2025年中考数学专题突破系列:倍长中线模型

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2025年中考数学专题突破系列:倍长中线模型

1.倍长中线是初中数学一种重要的数学思想.某同学在学习过程中,遇到这样的一个问题:如图1:在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId305a88d4e0249bd16d48eda01331d2d4,eqIda8a7b5adfcac0f46a4cd19da4ebb4a2b,求eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线eqId03902478df1a55bc99703210bccab910的取值范围,经过和小组同学的探讨,共同得到了这样的解决方法:延长eqId03902478df1a55bc99703210bccab910到点E,使eqId0ad98ad714864041a632ca949308e417.请根据他们的方法解决以下问题:

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(1)求eqId03902478df1a55bc99703210bccab910的取值范围:_________.

【问题解决】请利用上述方法(倍长中线)解决下列三个问题:

如图:已知eqIdaabd1d9b7e7f7ecb788ff542218af2b9,eqId047dc9795efa99b6fb9fdf9778085dab,eqIdd831c9ba6d18774540e2aaa29132fec9,eqIddad2a36927223bd70f426ba06aea4b45为eqId85c4bdfb0db1e31e8459df1d15f9ab55的中点;

(2)如图 2,若A、C、D三点共线,eqId9cc931adf299249990ed3d2481a25729,eqId749081528d5b9140ab6183b4e391f068,求eqIdd428461f76afe63771722ae7cda7b9e7;

(3)如图3,若A、C、D三点不共线,eqIda6698d3452602370e219ec33b4882441,求证:eqId36c4559d27e3905980d1a4f1856f07de.

2.(1)如图①,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,若eqIdfc34db5860990e51ba31edc8cdd077c2,eqIdf1682d306c38087d9e6f7efb9cec596a,则eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线eqId03902478df1a55bc99703210bccab910的取值范围是_____;

(2)如图②,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,D是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中点,eqId3efffb3e6a571832b723b3c5795b8e8c于点eqId59ef303fe88a634f3e5add24867fcbd1交eqIdf52a58fbaf4fea03567e88a9f0f6e37e于点eqId0f18adb1decb7786539ce7311567bc91交eqId60ef95894ceebaf236170e8832dcf7e3于点F,连接eqId49b50357a6545cae8348e3059312f520,求证:eqId74aa9a5332ccc8993faa3074ca643224;

(3)如图③,在四边形eqId411b38a18046fea8e9fab1f9f9b80a5f中,eqId173904239da66b7bef7cb1d997cc40ed,eqIda651eb577dbada1f29590e558d6f9fa2,eqId88ceedfc3cd57591792567c8beb7bedd,以eqIdc5db41a1f31d6baee7c69990811edb9f为顶点作一个eqId16aa0b9869db50a9ab48cc32925d8e96角,角的两边分别交eqIdf52a58fbaf4fea03567e88a9f0f6e37e,eqId03902478df1a55bc99703210bccab910于E,F两点,连接eqId49b50357a6545cae8348e3059312f520,探索线段eqId85c4bdfb0db1e31e8459df1d15f9ab55,eqIdd004d2d115b477ade6af7ddb93db0df8,eqId49b50357a6545cae8348e3059312f520之间的数量关系,并加以证明.

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3.【特例感知】

如图1,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId2664e0c44eaa5487cd8b99772f68a80a,求边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的中线eqId03902478df1a55bc99703210bccab910的取值范围.page number 0

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(1)中线eqId03902478df1a55bc99703210bccab910的取值范围是______.

【类比迁移】

(2)如图2,在四边形eqIde1d70676406f26d339465fe3473c0c05中,eqIddad2a36927223bd70f426ba06aea4b45为eqId85c4bdfb0db1e31e8459df1d15f9ab55的中点,点eqIdc5db41a1f31d6baee7c69990811edb9f在eqId03902478df1a55bc99703210bccab910上,eqIde11077e0d3504381e2c299b74bbd074a,eqIdf56a758cace44a5265702a27900ef07e,求证:eqId20a541b81584a032f571159ea152c85a平分eqId7cbce11aa19b8bd2bf6ee5a834e005de.

【拓展应用】

(3)如图3,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId03902478df1a55bc99703210bccab910是边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的中线,E是eqId03902478df1a55bc99703210bccab910上一点,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55并延长交eqId60ef95894ceebaf236170e8832dcf7e3于点F,eqIdf2e59617707e98c3441445392333b491,求证:eqId1120e471627069e78a6733af07687684.

4.小雨同学喜欢学习数学,他喜欢不断地主动探索思考,总结方法,探究问题的本质.学完三角形的中线,他主动进行探究:如图1,eqId8455657dde27aabe6adb7b188e031c11是eqId15c0dbe3c080c4c4636c64803e5c1f76的边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,连接eqId03902478df1a55bc99703210bccab910,则eqId03902478df1a55bc99703210bccab910为边eqId0dc5c9827dfd0be5a9c85962d6ccbfb1上的中线.他尝试延长eqId03902478df1a55bc99703210bccab910到点eqId2a30f3a8b673cc28bd90c50cf1a35281,使得eqId0ad98ad714864041a632ca949308e417,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,发现eqIdc3d62d8fa4b680a59ece602d06167ee3.

