2025年九年级数学中考二轮复习 与轴对称相关的几何动态问题探究 解答题专题提升训练

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2025年九年级数学中考二轮复习《与轴对称相关的几何动态问题探究》解答题专题提升训练

1.已知eqId15c0dbe3c080c4c4636c64803e5c1f76是边长为6的等边三角形,eqId8455657dde27aabe6adb7b188e031c11是边eqId60ef95894ceebaf236170e8832dcf7e3上的动点(点eqId8455657dde27aabe6adb7b188e031c11不与点eqId6d37a5a3169cebebe61b99b2ba7eb829重合),以eqIdd40b319212a7e7528b053e1c7097e966为边作等边三角形eqId34be4e71cabf458f17a6cd7f24bc70af(点eqId2a30f3a8b673cc28bd90c50cf1a35281在eqIdf52a58fbaf4fea03567e88a9f0f6e37e的上方).

@@@72aa23fc-7482-40c7-8ebd-33e8345ea63d

(1)如图①,当eqId8455657dde27aabe6adb7b188e031c11为边eqId60ef95894ceebaf236170e8832dcf7e3的中点时,求证:eqIdbffd657e48b15b9b54a55817e2c26b22;

(2)如图②,连接eqId4eedae8d316c76e3d0b451256de03fb9,求证:eqId126fdae0b1adc7361f945187b861fb20;

(3)eqIda0ed1ec316bc54c37c4286c208f55667为边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,连接eqId49b50357a6545cae8348e3059312f520,当eqId30f662e4cf38298b85e32f48747ec34b取得最小值时,延长eqId85c4bdfb0db1e31e8459df1d15f9ab55与直线eqId60ef95894ceebaf236170e8832dcf7e3相交于点eqId895dc3dc3a6606ff487a4c4863e18509,求线段eqIdabf80148409afb32ced0b4f59f1ba709的长(直接写出结果即可).

2.在等腰直角三角形eqId7bef5239ddbb0972700ce01daf9ee7cf中,eqId45acdbac251ca6b76a166c1242e71df9,eqId1ffc2817fa590affb5a760a25dc65308,点eqId8455657dde27aabe6adb7b188e031c11为边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的一点,连接eqId03902478df1a55bc99703210bccab910,过点eqId5963abe8f421bd99a2aaa94831a951e9作eqIdb8b1472e121da0ae5550329cfda5f0a2,取eqIde30e50e094cd2849e38859b36aad0b0c,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,eqId4eedae8d316c76e3d0b451256de03fb9,eqId4eedae8d316c76e3d0b451256de03fb9与eqIdf52a58fbaf4fea03567e88a9f0f6e37e交于点eqIda0ed1ec316bc54c37c4286c208f55667.

@@@90ab123d-b8a6-41ed-831b-d83400063bc8

(1)如图1,若eqId615423de8cae2a76d73625352c46dbfe,求eqIde742966e3711cfa53dce04022acf4bcc的面积;

(2)如图2,求证:eqId57faa4f1b1f6a7203e14ae4385b477b9;

(3)如图3,若点eqId8455657dde27aabe6adb7b188e031c11为直线eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上一点,过点eqId2a30f3a8b673cc28bd90c50cf1a35281作eqIdc8c13ab7f17263c4e6163d960f1c5060于点eqId895dc3dc3a6606ff487a4c4863e18509,连接eqIdc63e36329f5e0979f5ee776ac5d06327,eqId85c4bdfb0db1e31e8459df1d15f9ab55.当eqId9810b815b1bdaadc68c6aa49d2cc76f7的值最小时,请直接写出eqIdd40b319212a7e7528b053e1c7097e966的长.

3.如图,已知eqId3798a74058ec4bc40b6d9b5d268c359b,eqId5a16dc02090b6e9263555061f14fbc8c,eqId9a08599072e368d5a36cf72583853f4c.

@@@76349981-5bd7-4456-8b34-3de56a2cd4b5  page number 0

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(1)求证:eqIde294887ab065cedf03b77f49292bc6a9;

(2)求eqIdf9940b7a52cfb34f91389c8adac6b69e的度数;

(3)过点eqId2a30f3a8b673cc28bd90c50cf1a35281作eqId0077f024597a51e2bb621d554b61711a交eqId60ef95894ceebaf236170e8832dcf7e3的延长线于点eqIdac047e91852b91af639feec23a9598b2,过点eqIdac047e91852b91af639feec23a9598b2作eqId14f8900d164875e70cbdd6a906abf1d9交eqId9e52a8f07834cbbbe4224962672fbbb2的延长线于点eqIddad2a36927223bd70f426ba06aea4b45,连接eqIdfc5adb5eb60ae4435a12d93854066298,eqId27253220fa002c1721f0aa81e37a49be,eqId1dde8112e8eb968fd042418dd632759e是直线eqId68a83fdd2ba72a2dba0b6b10bb3e06b9上的动点,当eqId5842f56211749f47dddb3b06a1510dbe的值最小时,求证:点eqId1dde8112e8eb968fd042418dd632759e与点eqId2a30f3a8b673cc28bd90c50cf1a35281重合.

4.在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f中,E是eqIdf52a58fbaf4fea03567e88a9f0f6e37e边上一点(不与点A,B重合),作点D关于eqId4eedae8d316c76e3d0b451256de03fb9的对称点F,连接eqId4cae70b8a9d2d2e96dea62c00ced04b9.

