdd0e9ff047790909250f246df580c273e在x轴上,点eqIdf635b1a616942e3b5d00d348eeee3cfd在y轴上,则eqId8fd1f0ace9ca0b79929e73af6c201c2e的值为(   )

A.1 B.eqIdacbc6a613224461ade69362d46550474 C.3 D.eqId81fb134b2b48acc99213fff6ccfee65f

 

三、到坐标轴距离

1.在平面直角坐标系中,点M的坐标是eqIdb69abe959988e4c8c0739f5857ccfb0f,则点M到x轴的距离是      .

2.点eqIddad2a36927223bd70f426ba06aea4b45位于eqIdd053b14c8588eee2acbbe44fc37a6886轴左方,距eqIdd053b14c8588eee2acbbe44fc37a6886轴3个单位长度,位于eqId81dea63b8ce3e51adf66cf7b9982a248轴上方,距eqId81dea63b8ce3e51adf66cf7b9982a248轴4个单位长度,则点eqIddad2a36927223bd70f426ba06aea4b45的坐标为      .

3.在平面直角坐标系中,点eqId99c4c5dc238862aa41b4d127ec17df23到y轴的距离为2,则m的值为(     )

A.eqIdacbc6a613224461ade69362d46550474 B.3 C.3或eqIdacbc6a613224461ade69362d46550474 D.4

4.在平面直角坐标系中,若点eqIddad2a36927223bd70f426ba06aea4b45在第二象限,且点eqIddad2a36927223bd70f426ba06aea4b45到eqId81dea63b8ce3e51adf66cf7b9982a248轴的距离为4,到eqIdd053b14c8588eee2acbbe44fc37a6886轴的距离为2,则点eqIddad2a36927223bd70f426ba06aea4b45的坐标为(   )

A.eqIdcc1933c276d62d5018a5a465ea6d9dcb B.eqIdba3dfb53a7865e0ee8434f22ebb62de3 C.eqId721f31f7e1da07fc5f20ba1f624d24d7 D.eqId7049f74148ef34d0a0c564d0ca81e57dpage number 0

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5.在平面直角坐标系中,第三象限点eqId9c831f9f125c08472cad4e1986b01db0,且eqIddad2a36927223bd70f426ba06aea4b45到eqId81dea63b8ce3e51adf66cf7b9982a248轴的距离为eqIdb8860d9787671b53b1ab68b3d526f5ca,则点eqIddad2a36927223bd70f426ba06aea4b45的坐标是      .

6.已知第二象限的点P的坐标为eqId2a92528661487db77af340042e1b0126,且点P到两坐标轴的距离相等,则点P的坐标为(   )

A.eqIda195eea52ebe55bbc18cbd4b06a240c1 B.eqIdc7308b63b49d6c6f48e757b74635bac0 C.eqId455ba3d3e46977fcbe5b71f8bb9df4be D.eqIdcd97f6498211e30d01c2f092c1fbf54b

7.在平面直角坐标系中,有一点eqId78628d4f14d9985c07f05204747feda0.若点eqIdac047e91852b91af639feec23a9598b2在第二象限,且到两坐标轴的距离之和为5,求点eqIdac047e91852b91af639feec23a9598b2的坐标.

 

 

 

 

 

 

四、平行坐标轴

1.已知eqIddc195a9f7ac138e5a1ad87d5fa201c49轴,且点A的坐标为eqId785449314b0bde3ea8bf79f9bd698390,点B的坐标为eqIdad42625f296d2a4b65180e2f7b776beb,则点A的坐标为(   )

A.eqId1c39c16d3c056a9627afbc9501e3f8b1 B.eqId0ccc7cac1ecfc77a334412e721878482 C.eqId643bd4262ef926c64e1ab83a3e63e5a4 D.eqId3654254401fc902c3cb4912969f21f88

2.已知线段eqId13ecbb94ac8dfe5fbc3bffad8c9da301轴,点eqId5963abe8f421bd99a2aaa94831a951e9的坐标为eqId91ebb41fcb09f9d9024e7c7af6df532b,点eqId7f9e8449aad35c5d840a3395ea86df6d的坐标为eqIdc6e5d092a665c0b7542fb290e1aa6b6a,则eqId0f3cb8d72bb2e281b943b3b430138ef7      .

