2025年中考数学总复习全等三角形模型的应用

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2025年中考数学总复习

全等三角形模型的应用

 

1.综合与实践:如图1,已知eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIded10df4140819d5451773a45de66201b,eqId4b10134e7a46e6f6f7cb9d5e2371727d,eqId85c4bdfb0db1e31e8459df1d15f9ab55、eqId03902478df1a55bc99703210bccab910分别与过点eqIdc5db41a1f31d6baee7c69990811edb9f的直线垂直,且垂足分别为eqId2a30f3a8b673cc28bd90c50cf1a35281,eqId8455657dde27aabe6adb7b188e031c11.

@@@b3533344-a5d8-4f8b-a6a8-3e7dcfa0cde0

(1)猜想线段eqId03902478df1a55bc99703210bccab910、eqIde6e490f703eb6c9bb1278c78ebc2d661、eqId85c4bdfb0db1e31e8459df1d15f9ab55三者之间的数量关系,并给予证明.

(2)如图2,当过点eqIdc5db41a1f31d6baee7c69990811edb9f的直线绕点eqIdc5db41a1f31d6baee7c69990811edb9f旋转到eqId15c0dbe3c080c4c4636c64803e5c1f76的内部,其他条件不变,线段eqId03902478df1a55bc99703210bccab910、eqIde6e490f703eb6c9bb1278c78ebc2d661、eqId85c4bdfb0db1e31e8459df1d15f9ab55三者之间的数量关系是否发生改变?若改变,请直接写出三者之间的数量关系,若不改变,请说明理由;

2.如图,已知eqId15c0dbe3c080c4c4636c64803e5c1f76是等腰直角三角形,动点eqIddad2a36927223bd70f426ba06aea4b45在斜边eqIdf52a58fbaf4fea03567e88a9f0f6e37e所在的直线上,以eqId48f3c9abbd78e9a6840ee5f30381daac为直角边作等腰直角eqIdba70863115b0947e98214a7b2512167d,其中eqIdfc7e85d40f8c9aee89f50e6f10c5d641,探究并解决下列问题:

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(1)如图1,若点eqIddad2a36927223bd70f426ba06aea4b45在线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e上时,猜想eqIdf02d0cbc0c9b66fca1191e39c4b647fb,eqIda479f39503902aa5176d654032eb4f32,eqId943f8d69b44b658fdcbd992215831be9三者之间的数量关系,并证明你的结论;

(2)如图2,若点eqIddad2a36927223bd70f426ba06aea4b45在eqIdf52a58fbaf4fea03567e88a9f0f6e37e的延长线上,在(1)中所猜想的eqIdf02d0cbc0c9b66fca1191e39c4b647fb,eqIda479f39503902aa5176d654032eb4f32,eqId943f8d69b44b658fdcbd992215831be9三者之间的数量关系仍然成立,请利用图2进行证明.

3.如图,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId7c3e9ef3e849788645552cfb0735d987,eqId2a46ef5fc6cdb5367efae4b8b829f5c0,点D在线段eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上运动(D不与B、C重合),连接eqId03902478df1a55bc99703210bccab910,作eqId3a9608cad892644b4094ed6438b69572,eqIde6e490f703eb6c9bb1278c78ebc2d661交线段eqId60ef95894ceebaf236170e8832dcf7e3于E.

  @@@1138b76a-74a2-4c9f-a66d-967f31bd420b

(1)当eqIdd66f960a3bcd33415c0541fe5778f9c1时,eqId06df3b822800139fd3ba2cb1ceaeaf73  °,eqIdb2b1bda34f3a04c19d5bf5f3155b6187  °;点D从B向C运动时,eqId60b47abcacc10f90489c0d52a9e269ab逐渐变  (填“大”或“小”);

(2)当eqId9e52a8f07834cbbbe4224962672fbbb2等于多少时,eqId22cda279d3cd75eeb603b14a3b94e420,请说明理由;

(3)在点D的运动过程中,eqIda25c28359f8d8da9eaf4672a6cf8ae4f的形状可以是等腰三角形吗?若可以,请直接写出eqId60b47abcacc10f90489c0d52a9e269ab的度数.若不可以,请说明理由.

4.如图,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId23b6e08fde74010412a6f14ad4dfbcc9,eqIdcd95dc30c0344788b94289c464a3158e,eqId2f10d7b2b90d572faa0834128a3199d3,eqId9547f6b5c7c54d216ecea72becb7d373,page number 0

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(1)求eqId03902478df1a55bc99703210bccab910的长;

(2)点eqId2a30f3a8b673cc28bd90c50cf1a35281从点eqId5963abe8f421bd99a2aaa94831a951e9出发以每秒eqIdc78d0ab561d0c9bb9099772c596af8bf速度沿着射线eqIdf52a58fbaf4fea03567e88a9f0f6e37e运动,设运动时间为eqId36a1b09c653185842513e24ebba60bb3秒,点eqIda0ed1ec316bc54c37c4286c208f55667在射线eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,且eqId68b86e8d9d1fb0fc568721e61bee99a7.

