代数新定义问题常考考点预测练2025年中考数学三轮复习备考

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代数新定义问题常考考点预测练

2025年中考数学三轮复习备考

 

 

1.对于有理数a、b,定义一种新运算:eqId53e80e73c8f92265e7ec210e7a59507c

(1)计算eqIdf1dde5c7a6d155463cc21172347c5168的值

(2)若m是最大的负整数,n的绝对值是3,计算eqIdfc09674f5b48f28caa96310fc0703c5a

2.定义一种新运算:对任意有理数a,b都有eqIda2e0774a0646e5549aba86e4f00e82d3,例如:eqIdc5b1552ddb779a3a2c9aabd0b9c9d69d.

(1)求eqId7f8aafbf7f78789cefbf967f8177f767的值;

(2)化简并求值:eqIde02850d76a2230105d5a53d66a467758,其中a,b互为相反数,x是最大的负整数.

(3)已知eqId5e17b434a356e85fe12f5d1e8a2c0195与eqId230cfac15ff16d9c0ba6c50e90eebb76的差中不含eqId9b0a89e3c30f6e4d4c5db4378b05d987项,求a的值.

3.定义一种新运算“※”,eqId0272d21a4403cb57377dc4f4810b56be,例如eqId470fe90d08769d3880952a6be9101ea4.

(1)eqId5d27c21b411293c6495633563c6d2364______;

(2)当eqIdd0db2c49919467a2e14540f2aabd05cb时,求eqId9e22d02d8ee8848016d037821e93d5d7的值.

4.对于实数a,b,定义新运算“*”,规定如下:eqIdadf278fe10c350425394936209abf8c8.

例如:eqId0c46d5d6f01a241683a5ff22f74f82d9.

(1)若eqId12b40b1544e62be8b9e9f4dc9f2c0c74,求eqId662068773926ac024904d9565a8f3b97的值.

(2)若eqId063df5c2717a9e5eec46cadde54f35d4,求eqIdfa1a66103aacaf8101f040016d4c0c4e的值.

(3)若eqId8792eaab0b6464e5d07436c64aa751a2,eqId58b0ba5c937b27a27b5ef5ab9e51a935,求eqId7b15c623159d8401e528258212119573的值.

5.对于eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886定义一种新运算,规定eqId1ff87a29e29658b6bf7841d7758d5dfd(其中eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1均为非零常数),例如:eqId8a992b64686b2848580148be416c2a6f.

(1)eqId7e6afc6f222ebaaa478ea33fb5f1b6e2___________(用含有eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1的代数式表示).

(2)已知eqId5472ff553cf1837f538b2af656fda7ed,且eqId710f5f7ad74c1696cb471d039ab835f0.

①求eqId0a6936d370d6a238a608ca56f87198de,eqId2c94bb12cee76221e13f9ef955b0aab1的值;

②直接写出eqId59ea867344e3acd2dd6d200dac7f98f4的值为___________.

6.我们规定一种新定义:eqId3c9f60792da960542e0f146deb1c9857,其中符号“※”是我们规定的一种新定 义,如eqId8484c3f4bfccc988304498475a84c1bc.

(1)根据新定义计算:eqIda629cbc52ad93aa697fedad52814f127;

(2)已知eqId05a8c5cdc1bf4e7692a8986e8b58d1db,求b的值.

(3)若eqId3d534e3c13cdd68bb85779461968ef2c,求eqId4b8320960b778c31e82c72a82aaeaaba的值.

7.定义∶对于一个两位数eqId81dea63b8ce3e51adf66cf7b9982a248,如果eqId81dea63b8ce3e51adf66cf7b9982a248满足个位数字与十位数字互不相同,且都不为零,那么称这个两位数为“相异数”,将一个“相异数”的个位数字与十位数字对调后得到一个新的两位数,将这个新两位数和原两位数的和除以eqId2d0b71b8d2c183154221f717ce09077b得到的商记为eqId3888740fa8b552b55b4a0c8ae4166007.例如∶eqIdc78daf39ea522a6b4584ca2b699ba720,对调个位数字与十位数字得到的新两位数为eqId814397354c2ae1cb08e0271305970811,新两位数与原两位数page number 0

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的和为eqIddc228f5ffd23ca544083fe5c7bdd5de4,eqId92128c6c226ce688bc160fb86854f2fc除以11的商为eqId90fc7ed1ea9a0656c5ec712b4d1f3e4e,所以eqId4ae4ec6a327a51b32a33fa64c76ea4e0.