3.在平面直角坐标系中,已知点eqId351bdbdcaf6ee0e13ac0d7af9c67921d,点eqId5963abe8f421bd99a2aaa94831a951e9在第二象限,eqId340f0e34fb3926f27f26ca9811ef5e37轴,eqId00bab2c27eac56fffa4cd7dbe1dcdf1a,则点A的坐标为          .

4.已知点A坐标为eqId916f60ddfffd05dde1c297170b7ca20c,若eqId24624dffd30b66a5e4de57362b32b2a3轴且eqId3d2c15801fee2405573677484f5dcfa4,则第二象限的点B的坐标为      .

5.已知点eqIdf097f96f53bdf4dead0648faf2645170,若点Q满足eqId24f27083267432a9352fb6677a07d461轴,点Q的横坐标是3,且eqId57a2d7742a001efebcb78fc5504be8e8,求点Q的坐标.

 

 

 

 

 

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平面直角坐标系含参问题解析

一、各象限坐标符号

1.在平面直角坐标系中,点eqIdaa39c785e9adf9ef1f97553ece0354fe一定在第      象限.

【答案】一

【详解】解:∵eqId9d2f98894ba7fd1d72071cabe0e11896,

∴在平面直角坐标系中,点eqIdaa39c785e9adf9ef1f97553ece0354fe一定在第一象限,

故答案为:一.

2.已知点eqIdaee82283f06cedef32eb15b87964f5d2在第三象限,且eqIdb2bf04745abf8e0bbfc2f2bc7bf39a32,则点eqIddad2a36927223bd70f426ba06aea4b45的坐标是(  )

A.eqId3e0b78171a4d834a3c1fd9a484bd2e2f B.eqIdbf6429442381aa4ee5cf39b972ede0a9 C.eqId601b6e8e0de5e22fb87f5ecac715c5e0 D.eqId120ad1042106887e2916cfe6fd174890

【答案】D

【详解】解:由题意,eqIde3f4fac6f8f68051a1dc1af39e94979e,

eqId5e36df8784e4aef325fc465812ea9621,eqIdeb1b20e2defce23fef84a27413d39edd,

又eqId2c77ccada074400aa8d24e9c2f0b5848在第三象限,

eqIdf7537db79ce179fe941d5331974d5317,eqId9b27aee52676f4237adac068fe745fde,

eqId2de0d10ef8b748d4531250c37c5d3f9e点eqIddad2a36927223bd70f426ba06aea4b45的坐标为eqId120ad1042106887e2916cfe6fd174890

故选:D.

3.若第四象限内的点eqIdaee82283f06cedef32eb15b87964f5d2满足eqId342e44ab6b4cb9a16afa2804fad04d21,eqId1e6583f77adaadd380376a15ef1eabcd,则点P的坐标是      .

【答案】eqIdbf6429442381aa4ee5cf39b972ede0a9

【详解】解:∵eqIdaee82283f06cedef32eb15b87964f5d2在第四象限

∴eqId08115d6d9f876dea921a4d32260ff1fb,eqIda57458464618fcf619375a93d3c66d69

∵eqId342e44ab6b4cb9a16afa2804fad04d21

∴eqIdda322ac8867e8a47c6588601078abf18或eqId99c6875d552e9fff3c7d655f3a59b166(舍去)

∵eqId1e6583f77adaadd380376a15ef1eabcd

∴eqIdc9355031ea0b2dc9cef3777621bc6d38(舍去)或eqId9b27aee52676f4237adac068fe745fdepage number 2

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