①如图1,若点E在线段eqIdf52a58fbaf4fea03567e88a9f0f6e37e上,判断线段eqId74a3e51bebe0374a14b8ba31f76f662e之间的数量关系,并加以证明.

②在整个运动过程中,求eqId5f2ea13010e2399194be2a681310543e的周长(结果可用含eqId36a1b09c653185842513e24ebba60bb3的式子表示).

5.已知在eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f中,eqId26813466e2ee49a493881a4384fc8748,eqId047dc9795efa99b6fb9fdf9778085dab,eqIde2d212c1709b8e72a055cf1b5381ef64,点D是直线eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的一动点(点D不与点B,C重合),连接eqId4eedae8d316c76e3d0b451256de03fb9.

@@@4bf79016-6e07-4b6e-abaf-6f56cc16ca5e

(1)在图①中,当点D在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上时,求证:eqId031ee2eebc08cbb43325b98d142f9578;(提示:证全等)

(2)在图②中,当点D在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的延长线上时,结论eqId031ee2eebc08cbb43325b98d142f9578是否成立?若不成立,请猜想eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId4eedae8d316c76e3d0b451256de03fb9,eqId9d78abbad68bbbf12af10cd40ef4c353之间存在的数量关系,并说明理由;猜想eqId4eedae8d316c76e3d0b451256de03fb9与eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的位置关系,并说明理由;

(3)在图③中,当点D在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的反向延长线上时,补全图形,不需要写证明过程,直接写出eqId0dc5c9827dfd0be5a9c85962d6ccbfb1,eqId4eedae8d316c76e3d0b451256de03fb9,eqId9d78abbad68bbbf12af10cd40ef4c353间存在的数量关系.

6.综合与探究

发现问题:

(1)如图1,在eqIddd967903ed5a6f640a5b801ec8be0070与eqId4c2598f844644c4245eb226ecca57ee4中,eqIde93f8549c94a98fc8b633a96dee7fbce,eqId212bfbd5575772ca36d6fc3e7b246e49,eqId7f9e8449aad35c5d840a3395ea86df6d,eqIdc5db41a1f31d6baee7c69990811edb9f,eqId2a30f3a8b673cc28bd90c50cf1a35281三点在同一直线上.若eqIdf5cef5f71528e58757f7bf215062adb3,eqId1b9f1feb79ffb2d8cb46132f9a8eee20,则eqIdd4f76e37d6e6b182896ccaaa187cfe07______.

提出问题:

(2)如图2,在eqIddd967903ed5a6f640a5b801ec8be0070中,eqId45acdbac251ca6b76a166c1242e71df9,eqIdef0402dd5ae3db10281f9f1e11738bcb,将eqId60ef95894ceebaf236170e8832dcf7e3绕点eqIdc5db41a1f31d6baee7c69990811edb9f顺时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到eqId9e52a8f07834cbbbe4224962672fbbb2,连结eqIdd40b319212a7e7528b053e1c7097e966,求eqId661ff55b5ebbadfb600989af3cfce2fd的面积.

灵活应用:

(3)如图3,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,将eqIdf52a58fbaf4fea03567e88a9f0f6e37e绕点eqId5963abe8f421bd99a2aaa94831a951e9顺时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到eqId68a83fdd2ba72a2dba0b6b10bb3e06b9,将eqId60ef95894ceebaf236170e8832dcf7e3绕点eqId5963abe8f421bd99a2aaa94831a951e9逆时针旋转eqIdc02b54dc6b3e1bb6544f47d4c8743fcf得到eqId77a7e4a6765ce78b05ee97764771e01f,连结eqId31e55e398e8520d8a36fb5a625a085b8,过点eqId5963abe8f421bd99a2aaa94831a951e9作eqIdff4744b427f036dfbc6db68c87cd5c54于点eqId73465a1f9aa03481295bf6bd3c6903ac,延长eqId184921a45f87423e92cf1e627ad55143交eqId31e55e398e8520d8a36fb5a625a085b8于点eqIde105760638b22b26ff8bec4354255e4c.求证:eqIde105760638b22b26ff8bec4354255e4c是eqId31e55e398e8520d8a36fb5a625a085b8的中点.