(1)下列两位数∶eqIdd07ae0b4264da6a8812454ffd2f20d94,eqId3c2f0486c5492c0a71c2e63edcb60033,eqId3ef0a9f421547e737ec464d29b314403中,“相异数”为______,计算∶eqIde653f9b4678cb7edb2a67bd40624040d______;

(2)若一个“相异数”eqIdd053b14c8588eee2acbbe44fc37a6886的十位数字是eqIdf0a532e15e232cb4b99a8d4d07c89575,个位数字是eqIdb0b26b2c701580aa8cc7aaf3e414692e,且eqId5113d95632f02b4c4794cde885054556,求“相异数”eqIdd053b14c8588eee2acbbe44fc37a6886的值;

(3)小美同学发现∶若eqIdd29ba0e24bf4a3e4b19f7120aafc3db5,则“相异数”x的个位数字与十位数字之和一定为eqId6f8c4c029e552954bd493b49aeab82d5,请判断小美同学的发现是否正确.如果正确,请说明理由;如果不正确,请举出反例.

8.定义:对任意一个两位数eqId0a6936d370d6a238a608ca56f87198de,如果eqId0a6936d370d6a238a608ca56f87198de满足个位数字比十位数字大eqId5ca7d1107389675d32b56ec097464c14,那么称这个两位数为“慧泉数”eqIdc90282d4a37c9a20620d4bbb0c263cae将一个“慧泉数”的个位数字与十位数字对调后得到一个新的两位数,把这个新两位数与原两位数的和与eqId2d0b71b8d2c183154221f717ce09077b的商记为eqId2f484115a9df1b6060d6b14df85c6f38.例如:eqId486160ebd73a249a96d369f8249cf114,对调个位数字与十位数字后得到新的两位数为eqId4b1a11655c1e9668515ca8551cbd8b3b,新两位数与原两位数的和为eqId0a81f0eca60d684864494616f49d49de,其和与eqId2d0b71b8d2c183154221f717ce09077b的商为:eqId90fc7ed1ea9a0656c5ec712b4d1f3e4e,所以eqIdc8b0f4cbd6aca76f9e7579c001bc221c.

根据以上定义,回答下列问题:

(1)eqId0a5e46f42a8346c3c6a8518e02e28d54______;

(2)若eqId57028e0fa0660921c974514e09b2d7f6,求eqId0a6936d370d6a238a608ca56f87198de;

(3)如果一个“慧泉数”eqId294f5ba74cdf695fc9a8a8e52f421328的十位数字是eqId81dea63b8ce3e51adf66cf7b9982a248,另一个“慧泉数”eqIdb6a24198bd04c29321ae5dc5a28fe421的个位数字是eqId81dea63b8ce3e51adf66cf7b9982a248,且满足eqId6bbf7b032457e5a956442c48d28cdf7c,求eqId294f5ba74cdf695fc9a8a8e52f421328、eqIdb6a24198bd04c29321ae5dc5a28fe421的值.

9.定义一种新运算“※”,其规则为eqId85acc6ad31b0df4ff22db7358dc91a34(等式右边的运算为平常的加、减、乘法运算).

例如,eqId3c53d0ad54dbaf2fd1fcf7e010ac9c09,eqId26af0d552c5ab2b4452b8a2efe692fde.

(1)根据规则计算eqId9520adb1880497f29664a5783673b463值为______;

(2)已知eqIdca27cc54ca0332245f5167488daa3408,eqId11fbf630427da7e2520a3318e9483a40,试求eqId306072b9ef6dfa6e871fe4d45841df0d的值.