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请根据小雨的探究过程,解答下面的问题.

如图2,eqId03902478df1a55bc99703210bccab910是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId2a30f3a8b673cc28bd90c50cf1a35281在eqId60ef95894ceebaf236170e8832dcf7e3上,连接eqId85c4bdfb0db1e31e8459df1d15f9ab55,与eqId03902478df1a55bc99703210bccab910交于点eqIda0ed1ec316bc54c37c4286c208f55667,且eqIda5787c784b686435a2073bdeb836307c.试说明eqId401fd36b192170a8ed24e8cd3e682779.

5.几何探究与实践page number 1

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(1)【模型认识】如图1所示,已知在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId29edec1f0ccd57a096fa9ef344d23568,分别以eqIdf0d54431bbb28ebd98db5c1dc6083a75为直角边构造等腰直角三角形eqId7abd284f76d9f5769bc189508ce2572b和eqId4c66d99a6a8415ddad22bbed33b64cfb,连接eqIdb75e2eaf6394f3b07703e4176541b7f3,则eqId85c4bdfb0db1e31e8459df1d15f9ab55与eqId9d78abbad68bbbf12af10cd40ef4c353的关系是: ;

(2)【初步应用】如图2所示,连接eqIde6e490f703eb6c9bb1278c78ebc2d661,求证:eqIdd1df6b1b2748edf7c4a2e69263d300f3;

(3)【深入研究】在(2)的条件下,试判断eqId15c0dbe3c080c4c4636c64803e5c1f76和eqIda25c28359f8d8da9eaf4672a6cf8ae4f的面积有何关系,并加以证明;

(4)【拓广探索】如图3,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqIdeb3f8cb648966fd4ff28896fe8f9e04d,eqIdcedd51383f8f047f565191b128cec637,eqId7bb5b12692517a39c320f99a479eb055,以eqId0dc5c9827dfd0be5a9c85962d6ccbfb1为直角边构造等腰直角三角形eqIdc1b489c25405ce48699d4f0a62820bed,且eqId142b5bb5452fa06ab3d0d556ae1b9088,连接eqId20a541b81584a032f571159ea152c85a,试直接写出eqId20a541b81584a032f571159ea152c85a的长度.

6.某数学兴趣小组在活动时,老师提出了这样一个问题:如图1,在eqId15c0dbe3c080c4c4636c64803e5c1f76中,eqId305a88d4e0249bd16d48eda01331d2d4,eqId4494a85de0be0b97a69348115aef8513,D是eqId0dc5c9827dfd0be5a9c85962d6ccbfb1的中点,求eqId0dc5c9827dfd0be5a9c85962d6ccbfb1边上的中线eqId03902478df1a55bc99703210bccab910的取值范围.小明在组内经过合作交流,得到了如下的解决方法:延长eqId03902478df1a55bc99703210bccab910到E,使eqId0ad98ad714864041a632ca949308e417,请补充证明(1)中“eqIdbd84a6a27b9a9f3f3e4a9baf8c2235f2”的推理过程.

@@@9bff3bf9-0c25-493f-99df-5d2527ac9f06

(1)求证:eqIdbd84a6a27b9a9f3f3e4a9baf8c2235f2

证明:延长eqId03902478df1a55bc99703210bccab910到点E,使eqId0ad98ad714864041a632ca949308e417.

(2)由(1)的结论,根据eqId03902478df1a55bc99703210bccab910与eqId68a83fdd2ba72a2dba0b6b10bb3e06b9之间的关系,探究得出eqId03902478df1a55bc99703210bccab910的取值范围是___________;

【小结】将上面题中“eqId305a88d4e0249bd16d48eda01331d2d4,eqId4494a85de0be0b97a69348115aef8513”改为eqIdfa375c3888b332f24e7d0f9b9600c694,eqIdf19a6aeeea5bd6e49c1eb86b7a22e7c7,且eqIdcb7961cbe98aac6a5fdee94582c341b4”,则eqId88929f4ba0851730d5f941d426b87548的取值范围是__________(用m,n的代数式表示)

【感悟】解题时,条件中若出现“中点”“中线”等字样,可以考虑延长中线构造全等三角形,把分散的已知条件和所求证的结论集合到同一个三角形中.

【问题解决】如图2,eqId60d9142db4dd2ef151bf3d4a63afb61e,eqIdefc6e4b936d7a800e839a30c3839574d,eqId88929f4ba0851730d5f941d426b87548是eqId15c0dbe3c080c4c4636c64803e5c1f76的中线,eqId531d6f90f144551a35d494b1fe7d2b89,eqIdc8832c5450a61500ccbf73d95e16f449,且page number 2

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