2025年九年级中考数学学业水平考解答题复习-旋转综合题(角度问题)

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2025年九年级中考数学学业水平考解答题复习-旋转综合题(角度问题)

1.已知eqIde428e7a09732be85c1224e9c8f6a71c5是等腰三角形,eqId10e493085e3d0d3b36270a264eb7b511,将eqIde428e7a09732be85c1224e9c8f6a71c5绕点B逆时针旋转得到eqId601844bbcc81bfacb796d315e6aa5204,

@@@a9dd2d09-b175-491e-9fa2-90a7b78c2f97

(1)感知:如图①,当eqId5d21047e6fdc1d6dd7c9f3e1d5c16b5c落在AB边上时,eqId2bf26aeaed71ef5d2d663b226c844ad5与eqId5c6d76998b8044d6bf098eb48ceaf011之间的数量关系是 (不需要证明);

(2)探究:如图②,当eqId5d21047e6fdc1d6dd7c9f3e1d5c16b5c不落在AB边上时,eqId71ad82b53030ae05b22824dcbffe07e5AB与eqId5c6d76998b8044d6bf098eb48ceaf011是否相等?如果相等;如果不相等,请说明理由;

(3)应用:如图③,若eqId4300aefd67369742e2b1ddcdc02dd495,eqId864c8d02bccb89a4b916efc680bfcf84、eqIdc3857b48615cbf9be53c4c885e908824交于点E,则eqIde8377f89ed7b8840f4e888f16226e279  度.

2.如图,已知eqId15c0dbe3c080c4c4636c64803e5c1f76为等腰直角三角形,eqId9c06154cae3bf7a8ce5a1e97a7380875,eqId047dc9795efa99b6fb9fdf9778085dab,点D、E分别为边eqIdf52a58fbaf4fea03567e88a9f0f6e37e、eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的一动点(且满足eqId282456474dfbc7bbd237c04fd93d9740),连接eqIde6e490f703eb6c9bb1278c78ebc2d661,将线段eqIde6e490f703eb6c9bb1278c78ebc2d661绕点D逆时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到线段eqIdd004d2d115b477ade6af7ddb93db0df8,连接eqId49b50357a6545cae8348e3059312f520、eqId274cf35acb4a1748d15c39d15a9bea7b.

@@@82a6718c-6718-466a-b31e-25fe675f8aa1

(1)如图1,当点D与点A重合时,求证:①eqId533f1f6ead0d794bb7c70cce9173d4a5;②eqId740543d6aeac697a5f64fdecc5805ae4;

(2)如图2,当点D与点A不重合时,结论eqId740543d6aeac697a5f64fdecc5805ae4是否仍然成立?请说明理由:

(3)如图3,在(2)的条件下,过点D作eqIdecf66bee4cb286d06b4f25ede08a6db4,垂足为M.试探究线段eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqId274cf35acb4a1748d15c39d15a9bea7b、eqId907d5147cea4c9ce855074864fe54506之间的数量关系,并证明你的结论.

3.已知:如图,点eqIdc5db41a1f31d6baee7c69990811edb9f为直线eqId411461db15ee8086332c531e086c40c7上的一点,点eqId7f9e8449aad35c5d840a3395ea86df6d为直线eqId411461db15ee8086332c531e086c40c7外一点,将线段eqId6b1bd1adfe4cc6566218f19970c2fd3b绕点eqIdc5db41a1f31d6baee7c69990811edb9f顺时针旋转eqIdbe6a6301878fed2a01413020b27310a5后得eqId9abaeba15f3abdd877bc701af52c5cd9,连接eqIdf52a58fbaf4fea03567e88a9f0f6e37e,过点eqId5963abe8f421bd99a2aaa94831a951e9作eqIdfdf23e73ae2a15c04bbed3981cb8e511,垂足为点eqIda0ed1ec316bc54c37c4286c208f55667,eqIdb400a6c61254b81d4ccc5a2a7cf4c967的平分线交eqId0dc5c9827dfd0be5a9c85962d6ccbfb1于点eqIddad2a36927223bd70f426ba06aea4b45,交eqId45aa9dc428cdd15252b9378fe07b8baf的平分线于点eqId2a30f3a8b673cc28bd90c50cf1a35281,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55.page number 0

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@@@aa4bf4f3-bde2-4a7c-88e7-f703464dfff9

(1)当eqId67662c47e2dfa08001a62fa17320f477,

①求eqId4598486f8c5ac28b1165b76e78105979的度数;

②证明eqIde7393d6ab4663b9c23080c0f007bff63.

(2)将eqId15c0dbe3c080c4c4636c64803e5c1f76绕点eqIdc5db41a1f31d6baee7c69990811edb9f旋转,当eqIdec6411702a396af7b9511d92762a9db5为等腰三角形时,直接写出eqId4598486f8c5ac28b1165b76e78105979的度数.

4.综合与实践.