10.定义:对任意一个两位数eqId0a6936d370d6a238a608ca56f87198de,如果eqId0a6936d370d6a238a608ca56f87198de满足个位数字与十位数字互不相同,且都不为零那么称这个两位数为“互异数”.将一个“互异数”的个位数字与十位数字对调后得到一个新的两位数,把这个新两位数与原两位数的和与11的商记为eqId2f484115a9df1b6060d6b14df85c6f38.例如:eqId22a688b51f4862f610d3064199aeb336,对调个位数字与十位数字得到新两位数21,新两位数与原两位数的和为eqId429292d13b3dc2722028089604a5ed88,和与11的商为eqId5460730d1c4ea128323bba0f813b131f,所以eqIdbac24190a701c808a2c2552488045978.根据以上定义,回答下列问题:

(1)①下列两位数:50,44,35中,“互异数”为______;②计算:eqId6ffd142b7c01fc6de67cc8f1cb3bb527 ______;

(2)一个“互异数”eqId2c94bb12cee76221e13f9ef955b0aab1的十位数字是eqId294f5ba74cdf695fc9a8a8e52f421328,个位数字是eqIdb6a24198bd04c29321ae5dc5a28fe421,且eqId1734333c64d445ffb88d719827a1969c,求eqId35770a47ffcba6bf1d94eceabb416d96的值;

(3)如果一个“互异数”eqId071a7e733d466949ac935b4b8ee8d183的十位数字是eqId394aee19f94c2b70fcce1d69b31dc7fd,个位数字是eqId028ad9cf772b0c071866972f303528fe,且eqId2819a55a0a70f60ffd2b974921f98031,求“互异数”eqId071a7e733d466949ac935b4b8ee8d183的值.

11.定义一种新运算eqIdf5e7256d86c51406384a89d5b4102da5:对于任意有理数eqId81dea63b8ce3e51adf66cf7b9982a248和eqIdd053b14c8588eee2acbbe44fc37a6886,有eqId0dbfa5cbc5cad801d1b0e389daa578a5,eqIdb6a24198bd04c29321ae5dc5a28fe421为常数且eqIda70d2613a895b9be7cb32840a6499340,如:eqId6725cf92386ea7bd699d71802a74ca4d.

(1)①eqId7fcbd5bba455cacef5b06ac9631ba588=  (用含有m,n的式子表示);

②若eqId789a17b5982303eaae8577adf0ac9040,求eqId0d9510e83d77d05a613fb0e61f4ef8a7的值;

(2)请你写出一组m,n的值,使得对于任意有理数eqId81dea63b8ce3e51adf66cf7b9982a248,eqIdd053b14c8588eee2acbbe44fc37a6886,eqIdba64f167983b97b8265ae4b7cafe889d均成立.

12.定义一种新运算,观察下列各式:

eqIde204acd705e334a7e28a729e4fbc4cbf;

eqId8c5779092b07658a598f71c6eb94b28e;page number 1

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eqIdd46ae33171fe4cd7d92185f28d85d8b1;

eqId9805b89a4946cb5fc824b50b5838db2e;

(1)请你想一想:用代数式表示eqIdfe5597cb382642e0b153ac3e5294c48e的结果为_______________;

(2)若eqId2958030ec9d7543dda1f529593a915e2,那么eqIdfe5597cb382642e0b153ac3e5294c48e_______________eqIdfd6a6da0ee0cab0a9091f4f27dfe24ed(填入“=”或“eqId411837b4b3078d05b43cb0439259a362”);

(3)若eqId9d745c8b1349fb0da1e4692763f9bf95,请计算eqId3eb359e775ab9b28d82e48fbabcdb1e9的值.

13.对于有理数a,b,定义了一种新运算“※”为eqIdf8a2951dc52277d29e9973d13b9b569a,如:eqIda4c73d245371b8036d283b8bf8e1aadd,eqId6d05d2a2acfbda1f062633d777bbcad6.

(1)计算:①eqId5296b6d015559a30cd7c8cd793d733bd  ;②eqIde46aee8c45efa21249493f80734b4b6b  ;

(2)若eqIdec518ee04e54ca8284fc2f6028811956是关于x的一元一次方程,且方程的解为eqId707ea658f3a9359f5740d5aab48f7948,求m的值;

(3)若eqId98d0b9c0c01b49be6e08a111568f77f4,eqId4c24e4e521bce2dc09cc10690bfe39b7,且eqId3799b445cfd1794e76a000197cabbd51,求eqIdce0439d24d203bcd2b76fb684bcb4e79的值.