@@@1fb0e498dee54e5d8cc0994a3349c940  

(1)如图1,连接eqId49b50357a6545cae8348e3059312f520,若eqId00334461f72c07c50e1d46679eb98378,求证:E是eqIdf52a58fbaf4fea03567e88a9f0f6e37e的中点;

(2)如图2,连接eqId274cf35acb4a1748d15c39d15a9bea7b,eqIdd004d2d115b477ade6af7ddb93db0df8,作eqId962eedca18b86c8f01b8e07c00a92738于点G,M,N分别为eqId274cf35acb4a1748d15c39d15a9bea7b,eqId1e72b2e1ff83e95df048745322982451的中点,连接eqIdf50b3ae183997b707d16eb4e7f6712fa,eqId411461db15ee8086332c531e086c40c7.

①求eqIdf54c6f5286b3b913e0a2af5fea1f71ba的大小;

②猜想线段eqIdf50b3ae183997b707d16eb4e7f6712fa与eqId411461db15ee8086332c531e086c40c7的关系,并证明.

5.如图,在正方形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId2a30f3a8b673cc28bd90c50cf1a35281是边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的一点(不与eqId7f9e8449aad35c5d840a3395ea86df6d,eqIdc5db41a1f31d6baee7c69990811edb9f重合),点eqId8455657dde27aabe6adb7b188e031c11关于直线eqId68a83fdd2ba72a2dba0b6b10bb3e06b9的对称点是点eqIda0ed1ec316bc54c37c4286c208f55667,连接eqId6aa2b5e09f8ec785c59900a529390a02,eqId274cf35acb4a1748d15c39d15a9bea7b,直线eqId68a83fdd2ba72a2dba0b6b10bb3e06b9,eqId274cf35acb4a1748d15c39d15a9bea7b交于点eqIddad2a36927223bd70f426ba06aea4b45,连接eqIdd004d2d115b477ade6af7ddb93db0df8.

@@@cda0fa71-8a73-41cc-9567-1e3a1baa9c60

(1)在图1中补全图形,eqIdf90026b96116424a245b335b1adb886b_____eqIdb48771358b76e240743bb49c497ef7fd(填“eqId392cdb9d30684cce244bef94b8d861b9”“eqId6706fe00b4e231e62d9ecbec567d526b”或“eqId4ff7942da6c3fc4005256fb1458557c0”);

(2)求证:eqId0018babdb3dc2d2445b9defe522caa0b;

(3)用等式表示线段eqIdbd33764ff4efddfe11a98a609753715c,eqIdd2be49c37e30a3ced0364c3e74d8c687,eqId4fb26d84907c923278ac4626a9d58947之间的数量关系,并证明.

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《2025年九年级数学中考二轮复习《与轴对称相关的几何动态问题探究》解答题专题提升训练》参考答案

1.(1)证明过程见详解

(2)证明过程见详解

(3)eqId5ca7d1107389675d32b56ec097464c14

【分析】(1)根据等边三角形的性质可得eqIdb17874724f5b50ff34475e5151e136e6,在eqId989bd3073d980def40e1f602d00b63da中,由三角形内角和定理即可求解;

(2)根据等边三角形的性质可证eqIdfe126c539ccca00a55a34933ca738b02,得到eqId03eb6cb89119721d3201fc436850bc30,由此即可求解;

(3)如图所示,作点eqId7f9e8449aad35c5d840a3395ea86df6d关于eqIda6b41d4070854edfaa24071137b314cb的对称点eqId3998da44d274e5751d357beb1fa15a02,连接eqId8a5d38ebd68808337b37e125657e10d1交eqIda6b41d4070854edfaa24071137b314cb于点eqId2a30f3a8b673cc28bd90c50cf1a35281,设eqIdb836278bda82c318521b7f56cbfa4b91与eqIda6b41d4070854edfaa24071137b314cb延长线交于点eqId1dde8112e8eb968fd042418dd632759e,根据对称的性质可得eqIdd1d2fe5730bb2ebedb3f50320aeb7c5a,此时eqId30f662e4cf38298b85e32f48747ec34b取得最小值,可证eqIdd0f9e9ce252b81c5c4ef4a98a9e6f4dd,得到eqId84beeeabf4d73206bbbe294b7a1264e7,由此即可求解.

【详解】(1)证明:∵eqIde428e7a09732be85c1224e9c8f6a71c5是等边三角形,

∴eqId31d0eeeea8625c69dca3997b7db13273,

∵eqIdf1c8029d595ad6792877ce32532869e7是等边三角形,

∴eqId37dd74a6a24849bd20fe7c73f5f640a0,

当点eqId8455657dde27aabe6adb7b188e031c11是eqIde1a9c6a736e6eac98a676fa3232db5a5中点时,eqId84757ce6c1f91aa44edc5a69cf0516a7,

∴eqId4b6c2c41a5410e091433dcaff24a1c75,

∴eqId9fa903529afdee02f351a8444e122794,

设eqId2e0f8dfc388a4504dfdd3642677e82c9交于点eqIdac047e91852b91af639feec23a9598b2,

@@@3fe69704-a51c-4d35-8048-2ab30f2b4634

在eqId989bd3073d980def40e1f602d00b63da中,eqId64138240cf84ff446e35c87e17346833,

∴eqId4096dc2e1dd2abac5f0a8cf617132124,

∴eqIdf6402a3bb6be38f5bfafacc86c7bd008;

(2)证明:∵eqId702c773211303a5df135785386cd1b9d都是等边三角形,

∴eqId68e3396908ed4c3bb22297c6d5a949b1,page number 2

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