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7.如图,回答下列题:page number 1

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【操作发现】

如图(1),在eqId3fe95f656b98b53f71a9d72bf0c9a4b9和eqId4807ca16360c0cca436e59d4be98f626中,eqId9fca3734de79f7f50b552ef62b29dc7c,eqId33cbad6599796efc1c177ae9349feda9,eqIdb1276bed26dfc63138b7a24136e2fdea,连接eqId60ef95894ceebaf236170e8832dcf7e3,eqIdd40b319212a7e7528b053e1c7097e966交于点M.

①eqId60ef95894ceebaf236170e8832dcf7e3与eqIdd40b319212a7e7528b053e1c7097e966之间的数量关系为_________;

②eqIdb2f9c3b578fc0598d5ec6c79404c6cc2的度数为_________;

【类比探究】

如图(2),在eqId3fe95f656b98b53f71a9d72bf0c9a4b9和eqId4807ca16360c0cca436e59d4be98f626中,eqIde3d3c378b1118d331d30b63fc587b270,eqId332084cfb20ebc7efa528abeb9c49e07,连接eqId60ef95894ceebaf236170e8832dcf7e3,交eqIdd40b319212a7e7528b053e1c7097e966的延长线于点M,请计算eqId11c0fed1bec279a67db01c918711d4f5的值及eqIdb2f9c3b578fc0598d5ec6c79404c6cc2的度数.

【实际应用】

如图(3),是一个由两个都含有eqIdf6b86c22b670a8e9f3896f9e8883fbbb角的大小不同的直角三角板eqId7bef5239ddbb0972700ce01daf9ee7cf、eqId422210c777ac0d625bbd81cc7601bf9b组成的图形,其中eqId0fc75953bf5dcfa4af308c34bf9952d3,eqIdb9726297323de4c8509d4742bb526602,绕点C转动其中较小的三角板,使得点D、E、B在同一直线上,eqId348fb71fbc47fd87e9ce011652ef4186,eqIdea3f00496643c3411f7f21d161830b19,请直接写出eqId03902478df1a55bc99703210bccab910之间的距离.

8.如图1,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId9ed8f7d3d7043d4b1eb98fc5c4e2fcd3,eqId3d89ba4036a5d18ec4abed44d7fd8e89,点eqId8455657dde27aabe6adb7b188e031c11在边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上,点eqId2a30f3a8b673cc28bd90c50cf1a35281在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e的延长线上,且eqId810242c9205006b28c6bc6612c2b1cd0.

@@@cc8142c4-674a-4664-a8c9-b7bfc7286744

(1)设eqIdb2a9ab5a9114daaa0fd3f6c5f1885f90,求eqId9d3e081637bcea5368cc72370bae283b的度数(用含eqIde170f206fdbbd834aad7580c727e2cc6的代数式表示).

(2)如图2,过点eqId8455657dde27aabe6adb7b188e031c11作eqIdeba49c4f6fd70a72785074a7e2d974c4,交eqId60ef95894ceebaf236170e8832dcf7e3于点eqIda0ed1ec316bc54c37c4286c208f55667,求证:eqId92034dd2bb9480b18709d01153467f8f.

(3)如图3,在边eqIdf52a58fbaf4fea03567e88a9f0f6e37e上取点eqIdac047e91852b91af639feec23a9598b2,使eqIdc733f446c75747b0477e9b42df458f01,作eqId685d7f4b01cb83c7165de819aa5ec6b6交eqIdbe2e2c0d4ac2bd79f6cea7a9b1a50662的延长线于点eqId54a5d7d3b6b63fe5c24c3907b7a8eaa3,若eqIddb65c1d07d95810704181b60bb25e3d0,eqIdfc5b211e09882e0106aac524801eb4a1,求eqId85c4bdfb0db1e31e8459df1d15f9ab55的长.

9.课外兴趣小组活动时,老师提出了如下问题:如图1,eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId03902478df1a55bc99703210bccab910是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线,若eqId54275b7e571660d0a9e0370fbfe5050b,eqIdecf7679c8b4b1e442ce4286d4b0e9c32,求边eqId60ef95894ceebaf236170e8832dcf7e3的取值范围.小琪同学在组内经过合作交流,得到了如下的解决方法:延长eqId03902478df1a55bc99703210bccab910至点eqId2a30f3a8b673cc28bd90c50cf1a35281,使eqId0ad98ad714864041a632ca949308e417,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,请根据小琪的方法思考:

@@@edcd1f4b-91ef-467b-8bad-f7d0ae6aa345

(1)由已知和作图能得到eqIded22093ece26eca6dfdb31d58698c929,依据是________.

A.SSS    B.SAS    C.AAS

(2)由“三角形的三边关系”可求得边eqId60ef95894ceebaf236170e8832dcf7e3的取值范围是_____________.

解后反思:题目中出现“中点”、“中线”等条件,可考虑延长中线构造全等三角形,把分散的已知条件和所求证的结论集中到同一个三角形之中.

【感悟方法】page number 2

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