14.用“eqIdf85d735e2b3e384ef63d04025edf87eb”定义一种新运算:对于任何有理数eqId81dea63b8ce3e51adf66cf7b9982a248和eqIdd053b14c8588eee2acbbe44fc37a6886,规定eqIdaabf438b18cf944f0ababc42cc86d374.

(1)若eqId57ecda8d9c3dc0aee187c084cd102bb4,求eqId294f5ba74cdf695fc9a8a8e52f421328的最大整数;

(2)若关于eqIdb6a24198bd04c29321ae5dc5a28fe421的方程满足:eqIdfe21776832c9e1d3a6eb79f2631efa23,求eqIdb6a24198bd04c29321ae5dc5a28fe421的值;

(3)若eqId6f8e9939ff9c87e2824a3e85cc1346b0,eqIdc3416c992a41b013a9b51d11e7d30752,且eqId8653f3769c890224a9498393fba08008,求eqIda13bbe4362d9e2b1be9c93cda3bc898b的值.

15.将eqIdb6a24198bd04c29321ae5dc5a28fe421个0或1排列在一起组成了一个数组,记为eqIde3e318c31fa300e8c98e57ab37ff1ab8,其中,eqId03cac6f8bd373767fee6641563cb6867都取0或1,称eqId5963abe8f421bd99a2aaa94831a951e9是一个eqIdb6a24198bd04c29321ae5dc5a28fe421元完美数组(eqId0704f453b2de48d36911f7db496bbf82且eqIdb6a24198bd04c29321ae5dc5a28fe421为整数).例如:eqId7160d93f92089ef36f3dab809d3114b8,eqId29343388ca8b33dc98325e65382b38a0都是2元完美数组,eqId8eea8e7edf0d48f140c007d9a691c0ad,eqIde8b022fd6e5e4a945b2db5c0962ecfee都是4元完美数组,但eqId990eaf5dbba84f199bdc438da81fcfa6不是任何完美数组.定义以下两个新运算:新运算1:对于eqId81dea63b8ce3e51adf66cf7b9982a248和eqIdd053b14c8588eee2acbbe44fc37a6886,eqIde3ade472f5dc4e41d237837776c871c5,

新运算2:对于任意两个eqIdb6a24198bd04c29321ae5dc5a28fe421元完美数组eqId2325f92e49201bb9c5e7750f08a256c8和eqId78c5f3bed5199a1184804a2111633cda, eqIdbd1fa653a19c2366afe7a1db6d4349c6,例如:对于3元完美数组eqIdd5e618e91505e098b24724ae26ef4a5c和eqIdb5a25e691a51136a16b1d5990a62759e,有eqIda1ebab8863e39597d3d6578baf120033.

(1)在eqId9c8bb2a267bd5fd30513a259168c50f9,eqId4b65d25c58d96aa21a850d164cdccb22,eqId9effd17c153f28ce1cf21fd174606819,eqId98b01af54049b27ca6e8159518b7b18b中是3元完美数组的有:______;

(2)设eqIdbeb810245dc7dfd3d663e55cf08bca5e,则eqId619c485c6a9a959daebbd4bad00842d3______;

(3)已知完美数组eqId1659612005a9a5fc0390d4e809e284c1求出所有4元完美数组eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3,使得eqId8b6cac9f69999485662eb40dc01a8ba1;

(4)现有eqId294f5ba74cdf695fc9a8a8e52f421328个不同的eqId4d01dd350dc95f42f1883e0cc7aae084元完美数组,eqId294f5ba74cdf695fc9a8a8e52f421328是正整数,且对于其中任意的两个完美数组eqIdc5db41a1f31d6baee7c69990811edb9f,eqId8455657dde27aabe6adb7b188e031c11均有:eqIdeca88440b325fa74f88da26e486c7846;则eqId294f5ba74cdf695fc9a8a8e52f421328的最大可能值是多少?写出答案,并给出此时这些完美数组的一个构造.

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