【问题初探】(1)如图eqIdbdaa19de263700a15fcf213d64a8cd57,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9673cb91a7efbc4abaa7124ab986bf1e,eqId07160f14b3b453bebb64cb2bf96dc85a,eqIdd40b319212a7e7528b053e1c7097e966为eqId60ef95894ceebaf236170e8832dcf7e3边上的中线,求eqIdd40b319212a7e7528b053e1c7097e966的取值范围.解答这个问题,我们可以将eqIdab2a2834d80ff574e79eae8ca8d4e94f绕点eqId8455657dde27aabe6adb7b188e031c11旋转eqIdbfe639eab78eafd2d40ea70aa5d3f21d,得到eqIdecd75c2244c18120b8fc35d5d309ab66,则eqIdd40b319212a7e7528b053e1c7097e966的取值范围可解.请作出eqIdecd75c2244c18120b8fc35d5d309ab66并直接写出eqIdd40b319212a7e7528b053e1c7097e966的取值范围;

【问题解决】(2)如图eqId61128ab996360a038e6e64d82fcba004,eqIddad2a36927223bd70f426ba06aea4b45为等边三角形内一点,满足eqId9d3fcba360d97fb1fabd96a7ad9384fb,eqId364d6c88726d8c3bb8ed297057332bac,eqId9641d01140939c44450bf39773272af6,试求eqId93b1d3ba8a6c2acb3540714e99481f8e的大小(提示:将eqIde08b395fcd6ac97b243d81ffa189fac3绕点eqId7f9e8449aad35c5d840a3395ea86df6d顺时针旋转eqIdbe6a6301878fed2a01413020b27310a5);

【问题拓展】(3)如图eqId5ca7d1107389675d32b56ec097464c14,在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2a30f3a8b673cc28bd90c50cf1a35281,eqIda0ed1ec316bc54c37c4286c208f55667分别为eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId9d78abbad68bbbf12af10cd40ef4c353边上的点,且满足eqId192155e6a3aade305b76b1eb7c75e30c,eqIdfcd0ced286a0fbc7e4862f8147264277,eqId5ed96dea1e8d1dcf68cf57694808b008,求eqId4c105d6ba18fbb0581fb982175e2eac9的面积.

@@@e1c5c4e8-ed5a-49b6-8386-5651fdd95bea

5.如图1,在Rt△ABC中,∠ACB=90°,AB=10,BC=6.D、E分别是AB、AC边的中点,连接DE.现将△ADE绕A点逆时针旋转,连接BD,CE并延长交于点F.page number 1

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@@@ea7021b5739e4dd1a1f7beb37449304c

(1)如图2,点E正好落在AB边上,CF与AD交于点P.

①求证:AE•AB=AD•AC;

②求BF的长;

(2)如图3,若AF恰好平分∠DAE,直接写出CE的长.

6.如图,抛物线eqIda90385c676848de67293e3ed6bc000fe经过点eqIda0929421a6188c3122442866b0b85a5e,点eqId08ef03f452410ab19c6246567c427178,点eqIdc052d7af2f98d95bac8725b608fba0fc,eqId8455657dde27aabe6adb7b188e031c11为抛物线的顶点.

@@@c6a8e0b7-9cec-4350-b4a9-7d56ec0ca606

(1)求抛物线的表达式;

(2)连接eqId60ef95894ceebaf236170e8832dcf7e3,eqIdac047e91852b91af639feec23a9598b2是平面内一点,将eqId173bc7a36757d77f01213411edd25241绕点eqIdac047e91852b91af639feec23a9598b2沿逆时针旋转90°后,得到eqId66f6a10633157469632a5618047757ba,点eqId1dde8112e8eb968fd042418dd632759e、eqId5963abe8f421bd99a2aaa94831a951e9,eqIdc5db41a1f31d6baee7c69990811edb9f对应的点分别是点eqId23f919bd3dde10dbbc076f7ec5149699,eqIda18722354086c42e62334983fc50eb6a、eqIdb1241216f3c1cb5e73043dd1037f556d,若eqId66f6a10633157469632a5618047757ba的两个顶点恰好落在抛物线上,求出点eqIdb1241216f3c1cb5e73043dd1037f556d的横坐标;

(3)在坐标平面内找一点eqIddad2a36927223bd70f426ba06aea4b45,使eqId4807ca16360c0cca436e59d4be98f626与eqId403d74859e7b8b4cebf40add6e92b0f8相似,且eqId8b4b5e0fee00844bb14864698ea64596,求出所有点eqIddad2a36927223bd70f426ba06aea4b45的坐标.

7.(1)模型探究:如图1,已知△ABC,以A为旋转中心将边AB顺时针旋转至AD,将边AC逆时针旋转至AE,旋转角均为α(0º<α<180º),连接BE,CD.

①请找出图中与BE相等的线段,并说明理由;

②△ABE可以认为是由△ADC经过怎样的变换得到的?page number 2

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